Management of Mittel Rhein AG of Köln, Germany, would like to reduce the amount of time between when a customer places an order and when the order is shipped. For the first quarter of operations during the current year the following data were reported:

Inspection time 0.4 days Wait time (from order to start of production) 16.2 days Process time 3.4 days Move time 1.0 days Queue time 3.5 days

Required: 1. Compute the throughput time. (Round your answer to 1 decimal place.) 2. Compute the manufacturing cycle efficiency (MCE) for the quarter. (Round your percentage answer to nearest whole percent.) 3. What percentage of the throughput time was spent in non–value-added activities? (Round your percentage answer to nearest whole percent.) 4. Compute the delivery cycle time. (Round your intermediate calculations and final answer to 1 decimal place.) 5. If by using Lean Production all queue time during production is eliminated, what will be the new MCE? (Do not round intermediate calculations. Round your percentage answer to 1 decimal place.)

Use the following information to answer questions 13 through 17. Sawyer, Selbo and Shaw (SSS), an investment management firm, has compiled the following information concerning Treasury securities: Maturity Coupon Y-T-M Price 0.5 Years 0 8.0% $ 96.15 1.0 Year 0 8.3% $ 92.19 1.5 Years 8.5% 8.9% $ 99.45 2.0 Years 9.0% 9.2% $ 99.64 2.5 Years 11.0% 9.4% $103.49 3.0 Years 9.5% 9.7% $ 99.49 3.5 Years 10.0% 10.0% $100.00 4.0 Years 10.0% 10.4% $ 98.72 4.5 Years 11.5% 10.6% $103.16 5.0 Years 8.75% 10.8% $ 92.24

13. What is the one-year T-bill spot rate? (1 point)

14. What is the 1.5-year T-note theoretical spot rate? (4 points)

15. What is the two-year theoretical spot rate? (4 points)

16. What is the one-year implied forward rate six months from now? (3 points)

17. What is the one-year implied forward rate one-year from now? (3 points)

Glucose are stored as glycogen in muscle cells, from which it can again be mobilized during exercise.
a) Write down the partial reactions as well as the net yield for the conversion of glucose-6-phosphate to glycogen and for the conversion of glycogen to glucose-6-phosphate.
b) Calculate the energy required for the consumption of the total process of converting glucose-6-phosphate to glycogen and back to glucose-6-phosphate expressed as energy-rich phosphate bonds (ATP equivalents).
ΔG0’ for the reaction: ATP + H2O → ADP + Pi = –30.5 kJ∙mol-1.
c) Calculate ΔG’ for the reaction at 25 °C and pH 7, when [ATP] = 5 mM, [ADP] = 0.5 mM and [Pi] = 1.0 mM.
Phosphocreatin constitutes a small extra storage of energy within muscle cells, and is formed from phosphorylation of creatin. The reaction is catalyzed by creatine kinase and ΔG0’ for the reaction is +2.3 kJ∙mol-1 (progressing towared the formation of phosphocreatin).
d) Calculate how much phosphocreatin formed relative to creatin at equilibrium in the creatin kinase catalyzed reaction (assuming the same temperature, pH and concentrations of ATP and ADP as indicated in the previous question).

The December 31, Year 4, balance sheet for Rundle Corporation is presented here. These are the only accounts on Rundle’s balance sheet. Amounts indicated by question marks (?) can be calculated using the following additional information:

Required
a. Compute the balance in trade accounts payable as of December 31, Year 4.
b. Compute the balance in retained earnings as of December 31, Year 4.
c. Compute the balance in the inventory account as of December 31, Year 4. (Assume that the level of inventory did not change from last year.)

Electric Potential (Parallel Plate Capacitor Potential Energy and Potential)

A parallel plate capacitor has two terminals, one (+) and the other (-). When you move a test positive charge, q at uniform velocity from the negative terminal (Ui and Vi) to the positive terminal (Uf and Vf), work W = ΔU = qΔV is done on the charge, increasing the energy of the field by this amount. The work done by the field on the charge is – W. (V = U/q, all have their usual meaning)

QUESTIONS on the above observations:

(i) What is the work done to move a negative charge, q at uniform velocity from the positive to the negative terminal? Increasing the potential energy, a push (work) is needed to move the object.

(ii) Which terminal is the high potential for the plus charge?

(iii) Which terminal is the high potential for the negative charge?

(iv) If you do work 1.0 eV to move a proton from the negative to the positive terminal of a capacitor, how much work will you do to move an electron in the exact same manner from the positive the negative terminal of the same capacitor?

(v) What is the potential difference across the above capacitor?

Please explain how to solve and give me an answer.

14-3 Suppose you and most other investors expect the rate of inflation to be 7 percent next year, to fall to 5 percent during the following year, and then to remain at a rate of 3 percent thereafter. Assume that the real risk-free rate, r*, is 2 percent and that maturity risk premiums on Treasury securities rise from zero on very short-term bonds (those that mature in a few days) by 0.2 percentage points for each year to maturity, up to a limit of 1.0 percentage point on five-year or longer-term T-bonds. IBM warrants a DRP of 0.4% and a liquidity premium of 0%. a. Calculate the interest rate on one-, two-, three-, four-, five-, 10-, and 20-year Treasury securities and plot the yield curve. b. Now suppose IBM, a highly rated company, had bonds with the same maturities as the Treasury bonds. As an approximation, plot a yield curve for IBM on the same graph with the Treasury bond yield curve. (Hint: Think about the default risk premium on IBM’s long-term versus its short-term bonds.)

1. Suppose 50.00 mL of 2.0 × 10–4 M Fe(NO3)3 is added to 50.00 mL of 2.0 ×10-6 M KIO3. Which of the following statements is true? For Fe(IO3)3, Ksp = 1.0 × 10–14.
A) A precipitate forms because Qc > Ksp.
B) A precipitate forms because Qc < Ksp.

C) No precipitate forms because Qc < Ksp.

D) No precipitate forms because Qc = Ksp.

E) No precipitate forms because Qc > Ksp.

2. For which of the following reactions is ∆S° > 0 at 25°C?

A) 2H2(g) + O2(g) → 2H2O(g)
B) 2ClBr(g) → Cl2(g) + Br2(g)
C) I2(g) → I2(s)

D) 2NO(g) + O2(g) → 2NO2(g)

E) NH4HS(s) → NH3(g) + H2S(g

3. What is E of the following cell reaction at 25°C? Cu(s) | Cu2+(0.017 M) || Ag(s), (Ag+ = 0.18M)

E°cell = 0.460 V.

A) 0.468V

B) 0.282 V

C) 0.460 V

D) 0.490 V

E) 0.479V

I NEED STEP BY STEP SOLUTIONS FOR EACH PART. DO NOT SKIP ANY PART. ANSWERS TO EACH ARE MARKED IN BOLD

18. Determine the market value of a “comparable” firm based on the following information: value of target firm = $4,000,000; net income of target firm = $200,000; and net income of “comparable” firm = $500,000.

                        a.   $4 million

                        b.   $7.5 million

                        c.   $10 million

                        d.   $12.5 million

                        e.   $15 million

19. Determine the net income of a “comparable” firm based on the following information: value of target firm = $4,000,000; net income of target firm = $200,000; stock price of “comparable” firm = $30.00; and 300,000 shares of stock outstanding for the comparable firm.

                        a.   $450,000

                        b.   $500,000

                        c.   $550,000

                        d.   $600,000

                        e.   $700,000

20. Determine the future value of a target venture which has net income expected to be $40,000 at the end of four years from now. A comparable firm currently has a stock price of $20.00 per shares; 100,000 shares outstanding; and net income of $50,000.

                        a.   $1.0 million

                        b.   $1.4 million  

                        c.   $1.6 million

                        d.   $2.0 million

Consider the following statements: #include #include class Temporary { private: string description; double first; double second; public: Temporary(string = "", double = 0.0, double = 0.0); void set(string, double, double); double manipulate(); void get(string&, double&, double&); void setDescription(string); void setFirst(double); void setSecond(double); }; Write the definition of the member function set() so that the instance variables are set according to the parameters. Write the definition of the constructor so that it initializes the instance variables using the function set() Write the definition of the member function manipulate() that returns a decimal number (double) as follows: If the value of description is "rectangle", it returns first * second If the value of description is "circle" it returns the area of a circle with radius first if the value of description is "cylinder" it returns the volume of a cylinder with radius first and height second. HINT: the volume of a cylinder is simply the area of the circle at the base times the height. If the value of description is "sphere" it returns the volume of the sphere with radius first. Otherwise it returns -1.0; To save you googling what the formula for the volume of a sphere is, given the radius of the sphere, it is V=43πr3 HINT: was included for a reason for the manipulate() function.