Questions
For Part 2 of this assignment, you will use the “Assignment 1 – Linear Kinematics Data”...

For Part 2 of this assignment, you will use the “Assignment 1 – Linear Kinematics Data” excel file. In the data set you are provided with vertical position and time data for a person’s vertical center of mass motion for an unspecified movement task.

You will utilize excel in all (well, some…) of its glory to calculate the vertical velocity and vertical acceleration data from the position and time data provided in the excel file. Again you will use the First Central Difference Method to calculate velocity and acceleration at each frame. Once the velocity and acceleration data have been calculated, plot the position, velocity, and acceleration data against time, either as one graph per variable or all three variables on one graph (using primary and secondary axes). Be sure to label the graphs neatly and appropriately such that you would be confident including them in a formal presentation based on the instructions provided in the tutorials.

Frame Time Vertical COM Position (m)
0 0.0 5.00
1 0.1 5.00
2 0.2 5.00
3 0.3 5.00
4 0.4 5.00
5 0.5 5.00
6 0.6 4.99
7 0.7 4.99
8 0.8 4.98
9 0.9 4.98
10 1.0 4.97
11 1.1 4.93
12 1.2 4.86
13 1.3 4.76
14 1.4 4.67
15 1.5 4.66
16 1.6 4.71
17 1.7 4.89
18 1.8 5.14
19 1.9 5.24
20 2.0 5.35
  1. Between 1 and 1.5 seconds, what direction is the person moving? Are they speeding up, slowing down, or both during this time period?
  2. Between 1.75 and 2 seconds, was the acceleration positive, negative, or both? In addition, was the person moving upward, downward, or both during this time period?
  3. At approximately what time is the person moving at the fastest velocity and in what direction are they moving at this time?
  4. Based on your understanding of the position-velocity-acceleration relationship, what human movement does this data represent assuming the data represent the entire movement task from start to finish?

In: Physics

In 2019, Pittsburgh Steelers starting quarterback Ben Roethlisberger suffered a season-ending elbow injury in Week 2....

In 2019, Pittsburgh Steelers starting quarterback Ben Roethlisberger suffered a season-ending elbow injury in Week 2. The team struggled to find a quarterback until Week 12, when undrafted rookie Devlin “Duck” Hodges entered a game against the Cincinnati Bengals at halftime and led the Steelers to a surprising comeback victory. His performance earned him the starting job for the rest of the season and engendered a flurry of media speculation about his potential as a future quarterback for the Steelers.

Assume quarterbacks can either be good, average, or bad. Because Hodges was undrafted, it’s fair to say that coaches and fans had low expectations for him. Assume the initial probability distribution for Hodges was:

P(Good) =0.1

P(Average)=0.2

P(Bad)= 0.7

Also assume quarterbacks can either have strong performances or weak performances (there are only two types of performances, strong or weak). The chance of a good quarterback having a strong performance is 80%, the chance of an average QB having a strong performance is 50%, and the chance of a bad QB having a strong performance is 30%. We have:

P(S | G) =0.8

P(S | A)=0.5

P(S | B)= 0.3

From ESPN.com, Hodges turned in the following performances during the last 6 weeks of the season:

Date

Opponent

Hodges Passer Rating

Evaluation*

24-Nov

Bengals

115

Strong

1-Dec

Browns

95.7

Strong

8-Dec

Cardinals

117.5

Strong

15-Dec

Bills

43.9

Weak

22-Dec

Jets

37

Weak

29-Dec

Ravens

47.9

Weak

*the average passer rating is around 88

Use Bayes’s Rule to fill in the following table with the week-by-week probabilities of Duck being good, average, or bad.

Consecutive Wins

Prior to the Season

Game 1

Game 2

Game 3

Game 4

Game 5

Game 6

Chances of Being Good

10%

Chances of Being Average

20%

Chances of being Bad

70%

In: Statistics and Probability

In 2019, Pittsburgh Steelers starting quarterback Ben Roethlisberger suffered a season-ending elbow injury in Week 2....

In 2019, Pittsburgh Steelers starting quarterback Ben Roethlisberger suffered a season-ending elbow injury in Week 2. The team struggled to find a quarterback until Week 12, when undrafted rookie Devlin “Duck” Hodges entered a game against the Cincinnati Bengals at halftime and led the Steelers to a surprising comeback victory. His performance earned him the starting job for the rest of the season and engendered a flurry of media speculation about his potential as a future quarterback for the Steelers.

Assume quarterbacks can either be good, average, or bad. Because Hodges was undrafted, it’s fair to say that coaches and fans had low expectations for him. Assume the initial probability distribution for Hodges was:

P(Good) =0.1

P(Average)=0.2

P(Bad)= 0.7

Also assume quarterbacks can either have strong performances or weak performances (there are only two types of performances, strong or weak). The chance of a good quarterback having a strong performance is 80%, the chance of an average QB having a strong performance is 50%, and the chance of a bad QB having a strong performance is 30%. We have:

P(S | G) =0.8

P(S | A)=0.5

P(S | B)= 0.3

From ESPN.com, Hodges turned in the following performances during the last 6 weeks of the season:

Date

Opponent

Hodges Passer Rating

Evaluation*

24-Nov

Bengals

115

Strong

1-Dec

Browns

95.7

Strong

8-Dec

Cardinals

117.5

Strong

15-Dec

Bills

43.9

Weak

22-Dec

Jets

37

Weak

29-Dec

Ravens

47.9

Weak

*the average passer rating is around 88

Use Bayes’s Rule to fill in the following table with the week-by-week probabilities of Duck being good, average, or bad.

Consecutive Wins

Prior to the Season

Game 1

Game 2

Game 3

Game 4

Game 5

Game 6

Chances of Being Good

10%

Chances of Being Average

20%

Chances of being Bad

70%

In: Statistics and Probability

We revisit Example 3.6 in Chapter 3’s lecture note, which shows the relationship between the price...

We revisit Example 3.6 in Chapter 3’s lecture note, which shows the relationship between the price of a diamond and its carat.

Carat (C) Price (P) Carat (C) Price (P)
0.25 3110 0.7 16896
0.3 3786 0.8 22602
0.35 4685 0.9 29775
0.4 5966 1 40022
0.45 7718 1.5 71031
0.5 10478 2 121734
0.55 13156 3 391770
0.6 13877 4 562342

Now we assume that the relationship is of the form P = a 0 e a 1 C .

a) (10pt) Discuss how to estimate a 0 and a 1 using linear regression technique.

b) (10pt) Using the method discussed in a), by Excel, estimate a 0 and a 1 , determine a CER equation to fit these data, and plot the data points and the associated CER curve.

c) (5pt) Using this method, what will be the price for a 1.2 carat diamond?

d) (10pt) Compute the standard error of this method.

e) (10pt) Using the coefficient obtained on page 31 of Chapter 3’s lecture note, compute the standard error of the method assuming the power form P = a 0 C a 1 , and compare it with the result in d). (Note that “SE = 0.1136" on the page is not an answer for this question.)

In: Economics

Research Scenario: Does distraction and/or amount of details affect the ability of people to make good...

Research Scenario: Does distraction and/or amount of details affect the ability of people to make good decisions? In this fictitious scenario, researchers used a mixed design. Thirty participants were split into two groups – No Distraction or Distraction (n=15 per group). All participants were given TWO scenarios based on amount of details (4 or 12), and were asked to make an objective decision at the end of each scenario. Objective decision was the dependent variable and was quantified numerically using an interval scale of measurement.

Assume the data is parametric. Select and conduct the most appropriate statistical test to determine whether distraction and/or amount of details affect people’s ability to make good decisions.

No Distraction

Distraction

4 details

12 details

4 details

12 details

5.5

0.8

2.5

4.7

5.2

1.2

2.1

5.8

5.3

1.5

2.3

5.3

4.7

1.2

2.4

4.9

4.9

1.3

2.7

4.8

4.8

1.1

2.9

5.7

5.1

0.5

3

5.5

5.2

0.3

2

5.1

5.4

1

2.1

5.3

5.7

0.7

2.4

5.1

5.3

1.4

1.7

5.6

5.1

1.1

2.5

5

5.9

0.9

2.7

4.3

6

1.3

2.3

4.8

5.7

1.2

2.1

4.9

In: Statistics and Probability

(a) Chau’s electric circuit is a simple electronic circuit that can exhibit chaotic behaviour. The voltages...

(a) Chau’s electric circuit is a simple electronic circuit that can exhibit chaotic behaviour. The voltages x(t) and y(t), and current z(t), across components in the circuit can be investigated using the Matlab command

[t,xyz] = ode45(@ChuaFunction,[-10 100],[0.7 0.2 0.3]);

and the function:

1 function dxyzdt = ChuaFunction(~,xyz)

2 % xyz(1) = X, xyz(2) = Y, xyz(3) = Z

3 4 dxdt = 15.6*(xyz(2) - xyz(1) + 2*tanh(xyz(1)));

5 dydt = xyz(1) - xyz(2) + xyz(3);

6 dzdt = -28*xyz(2); 7

8 dxyzdt = [dxdt dydt dzdt]’;

9 end

(i) What is the differential equation involving x˙(t)? Here a dot represents differentiation with respect to time t.

(ii) What is the initial condition for the variable y(t)?

(iii) What does the apostrophe after the square brackets in line 8 of the function signify and why is the apostrophe needed here?

(b) For a given function u(t), explain how the derivative of u(t) with respect to t can be approximated on a uniform grid with grid spacing ∆t, using the one-sided forward difference approximation

du/dt ≈ Ui+1 − Ui/ ∆t ,

where ui = u(ti). You should include a suitable diagram explaining your answer

(c) Using the one-sided forward difference approximation from part (b) and Euler’s method, calculate the approximate solution to the initial value problem

du/dt + t cos(u) = 0, subject to u(0) = −0.2,

at t = 0.4, on a uniform grid with spacing ∆t = 0.1.

In: Electrical Engineering

Particles of charge -60 E-6 C, +40 E-6 C, and – 95 E-6 C are placed...

Particles of charge -60 E-6 C, +40 E-6 C, and – 95 E-6 C are placed along the x-axis at 0.2 m, 0.4 m and 0.6 m, respectively. (a) Calculate the magnitude of the net electric field x = 0.3 m. (b) Calculate the magnitude of the net force on the +40 E-6 C charge

In: Physics

Better Mousetraps has developed a new trap. It can go into production for an initial investment...

Better Mousetraps has developed a new trap. It can go into production for an initial investment in equipment of $5.4 million. The equipment will be depreciated straight line over 6 years to a value of zero, but in fact it can be sold after 6 years for $584,000. The firm believes that working capital at each date must be maintained at a level of 10% of next year’s forecast sales. The firm estimates production costs equal to $1.30 per trap and believes that the traps can be sold for $5 each. Sales forecasts are given in the following table. The project will come to an end in 6 years, when the trap becomes technologically obsolete. The firm’s tax bracket is 35%, and the required rate of return on the project is 10%.

Year: 0 1 2 3 4 5 6 Thereafter
Sales (millions of traps) 0 0.6 0.7 0.8 0.8 0.7 0.4 0


a. What is project NPV? (Negative amount should be indicated by a minus sign. Do not round intermediate calculations. Enter your answer in millions rounded to 4 decimal places.)


b. By how much would NPV increase if the firm depreciated its investment using the 5-year MACRS schedule?

In: Finance

A spring with a mass of 2 kg has a damping constant 14 kg/s. A force...

A spring with a mass of 2 kg has a damping constant 14 kg/s. A force of 3.6 N is required to keep the spring stretched 0.3 m beyond its natural length. The spring is stretched 0.7 m beyond its natural length and then released. Find the position of the mass at any time t. (Assume that movement to the right is the positive x-direction and the spring is attached to a wall at the left end.) What is x(t)?

In: Math

Using the below data: Mass (g) of copper gluconate: 1.0 g Mass (g) of wrapper: 0.6...

Using the below data:

Mass (g) of copper gluconate: 1.0 g

Mass (g) of wrapper: 0.6 g

Mass (g) of wrapper + Cu: 0.9 g

Mass (g) of Cu: 0.3 g

Mass (g) of gluconate: 0.7 g

1. Determine the chemical formula of copper gluconate?

2. Calculate the percent composition of copper and the percent composition of gluconate in the compound copper gluconate?

3. Create a Experimental Chemical Formula:

In: Chemistry