In: Computer Science
Suppose marginal benefit from a hectare of for a public park (assume it is a pure public good) for two groups of consumers (A and B) is given by: MBa = 10 − Q and MBb = (8 – Q)/2 where Q is the number of hectares of the park. To simplify our analysis, assume that there are only 1 consumer of each type. The marginal cost to provide the park is a constant $5.
a) What is the socially efficient number of hectares for the park?
b) Assume that the consumers each makes a voluntary contribution to a fund which will be used to build the park. The size of the park depends on the amount of money collected. How many hectares will be built in the end? Assume both consumers know the marginal cost and marginal benefit function of each type.
In: Economics
The Naples Newspaper completes production of its daily edition by 5 a.m. A truck picks up pallets loaded with newspapers and delivers them to four neighbor sites, where carriers sort and fold the papers for individual routes. The mileage between locations is shown in the table below. Currently, the truck picks up the number of pallets required by each customer at the factory, delivers them, and then returns to the factory to get the papers for the next customer (i.e., current route 0-1-0-2-0-3-0-4-0). The truck always returns to Scottsville and gets 10 miles per gallon using diesel fuel. A truck can carry up to 17 pallets. A gallon of diesel fuel is $2.50. The newspaper operates 365 days per year.
| Factory (0) | Scottsville (1) | Hudson (2) | Bonita (3) | Walker (4) | Pallets Demanded | ||||||
| Factory (0) | — | 7 | 5 | 15 | 17 | ||||||
| Scottsville (1) | — | 16 | 8 | 11 | 11 | ||||||
| Hudson (2) | — | 9 | 6 | 6 | |||||||
| Bonita (3) | — | 4 | 8 | ||||||||
| Walker (4) | — | 9 | |||||||||
How many miles does the truck travel each day using the current route? What is the total number of miles traveled annually? Round your answers to the nearest whole number.
miles per day
miles per year
Use the Clarke-Wright Method to find a more efficient route. Round your answers to the nearest whole number.
| Routes | Travel Distance (miles) |
| 0-1-0, 0-1-2-0, 0-1-3-0, 0-1-4-0 | |
| 0-2-0, 0-2-3-0. 0-2-4-0 | |
| 0-2-3-0, 0-4-0, 0-3-4-0 | |
| Total |
How many miles, gallons, and dollars can be saved per year by adopting the current versus shorter route found by the Clarke–Wright Method? Do not round intermediate calculations. Round your answers to two decimal places.
miles per year
gallons per year
$ per year
How many pounds of gas are emitted into the atmosphere and saved per year using the shortest truck route versus the current truck route? Assume that one gallon of gas generates 13 pounds of carbon dioxide and other global-warming gases from the truck's tailpipe. Do not round intermediate calculations. Round your answer to one decimal place.
lbs of gas per year
In: Statistics and Probability
Find the variance of the following data. Round your answer to one decimal place. x 3 4 5 6 7 8 P(X=x) 0.1 0.1 0.1 0.2 0.2 0.3
In: Statistics and Probability
A 248 nC point charge is at co-ordinate (0, 0.2) . A 85 nC charge is at (0, -0.2). Find the electrostatic field at (0.4, -0.7). The Coulomb constant is k = 8.99 10^9 N m^2 / C^2 and the coordinates are given in meters.
In: Physics
it is a different table so please do the calculation again
Heat treating is often used to carburize metal parts, such as gears. The thickness of the carburized layer is considered a crucial feature of the gear and contributes to the overall reliability of the part. Because of the critical nature of this feature, two different lab tests are performed on each furnace load. One test is run on a sample pin that accompanies each load. The other test is a destructive test, where an actual part is cross-sectioned. This test involves running a carbon analysis on the surface of both the gear pitch (top of the gear tooth) and the gear root (between the gear teeth). Table 12-6 shows the results of the pitch carbon analysis test for
|
Temp |
SoakTime |
SoakPct |
DiffTime |
DiffPct |
Pitch |
|
1650 |
0.58 |
1.1 |
0.25 |
0.9 |
0.013 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.9 |
0.016 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.9 |
0.015 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.95 |
0.016 |
|
1600 |
0.66 |
1.15 |
0.33 |
1 |
0.015 |
|
1600 |
0.66 |
1.15 |
0.33 |
1 |
0.016 |
|
1650 |
1 |
1.1 |
0.5 |
0.8 |
0.014 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.021 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.018 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.019 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.9 |
0.021 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.9 |
0.019 |
|
1650 |
1.17 |
1.15 |
0.58 |
0.9 |
0.021 |
|
1650 |
1.2 |
1.15 |
1.1 |
0.8 |
0.025 |
|
1650 |
2 |
1.15 |
1 |
0.8 |
0.025 |
|
1650 |
2 |
1.1 |
1.1 |
0.8 |
0.026 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.8 |
0.024 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.8 |
0.025 |
|
1650 |
2.2 |
1.15 |
1.1 |
0.8 |
0.024 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.9 |
0.025 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.9 |
0.027 |
|
1650 |
2.2 |
1.1 |
1.5 |
0.9 |
0.026 |
|
1650 |
3 |
1.15 |
1.5 |
0.8 |
0.029 |
|
1650 |
3 |
1.1 |
1.5 |
0.7 |
0.03 |
|
1650 |
3 |
1.1 |
1.5 |
0.75 |
0.028 |
|
1650 |
3 |
1.15 |
1.66 |
0.85 |
0.032 |
|
1650 |
3.33 |
1.1 |
1.5 |
0.8 |
0.033 |
|
1700 |
4 |
1.1 |
1.5 |
0.7 |
0.039 |
|
1650 |
4 |
1.1 |
1.5 |
0.7 |
0.04 |
|
1650 |
4 |
1.15 |
1.5 |
0.85 |
0.035 |
|
1700 |
12.5 |
1 |
1.5 |
0.7 |
0.056 |
|
1700 |
18.5 |
1 |
1.5 |
0.7 |
0.068 |
In: Statistics and Probability
Heat treating is often used to carburize metal parts, such as gears. The thickness of the carburized layer is considered a crucial feature of the gear and contributes to the overall reliability of the part. Because of the critical nature of this feature, two different lab tests are performed on each furnace load. One test is run on a sample pin that accompanies each load. The other test is a destructive test, where an actual part is cross-sectioned. This test involves running a carbon analysis on the surface of both the gear pitch (top of the gear tooth) and the gear root (between the gear teeth). Table 12-6 shows the results of the pitch carbon analysis test for 32 parts.
|
Temp |
SoakTime |
SoakPct |
DiffTime |
DiffPct |
Pitch |
|
1650 |
0.58 |
1.1 |
0.25 |
0.9 |
0.013 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.9 |
0.016 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.9 |
0.015 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.95 |
0.016 |
|
1600 |
0.66 |
1.15 |
0.33 |
1 |
0.015 |
|
1600 |
0.66 |
1.15 |
0.33 |
1 |
0.016 |
|
1650 |
1 |
1.1 |
0.5 |
0.8 |
0.014 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.021 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.018 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.019 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.9 |
0.021 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.9 |
0.019 |
|
1650 |
1.17 |
1.15 |
0.58 |
0.9 |
0.021 |
|
1650 |
1.2 |
1.15 |
1.1 |
0.8 |
0.025 |
|
1650 |
2 |
1.15 |
1 |
0.8 |
0.025 |
|
1650 |
2 |
1.1 |
1.1 |
0.8 |
0.026 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.8 |
0.024 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.8 |
0.025 |
|
1650 |
2.2 |
1.5 |
1.1 |
0.8 |
0.024 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.9 |
0.025 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.9 |
0.027 |
|
1650 |
2.2 |
1.1 |
1.5 |
0.9 |
0.026 |
|
1650 |
3 |
1.15 |
1.5 |
0.8 |
0.029 |
|
1650 |
3 |
1.1 |
1.5 |
0.7 |
0.03 |
|
1650 |
3 |
1.1 |
1.5 |
0.75 |
0.028 |
|
1650 |
3 |
1.15 |
1.66 |
0.85 |
0.032 |
|
1650 |
3.33 |
1.1 |
1.5 |
0.8 |
0.033 |
|
1700 |
4 |
1.1 |
1.5 |
0.7 |
0.039 |
|
1650 |
4 |
1.1 |
1.5 |
0.7 |
0.04 |
|
1650 |
4 |
1.15 |
1.5 |
0.85 |
0.035 |
|
1700 |
12.5 |
1 |
1.5 |
0.7 |
0.056 |
|
1700 |
18.5 |
1 |
1.5 |
0.7 |
0.068 |
PLEASE answer only the STEPWISE part of the question
Repeat steps (a)-(d) except utilize stepwise regression to identify a model.]
All of them got answered check this link: https://www.chegg.com/homework-help/questions-and-answers/heat-treating-often-used-carburize-metal-parts-gears-thickness-carburized-layer-considered-q45865978
In: Statistics and Probability
Heat treating is often used to carburize metal parts, such as gears. The thickness of the carburized layer is considered a crucial feature of the gear and contributes to the overall reliability of the part. Because of the critical nature of this feature, two different lab tests are performed on each furnace load. One test is run on a sample pin that accompanies each load. The other test is a destructive test, where an actual part is cross-sectioned. This test involves running a carbon analysis on the surface of both the gear pitch (top of the gear tooth) and the gear root (between the gear teeth). Table 12-6 shows the results of the pitch carbon analysis test for 32 parts.
|
Temp |
SoakTime |
SoakPct |
DiffTime |
DiffPct |
Pitch |
|
1650 |
0.58 |
1.1 |
0.25 |
0.9 |
0.013 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.9 |
0.016 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.9 |
0.015 |
|
1650 |
0.66 |
1.1 |
0.33 |
0.95 |
0.016 |
|
1600 |
0.66 |
1.15 |
0.33 |
1 |
0.015 |
|
1600 |
0.66 |
1.15 |
0.33 |
1 |
0.016 |
|
1650 |
1 |
1.1 |
0.5 |
0.8 |
0.014 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.021 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.018 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.8 |
0.019 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.9 |
0.021 |
|
1650 |
1.17 |
1.1 |
0.58 |
0.9 |
0.019 |
|
1650 |
1.17 |
1.15 |
0.58 |
0.9 |
0.021 |
|
1650 |
1.2 |
1.15 |
1.1 |
0.8 |
0.025 |
|
1650 |
2 |
1.15 |
1 |
0.8 |
0.025 |
|
1650 |
2 |
1.1 |
1.1 |
0.8 |
0.026 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.8 |
0.024 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.8 |
0.025 |
|
1650 |
2.2 |
1.5 |
1.1 |
0.8 |
0.024 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.9 |
0.025 |
|
1650 |
2.2 |
1.1 |
1.1 |
0.9 |
0.027 |
|
1650 |
2.2 |
1.1 |
1.5 |
0.9 |
0.026 |
|
1650 |
3 |
1.15 |
1.5 |
0.8 |
0.029 |
|
1650 |
3 |
1.1 |
1.5 |
0.7 |
0.03 |
|
1650 |
3 |
1.1 |
1.5 |
0.75 |
0.028 |
|
1650 |
3 |
1.15 |
1.66 |
0.85 |
0.032 |
|
1650 |
3.33 |
1.1 |
1.5 |
0.8 |
0.033 |
|
1700 |
4 |
1.1 |
1.5 |
0.7 |
0.039 |
|
1650 |
4 |
1.1 |
1.5 |
0.7 |
0.04 |
|
1650 |
4 |
1.15 |
1.5 |
0.85 |
0.035 |
|
1700 |
12.5 |
1 |
1.5 |
0.7 |
0.056 |
|
1700 |
18.5 |
1 |
1.5 |
0.7 |
0.068 |
PLEASE answer only the STEPWISE part of the question
except utilize stepwise regression to identify a model.]
In: Statistics and Probability
eBook
Calculator
Simplifying the ABC System: Equally Accurate Reduced ABC Systems
Selected activities and other information are provided for Patterson Company for its most recent year of operations.
| Expected Consumption Ratios |
||||||||
| Activity | Driver | Quantity | Wafer A | Wafer B | ||||
| 7. Inserting dies | Number of dies | 2,000,000 | 0.7 | 0.3 | ||||
| 8. Purchasing materials | Number of purchase orders |
1,900 | 0.2 | 0.8 | ||||
| 1. Developing test programs | Engineering hours | 11,000 | 0.25 | 0.75 | ||||
| 3. Testing products | Test hours | 18,000 | 0.6 | 0.4 | ||||
| ABC assignments | $150,000 | $150,000 | ||||||
| Total overhead cost | $300,000 | |||||||
Required:
1. Form reduced system cost pools for activities 7 and 8. Do not round interim calculations. Round your final answers to the nearest dollar.
| Inserting dies cost pool | $ |
| Purchasing cost pool | $ |
2. Assign the costs of the reduced system cost pools to Wafer A and Wafer B. Do not round interim calculations. Round your final answers to the nearest dollar.
| Wafer A | $ |
| Wafer B | $ |
3. What if the two activities were 1 and 3? Repeat Requirements 1 and 2.
Form reduced system cost pools for activities 1 and 3.
Do not round interim calculations. Round your final answers to the nearest dollar.
| Developing test programs cost pool | $ |
| Testing products cost pool | $ |
Assign the costs of the reduced system cost pools to Wafer A and Wafer B.
| Wafer A | $ |
| Wafer B | $ |
In: Accounting
Concord Air Express decided to offer direct service from Cleveland to Myrtle Beach. Management must decide between a full-price service using the company’s new fleet of jet aircraft and a discount service using smaller capacity commuter planes. It is clear that the best choice depends on the market reaction to the service Concord Air offers. Management developed estimates of the contribution to profit for each type of service based upon two possible levels of demand for service to Myrtle Beach: strong and weak. The following table shows the estimated quarterly profits (in thousands of dollars):
|
Demand for Service |
||
|
Service |
Strong |
Weak |
|
Full Price |
$960 |
-$490 |
|
Discount |
$670 |
$320 |
In: Economics