You are titrating 120.0 mL of 0.080 M Ca2+ with 0.080 M EDTA at pH 9.00. Log Kf for the Ca2+ -EDTA complex is 10.65, and the fraction of free EDTA in the Y4– form, αY4–, is 0.041 at pH 9.00.
(a) What is K'f, the conditional formation constant, for Ca2+ at pH 9.00?
(b) What is the equivalence volume, Ve, in milliliters?
(c) Calculate the concentration of Ca2 at V = 1/2 Ve.
(d) Calculate the concentration of Ca2 at V = Ve.
(e) Calculate the concentration of Ca2 at V = 1.1 Ve.
In: Chemistry
One mole of an ideal gas undergoes a process where the pressure varies according to
P = (-17.0 atm/m6) V2 + (32.5 atm/m3) V + 1.80 atm
where V is the volume. The volume initially starts at 0.0265 m3 and ends at a value of 1.05 m3.
In: Physics
a random variable X has the following pmf:
|
X |
-1 |
0 |
1 |
|
P[X] |
0.25 |
0.5 |
0.25 |
Define Y = X2 & W= Y+2.
Which one of the following statements is not true?
V[Y] = 0.25.
E[XY] = 0.
E[X3] = 0.
E[X+2] = 2.
E[Y+2] = 2.5.
E[W+2] = 4.5.
V[X+2] = 0.5.
V[W+2] = 0.25.
P[W=1] = 0.5
X and W are not independent.
In: Statistics and Probability
Assume n independent observations, denoted Xi, (i=1,....n), are taken from a distribution with a mean of E(X)=μ and variance V(X) =σ2. Prove that the mean of the n observations has an expected value of E(X)=μ and a variance of V(X) =σ2/n. Use the appropriate E and V rules in your answer. What happens as n becomes large? What does this tell you about the quality of the sample mean as an estimate of μ as the sample size increases?
In: Math
[S] µM V (µmol/min) V (µmol/min) V (µmol/min)
with 0.0 nM with 25 nM with 50 nM
Inhibitor Inhibitor Inhibitor
______ ___________ ___________ ___________
0.4 0.22 0.21 0.20
0.67 0.29 0.26 0.24
1.00 0.32 0.30 0.28
2.00 0.40 0.36 0.32
In: Chemistry
A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.50 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1830 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.10 V/m, (b) in the negative z direction and has a magnitude of 5.10 V/m, and (c) in the positive x direction and has a magnitude of 5.10 V/m?
In: Physics
Billiard ball A of mass mA = 0.116 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.135 kg . As a result of the collision, ball A is deflected off at an angle of θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with a speed v′B at an angle of θ′B to original direction of motion of ball A. Solve these equations for the speed, v′B, of ball B after the collision. Do not assume the collision is elastic.
In: Physics
A single-phase 300-kVA, 220/4400 V, 60 Hz transformer yielded the following information when tested: High voltage winding open: Voltage=220 V, Current=40 A Power=l 000W Low voltage terminal shorted: Voltage= 195 V, Current=68.18A Power=4000W Find the equivalent circuit of the transformer as viewed from the high voltage Calculate the .efficiency of the transformer when it delivers its rated load at rated terminal voltage and 8 power factor lagging.
In: Electrical Engineering
When the velocity v of an object is very large, the magnitude of the force due to air resistance is proportional to v squared with the force acting in opposition to the motion of the object. A shell of mass 5 kg is shot upward from the ground with an initial velocity of 500 m/sec. If the magnitude of the force due to air resistance is (0.1)v squared, when will the shell reach its maximum height above the ground? What is the maximum height? Assume the acceleration due to gravity to be 9.81 m divided by s squared.
In: Advanced Math
Trace this code:
1)
#include<iostream>
using namespace std;
class Test {
int value;
public:
Test(int v);
};
Test::Test(int v) {
value = v;
}
int main() {
Test t[100];
return 0;
}
===================================================================
2)
#include <iostream>
using namespace std;
int main()
{
int i, j;
for (i = 1; i <= 3; i++)
{
//print * equal to row number
for (j = 1; j <= i; j++)
{
cout << "* ";
}
cout << "\n";
}
system("pause");
return 0;
In: Computer Science