Questions
2.a. You are running a batch reactor. Each batch takes about four hours to run. You...

2.a. You are running a batch reactor. Each batch takes about four hours to run. You measure the purity of the batch four times in the last hour to ensure that it has stabilized. You want to monitor the results using an X-R chart. The data you have collected for the first 10 batches are given the table below. X1, X2, X3 and X4 are the four samples you pull from the batch in the last hour. Using all the data, find trial control limits for and R charts, construct the chart, and plot the data. (30 pts)

2.b. Is the process in statistical control? Identify out-of-control points. (30 pts)

Subgroup

X1

X2

X3

X4

X

R

1

98.4

98.6

98.3

98.7

98.5

0.4

2

97.5

97.6

98.0

97.6

97.7

0.5

3

98.8

98.9

98.4

98.7

98.7

0.5

4

99.1

99.3

99.4

99.2

99.3

0.3

5

97.8

98.0

98.2

98.0

98.0

0.4

6

98.3

98.5

98.5

98.5

98.5

0.2

7

98.9

99.0

98.6

99.0

98.9

0.4

8

97.5

97.7

97.6

97.9

97.7

0.4

9

99.3

99.3

99.2

99.4

99.3

0.2

10

98.5

98.7

98.7

98.3

98.6

0.4

In: Statistics and Probability

a. Caro Manufacturing has two production departments, Machining and Assembly, and two service departments, Maintenance and...

a. Caro Manufacturing has two production departments, Machining and Assembly, and two service departments, Maintenance and Cafeteria. Direct costs for each department and the proportion of service costs used by the various departments for the month of August follow:

Proportion of Services Used by
Department Direct Costs Maintenance Cafeteria Machining Assembly
Machining $ 98,000
Assembly 74,400
Maintenance 46,000 0.2 0.6 0.2
Cafeteria 37,000 0.6 0.1 0.3

Exercise 11-27 (Algo) Cost Allocation: Direct Method (LO 11-2)

Required:

Compute the allocation of service department costs to producing departments using the direct method. (Do not round intermediate calculations.)

b. Assume that both Machining and Assembly work on just two jobs during the month of August: CM-22 and CM-23. Costs are allocated to jobs based on machine-hours in Machining and labor-hours in Assembly. The number of labor- and machine-hours worked in each department are as follows:

Machining Assembly
Job CM-22: Machine-hours 230 60
Labor-hours 20 20
Job CM-23: Machine-hours 20 40
Labor-hours 30 100

Required:
How much of the service department costs allocated to Machining and Assembly in the direct method should be allocated to Job CM-22? How much should be allocated to Job CM-23?

In: Accounting

Stock Valuation: A stock has an initial price of $100 per share, paid a dividend of...

  1. Stock Valuation: A stock has an initial price of $100 per share, paid a dividend of $2.00 per share during the year, and had an ending share price of $125. Compute the percentage total return, capital gains yield, and dividend yield.

Capital Gains = 125-100 = 25 and Dividend Yield = $2

            Total return percent = (25+2)/100 = 27/100 = 27%

            Capital Gain return = 25/100 = 25%

            Dividend Yield = 2/100 = 2%

  1. Total Return: You bought a share of 4% preferred stock for $100 last year. The market price for your stock is now $120. What was your total return for last year?

Dividend = 4% of 100 = $4. The capital gain = 120-100 = 20

Total return for last year = $24 = 24%

  1. CAPM - A stock has a beta of 1.20, the expected market rate of return is 12%, and a risk-free rate of 5 percent. What is the expected rate of return of the stock?

CAPM - Expected return of Stock = Rf + beta*(Rm - Rf) = 5 +1.2*(12-5) = 13.4%

  1. WACC: The Corporation has a targeted capital structure of 80% common stock and 20% debt. The cost of equity is 12% and the cost of debt is 7%. The tax rate is 30%. What is the company's weighted average cost of capital (WACC)?

We*Re + Wd*Rd*(1-T) = 0.8*12 + 0.2*7*(1-0.3) = 10.58%

  1. Flotation Costs: Medina Corp. has a debt-equity ratio of .75. The company is considering a new plant that will cost $125 million to build. When the company issues new equity, it incurs a flotation cost of 10%. The flotation cost on new debt is 4%. What is the initial cost of the plant if the company raises all equity externally?

125 million will be raised by issuing both debt and equity so that D/E remains 0.75.

D = 0.75E

E + 0.75E = 125

E = 71.43, D =125- 71.43 = 53.57

Initial cost of the plant will be = 125 + 71.43*0.10 + 53.57*0.04 = 125 + 9.2858 = 134.2858

  1. Stock Valuation: A stock has an initial price of $100 per share, paid a dividend of $2.00 per share during the year, and had an ending share price of $125. Compute the percentage total return, capital gains yield, and dividend yield.

Capital Gains = 125-100 = 25 and Dividend Yield = $2

            Total return percent = (25+2)/100 = 27/100 = 27%

            Capital Gain return = 25/100 = 25%

            Dividend Yield = 2/100 = 2%

  1. Total Return: You bought a share of 4% preferred stock for $100 last year. The market price for your stock is now $120. What was your total return for last year?

Dividend = 4% of 100 = $4. The capital gain = 120-100 = 20

Total return for last year = $24 = 24%

  1. CAPM - A stock has a beta of 1.20, the expected market rate of return is 12%, and a risk-free rate of 5 percent. What is the expected rate of return of the stock?

CAPM - Expected return of Stock = Rf + beta*(Rm - Rf) = 5 +1.2*(12-5) = 13.4%

  1. WACC: The Corporation has a targeted capital structure of 80% common stock and 20% debt. The cost of equity is 12% and the cost of debt is 7%. The tax rate is 30%. What is the company's weighted average cost of capital (WACC)?

We*Re + Wd*Rd*(1-T) = 0.8*12 + 0.2*7*(1-0.3) = 10.58%

  1. Flotation Costs: Medina Corp. has a debt-equity ratio of .75. The company is considering a new plant that will cost $125 million to build. When the company issues new equity, it incurs a flotation cost of 10%. The flotation cost on new debt is 4%. What is the initial cost of the plant if the company raises all equity externally?

125 million will be raised by issuing both debt and equity so that D/E remains 0.75.

D = 0.75E

E + 0.75E = 125

E = 71.43, D =125- 71.43 = 53.57

Initial cost of the plant will be = 125 + 71.43*0.10 + 53.57*0.04 = 125 + 9.2858 = 134.2858

Based on the above answers explain how companies make financial decisions

In: Finance

Case Assignment: Tesla Motors Tesla Motors was founded with innovation in mind. Launched in 2003 by...

Case Assignment: Tesla Motors

Tesla Motors was founded with innovation in mind. Launched in 2003 by a group of engineers in Silicon Valley who wanted to prove that electric cars could replace gasoline-powered automobiles, Tesla’s mission is to accelerate the world’s transition to sustainable energy.

            The Tesla Roadster was launched in 2008 and can travel 245 miles per charge of its lithium ion battery. There are now more than 2,400 Roadsters being driven in more than 30 countries. The Roadster was followed by the Tesla Model S in 2012. The Model S can travel 265 miles per charge and has room for seven passengers with 64 cubic feet of storage. The Model S was named Motor Trend’s 2013 Car of the Year and achieved a 5-star safety rating from the U.S. National Highway Traffic Safety Administration.

            Next came the Model X, which Tesla began delivering in 2015, and the new Model 3 will begin production in mid-2017 with estimated delivery for new reservations at mid-2018 or later. Model 3 is Tesla’s most affordable model to date, starting at $35,000. It has seating for five adults and can travel 215 miles per charge.

            Improvements to battery life and safety features weren’t the only upgrades Tesla had quietly been putting together. They created a roar in the automobile industry when they announced in October 2016 that, moving forward, all vehicles produced in Tesla factories would have the hardware needed for full self-driving capabilities at a safety level higher than that of a human driver. Model S and Model X vehicles with the new hardware are already in production, and the hardware will be included on the new Model 3 when it goes into production.

            This hardware includes eight surround cameras providing 360-degree visibility around the car up to 250 meters of range; two updated ultrasonic sensors; forward-facing radar that can see through heavy rain, fog, dust, and even the car ahead; and a new onboard computer with more than 40 times the computing power of previous generations.

            Tesla’s move was unprecedented compared to that of other car companies, but not as much for them. While Tesla will be creating cars with the hardware needed for self-driving capabilities, they do not have the software finished yet. They will update the software in the cars produced now using over-the-air software updates. This is a method that Tesla already employs to enhance performance and fix security bugs; it allows them to continually improve cars even after they are on the road and to stay ahead of automakers who do not operate under this model.

            Tesla still has to complete millions of miles of real-world testing before the software can be implemented. They will run the software in the background while a professional drives the car and then compare what the computer would have done with what the person did do. The goal is for self-driving cars to be even better than humans at avoiding crashes.

            Tesla must also achieve regulatory approvals of full self-driving cars before they can legally drive on public roadways. So it is still unclear when customers (even those currently purchasing models featuring the new hardware) will be able to experience fully autonomous driving.

TRUE/FALSE

1. Telsa’s new products have been successful, in part, because they have a well-defined new product strategy at their core and are driven by the corporate objectives and strategies of using electricity over gasoline when designing automobiles.

ANS:

2. A new-product strategy is a plan that links the new-product development process with the objectives of the marketing department, the business unit, and the corporation.

ANS:

3. The business analysis to determine if Tesla should equip their cars with the self-driving hardware before the software was complete would have been a simple process.

ANS:

4. Tesla employed simultaneous product development by having their hardware and their software design teams work together on the autonomous automobile initiative.

ANS:

5. Tesla will use test marketing to teach the self-driving software how to appropriately respond in different driving situations.


In: Operations Management

Say that a sample of size 49 taken from a normally distributed population, has variance =...

Say that a sample of size 49 taken from a normally distributed population, has variance = 1. The sample has a mean of 0.49. Then, a 95% confidence interval for µ will be

0.49 – (1.96)(1/7) < µ < 0.49 + (1.96)(1/7)

0.49 – (2.575)(1/7) < µ < 0.49 + (1.96)(1/7)

49 – (1.96)(1/0.7) < µ < 49 + (1.96)(1/0.7)

49 – (2.575)(1/0.7) < µ < 49 + (2.575)(1/0.7)

In: Statistics and Probability

A well-known brokerage firm executive claimed that 70% of investors are currently confident of meeting their...

A well-known brokerage firm executive claimed that 70% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 800 people, 67% of them said they are confident of meeting their goals.

Test the claim that the proportion of people who are confident is smaller than 70% at the 0.005 significance level.

The null and alternative hypothesis would be:

H0:p≥0.7H0:p≥0.7
H1:p<0.7H1:p<0.7

H0:μ=0.7H0:μ=0.7
H1:μ≠0.7H1:μ≠0.7

H0:μ≥0.7H0:μ≥0.7
H1:μ<0.7H1:μ<0.7

H0:p=0.7H0:p=0.7
H1:p≠0.7H1:p≠0.7

H0:p≤0.7H0:p≤0.7
H1:p>0.7H1:p>0.7

H0:μ≤0.7H0:μ≤0.7
H1:μ>0.7H1:μ>0.7



The test is:

left-tailed

two-tailed

right-tailed



The test statistic is:  (to 3 decimals)

The p-value is:  (to 4 decimals)

Based on this we:

Fail to reject the null hypothesis

Reject the null hypothesis

2) Test the claim that the proportion of men who own cats is significantly different than 60% at the 0.05 significance level.


The null and alternative hypothesis would be:

H0:p=0.6H0:p=0.6
H1:p<0.6H1:p<0.6

H0:μ=0.6H0:μ=0.6
H1:μ<0.6H1:μ<0.6

H0:μ=0.6H0:μ=0.6
H1:μ≠0.6H1:μ≠0.6

H0:p=0.6H0:p=0.6
H1:p≠0.6H1:p≠0.6

H0:μ=0.6H0:μ=0.6
H1:μ>0.6H1:μ>0.6

H0:p=0.6H0:p=0.6
H1:p>0.6H1:p>0.6



The test is:

two-tailed

left-tailed

right-tailed



Based on a sample of 20 people, 65% owned cats

The test statistic is:  (to 2 decimals)

The positive critical value is:  (to 2 decimals)

Based on this we:

Fail to reject the null hypothesis

Reject the null hypothesis

In: Statistics and Probability

Lynch was the loan officer at First Bank. Patterson applied to borrow $25,000. Bank policy required...

Lynch was the loan officer at First Bank. Patterson applied to borrow $25,000. Bank policy required that Lynch obtain a loan guaranty from Patterson’s employer, a milk company. The manager of the milk company visited the bank and signed a guaranty on behalf of the company. The last paragraph of the guaranty stated, “This guaranty is signed by an officer having legal right to bind the company through authorization of the Board of Directors.” Should Lynch be satisfied with this guaranty? Would he be satisfied if the president of the milk company, who was also a director, affirmed that the manager had authority to sign the guaranty? Explain.

Ralph owned a retail meat market. Ralph’s agent Sam, without authority but purporting to act on Ralph’s behalf, borrowed $7,500 from Ted. Although he never received the money, Ralph repaid $700 of the alleged loan and promised to repay the rest. If Sam had no authority to make the loan, is Ralph liable? Why?

A guest arrived early one morning at the Hotel Ohio. Clemens, a person in the hotel office who appeared to be in charge, walked behind the counter, registered the guest, gave him a key, and took him to his room. The guest also checked valuables (a diamond pin and money) with Clemens, who signed a receipt on behalf of the hotel. Clemens in fact was a roomer at the hotel, not an employee, and had no authority to act on behalf of the hotel. When Clemens absconded with the valuables, the guest sued the hotel. Is the hotel liable? Why?

In: Operations Management

You have recently been promoted to General Manager at Creekview Lodge, a 50 room hotel in...

You have recently been promoted to General Manager at Creekview Lodge, a 50 room hotel in Gatlinburg, Tennessee. You started working at the lodge in high school in the restaurant and after college, returned to Creekview as one of the assistant managers before being promoted to hotel manager. Recently, a 200-room hotel opened not far from Creekview Lodge, and although Creekview still maintains near 100% capacity there has been quite a bit of turnover. More than ten employees left to work for the larger hotel which boasted higher pay and better health insurance.

You were informed this morning by the front desk team that the latest customer survey results show a drop in the satisfaction rating for guest room cleanliness. The current report indicates that 73% of guests responded “completely satisfied”, 12% responded “satisfied”, 10% responded “neither satisfied nor unsatisfied”, and 5% responded “unsatisfied.” The housekeeping staff lost four employees to the new hotel, so although disappointed, you aren’t surprised by this news. Still, you could not remember a time that the hotel had received such a low satisfaction rating.

As manager of Creekview Lodge, what is your next step in addressing the problem?

A)Take immediate action and require that all rooms be inspected by the hotel manager (you) or an assistant manager before being made available to customers

D)Review the standards of performance and compare to current performance

In: Operations Management

Section A (25 marks) – Hotel Business in Hong Kong Question A1 Answer the below short...

Section A – Hotel Business in Hong Kong Question A1 Answer the below short questions (a) to (i) according to A Statistical Review of Hong Kong Tourism 2018, published by Hong Kong Tourism Board in June 2019.

a) What is the total number of visitor arrival to Hong Kong upon 2018? How many visitors stayed overnight?

b) Identify Hong Kong’s top THREE source markets of visitors’ arrival to Hong Kong in 2018.

c) Which month contained the highest visitor arrivals number in 2018?

d) Briefly describe the hotel performance in 2018.

e) Which hotel category noted a highest gain percentage in room occupancy compare with 2017?

f) State TWO districts which recorded the highest room occupancy rate in Hong Kong.

g) In 2017, which department in the hotel earn the second highest revenue and what is the total percentage.

h) Refer to the hotel room occupancy rate and average achieved hotel room rate in 2018, illustrate TWO indicators or messages reflected from those figures.

i) The percentage distribution of visitor arrivals by months 2018 were quite steady along the year, the range of percentage starting from 7.2% to 10.1%. If you were the manager of a hotel, try to briefly explain the reasons behind of the distributions. (For example: What is/are the factor(s) may affect the percentage of arrival on Dec 2018.)

In: Operations Management

The health of the bear population in Yellowstone National Park is monitored by periodic measurements taken...

The health of the bear population in Yellowstone National Park is monitored by periodic measurements taken from anesthetized bears. A sample of 38 bears has a mean weight of 189.6 lb.

At α = .05, can it be concluded that the average weight of a bear in Yellowstone National Park is different from 187 lb? Note that the standard deviation of the weight of a bear is known to be 8.2 lb.

(a) Find the value of the test statistic for the above hypothesis.
(b) Find the critical value.
(c) Find the p-value.
(d) What is the correct way to draw a conclusion regarding the above hypothesis test?
(A) If the answer in (b) is greater than the answer in (c) then we cannot conclude at the 5% significance
level that the average weight of a bear in Yellowstone National Park is different from 187 lb.
(B) If the answer in (b) is greater than the answer in (c) then we conclude at the 5% significance
level that the average weight of a bear in Yellowstone National Park is different from 187 lb.
(C) If the answer in (a) is greater than the answer in (b) then we conclude at the 5% significance
level that the average weight of a bear in Yellowstone National Park is different from 187 lb.
(D) If the answer in (a) is greater than the answer in (c) then we conclude at the 5% significance
level that the average weight of a bear in Yellowstone National Park is different from 187 lb.
(E) If the answer in (c) is less than 0.05 then we cannot conclude at the 5% significance
level that the average weight of a bear in Yellowstone National Park is different from 187 lb.
(F) If the answer in (c) is greater than 0.05 then we conclude at the 5% significance
level that the average weight of a bear in Yellowstone National Park is different from 187 lb.
(G) If the answer in (a) is greater than the answer in (b) then we cannot conclude at the 5% significance
level that the average weight of a bear in Yellowstone National Park is different from 187 lb.
(H) If the answer in (a) is greater than the answer in (c) then we cannot conclude at the 5% significance
level that the average weight of a bear in Yellowstone National Park is different from 187 lb.

In: Math