494: Which of the following is NOT true in regards to blocking?
A. A block is a dummy factor which doesn’t interact with real factors
B. A blocking factor has 2 levels
C. A block is a subdivision of the experiment
D. Blocks are used to compensate when production processes restrict randomization of runs
In: Statistics and Probability
A Stirling Engine uses 8.1 x 10^-3 mol of an ideal gas, operates between hot and cold heat reservoirs of temperatures 95 degree celsius and 24 degree celsius, and runs at a rate of 0.7 cps. Q) What is the net transfer into the gas during in cycle?
In: Physics
Overview
In this assignment you are required to implement binary code comparator using Xilinx that it is compatible with the MXK Seven Segment Displays. You will draw your digital logic circuit using Xilinx and then simulate it to verify the functionality of your design.
Software Requirements
? Xilinx ISE 10.1 or higher
Specifications
Binary Code Comparator
The binary code comparator is to be implemented and made compatible with the seven 7-segment displays of the board. Represent the first five digits of your student number into binary. If a given decimal digit is odd, then the binary equivalent will be 1, otherwise it will be 0. For example, the student (decimal) number 99805234 will produce 11001. The user is to enter a 5-bit binary sequence one bit at a time. The five bits will be displayed on five of the seven segment displays. If the five entered bits equal to the stored binary code, then ‘E’ is to be displayed on the sixths seven- segment display. However, if the five entered bits do not equal the binary code, then ‘n’ is to bedisplayed. Note that you do not have to display bits as they are received in accumulating manner (as shown in the figure below), rather, you can display all five bits and the comparator outcome (‘E’ or ‘n’) when the fifth bit is received. All six seven-segment displays are to stay on for five seconds, then they will be erased. Once the displays are erased, the circuit will be ready for receiving a new set of five input bits.
- Reset: if pressed, the circuit will return to the initial state and all seven segment displays are to be erased.
- Input (could be received from a dipswitch in your MXK): to specify the binary input (1 or 0).
- Trigger (could be received from a pushbutton in your MXK): to allow the input to be received by the circuit.
- Clock: to alternate between the 7-segment displays (expected to be around 1000 Hz).
There are two sets of outputs, which are:
- d1, d2, ..., d7 (anodes to switch between the seven 7-segment displays)
In: Electrical Engineering
Burnside Marketing Research conducted a study for Barker Foods on several formulations for a new dry cereal. Three attributes were found to be most influential in determining which cereal had the best taste: ratio of wheat to corn in the cereal flake, type of sweetener (sugar, honey, or artificial), and the presence or absence of flavor bits. Seven children participated in taste tests and provided the following part-worths for the attributes (see section 13.4 ):
| Wheat/Corn | Sweetener | Flavor Bits | |||||
| Child | Low | High | Sugar | Honey | Artificial | Present | Absent |
| 1 | 15 | 35 | 30 | 40 | 25 | 15 | 9 |
| 2 | 30 | 20 | 40 | 35 | 35 | 8 | 11 |
| 3 | 40 | 25 | 20 | 40 | 10 | 7 | 14 |
| 4 | 35 | 30 | 25 | 20 | 30 | 15 | 18 |
| 5 | 25 | 40 | 40 | 20 | 35 | 18 | 14 |
| 6 | 20 | 25 | 20 | 35 | 30 | 16 | 9 |
| 7 | 30 | 15 | 40 | 25 | 40 | 20 | 11 |
| (a) | Suppose the overall utility (sum of part-worths) of the current favorite cereal is 75 for each child. What product design will maximize the number of children in the sample who prefer the new dry cereal. Note that a child will prefer the new dry cereal only if its overall utility is at least 1 part-worth larger then the utility of their current preferred cereal. | ||||||||
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Share of Choice |
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| (b) | Assume that the overall utility of the current favorite cereal for children 1 to 4 is 70, and the overall utility of the current favorite cereal for children 5 to 7 is 80. What product design will maximize the share of choice for the seven children in the sample? | ||||||||
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Share of Choice |
In: Accounting
Manager T. C. Downs of Plum Engines, a producer of lawn mowers and leaf blowers, must develop an aggregate plan given the forecast for engine demand shown in the table. The department has a regular output capacity of 140 engines per month. Regular output has a cost of $65 per engine. The beginning inventory is zero engines. Overtime has a cost of $115 per engine.
Month 1 2 3 4 5 6 7 8
Total Forecast 130 135 130 143 130 135 135 134 1,072
b. Compare the costs to a level plan that uses inventory to absorb fluctuations. Inventory carrying cost is $3 per engine per month. Backlog cost is $135 per engine per month. There should not be a backlog in the last month. Set regular production equal to the monthly average of total forecasted demand. Assume that using overtime is not an option. (Negative amounts should be indicated by a minus sign. Leave no cells blank - be certain to enter "0" wherever required. Round average inventory row, Inventory cost row, and Total row values to 1 decimal.)
In: Operations Management
Periodic inventory by three methods; cost of goods sold
The units of an item available for sale during the year were as follows:
| Jan. 1 | Inventory | 50 units at $118 |
| Mar. 10 | Purchase | 70 units at $130 |
| Aug. 30 | Purchase | 30 units at $138 |
| Dec. 12 | Purchase | 50 units at $142 |
There are 60 units of the item in the physical inventory at December 31. The periodic inventory system is used.
Determine the ending inventory cost and the cost of goods sold by three methods. Round interim calculations to one decimal and final answers to the nearest whole dollar.
| Cost of Ending Inventory and Cost of Goods Sold | ||
| Inventory Method | Ending Inventory | Cost of Goods Sold |
| First-in, first-out (FIFO) | $ | $ |
| Last-in, first-out (LIFO) | ||
| Weighted average cost | ||
In: Accounting
The table below represents the number of young people in a certain city enrolled in the academic support and enrichment program of youth services. Here, x represents the number of months from January 2011, and y represents the number of young people enrolled. Use Excel to find the best fit linear regression equation. Round the slope and intercept to two decimal places.
x y
0 3199
1 3282
2 3432
3 3245
4 3076
5 3485
6 1524
7 1880
8 2715
9 2963
10 2917
11 3064
12 2730
13 3002
14 3115
15 3148
16 3372
17 3070
18 1813
19 1820
20 2720
21 3297
22 3157
23 2932
24 2839
25 2738
26 2721
27 2999
28 807
29 221
30 1537
31 1922
32 2532
33 3070
34 3091
35 2965
36 2956
37 3116
38 3294
39 3271
40 3211
41 3383
42 2243
43 2035
44 2625
45 2970
46 3046
47 2785
48 2650
49 1121
50 204
51 2796
52 2692
53 2830
54 2068
55 1802
56 2181
57 2675
58 2625
59 2632
60 2354
61 2501
62 2476
63 2458
64 2391
65 2375
In: Statistics and Probability
Expected Return and Standard Deviation / This problem will give you some practice calculating measures of prospective portfolio performance. There are two assets and three states of the economy
|
State of Economy |
Probability of State of Economy |
Rate of Return If State Occurs |
|
|
Stock A |
Stock B |
||
|
Recession |
.20 |
-.15 |
.20 |
|
Normal |
.50 |
.20 |
.30 |
|
Boom |
.30 |
.60 |
.40 |
Expected Returns :
Stock A = (.20 * -.15) + (0.50 * .20) + (.30 * .60) = .25
Stock B = (.20 * .20) + (.50 * .30) + (.30 * .40) = .31
Standard Deviation :
Stock A = .20 * (-.15 - .25)^2 + .50 * (.20 - .25)^2 + .30 * (.60 - .25)^2 = 0.07
√0.07 = .2646, 26.46%
Stock B = .20 * (.20 - .31)^2 + .50 * (.30 - .31)^2 + .30 * (.40 - .31)^2 = 0.0049
√0.0049 = .07, 7%
Portfolio Risk and Return / Using the information in the precious problem, suppose you have $20,000 total. If you put $15,000 in Stock A and the remainder in Stock B. what will be the expected return and standard deviation of your portfolio?
In: Finance
**** In C++ ****Exercise #3: Design and implement a program (name it ArrayMethods), that defines 4 methods as follows: int arrayMax(int[] arr) returns the maximum value in the an array int arrayMin(int[] arr) returns the minimum value in an array void arraySquared(int[] arr) changes every value in the array to its square (value²) void arrayReverse(int[] arr) reverses the array (for example: array storing 7 8 9 becomes 9 8 7 ) The program main method creates a single-dimensional array of length 5 elements and initialize it with random integers between 1 and 100. The program displays the original array, then calls each of the above methods and displays their results as shown below. Document your code and organized your output following these sample runs. Sample run 1: Original array: 3, 5, 2, 6, 1 Max value: 6 Min value: 1 Squared array: 9, 25, 4, 36, 1 Reversed array: 1, 36, 4, 25, 9 Sample run 2: Original array: 3, 2, 3, 7, 2 Max value: 7 Min value: 2 Squared array: 9, 4, 9, 49, 4 Reversed array: 4, 49, 9, 4, 9 Sample run 3: Original array: 2, 2, 2, 2, 2 Maxvalue: 2 Min value: 2 Squared array: 4, 4, 4, 4, 4 Reversed array: 4, 4, 4, 4, 4
In: Computer Science
8. Complete the program that calculates the volume of a cube. If the side length entered for the cube is negative, the program should display an error message saying the length should be positive. If the side length entered for the cube is greater than 100, the program should print a message saying the side is too big. Otherwise the program should calculate and print the volume of the cube of the given side length.
Sample program runs are shown below: import java.util.Scanner; public class CubeVolume { public static void main(){ Scanner reader = new Scanner(System.in); System.out.print("Enter the cube side length: "); double side = reader.nextDouble();
In: Computer Science