| The health of the bear population in Yellowstone National Park
is monitored by periodic measurements taken from anesthetized
bears. A sample of 38 bears has a mean weight of 188.2 lb. At α = .01, can it be concluded that the average weight of a bear in Yellowstone National Park is different from 187 lb? Note that the standard deviation of the weight of a bear is known to be 8.2 lb. |
| (a) | Find the value of the test statistic for the above hypothesis. |
| (b) | Find the critical value. |
| (c) | Find the p-value. |
| (d) | What is the correct way to draw a conclusion regarding the above hypothesis test? |
(A) If the answer in (c) is greater than 0.01 then we conclude
at the 1% significance
level that the average weight of a bear in Yellowstone National
Park is different from 187 lb.
(B) If the answer in (c) is less than 0.01 then we
cannot conclude at the 1% significance
level that the average weight of a bear in Yellowstone National
Park is different from 187 lb.
(C) If the answer in (a) is greater than the answer in (b) then
we cannot conclude at the 1% significance
level that the average weight of a bear in Yellowstone National
Park is different from 187 lb.
(D) If the answer in (c) is less than 0.01 then we conclude at
the 1% significance
level that the average weight of a bear in Yellowstone National
Park is different from 187 lb.
(E) If the answer in (a) is greater than the answer in (c) then
we cannot conclude at the 1% significance
level that the average weight of a bear in Yellowstone National
Park is different from 187 lb.
(F) If the answer in (b) is greater than the answer in (c) then
we cannot conclude at the 1% significance
level that the average weight of a bear in Yellowstone National
Park is different from 187 lb.
(G) If the answer in (a) is greater than the answer in (c) then
we conclude at the 1% significance
level that the average weight of a bear in Yellowstone National
Park is different from 187 lb.
(H) If the answer in (b) is greater than the answer in (c) then
we conclude at the 1% significance
level that the average weight of a bear in Yellowstone National
Park is different from 187 lb.
In: Math
An important quality characteristic used by the manufacturers of
ABC asphalt shingles is the amount of moisture the shingles contain
when they are packaged. Customers may feel that they have purchased
a product lacking in quality if they find moisture and wet shingles
inside the packaging. In some cases, excessive moisture
can cause the granules attached to the shingles for texture and
colouring purposes to fall off the shingles resulting in appearance
problems. To monitor the amount of moisture present, the company
conducts moisture tests. A shingle is weighed and then dried. The
shingle is then reweighed, and based on the amount of moisture
taken out of the product, the pounds of moisture per 100 square
feet is calculated. The company claims that the mean moisture
content cannot be greater than 0.35 pound per 100 square
feet.
The file (A & B shingles.csv) includes 36 measurements (in
pounds per 100 square feet) for A shingles and 31 for B
shingles.
3.1. For the A shingles, form the null and alternative hypothesis
to test whether the population mean moisture content is less than
0.35 pound per 100 square feet.
3.2. For the B shingles, form the null and alternative hypothesis
to test whether the population mean moisture content is less than
0.35 pound per 100 square feet.
3.3. Do you think that the population means for shingles A and B
are equal?
Form the hypothesis and conduct the test of the hypothesis.
What assumption do you need to check before the test for equality
of means is performed?
3.4. What assumption about the population distribution is needed in
order to conduct the hypothesis tests above?
|
A |
B |
|
0.44 |
0.14 |
|
0.61 |
0.15 |
|
0.47 |
0.31 |
|
0.3 |
0.16 |
|
0.15 |
0.37 |
|
0.24 |
0.18 |
|
0.16 |
0.42 |
|
0.2 |
0.58 |
|
0.2 |
0.25 |
|
0.2 |
0.41 |
|
0.26 |
0.17 |
|
0.14 |
0.13 |
|
0.33 |
0.23 |
|
0.13 |
0.11 |
|
0.72 |
0.1 |
|
0.51 |
0.19 |
|
0.28 |
0.22 |
|
0.39 |
0.44 |
|
0.39 |
0.11 |
|
0.25 |
0.11 |
|
0.16 |
0.31 |
|
0.2 |
0.43 |
|
0.22 |
0.26 |
|
0.42 |
0.18 |
|
0.24 |
0.44 |
|
0.21 |
0.43 |
|
0.49 |
0.16 |
|
0.34 |
0.52 |
|
0.36 |
0.36 |
|
0.29 |
0.22 |
|
0.27 |
0.39 |
|
0.4 |
|
|
0.29 |
|
|
0.43 |
|
|
0.34 |
|
|
0.37 |
In: Statistics and Probability
451 438 430 471 434 449 460 470 449 452 448 445 454 452 442 436 457 446 462 454 414 453 457 442 442 447 446 447 456 447 431 452 437 446 466 454 443 439 443 433 Assuming that the population standard deviation for the 40 arrival times above is 12. And you are performing a 1-sample t test… A) How many data points would be needed if you wanted to detect a difference of 5 minutes. Assume that alpha is 0.05. Beta is 0.10 (Power is .9). B) Given that you have already collected 40 data points, what was the Power of the test? Assume alpha is 0.05 and the difference is 5 again. C) Suppose you would like to look at several possibilities at once…Find the sample size needed if the difference is 3, 4 and 5 minutes while the power is 0.7, 0.8, and 0.9.
In: Statistics and Probability
Q1. Roller bearings are subject to fatigue failure caused by large contact loads. The
problem of finding the location of the maximum stress along the x axis can be shown to be
equivalent to maximizing the function:
= + x
With the aid of the secant method, use xo=0.98 and x1=0.7 to determine to within 10-5 the
value of x that maximizes f(x).
Q 2. In an LRC series circuit, the impressed voltage E(t) and the charge q(t) on the
capacitor are related to each other by the linear second-order ordinary differential equation,
where L is the inductance, R is the resistance and C is the capacitance. Suppose we measure
the charge on the capacitor for several values of t and obtain
|
t |
1.50 |
1.525 |
1.55 |
1.575 |
1.60 |
|
q |
0.8 |
1.2 |
1.15 |
1.3 |
1.8 |
where t is in seconds, q is in coulombs, the inductance L is a constant 0.5h , the resistance R
is 0.3Ω and the Capacitance is 0.01 f . Approximate the voltage E(t) when t = 1.525, 1.55 and
1.575.
In: Physics
TABLE 10-16
A realtor wants to compare the average sales-to-appraisal ratios of
residential properties sold in four neighborhoods (A, B, C, and D).
Four properties are randomly selected from each neighborhood and
the ratios recorded for each, as shown below.
A: 1.2, 1.1, 0.9, 0.4 C: 1.0, 1.5, 1.1, 1.3
B: 2.5, 2.1, 1.9, 1.6 D: 0.8, 1.3, 1.1, 0.7
Interpret the results of the analysis summarized in the following
table:
Referring to Table 10-16, what should be the decision for the
Levene’s test for homogeneity of variances at a 5% level of
significance?
Group of answer choices
Do not reject the null hypothesis because the p-value is larger than the level of significance.
Reject the null hypothesis because the p-value is larger than the level of significance.
Do not eject the null hypothesis because the p-value is smaller than the level of significance.
Reject the null hypothesis because the p-value is smaller than the level of significance.
In: Statistics and Probability
Suppose that oil fouls the beaches along the Florida panhandle. Vacationers are the primary customers of the hotels along the panhandle. The oil _____ the price of a hotel room and _____ the quantity of hotel rooms rented
In: Economics
How is the concept of resort hotel different from other types of hotels? From a manager’s perspective, how is managing a resort hotel different from running other properties?
In: Operations Management
In: Operations Management
As a concerned employee of 'Delexis Hotel', Sunyani, write a letter to the General Manager informing him of four (4) inherent challenges inhibiting the success of interpersonal communications within the hotel.
In: Operations Management
What are the knowledge important for hotel business (Customer, supplier, administrator)(Small hotels like darwin city hotel)? How they use these knowledge? Develop a KMS framework for the business
In: Finance