In: Economics
In: Operations Management
BEST CO sponsors a defined benefit pension plan for its employees.
On January 1, 2010, the following balances relate to this plan.
GHS Plan assets 480,000
Defined benefit obligation 625,000
Pension asset/liability 45,000
Unrecognized past service cost 100,000
As a result of the operation of the plan during 2010, the following additional data are provided by the actuary. Service cost for 2010 is 90,000
Discount rate, 9%
Actual return on plan assets in 2010 is 57,000
Amortization of past service cost 19,000
Expected return on plan assets 52,000
Unexpected loss from change in defined benefit obligation, due to change in actuarial predictions 76,000
Contributions in 2010 is 99,000
Benefits paid retirees in 2010 is 85,000
Instructions
(a) Using the data above, compute pension expense for BEST Co. for the year 2010 by preparing a pension worksheet that shows the journal entry for pension expense and the year-end balances in the related pension accounts.
(b) At December 31, 2010, prepare a schedule reconciling the funded status of the plan with the pension amount reported on the statement of financial position.
In: Accounting
please answer each question with steps if possible.
In 2010 Glacial HVAC, Inc. sold 3,305 air conditioning units in Fulton County. During that same year 46,786 air conditioning units were sold in Fulton County. Calculate Glacial's 2010 market share. Report your answer as a percentage, rounded to one decimal place.
Question 2 (10 points)
In 2010 47,413 air conditioning units were sold in Fulton County. Glacial HVAC, Inc. sold 3,275 units in 2010. 2010 industry sales represent a 8.9 % decrease over 2009 sales. Calculate 2009 industry sales. Round your answer to the nearest unit.
Question 3 (10 points)
In 2010 47,250 air conditioning units were sold in Fulton County. Glacial HVAC Inc. sold 3,269 units in 2010, compared to 2009 sales of 3,969 units. Calculate the percent change in Glacial's sales, from 2009 to 2010. Report your answer as a percentage, rounded to one decimal place.
In: Finance
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Consider a monthly return data on 20-year Treasury Bonds from 2006–2010. |
| Year | Month | Return | Year | Month | Return |
| 2006 | Jan | 5.39 | 2008 | Jul | 4.94 |
| 2006 | Feb | 4.83 | 2008 | Aug | 3.90 |
| 2006 | Mar | 5.41 | 2008 | Sep | 4.72 |
| 2006 | Apr | 4.64 | 2008 | Oct | 4.58 |
| 2006 | May | 4.05 | 2008 | Nov | 4.83 |
| 2006 | Jun | 3.41 | 2008 | Dec | 4.17 |
| 2006 | Jul | 3.92 | 2009 | Jan | 4.68 |
| 2006 | Aug | 3.46 | 2009 | Feb | 4.35 |
| 2006 | Sep | 5.06 | 2009 | Mar | 4.10 |
| 2006 | Oct | 5.44 | 2009 | Apr | 4.98 |
| 2006 | Nov | 4.96 | 2009 | May | 5.22 |
| 2006 | Dec | 4.17 | 2009 | Jun | 4.79 |
| 2007 | Jan | 3.48 | 2009 | Jul | 5.00 |
| 2007 | Feb | 4.70 | 2009 | Aug | 3.58 |
| 2007 | Mar | 4.38 | 2009 | Sep | 4.34 |
| 2007 | Apr | 3.82 | 2009 | Oct | 3.15 |
| 2007 | May | 4.19 | 2009 | Nov | 5.48 |
| 2007 | Jun | 4.35 | 2009 | Dec | 4.28 |
| 2007 | Jul | 3.83 | 2010 | Jan | 4.35 |
| 2007 | Aug | 5.42 | 2010 | Feb | 3.24 |
| 2007 | Sep | 3.29 | 2010 | Mar | 3.27 |
| 2007 | Oct | 4.00 | 2010 | Apr | 4.72 |
| 2007 | Nov | 3.42 | 2010 | May | 5.00 |
| 2007 | Dec | 3.24 | 2010 | Jun | 4.82 |
| 2008 | Jan | 5.21 | 2010 | Jul | 3.59 |
| 2008 | Feb | 4.84 | 2010 | Aug | 4.52 |
| 2008 | Mar | 4.59 | 2010 | Sep | 4.44 |
| 2008 | Apr | 3.82 | 2010 | Oct | 4.59 |
| 2008 | May | 3.61 | 2010 | Nov | 4.62 |
| 2008 | Jun | 4.34 | 2010 | Dec | 3.74 |
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Estimate a linear trend model with seasonal dummy variables to make forecasts for the first three months of 2011. (Round intermediate calculations to 4 decimal places and final answers to 2 decimal places.) |
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Year |
Month |
y-forecast |
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2011 |
Jan |
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2011 |
Feb |
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2011 |
Mar |
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In: Math
The program is to be called CarClub
The application will display menu as below
1. load cars
2. display all cars
3. search car
4 count cars older the 30 years
5 exit
Please enter your option:
Load car menu should read input data from text file name (car.txt)
Car class have 4 data members which are. Car make, car model, car year and car price
In addition
If both car year and price were not provided, year has a default value as 2020 and price has a default value as $20000
If only price was not provided, price should be set to a default value based on this table
2015<year<=2020 and price has a default value as $20000
2010<year<=2015 and price has a default value as $14000
1980<year<=2010 and price has a default value as $7000
2015<year<=2020 and price has a default value as $20000
year<=1980 and price has a default value as $40000
Using dynamic memory allocation to store Car Object
You should implement at least 1 custom excepetion and 1 file exception
You have to implement 1 operator overloading for operator "<<" to use as a print
WHY IS BUILD FAILED?????
#include
#include
using namespace std;
#include
class Ccar
{
private:
string make;
string model;
int year;
double price;
public:
Ccar(string="", string="", int=2020, double=20000);
~Ccar();
// setters
void setMake(string);
void setModel(string);
void setYear(int);
void setPrice(double);
// getters
string getMake();
string getModel();
int getYear();
double getPrice();
};
void Ccar:: setMake(string ma){
ma=make;
}
void Ccar :: setModel(string m){
m=model;
}
void Ccar :: setYear(int y){
y=year;
}
void Ccar :: setPrice(double p){
p=price;
}
// getters
string Ccar::getMake()
{
return make;
}
string Ccar::getModel()
{
return model;
}
int Ccar::getYear()
{
return year;
}
double Ccar::getPrice()
{
return price;
}
int main() {
int option, i, numberOffCars, year = 0;
string line, make, model, yearString, priceString;
double price;
bool loaded =false;
ifstream fin;
// file exception to be typed here
// num of cars counted
fin.open("cars.txt");
numberOffCars=0;
while (fin.good()) //while i have not reached the eof
{
getline(fin, line);
numberOffCars++;
}
fin.close();
//memory allocation
Ccar *carList = new Ccar[numberOffCars]; // Dynamic memory allocation
//menu
do{
cout <<"1. Load Cars"<
cout <<"2. Display all Cars"<
cout <<"3. Search Cars"<
cout <<"4. Count Cars older than 30 years"<
cout <<"5. Exit"<
cin>>option;
if (option <1 || option >5)
{
cout<<"error"<
else
{
switch (option)
{case 1: // load
loaded=true;
fin.open("car.txt");
i=0;
while (fin.good())
{
yearString="";
priceString="";
getline(fin, make,'$');
carList[i].setModel(model);
getline(fin, yearString,'$');
if (yearString!="")
year= stoi(yearString);
getline(fin, priceString,'$');
if (priceString!="")
price= stod(priceString);
if (yearString=="" && priceString =="")
{
carList[i].setYear(2020);
carList[i].setPrice(20000);
}
else if (priceString=="")
{
if (year>2015 && year<=2020)
carList[i].setPrice(20000);
else if (year>2010 && year<=2015)
carList[i].setPrice(14000);
else if (year>1980 && year<=2010)
carList[i].setPrice(7000);
else
carList[i].setPrice(400000);
}
i++; //next car
} //end of while
fin.close();
break;
case 2: // display
if (loaded)
{i=0;
while(i
{cout <<"carList[i]"<
i++; //next car
}
}
break;
case 3: // search
if (loaded)
{
cout << "Enter a car make: "<< endl;
cin>>make;
cout << "Enter a car model: "<< endl;
cin>>model;
// search for this make and model
}
else {
cout << "Load the cars first! "<< endl;
}
break;
case 4: // count the cars older than 30 years
break;
case 5: // exit
cout << "\n\n\t\t\t Thanks for using our aplication"<< endl;
default: // already handled by cust excep
cout << "Invalid option! Try again"<< endl;
break;
}}} // end of switch
while (option !=5); // 5 exit option
delete[] carList;
return 0;
}
In: Computer Science
Provide an informed opinion about Shake Shack’s future quarterly earnings in an appealing and convincing format. Concretely, you should:
In: Operations Management
. Computer programmers work under much more pleasant conditions than garbage collectors. Yet, according to the Bureau of Labor Statistics, the median salary of a sanitation worker is about $35,270 and the median salary of a computer programmer is about $79,840. True or false: This shows that the theory of compensating wage differentials is wrong. Explain.
In: Economics
Analyse the risks associated with Innovation in Healthcare.
In: Nursing
What is the difference between invention and innovation?
In: Mechanical Engineering