Pin Corporation paid $4,500,000 for a 90 percent interest in San Corporation on January 1, 2016; San’s total book value was $4,500,000. The excess was allocated as follows: $150,000 to undervalued equipment with a three-year remaining useful life and $350,000 to goodwill. The income statements of Pin and San for 2016 are summarized as follows (in thousands):
Pin San
Sales $9,000 $5,200
Income from San 450
Cost of sales (5,000) (3,600)
Depreciation expense (1,000) (520)
Other expenses (1,450) (580)
Net income $2,000 500
Required:
In: Accounting
The PFK1 enzyme is regulated by a number of factors in the cell, including the level of ATP. ATP is not only
involved in the reaction the enzyme catalyses but also binds to an allosteric site leading to a reduction in
activity.
The binding of ATP can be measured using a fluorescently labelled derivative of ATP – TNP-ATP. The data
presented below represents the determination of the binding of ATP to PFK. The change in fluorescence (?
fluor.) represents the concentration of PFK1 with TNP-ATP bound. This value was determined at 5
different concentrations of TNP-ATP, and the experiment was carried out in triplicate.
|
? fluor. (arbitrary units) |
|||
|
[TNP-ATP] (µM) |
Experiment 1 |
Experiment 2 |
Experiment 3 |
|
60 |
0.078 |
0.081 |
0.085 |
|
120 |
0.131 |
0.139 |
0.140 |
|
240 |
0.240 |
0.241 |
0.250 |
|
480 |
0.325 |
0.335 |
0.319 |
|
960 |
0.416 |
0.442 |
0.409 |
a) Create a double reciprocal plot of this data (1/[TNP-ATP] vs. 1/ ? fluor.). Plot the data from
each experiment as a separate dataset on the same graph. Only plot the data points – do
not join data points with lines. Ensure that each dataset is distinct from the others (use
alternate colours and/or shapes for the data points).
b) Fit an equation to each dataset separately. Do not show these on your plots. For each
experiment give the fitted equation and the value of Kd. Show these in a table. Ensure you
include the units of this value. Show your working for the Experiment 1 data.
c) Determine the mean and standard deviation of the data for each concentration of TNPATP.
Show these in a table. Transform this data as you have done in (a). Fit an equation to
the transformed data. Give the fitted equation and the calculated Kd for the averaged
data. Add a trendline defined by this equation to your graph.
d) With reference the data you plotted and Kd values you determined, explain the positive
and negative aspects of using a double reciprocal plot.
In: Biology
Calculate the 5-day and 50-day simple MA for the stock price from 28 Oct 2016 to 14 June 2017. Plot the MA5 and MA50. How many golden crosses (if any) are there?
| Date | Time | Closing Price | 5-day MA | 50-day MA |
| 2016/10/28 | 1 | 204 | ||
| 2016/10/31 | 2 | 205.399994 | ||
| 2016/11/1 | 3 | 206 | ||
| 2016/11/2 | 4 | 203 | ||
| 2016/11/3 | 5 | 200.199997 | ||
| 2016/11/4 | 6 | 199.699997 | ||
| 2016/11/7 | 7 | 202.600006 | ||
| 2016/11/8 | 8 | 203.600006 | ||
| 2016/11/9 | 9 | 202.399994 | ||
| 2016/11/10 | 10 | 204.800003 | ||
| 2016/11/11 | 11 | 206.199997 | ||
| 2016/11/14 | 12 | 204.199997 | ||
| 2016/11/15 | 13 | 203.399994 | ||
| 2016/11/16 | 14 | 203.399994 | ||
| 2016/11/17 | 15 | 204 | ||
| 2016/11/18 | 16 | 203 | ||
| 2016/11/21 | 17 | 202.399994 | ||
| 2016/11/22 | 18 | 203.800003 | ||
| 2016/11/23 | 19 | 203.600006 | ||
| 2016/11/24 | 20 | 203.800003 | ||
| 2016/11/25 | 21 | 205 | ||
| 2016/11/28 | 22 | 204.800003 | ||
| 2016/11/29 | 23 | 203.600006 | ||
| 2016/11/30 | 24 | 204 | ||
| 2016/12/1 | 25 | 204.199997 | ||
| 2016/12/2 | 26 | 202.800003 | ||
| 2016/12/5 | 27 | 197.399994 | ||
| 2016/12/6 | 28 | 196.399994 | ||
| 2016/12/7 | 29 | 193.600006 | ||
| 2016/12/8 | 30 | 195 | ||
| 2016/12/9 | 31 | 192.699997 | ||
| 2016/12/12 | 32 | 189.600006 | ||
| 2016/12/13 | 33 | 189.600006 | ||
| 2016/12/14 | 34 | 190 | ||
| 2016/12/15 | 35 | 186.899994 | ||
| 2016/12/16 | 36 | 185.100006 | ||
| 2016/12/19 | 37 | 182.600006 | ||
| 2016/12/20 | 38 | 182.100006 | ||
| 2016/12/21 | 39 | 182.100006 | ||
| 2016/12/22 | 40 | 181 | ||
| 2016/12/23 | 41 | 179.899994 | ||
| 2016/12/28 | 42 | 180.699997 | ||
| 2016/12/29 | 43 | 180.899994 | ||
| 2016/12/30 | 44 | 183.199997 | ||
| 2017/1/3 | 45 | 184.300003 | ||
| 2017/1/4 | 46 | 182.600006 | ||
| 2017/1/5 | 47 | 185.300003 | ||
| 2017/1/6 | 48 | 185.399994 | ||
| 2017/1/9 | 49 | 185.600006 | ||
| 2017/1/10 | 50 | 187.5 | ||
| 2017/1/11 | 51 | 188.300003 | ||
| 2017/1/12 | 52 | 186.600006 | ||
| 2017/1/13 | 53 | 186.5 | ||
| 2017/1/16 | 54 | 185 | ||
| 2017/1/17 | 55 | 185.899994 | ||
| 2017/1/18 | 56 | 187.899994 | ||
| 2017/1/19 | 57 | 187.199997 | ||
| 2017/1/20 | 58 | 185.5 | ||
| 2017/1/23 | 59 | 185.199997 | ||
| 2017/1/24 | 60 | 185.199997 | ||
| 2017/1/25 | 61 | 185.800003 | ||
| 2017/1/26 | 62 | 187.800003 | ||
| 2017/1/27 | 63 | 188.699997 | ||
| 2017/2/1 | 64 | 188.5 | ||
| 2017/2/2 | 65 | 187.300003 | ||
| 2017/2/3 | 66 | 186.399994 | ||
| 2017/2/6 | 67 | 187.199997 | ||
| 2017/2/7 | 68 | 186.699997 | ||
| 2017/2/8 | 69 | 195.5 | ||
| 2017/2/9 | 70 | 195.5 | ||
| 2017/2/10 | 71 | 195.800003 | ||
| 2017/2/13 | 72 | 198.699997 | ||
| 2017/2/14 | 73 | 197.800003 | ||
| 2017/2/15 | 74 | 202 | ||
| 2017/2/16 | 75 | 202.399994 | ||
| 2017/2/17 | 76 | 200.199997 | ||
| 2017/2/20 | 77 | 200.800003 | ||
| 2017/2/21 | 78 | 199 | ||
| 2017/2/22 | 79 | 200 | ||
| 2017/2/23 | 80 | 200.399994 | ||
| 2017/2/24 | 81 | 198 | ||
| 2017/2/27 | 82 | 195.399994 | ||
| 2017/2/28 | 83 | 192.699997 | ||
| 2017/3/1 | 84 | 193.5 | ||
| 2017/3/2 | 85 | 192 | ||
| 2017/3/3 | 86 | 191.399994 | ||
| 2017/3/6 | 87 | 191.699997 | ||
| 2017/3/7 | 88 | 192.199997 | ||
| 2017/3/8 | 89 | 191.800003 | ||
| 2017/3/9 | 90 | 190.399994 | ||
| 2017/3/10 | 91 | 190.100006 | ||
| 2017/3/13 | 92 | 191.800003 | ||
| 2017/3/14 | 93 | 192 | ||
| 2017/3/15 | 94 | 194.699997 | ||
| 2017/3/16 | 95 | 197.399994 | ||
| 2017/3/17 | 96 | 196.5 | ||
| 2017/3/20 | 97 | 200.399994 | ||
| 2017/3/21 | 98 | 199.699997 | ||
| 2017/3/22 | 99 | 196.399994 | ||
| 2017/3/23 | 100 | 196.399994 | ||
| 2017/3/24 | 101 | 196.399994 | ||
| 2017/3/27 | 102 | 195 | ||
| 2017/3/28 | 103 | 195.399994 | ||
| 2017/3/29 | 104 | 194.600006 | ||
| 2017/3/30 | 105 | 194.399994 | ||
| 2017/3/31 | 106 | 195.600006 | ||
| 2017/4/3 | 107 | 196.100006 | ||
| 2017/4/5 | 108 | 197.399994 | ||
| 2017/4/6 | 109 | 196 | ||
| 2017/4/7 | 110 | 195.899994 | ||
| 2017/4/10 | 111 | 195.5 | ||
| 2017/4/11 | 112 | 193.800003 | ||
| 2017/4/12 | 113 | 195.199997 | ||
| 2017/4/13 | 114 | 194.199997 | ||
| 2017/4/18 | 115 | 191.699997 | ||
| 2017/4/19 | 116 | 190.800003 | ||
| 2017/4/20 | 117 | 191.5 | ||
| 2017/4/21 | 118 | 190.800003 | ||
| 2017/4/24 | 119 | 190.800003 | ||
| 2017/4/25 | 120 | 192 | ||
| 2017/4/26 | 121 | 193.699997 | ||
| 2017/4/27 | 122 | 194.100006 | ||
| 2017/4/28 | 123 | 191.600006 | ||
| 2017/5/2 | 124 | 191.600006 | ||
| 2017/5/4 | 125 | 190.600006 | ||
| 2017/5/5 | 126 | 189.300003 | ||
| 2017/5/8 | 127 | 189.600006 | ||
| 2017/5/9 | 128 | 194.399994 | ||
| 2017/5/10 | 129 | 194.199997 | ||
| 2017/5/11 | 130 | 195.699997 | ||
| 2017/5/12 | 131 | 195.5 | ||
| 2017/5/15 | 132 | 197.100006 | ||
| 2017/5/16 | 133 | 196.699997 | ||
| 2017/5/17 | 134 | 197.699997 | ||
| 2017/5/18 | 135 | 195.300003 | ||
| 2017/5/19 | 136 | 195.699997 | ||
| 2017/5/22 | 137 | 196.399994 | ||
| 2017/5/23 | 138 | 195.199997 | ||
| 2017/5/24 | 139 | 194.899994 | ||
| 2017/5/25 | 140 | 196.300003 | ||
| 2017/5/26 | 141 | 196 | ||
| 2017/5/29 | 142 | 197.199997 | ||
| 2017/5/31 | 143 | 196.699997 | ||
| 2017/6/1 | 144 | 196.800003 | ||
| 2017/6/2 | 145 | 205 | ||
| 2017/6/5 | 146 | 203.800003 | ||
| 2017/6/6 | 147 | 205 | ||
| 2017/6/7 | 148 | 204.199997 | ||
| 2017/6/8 | 149 | 205.600006 | ||
| 2017/6/9 | 150 | 205.399994 | ||
| 2017/6/12 | 151 | 199.699997 | ||
| 2017/6/13 | 152 | 201 | ||
| 2017/6/14 | 153 | 200.600006 |
In: Finance
Pension Expense and Liability
On December 31, 2016, Robey Company accumulated the following information for 2016 in regard to its defined benefit pension plan:
| Service cost | $113,390 |
| Interest cost on projected benefit obligation | 11,810 |
| Expected return on plan assets | 11,250 |
| Amortization of prior service cost | 2,130 |
On its December 31, 2015, balance sheet, Robey had reported an accrued/prepaid pension cost liability of $14,100.
Required:
| 1. | Compute the amount of Robey’s pension expense for 2016. |
| 2. | Prepare all the journal entries related to Robey’s pension plan for 2016 if it funds the pension plan in the amount of (a) $116,080, (b) $115,170, and (c) $119,920. |
| 3. | Next Level Assuming Robey’s beginning 2016 Accumulated Other Comprehensive Income: Prior Service Cost balance was $55,640 what would be its ending balance? |
| 4. | Next Level How much would Robey need to fund its pension plan for 2016 in order to report an accrued/ prepaid pension cost asset of $4,870 at the end of 2016? |
General Journal
Assume Robey Company funds the pension plan in the amount of $116,080. Prepare the entries to record the pension expense for 2016 on December 31 and the amortized prior service cost for 2016 on December 31.
PAGE 1
GENERAL JOURNAL
| DATE | ACCOUNT TITLE | POST. REF. | DEBIT | CREDIT | |
|---|---|---|---|---|---|
|
1 |
|||||
|
2 |
|||||
|
3 |
|||||
|
4 |
Assume Robey Company funds the pension plan in the amount of $115,170. Prepare the entries to record the pension expense for 2016 on December 31 and the amortized prior service cost for 2016 on December 31.
PAGE 1
GENERAL JOURNAL
| DATE | ACCOUNT TITLE | POST. REF. | DEBIT | CREDIT | |
|---|---|---|---|---|---|
|
1 |
|||||
|
2 |
|||||
|
3 |
|||||
|
4 |
|||||
|
5 |
Assume Robey Company funds the pension plan in the amount of $119,920. Prepare the entries to record the pension expense for 2016 on December 31 and the amortized prior service cost for 2016 on December 31.
PAGE 1
GENERAL JOURNAL
| DATE | ACCOUNT TITLE | POST. REF. | DEBIT | CREDIT | |
|---|---|---|---|---|---|
|
1 |
|||||
|
2 |
|||||
|
3 |
|||||
|
4 |
|||||
|
5 |
Calculations
Compute the amount of Robey’s pension expense for 2016.
Next Level: Assuming Robey’s beginning 2016 Accumulated Other Comprehensive Income: Prior Service Cost balance was $55,640 what would be its ending balance?
How much would Robey need to fund its pension plan for 2016 in order to report an accrued/ prepaid pension cost asset of $4,870 at the end of 2016?
In: Accounting
In: Physics
In: Physics
A concentration cell based on the following half reaction at 309 K Ag+ + e- → Ag SRP = 0.80 V has initial concentrations of 1.37 M Ag+, 0.269 M Ag+, and a potential of 0.04334 V at these conditions. After 9.3 hours, the new potential of the cell is found to be 0.01406 V. What is the concentration of Ag+ at the cathode at this new potential?
In: Chemistry
Consider the galvanic cell described by (N and M are metals):
N(s)|N2+(aq)||M+(aq)|M(s)
If Eocathode = 0.182 V and Eoanode = 1.411 V, and [N2+(aq)] = 0.931 M and [M+(aq)] = 0.655 M, what is Ecell, using the Nernst equation? ____ V
(the answer is supposed to be 1.233 but I don't understand how)
In: Chemistry
A concentration cell based on the following half reaction at 299 K
Zn2+ + 2 e- → Zn SRP = -0.760 V
has initial concentrations of 1.27 M Zn2+, 0.319 M Zn2+, and a potential of 0.01780 V at these conditions. After 5.6 hours, the new potential of the cell is found to be 0.002816 V. What is the concentration of Zn2+ at the cathode at this new potential?
In: Chemistry
A concentration cell based on the following half reaction at 318 K
Cu2+ + 2 e- → Cu SRP = 0.340 V
has initial concentrations of 1.31 M Cu2+, 0.291 M Cu2+, and a potential of 0.02061 V at these conditions. After 8.1 hours, the new potential of the cell is found to be 0.006576 V. What is the concentration of Cu2+ at the cathode at this new potential?
In: Chemistry