The Gourmand Cooking School runs short cooking courses at its small campus. Management has identified two cost drivers it uses in its budgeting and performance reports—the number of courses and the total number of students. For example, the school might run two courses in a month and have a total of 64 students enrolled in those two courses. Data concerning the company’s cost formulas appear below:
| Fixed Cost per Month | Cost per Course | Cost per Student |
|||||
| Instructor wages | $ | 2,900 | |||||
| Classroom supplies | $ | 260 | |||||
| Utilities | $ | 1,250 | $ | 55 | |||
| Campus rent | $ | 5,200 | |||||
| Insurance | $ | 2,300 | |||||
| Administrative expenses | $ | 3,600 | $ | 43 | $ | 4 | |
For example, administrative expenses should be $3,600 per month plus $43 per course plus $4 per student. The company’s sales should average $870 per student.
The company planned to run four courses with a total of 64 students; however, it actually ran four courses with a total of only 56 students. The actual operating results for September appear below:
| Actual | ||
| Revenue | $ | 52,780 |
| Instructor wages | $ | 10,880 |
| Classroom supplies | $ | 16,490 |
| Utilities | $ | 1,880 |
| Campus rent | $ | 5,200 |
| Insurance | $ | 2,440 |
| Administrative expenses | $ | 3,454 |
Required:
1. Prepare the company’s planning budget for September.
Prepare the company’s planning budget for September.
2. Prepare the company’s flexible budget for September. |
3. Calculate the revenue and spending variances for September.
In: Accounting
As a follow up to the analysis of his Stats classes, Dr. Walton wants to assess if the move to fully online learning as a result of the COVID-19 pandemic impacted student learning in his Research Methods class in anyway (i.e., either increased or decreased student learning). To do so he conducts a TWO-TAILED Z-test using a standardized Research Methods quiz. He compares his students’ scores (N = 27: x̅ = 83.5%) with the national average of scores on the same quiz (µ = 80.8%: σ = 6.2).
Write in words, Dr. Walton’s alternative hypothesis (remember, it is TWO-TAILED so we are testing for a difference in ANY direction) .
Write in words, the Null-hypothesis .
The Standard Error of the Mean for the sampling distribution of means is . Round to three decimal places (.XXX)
The z score for the sample mean of Dr. Walton’s students Stats test scores is . Round to two decimal places (.XX).
What is the Critical Z-value for a Two-Tailed Z-test with an alpha .05 criterion . Round to two decimal places (.XX)
Is the sample mean of Dr. Walton’s students’ test score in the region of rejection?
Will you reject the Null-Hypothesis?
Do Dr. Walton’s Students’ scores on the standardized research methods quiz appear to be significantly different than the national average on this quiz and what is your evidence?
In: Statistics and Probability
A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 1111 nursing students from Group 1 resulted in a mean score of 58.358.3 with a standard deviation of 8.98.9. A random sample of 1717 nursing students from Group 2 resulted in a mean score of 66.766.7 with a standard deviation of 5.15.1. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ1μ1 represent the mean score for Group 1 and μ2μ2 represent the mean score for Group 2. Use a significance level of α=0.01α=0.01 for the test. Assume that the population variances are equal and that the two populations are normally distributed.
Step 1 of 4:
State the null and alternative hypotheses for the test.
Step 2 of 4:
Compute the value of the t test statistic. Round your answer to three decimal places.
Step 3 of 4:
Determine the decision rule for rejecting the null hypothesis H0H0. Round your answer to three decimal places.
Step 4 of 4:
State the test's conclusion.
In: Statistics and Probability
The Gourmand Cooking School runs short cooking courses at its small campus. Management has identified two cost drivers it uses in its budgeting and performance reports—the number of courses and the total number of students. For example, the school might run two courses in a month and have a total of 50 students enrolled in those two courses. Data concerning the company’s cost formulas appear below: Fixed Cost per Month Cost per Course Cost per Student Instructor wages $ 3,080 Classroom supplies $ 260 Utilities $ 870 $ 130 Campus rent $ 4,200 Insurance $ 1,890 Administrative expenses $ 3,270 $ 15 $ 4 For example, administrative expenses should be $3,270 per month plus $15 per course plus $4 per student. The company’s sales should average $800 per student. The company planned to run three courses with a total of 45 students; however, it actually ran three courses with a total of only 42 students. The actual operating results for September appear below: Actual Revenue $ 32,400 Instructor wages $ 9,080 Classroom supplies $ 8,540 Utilities $ 1,530 Campus rent $ 4,200 Insurance $ 1,890 Administrative expenses $ 3,790 Required: 1. Prepare the company’s planning budget for September. 2. Prepare the company’s flexible budget for September. 3. Calculate the revenue and spending variances for September.
In: Accounting
The Gourmand Cooking School runs short cooking courses at its small campus. Management has identified two cost drivers it uses in its budgeting and performance reports—the number of courses and the total number of students. For example, the school might run two courses in a month and have a total of 64 students enrolled in those two courses. Data concerning the company’s cost formulas appear below:
| Fixed Cost per Month | Cost per Course | Cost per Student |
|||||
| Instructor wages | $ | 2,910 | |||||
| Classroom supplies | $ | 310 | |||||
| Utilities | $ | 1,210 | $ | 85 | |||
| Campus rent | $ | 5,200 | |||||
| Insurance | $ | 2,200 | |||||
| Administrative expenses | $ | 3,800 | $ | 41 | $ | 4 | |
For example, administrative expenses should be $3,800 per month plus $41 per course plus $4 per student. The company’s sales should average $890 per student.
The company planned to run four courses with a total of 64 students; however, it actually ran four courses with a total of only 60 students. The actual operating results for September appear below:
| Actual | ||
| Revenue | $ | 54,060 |
| Instructor wages | $ | 10,920 |
| Classroom supplies | $ | 19,690 |
| Utilities | $ | 1,960 |
| Campus rent | $ | 5,200 |
| Insurance | $ | 2,340 |
| Administrative expenses | $ | 3,646 |
Required:
1. Prepare the company’s planning budget for September.
2. Prepare the company’s flexible budget for September.
3. Calculate the revenue and spending variances for September.
In: Accounting
9. An engineering school reports that 56% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A), and that 25% were both male and between the ages of 18 and 20.What is the probability of choosing a random student who is a female or between the ages of 18 and 20? Assume P(F) = P(not M). Your answer should be given to two decimal places.
10. An engineering school reports that 55% of
its students were male (M), 30% of its students were between the
ages of 18 and 20 (A), and that 24% were both male and between the
ages of 18 and 20.What is the probability of a random student being
male or between the ages of 18 and 20? Your answer should be
rounded to two decimal places.
11. Let A and B be two independent events such
that P(A) = 0.37 and P(B) = 0.53.
What is P(A or B)? Your answer should be given to 4 decimal
places.
12. Let A and B be two independent events such
that P(A) = 0.1 and P(B) = 0.8.
What is P(A and B)? Your answer should be given to 2 decimal
places.
13. Let A and B be two disjoint events such
that P(A) = 0.25 and P(B) = 0.03.
What is P(A and B)?
14. Let A and B be two disjoint events such
that P(A) = 0.27 and P(B) = 0.52.
What is P(A or B)?
In: Statistics and Probability
A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 16 nursing students from Group 1 resulted in a mean score of 41.4 with a standard deviation of 6.5. A random sample of 12 nursing students from Group 2 resulted in a mean score of 52.6 with a standard deviation of 5.8. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ1 represent the mean score for Group 1 and μ2 represent the mean score for Group 2. Use a significance level of α=0.05 for the test. Assume that the population variances are equal and that the two populations are normally distributed.
Step 1 of 4: State the null and alternative hypotheses for the test.
Step 2 of 4: Compute the value of the t test statistic. Round your answer to three decimal places.
Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round your answer to three decimal places.
Step 4 of 4: State the test's conclusion.
In: Statistics and Probability
The Gourmand Cooking School runs short cooking courses at its small campus. Management has identified two cost drivers it uses in its budgeting and performance reports—the number of courses and the total number of students. For example, the school might run two courses in a month and have a total of 65 students enrolled in those two courses. Data concerning the company’s cost formulas appear below:
| Fixed Cost per Month | Cost per Course | Cost per Student |
|||||
| Instructor wages | $ | 2,950 | |||||
| Classroom supplies | $ | 280 | |||||
| Utilities | $ | 1,200 | $ | 65 | |||
| Campus rent | $ | 4,500 | |||||
| Insurance | $ | 2,000 | |||||
| Administrative expenses | $ | 3,600 | $ | 45 | $ | 6 | |
For example, administrative expenses should be $3,600 per month plus $45 per course plus $6 per student. The company’s sales should average $890 per student.
The company planned to run four courses with a total of 65 students; however, it actually ran four courses with a total of only 57 students. The actual operating results for September appear below:
| Actual | ||
| Revenue | $ | 54,950 |
| Instructor wages | $ | 11,080 |
| Classroom supplies | $ | 18,050 |
| Utilities | $ | 1,870 |
| Campus rent | $ | 4,500 |
| Insurance | $ | 2,140 |
| Administrative expenses | $ | 3,596 |
Required:
1. Prepare the company’s planning budget for September.
2. Prepare the company’s flexible budget for September.
3. Calculate the revenue and spending variances for September.
In: Accounting
In: Statistics and Probability
The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first determine the percentage of adults who have heard of the brand. How many adults must he survey in order to be 80% confident that his estimate is within six percentage points of the true population percentage? Complete parts (a) through (c) below.
a) Assume that nothing is known about the percentage of adults who have heard of the brand.
n=
(Round up to the nearest integer.)
b) Assume that a recent survey suggests that about 85% of adults have heard of the brand.
n=
(Round up to the nearest integer.)
c) Given that the required sample size is relatively small, could he simply survey the adults at the nearest college?
A.
Yes, a sample of students at the nearest college is a simple random sample, so the results should be representative of the population of adults.
B.
No, a sample of students at the nearest college is a stratified sample, not a simple random sample, so it is very possible that the results would not be representative of the population of adults.
C.
No, a sample of students at the nearest college is a cluster sample, not a simple random sample, so it is very possible that the results would not be representative of the population of adults.
D.
No, a sample of students at the nearest college is a convenience sample, not a simple random sample, so it is very possible that the results would not be representative of the population of adults.
In: Statistics and Probability