Two carts sit on a horizontal, frictionless track; the spring between them is compressed. The small cart has mass m, and the mass of the larger cart is M = 5.29m. NOTE: Every velocity needs magnitude and direction (given by the sign).
a) Suppose the carts are initially at rest, and after the "explosion" the smaller cart is moving at velocity v = +4.88 m/s. - Find the velocity of the larger cart. V =
Assume now that the mass of the smaller cart is m = 8.91 kg. Assuming there is no loss of energy: find the energy stored in the spring before the explosion. Wk =
If the spring has spring constant k = 935 N/m: find x, the distance the spring was compressed before the "explosion".
b) Suppose the carts are initially moving together, with the spring compressed between them, at constant velocity vo = +9.39 m/s. After the "explosion", the smaller cart is moving at velocity v = +4.88 m/s. Find the velocity of the larger cart.
c) Suppose now that the small cart (mass m) is initially moving at velocity vo = +3.3 m/s. At what velocity would the large cart (mass 5.29m) have to be moving so, when they collide and stick together, they remain at rest?
If you can show the work/ provide explanation I would greatly appreciate it :) Thanks
In: Physics
Ironman steps from the top of a tall building. He falls freely from rest to the ground a distance of h. He falls a distance of h/ 4 in the last interval of time of 1.0 s of his fall.
Hint: First, compute the velocity when Ironman reaches the height equal to the distance fallen. This requires that you do the following: define origin as the bottom of the building. Then use x-x0 = -v0*(t-t0)-(1/2)g(t-t0)^2 where x=0 and x0= (distance fallen) and t-t0 is the time interval given. In this formulation, you are going to get magnitude of v0 since you already inserted the sign. You then insert v0 that you just calculated into the kinematic equation that involves v, g, and displacement (v^2-v0^2 = 2g(height-(distance fallen)), but now v (which is the final velocity is v0 from above) and v0 in this case is the velocity that the Ironman has when he begins to fall, which is 0. This gives a quadratic equation for height h, and you will need to use the binomial equation to solve for h. Choose the larger of the two solutions.
Part A
What is the height h of the building?
Express your answer using two significant figures.
In: Physics
PostFixEvaluator.java
import java.util.Stack;
import java.util.Scanner;
/**
* Represents an integer evaluator of postfix expressions.
Assumes
* the operands are constants.
*
* @author Java Foundations
* @version 4.0
*/
public class PostfixEvaluator
{
private final static char ADD = '+';
private final static char SUBTRACT = '-';
private final static char MULTIPLY = '*';
private final static char DIVIDE = '/';
private Stack stack;
/**
* Sets up this evaluator by creating a new
stack.
*/
public PostfixEvaluator()
{
// complete this method
}
/**
* Evaluates the specified postfix expression. If an
operand is
* encountered, it is pushed onto the stack. If an
operator is
* encountered, two operands are popped, the operation
is
* evaluated, and the result is pushed onto the
stack.
* @param expr string representation of a postfix
expression
* @return value of the given expression
*/
public int evaluate(String expr)
{
// Step 3- complete this method
}
/**
* Determines if the specified token is an
operator.
* @param token the token to be evaluated
* @return true if token is operator
*/
private boolean isOperator(String token)
{
// Step 1 - complete this
method
}
/**
* Performs integer evaluation on a single expression
consisting of
* the specified operator and operands.
* @param operation operation to be performed
* @param op1 the first operand
* @param op2 the second operand
* @return value of the expression
*/
private int evaluateSingleOperator(char operation, int
op1, int op2)
{
// Step 2 - complete this method
}
}
PostFixTester.java
import java.util.Scanner;
/**
* Demonstrates the use of a stack to evaluate postfix
expressions.
*
* @author Java Foundations
* @version 4.0
*/
public class PostfixTester
{
/**
* Reads and evaluates multiple postfix
expressions.
*/
public static void main(String[] args)
{
String expression, again;
int result;
Scanner in = new Scanner(System.in);
do
{
PostfixEvaluator
evaluator = new PostfixEvaluator();
System.out.println("Enter a valid post-fix expression one token "
+
"at a time with a space
between each token (e.g. 5 4 + 3 2 1 - + *)");
System.out.println("Each token must be an integer or an operator
(+,-,*,/)");
expression =
in.nextLine();
result =
evaluator.evaluate(expression);
System.out.println();
System.out.println("That expression equals " + result);
System.out.print("Evaluate another expression [Y/N]? ");
again =
in.nextLine();
System.out.println();
}
while
(again.equalsIgnoreCase("y"));
}
}
Could you help, please?
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Write a javascript code to check if the JSON body follows the schema.
schema is
{
"name":"john doe",
"mood":"happy"
"major":"cs",
"date":"2024"
}
json body is
{
"name":"john doe",
"height":"170cm"
"major":"cs",
"date":"2024"
} the result should be false
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