The Farmer’s American Bank of Leesburg is planning to install a new computerized accounts system. Bank management has determined the activities required to complete the project, the precedence relationships of the activities, and activity time estimates as follows:
|
TIME ESTIMATES (WEEKS) |
|||||
|
ACTIVITY |
DESCRIPTION |
ACTIVITY PREDECESSOR |
a |
m |
b |
|
A |
Position recruiting |
— |
5 |
8 |
17 |
|
B |
System development |
— |
3 |
12 |
15 |
|
C |
System training |
A |
4 |
7 |
10 |
|
D |
Equipment training |
A |
5 |
8 |
23 |
|
E |
Manual system test |
B, C |
1 |
1 |
1 |
|
F |
Preliminary system changeover |
B, C |
1 |
4 |
13 |
|
G |
Computer-personnel interface |
D, E |
3 |
6 |
9 |
|
H |
Equipment modification |
D, E |
1 |
2.5 |
7 |
|
I |
Equipment testing |
H |
1 |
1 |
1 |
|
J |
System debugging and installation |
F, G |
2 |
2 |
2 |
|
K |
Equipment changeover |
G, I |
5 |
8 |
11 |
Determine the earliest and latest activity times, the expected completion time and standard deviation, and the probability that the project will be completed in 40 weeks or less.
In: Operations Management
One can find out date of the month when someone was born by asking five questions. Each question asks whether the day is in one of the five sets of numbers below
1 3 5 7 2 3 6 7 4 5 6 7 8 9 10 11 16 17 18 19
9 11 13 15 10 11 14 15 12 13 14 15 12 13 14 15 20 21 22 23
17 19 21 23 18 19 22 23 20 21 22 23 24 25 26 27 24 25 26 27
25 27 29 31 26 27 30 31 28 29 30 31 28 29 30 31 28 29 30 31
Set1 Set 2 Set 3 Set 4 Set 5
The birthday is the sum of the first numbers in the set where the day appears. For example, if the birthday is 19, it appears in Set 1, Set 2, and Set 5.
The first numbers in these three sets are 1, 2, and 16 whose sum is 19.
Write a C++ program using arrays that prompts the user to answer whether the day is in Sets 1‐5. If the number is in the particular set, the program adds the first number in the sets to calculate the day of the month. An array must be used in the problem. Refer to the sample output below.
Sample Run:
Is your birthday in Set 1?
1 3 5 7
9 11 13 15
17 19 21 23
25 27 29 31
Enter 0 for No and 1 for Yes: 1
Is your birthday in Set 2?
2 3 6 7
10 11 14 15
18 19 22 23
26 27 30 31
Enter 0 for No and 1 for Yes: 1
Is your birthday in Set 3?
4 5 6 7
12 13 14 15
20 21 22 23
28 29 30 31
Enter 0 for No and 1 for Yes: 1
Is your birthday in Set 4?
8 9 10 11
12 13 14 15
24 25 26 27
28 29 30 31
Enter 0 for No and 1 for Yes: 0
Is your birthday in Set 5?
16 17 18 19
20 21 22 23
24 25 26 27
28 29 30 31
Enter 0 for No and 1 for Yes: 0
Your birthday is on day: 7
In: Computer Science
Problem #1: On a certain island, there is a population of snakes, foxes, hawks and mice. Their populations at time t are given by s(t), f (t), h(t), and m(t) respectively. The populations grow at rates given by the differential equations
s′ = 21/8 s − f − 7/8 h − 1/8 m
f ′ = 5/8 s + f − 7/8 h − 1/8 m
h′ = 5/8 s + 0 f + 1/8 h − 1/8 m
m′ = 65/4 s − 5 f − 31/4 h − 5/4 m
Putting the four populations into a vector y(t) = [s(t) f (t) h(t) m(t)]T, this system can be written as y′ = Ay. Find the eigenvectors and eigenvalues of A. Label the eigenvectors x1 through x4 in order from largest eigenvalue to smallest (the smallest being negative). Scale each eigenvector so that its first component is 1. When you have done so, identify the eigenvector whose fourth component is the largest. What is that largest fourth component? Problem #1: 14 Problem #1 Attempt #1 Attempt #2 Attempt #3 Your Answer: 14 Your Mark: 0/3✘ 3/3 ✔
Problem #2: Continuing from the system of differential equations from Problem 1, each eigenvector represents a grouping of animals that changes with simple exponential growth or decay. The exponential rate of growth or decay is given by the corresponding eigenvalue. Because the matrix A is invertible and diagonalizable, any initial values for the animal population can be written as a combination of these four special groupings that each grow exponentially by their eigenvalue. Consider the initial population y(0) = [18 11 4 102]T. Solve for constants c1 through c4 in order to write y(0) = c1 x1 + c2 x2 + c3 x3 + c4 x4 where x1 through x4 are the eigenvectors as detailed in Problem 1 (i.e., the eigenvectors in order, and scaled so that the first component is 1). Enter the values of c1, c2, c3, and c4, separated with commas.
Problem #2: Problem #2 Attempt #1 Attempt #2 Attempt #3 Your Answer:
Problem #3: Based on the system of differential equations from Problem 1, with the initial population from problem 2, find the function for the population of hawks, h(t).
In: Advanced Math
Ginny’s Restaurant Problem
Ginny is endowed with $10 million and is deciding whether to invest in a restaurant. Assume perfect capital markets with an interest rate of 6%.
|
Investment Option |
Investment (millions) |
End of Year CFs (millions) |
|
1 |
1 |
1.8 |
|
2 |
2 |
3.3 |
|
3 |
3 |
4.4 |
|
4 |
4 |
5.4 |
1. _ ______
2. _ ______
3. ______
4. _ ______
Ginny is actively pursuing another business venture as a ticket scalper. She estimates that for a $2 million investment in inventory she can resell her tickets for $6 million over the next year (cash flows realized in exactly one year). Assume the same 6% interest rate.
(ix) According to Ginny’s prospectus, cash flows from ticket sales (net of expenses) are expected to follow the following distribution:
|
Prob |
Outcome |
|
0.2 |
$5M |
|
0.5 |
$3M |
|
0.3 |
-$2M |
What is the new value of Ginny’s Corporation?
(x) What price will new investors be willing to pay for Ginny’s shares?
In: Finance
A. On May 29, 1790, by a mere 2 votes, Rhode Island ratified the US Constitution and completed the Union of the original 13 English colonies into the United States of America. Today more than 220 years later, the US is 50 States, additional commonwealths, and more than 320 million human lives. Generations of Americans have been born, lived, and died as the country has grown and matured. To what can we owe the longevity and strength of the United States as a country on the global stage?
1. It was created by an legal act.
2. A country is a collection of individuals and states. Collections represent stocks that last.
3. A system goes on being itself as long as the interconnections and purposes remain intact.
4. It's not a system. It's a government.
B. The software components of an information system will act as a(n) ________.
functional anchor on the human side
2. actor on the computer side
3. actor on the human side
4.bridge between the computer side and the human side
5. instruction on the computer side
C. Which phase of the customer life cycle focuses on presenting prospects with information about the value the organization provides?
1. loss/churn
2. customer endorsement
3. marketing
4. customer acquisition
5. relationship management
D. Anyone who gathers data from a variety of sources, arranges that data into meaningful structure, and then aggregates the results to discover information hidden in the details engages in what activity?
1. automation
2.data mining
3.data hiding
4.encapsulation
5. cataloging
In: Operations Management
C2. Blanton Corporation is comprised of five operating segments. Information about each of these segments is as follows (in thousands):
|
Linens |
Kitchen |
Grocery |
Furniture |
Stationery |
||||||||||||||||||||||||
|
Sales to outsiders |
$ |
47 |
$ |
253 |
$ |
22 |
$ |
61 |
$ |
14 |
||||||||||||||||||
|
Intersegment transfers |
2 |
13 |
7 |
15 |
12 |
|||||||||||||||||||||||
|
Interest revenue - outsiders |
1 |
- |
2 |
4 |
- |
|||||||||||||||||||||||
|
Interest revenue - intersegment |
- |
3 |
- |
- |
11 |
|||||||||||||||||||||||
|
Operating expenses - outsiders |
58 |
207 |
20 |
51 |
13 |
|||||||||||||||||||||||
|
Operating expenses - intersegment |
1 |
10 |
3 |
8 |
11 |
|||||||||||||||||||||||
|
Interest expense |
- |
6 |
- |
1 |
- |
|||||||||||||||||||||||
|
Income taxes |
(2 |
) |
5 |
2 |
3 |
12 |
||||||||||||||||||||||
|
Tangible assets |
9 |
58 |
9 |
6 |
4 |
|||||||||||||||||||||||
|
Intangible assets |
- |
- |
2 |
4 |
- |
|||||||||||||||||||||||
|
Intersegment loans |
4 |
3 |
- |
- |
- |
|||||||||||||||||||||||
|
- |
Required:
A) Which operating segments are reportable under the revenue test?
B) What is the total amount of revenues in applying the revenue test?
C) Which operating segments are reportable under the profit or loss test?
D) In applying the profit or loss test, what is the minimum amount an operating segment must have in order to meet the profit or loss test for a reportable segment?
E) Which operating segments are reportable under the asset test?
F) In applying the asset test, what is the minimum amount an operating segment must have in order to meet the asset test for a reportable segment?
G) Which operating segments are reportable?
H) According to the test results for reportable segments, is there a sufficient number of reported segments or should any additional segments also be disclosed? Explain the reason for your conclusion.
In: Accounting
Question 1 options:
Below is a table of times for Taxis (A to H) to reach Customers
(1 to 8) who need a ride home after a night on the town. The goal
is to Minimize the time it takes for all of the Taxis to reach
their Customers. Only one Taxi will be sent to each Customer and
each Customer needs only one Taxi.
|
Taxi / Cust |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
|
A |
15 |
6 |
19 |
15 |
17 |
15 |
8 |
17 |
|
B |
4 |
7 |
9 |
17 |
3 |
17 |
3 |
12 |
|
C |
5 |
17 |
18 |
3 |
15 |
5 |
13 |
11 |
|
D |
14 |
2 |
10 |
13 |
11 |
16 |
11 |
2 |
|
E |
19 |
17 |
18 |
11 |
8 |
11 |
13 |
16 |
|
F |
11 |
19 |
2 |
14 |
9 |
17 |
3 |
8 |
|
G |
16 |
10 |
4 |
7 |
2 |
10 |
19 |
3 |
|
H |
10 |
19 |
4 |
7 |
15 |
10 |
18 |
15 |
The optimal solution to this problem requires the following:
Taxi A picks up Customer
Taxi B picks up Customer
Taxi C picks up Customer
Taxi D picks up Customer
Taxi E picks up Customer
Taxi F picks up Customer
Taxi G picks up Customer
Taxi H picks up Customer
Minimum Cost =
Hint: Your cost should be between 33 and 39
In: Operations Management
Using the below question and values how do you calculate the
standard deviation without using a calculator (by hand) of
(s1^2/n1+s2^2/n2) with the standard deviation answer being 1.4938
and 1.1361
/sqrt(1.4938^2/10 + 1.1361^2/10)
Choose two competing store and compare the prices of 10 items at
both stores. Preform a two-sample hypothesis test to try an prove
if one store is more expensive than the other based on your sample.
Store A item #1-$5.49, #2 $3.77, #3 $0.87, #4 $3.29, #5 $4.79, #6
$1.99, #7 $1.33, #8 $2.19, #9 $2.79, #10 $3.99 Store B items #1
$4.59, #2 3.99, #3 $1.79, #4 $2.99, #5 $4.59, # $1.79,
#7 $1.99, #8 $2.19, #9 $2.79, #10 $3.99
Hypothesis:
H0 ; mu1= mu2
HA: mu 1 > mu2
test statistics:
t = (x1-x2)/sqrt(s1^2/n1+s2^2/n2)
= (3.05 - 3.07)/sqrt(1.4938^2/10 + 1.1361^2/10)
= -0.0337
p value = .4872
FAil to reject the H0
In: Statistics and Probability
Python
Design a class named IP_address to represent IP address objects. The IP_addressclass contains the following
For example, consider the following code fragment:
ip_key = '192.168.0.24' data_list =[(0, 84), (1, 84), (2, 84), (3, 84), (4, 84), (5, 84), (6, 84), (7, 84), (8, 84), (9, 84), (10, 84), (11, 84), (12, 84), (13, 84), (14, 84), (15, 84), (16, 84), (17, 84), (18, 84), (19, 84), (20, 84)] size = 3 ip = IP_address(key, data_list, size)
The data_list contains a list of tuple objects. Each tuple consists of the time-period value and the packet-size. You should summarize this list and create a frequency list, a sum of the packet-size list and an average of the packet-size list. There are a lot of data for each time-period value. We calculate the total number of bytes that the source host sent for each 10-second interval. For example, the above data_list will be divided into 3 groups, such as (0-9 second), (10-19 second) and (20-29 second)
Therefore, the IP_address object should contain:
This will give
ip_key = '192.168.0.24' data_list =[(0, 84), (1, 84), (2, 84), (3, 84), (4, 84), (5, 84), (6, 84), (7, 84), (8, 84), (9, 84), (10, 84), (11, 84), (12, 84), (13, 84), (14, 84), (15, 84), (16, 84), (17, 84), (18, 84), (19, 84), (20, 84)] size = 3 ip = IP_address(ip_key, data_list, size) print(ip.get_ip_address()) |
192.168.0.24 |
And
For example, consider the following code fragment:
ip_key = '192.168.0.24' data_list =[(0, 84), (1, 84), (2, 84), (3, 84), (4, 84), (5, 84), (6, 84), (7, 84), (8, 84), (9, 84), (10, 84), (11, 84), (12, 84), (13, 84), (14, 84), (15, 84), (16, 84), (17, 84), (18, 84), (19, 84), (20, 84)] size = 3 ip = IP_address(key, data_list, size)
The data_list contains a list of tuple objects.
Therefore, the IP_address object should contain:
ip_key = '192.168.0.24' data_list =[(0, 84), (1, 84), (2, 84), (3, 84), (4, 84), (5, 84), (6, 84), (7, 84), (8, 84), (9, 84), (10, 84), (11, 84), (12, 84), (13, 84), (14, 84), (15, 84), (16, 84), (17, 84), (18, 84), (19, 84), (20, 84)] size = 3 ip = IP_address(ip_key, data_list, size) print(ip.get_freq_list()) |
[[0, 10], [1, 10], [2, 1]] |
|
ip_key = '192.168.0.24' data_list = [(0, 84), (1, 84), (2, 84), (3, 84), (4, 84)] size = 3 ip = IP_address(ip_key, data_list, size) print(ip.get_freq_list()) |
[[0, 5], [1, 0], [2, 0]] |
|
ip_key = '192.168.0.2' data_list = [(33, 60), (34, 64), (34, 1500), (34, 712), (35, 52), (35, 60), (36, 52), (36, 287), (37, 52), (37, 52), (37, 52), (39, 60), (40, 643), (40, 52)] size = 5 ip = IP_address(ip_key, data_list, size) print(ip.get_freq_list()) |
[[0, 0], [1, 0], [2, 0], [3, 12], [4, 2]] |
In: Computer Science
Suppose that the following processes arrive for execution at time 0 in the order A, B, C:
| process | Run Time | Priority |
| A | 4 | 1=high |
| B | 2 | 3=low |
| C | 3 | 2=medium |
In: Electrical Engineering