4. The highway department is testing two types of reflecting paint for concrete bridge end pillars. The two kinds of paint are alike in every respect except that one is orange and the other is yellow. The orange paint is applied to 12 bridges, and the yellow paint is applied to 12 bridges. After a period of 1 year, reflectometer readings were made on all these bridge end pillars. (A higher reading means better visibility.) For the orange paint, the mean reflectometer reading was x₁ = 9.4, with standard deviation s₁ = 2.1. For the yellow paint the mean was x₂ = 6.9, with standard deviation s₂ = 2.5. Based on the data, can we conclude that the yellow paint has less visibility after 1 year? Use a 1% level of significance.

a. What are we testing in this problem?

1. difference of proportions

2. difference of means

3. single mean

4. paired difference

5. single proportion

b. What is the level of significance?

c. State the null and alternate hypotheses.

H₀: μ₁ ≥ μ₂; H₁: μ₁ < μ₂

H₀: μ₁ ≤ μ₂; H₁: μ₁ > μ₂     

H₀: μ₁ = μ₂; H₁: μ₁ ≠ μ₂

H₀: μ₁ ≠ μ₂; H₁: μ₁ = μ₂

d. What sampling distribution will you use? What assumptions are you making?

The Student's t. We assume that both population distributions are approximately normal with known population standard deviations.

The Student's t. We assume that both population distributions are approximately normal with unknown population standard deviations.     

The standard normal. We assume that both population distributions are approximately normal with unknown population standard deviations.

The standard normal. We assume that both population distributions are approximately normal with known population standard deviations.

e. What is the value of the sample test statistic? (Test the difference μ₁ − μ₂. Round your answer to three decimal places.)

f. Estimate the P-value.

P-value > 0.250

0.125 < P-value < 0.250    

0.050 < P-value < 0.1250.025 < P-value < 0.050

0.005 < P-value < 0.025

P-value < 0.005

g. Sketch the sampling distribution and show the area corresponding to the P-value.

h. Will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α?

At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant.

At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.     

At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant.

At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant.

i. Interpret your conclusion in the context of the application.

There is sufficient evidence at the 0.01 level that the yellow paint has less visibility after 1 year.

There is insufficient evidence at the 0.01 level that the yellow paint has less visibility after 1 year.    

The highway department is testing two types of reflecting paint for concrete bridge end pillars. The two kinds of paint are alike in every respect except that one is orange and the other is yellow. The orange paint is applied to 11 bridges, and the yellow paint is applied to 11 bridges. After a period of 1 year, reflectometer readings were made on all these bridge end pillars. (A higher reading means better visibility.) For the orange paint, the mean reflectometer reading was x1 = 9.4, with standard deviation s1 = 2.1. For the yellow paint the mean was x2 = 6.4, with standard deviation s2 = 1.7. Based on these data, can we conclude that the yellow paint has less visibility after 1 year? Use a 1% level of significance.

What are we testing in this problem? single mean single proportion paired difference difference of means difference of proportions (a) What is the level of significance? State the null and alternate hypotheses. H0: μ1 = μ2; H1: μ1 < μ2 H0: μ1 = μ2; H1: μ1 > μ2 H0: μ1 > μ2; H1: μ1 = μ2 H0: μ1 = μ2; H1: μ1 ≠ μ2 (b) What sampling distribution will you use? What assumptions are you making? The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations. The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations. The standard normal. We assume that both population distributions are approximately normal with known standard deviations. The Student's t. We assume that both population distributions are approximately normal with known standard deviations. What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.) (d) Find (or estimate) the P-value. (Round your answer to four decimal places.) Sketch the sampling distribution and show the area corresponding to the P-value. Maple Generated Plot Maple Generated Plot Maple Generated Plot Maple Generated Plot (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α? At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant. At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant. (e) Interpret your conclusion in the context of the application. There is sufficient evidence at the 0.01 level that the yellow paint has less visibility after 1 year. There is insufficient evidence at the 0.01 level that the yellow paint has less visibility after 1 year.

The highway department is testing two types of reflecting paint for concrete bridge end pillars. The two kinds of paint are alike in every respect except that one is orange and the other is yellow. The orange paint is applied to 12 bridges, and the yellow paint is applied to 12 bridges. After a period of 1 year, reflectometer readings were made on all these bridge end pillars. (A higher reading means better visibility.) For the orange paint, the mean reflectometer reading was x1 = 9.4, with standard deviation s1 = 2.1. For the yellow paint the mean was x2 = 7.1, with standard deviation s2 = 2.3. Based on the data, can we conclude that the yellow paint has less visibility after 1 year? Use a 1% level of significance

a.) What are we testing in this problem?

-difference of means

-single proportion

-single mean

-difference of proportions

-paired difference

b.) What is the level of significance? ______

c.) State the null and alternate hypotheses.

-H0: μ1 ≥ μ2; H1: μ1 < μ2

-H0: μ1 = μ2; H1: μ1 ≠ μ2

-H0: μ1 ≠ μ2; H1: μ1 = μ2

-H0: μ1 ≤ μ2; H1: μ1 > μ2

d.) What sampling distribution will you use? What assumptions are you making?

-The Student's t. We assume that both population distributions are approximately normal with known population standard deviations.

-The standard normal. We assume that both population distributions are approximately normal with known population standard deviations.

-The Student's t. We assume that both population distributions are approximately normal with unknown population standard deviations.

-The standard normal. We assume that both population distributions are approximately normal with unknown population standard deviations.

e.) What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.) _____________

f.) Estimate the P-value.

-P-value > 0.250

-0.125 < P-value < 0.250

-0.050 < P-value < 0.125

-0.025 < P-value < 0.050

-0.005 < P-value < 0.025

-P-value < 0.005

f.) Sketch the sampling distribution and show the area corresponding to the P-value.

g.) Will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α?

-At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant.

-At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.

-At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant.

-At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant.

h.) Interpret your conclusion in the context of the application.

-There is sufficient evidence at the 0.01 level that the yellow paint has less visibility after 1 year.

-There is insufficient evidence at the 0.01 level that the yellow paint has less visibility after 1 year.

Q1.Which of the following are propositions?

(a) The Apple Macintosh is a 256-bit computer.

(b) Why are you here?

(c) 8 + 10 = 12

Q2.Construct truth tables for each of the following compound propositions. What do you notice about the results?

(a) p∨(¬p⋏q)

(b) p∨q

Q3.For the following multiple choice question, pick one choice (1. A tautology; 2. A contradiction; 3. Neither) for each compound proposition.

• p ⋏(¬p)    
• p ⋏(¬q)    

For the following multiple choice question, pick one choice by circling it (you may have to give some explanations.)

Q4. Match the term on the left to the number of the matching expression on the right.

(a) converse of Q ଠS                                                                              

(b) a tautology                                                                                               

(c) a contradiction                                                                                        1. ¬Q àS

(d) equivalent to Q àS                                                                                   2. ¬S v S ^ S

(e) inverse of Q à¬S                                                                                     

(f) contrapositive of QàS   

Q5.Is this a valid argument?                                                                                                                 

Q6. For each of the premise-conclusion pairs below, give a valid step-by-step argument (proof) along with the name of the inference rule used in each step.

Premise: {p v q, q àr, p ^ s àt, ¬r,¬q àu ^ s}, conclusion:t.

Q7.Use the truth table to verify the following statement:

¬ (p ∨¬q) ∨(¬p ∧¬q) ≡ p

Q8.Let Q(n) be the predicate “n²≤ 49.”

Write Q(3), Q(−3), Q(5), Q(−5), Q(8), and Q(−8) and indicate which of these statements are true and which are false.

Q9.In 1–2, write a negation (¬) for each statement.

1.∃x ∈R, if x²≥ 1 then x ≤ 0.

2. ∀n ∈Z, if n is composite then n is even or n =

PS: A composite number is a positive integer which is not prime (i.e., which has factors other than 1 and itself).

HINT: For Sales use "Total revenues" for your computations, when applicable.

(a) Compute net operating profit after tax (NOPAT) for 2016. Assume that the combined federal and state statutory tax rate is 37%. (Round to the nearest whole number.)

2016 NOPAT = Answer

($ millions)

(b) Compute net operating assets (NOA) for 2016 and 2015.

2016 NOA = Answer

($ millions)
2015 NOA = Answer ($ millions)

(c) Compute Costco’s RNOA, net operating profit margin (NOPM) and net operating asset turnover (NOAT) for 2016. (Do not round until final answer. Round two decimal places. Do not use NOPM x NOAT to calculate RNOA)

2016 RNOA = Answer

%
2016 NOPM = Answer%
2016 NOAT = Answer

(d) Compute net nonoperating obligations (NNO) for 2016 and 2015.

2016 NNO = Answer

($ millions)
2015 NNO = Answer ($ millions)

(e) Compute return on equity (ROE) for 2016. (Do not round until final answer. Round answer two decimal places)

2016 ROE = Answer

%

(f) Infer the nonoperating return component of ROE for 2016. (Use answers from above to calculate. Round two decimal places.)

Answer

%

(g) What does the relation between ROE and RNOA suggest about Costco's use of equity capital?

ROE > RNOA implies that Costco's equity has grown faster than its NOA.

ROE > RNOA implies that Costco has taken on too much financial leverage.

ROE > RNOA implies that Costco is able to borrow money to fund operating assets that yield a return greater than its cost of debt.

ROE > RNOA implies that Costco increased its financial leverage during the period.

Consider a disk with block size B = 512 bytes. A block pointer is P = 6 bytes long, and a record pointer is PR = 7 bytes long. A file has r = 30,000 EMPLOYEE records of fixed length. Each record has the following fields: Name (30 bytes),Ssn (9 bytes), Department_code (9 bytes), Address (40 bytes), Phone (10 bytes), Birth_date (8 bytes), Sex (1 byte), Job_code (4 bytes), and Salary (4 bytes, real number). An additional byte is used as a deletion marker.

Suppose that the file is not ordered by the key field Ssn and we want to construct a B+-tree access structure (index) on Ssn. Calculate (i) the orders p and pleaf of the B+-tree; (ii) the number of leaf-level blocks needed if blocks are approximately 69% full (rounded up for convenience); (iii) the number of levels needed if internal nodes are also 69% full (rounded up for convenience); (iv) the total number of blocks required by the B+-tree; and (v) the number of block accesses needed to search for and retrieve a record from the file—given its Ssn value—using the B+-tree.

Java Programming :

Email username generator Write an application that asks the user to enter first name and last name. Generate the username from the first five letters of the last name, followed by the first two letters of the first name. Use the .toLowerCase() method to insure all strings are lower case. String aString = “Abcd” aString.toLowerCase(); aString = abcd Use aString.substring(start position, end position + 1) aString.substring(0, 3) yields the first 3 letters of a string If the last name is no more than five letters, use the entire name. If it is more than five letters, use the first 5 letters Print the email username you generated with @myCollege.edu appended

Write a java program that prompts user to enter his name and KSU ID using format name-ID as one value, his gender as char, and his GPA out of 5. Then your program should do the following:

Print whether the ID is valid or not, where a valid ID should be of length = 9, and should start with 4.
Calculate the GPA out of 100 which is calculated as follows GPA/5 * 100.
Update the name after converting the first letter to uppercase.
Print “Mr.” before name if the gender is ‘M’, and print “Mrs.” before name if the gender is ‘F’. Otherwise print message “invalid gender” without name and GPA. Then print the new GPA.

Business law, please help for this court case below.

Gaskell v. Univ. of Kentucky

Identify several problems energy drinks such as V energy may face, especially in Australia.