|
Subject label |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
|
Blood pressure Reading before Drug A treatment |
XA1 |
XA2 |
XA3 |
XA4 |
XA5 |
XA6 |
XA7 |
XA8 |
XA9 |
|
Blood pressure Reading after Drug A Treatment |
YA1 |
YA2 |
YA3 |
YA4 |
YA5 |
YA6 |
YA7 |
YA8 |
YA9 |
|
Subject label |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
|
Blood pressure Reading before Drug B treatment |
XB1 |
XB2 |
XB3 |
XB4 |
XB5 |
XB6 |
XB7 |
XB8 |
XB9 |
|
Blood pressure Reading after Drug B Treatment |
YB1 |
YB2 |
YB3 |
YB4 |
YB5 |
YB6 |
YB7 |
YB8 |
YB9 |
ii)What test would you do to find out if Drug B is more effective than A? justify your choice with explanation. write the equation that determines the test-statistic and define all the terms.
iii) if both drugs have the same active compound but with different weight, how do you show the effect of the active compound on the effectiveness of the drug?
what are the key parameters that indicate the validity of the model in Question (iii).
In: Statistics and Probability
Exercise 12-4 Prepare a Statement of Cash Flows [LO12-1, LO12-2]
| The following changes took place last year in Pavolik Company’s balance sheet accounts: |
| Asset and Contra-Asset Accounts | Liabilities and Equity Accounts | ||||||
| Cash | $ | 28 | D | Accounts payable | $ | 86 | I |
| Accounts receivable | $ | 32 | I | Accrued liabilities | $ | 32 | D |
| Inventory | $ | 74 | D | Income taxes payable | $ | 37 | I |
| Prepaid expenses | $ | 27 | I | Bonds payable | $ | 268 | I |
| Long-term investments | $ | 29 | D | Common stock | $ | 128 | D |
| Property, plant, and equipment | $ | 515 | I | Retained earnings | $ | 106 | I |
| Accumulated depreciation | $ | 106 | I | ||||
| D = Decrease; I = Increase. |
|
Long-term investments that had cost the company $29 were sold during the year for $62, and land that had cost $61 was sold for $32. In addition, the company declared and paid $26 in cash dividends during the year. Besides the sale of land, no other sales or retirements of plant and equipment took place during the year. Pavolik did not retire any bonds during the year or issue any new common stock. |
| The company’s income statement for the year follows: |
| Sales | $ | 1,260 | ||
| Cost of goods sold | 558 | |||
| Gross margin | 702 | |||
| Selling and administrative expenses | 500 | |||
| Net operating income | 202 | |||
| Nonoperating items: | ||||
| Loss on sale of land | $ | (29) | ||
| Gain on sale of investment | 33 | 4 | ||
| Income before taxes | 206 | |||
| Income taxes | 74 | |||
| Net income | $ | 132 | ||
| The company’s beginning cash balance was $144 and its ending balance was $116. |
| Required: |
| 1. |
Using the indirect method, determine the net cash provided by / used in operating activities for the year. (List any deduction in cash and cash outflows as negative amounts.) |
| 2. |
Prepare a statement of cash flows for the year. (List any deduction in cash and cash outflows as negative amounts.) |
In: Accounting
| 1 | 11 | 1.771 |
| 2 | 9 | 1.392 |
| 3 | 10 | 1.495 |
| 4 | 16 | 4.561 |
| 5 | 14 | 3.136 |
| 6 | 11 | 1.606 |
| 7 | 15 | 2.835 |
| 8 | 10 | 1.317 |
| 9 | 9 | 0.925 |
| 10 | 10 | 1.761 |
| 11 | 9 | 0 |
| 12 | 19 | 5.902 |
| 13 | 17 | 4.624 |
| 14 | 9 | 0.84 |
| 15 | 12 | 2.802 |
| 16 | 15 | 3.789 |
| 17 | 8 | 1.334 |
| 18 | 7 | 1.244 |
| 19 | 12 | 1.578 |
| 20 | 8 | 1.231 |
| 21 | 9 | 1.693 |
| 22 | 3 | 0 |
| 23 | 11 | 2.035 |
| 24 | 11 | 1.885 |
| 25 | 12 | 1.482 |
| 26 | 14 | 3.719 |
| 27 | 14 | 1.333 |
| 28 | 15 | 2.244 |
| 29 | 7 | 0.572 |
| 30 | 9 | 1.924 |
| 31 | 9 | 1.413 |
| 32 | 9 | 0 |
nStandard methodology for a single sample mean can be used to calculate a confidence interval for the slope of the least‑squares line and to test hypotheses other than H0: ß1= 0. In both cases, one needs to have an estimate of the slope and of its standard deviation (sometimes called standard error). Furthermore, one needs to recognize that the degrees of freedom for the standard deviation is the same as the error degrees of freedom (n ‑ 2).
Note that the EXCEL gives the standard error of estimate directly, but correctly calls it the standard deviation of the slope. Therefore, you must not divide by the square root of sample sizeas in example 16.
Use the above information to calculate a 90% confidence interval for the slope of the true regression line. For 30 degrees of freedom and a= 0.1, the critical t‑value is 1.697.
|
16. What is the margin of error for calculating a 90% confidence interval for the slope of the regression line (i.e. 1.697 ´the standard deviation of the slope)? |
|
17. What is the lower 90% confidence limit for the slope? |
|
18. What is the upper 90% confidence limit for the slope? |
(i.e. slope + margin of error)
nUse this same information to calculate a statistic to test the null hypothesis H0: ß1= 0.05 against a one‑sided alternative H1: ß1> 0.05. Use a 1 percent significance level (for which the critical value is 2.423).
Reminder: t = estimated value - hypothesized value = slope - 0.05
standard error (deviation) of estimate st dev of slope
|
19. What is the value of the test statistic for testing this hypothesis? |
In: Statistics and Probability
| Subject | BMI | Percent Fat |
| 1 | 21.95 | 28.70 |
| 2 | 27.75 | 32.30 |
| 3 | 25.09 | 25.80 |
| 4 | 19.23 | 19.60 |
| 5 | 19.60 | 22.40 |
| 6 | 20.31 | 26.40 |
| 7 | 22.29 | 32.70 |
| 8 | 28.65 | 33.50 |
| 9 | 19.47 | 23.40 |
| 10 | 21.44 | 21.80 |
| 11 | 26.85 | 37.10 |
| 12 | 21.85 | 30.90 |
| 13 | 23.90 | 36.30 |
| 14 | 21.54 | 29.80 |
| 15 | 22.61 | 31.90 |
| 16 | 18.91 | 21.60 |
| 17 | 18.46 | 24.60 |
| 18 | 17.05 | 20.50 |
| 19 | 17.70 | 24.60 |
| 20 | 16.61 | 18.10 |
| 21 | 16.94 | 22.90 |
| 22 | 18.77 | 26.20 |
| 23 | 18.39 | 27.20 |
| 24 | 17.86 | 17.70 |
| 25 | 17.98 | 20.80 |
| 26 | 15.37 | 17.50 |
| 27 | 18.84 | 21.30 |
| 28 | 15.82 | 18.70 |
| 29 | 17.71 | 28.80 |
| 30 | 14.99 | 17.10 |
| 31 | 16.75 | 26.20 |
| 32 | 16.46 | 20.40 |
| 33 | 15.87 | 19.50 |
| 34 | 18.08 | 21.70 |
| 35 | 15.58 | 18.10 |
| 36 | 17.15 | 29.80 |
| 37 | 15.82 | 20.60 |
| 38 | 18.61 | 22.90 |
| 39 | 16.66 | 19.30 |
| 40 | 20.83 | 27.90 |
| 41 | 24.56 | 36.40 |
| 42 | 20.19 | 25.10 |
| 43 | 24.13 | 39.70 |
| 44 | 20.86 | 33.60 |
| 45 | 33.57 | 46.80 |
| 46 | 29.14 | 38.90 |
| 47 | 26.17 | 36.70 |
| 48 | 31.46 | 38.50 |
| 49 | 19.08 | 23.30 |
| 50 | 23.54 | 35.90 |
Perform a regression analysis to see if body fat percentage is a good predictor of BMI. Use Excel or statistical software and be sure to include the following:
a) A scatterplot.
b) A correlation measure r.
c) The graph of the regression line on the scatterplot
d) The regression equation.
e) A discussion that explains how well body fat works as a
predictor of BMI
In: Statistics and Probability
|
1 |
7 |
0.406 |
|
2 |
14 |
2.731 |
|
3 |
13 |
3.807 |
|
4 |
10 |
1.999 |
|
5 |
14 |
1.884 |
|
6 |
15 |
2.275 |
|
7 |
17 |
4 |
|
8 |
13 |
2.597 |
|
9 |
4 |
0 |
|
10 |
11 |
2.651 |
|
11 |
6 |
0 |
|
12 |
11 |
1.558 |
|
13 |
13 |
3.147 |
|
14 |
12 |
3.378 |
|
15 |
15 |
3.127 |
|
16 |
10 |
1.989 |
|
17 |
11 |
2.183 |
|
18 |
13 |
2.178 |
|
19 |
11 |
3.132 |
|
20 |
10 |
1.445 |
|
21 |
9 |
0.841 |
|
22 |
18 |
2.825 |
|
23 |
10 |
2.036 |
|
24 |
12 |
1.601 |
|
25 |
13 |
2.835 |
|
26 |
11 |
1.162 |
|
27 |
7 |
1.677 |
|
28 |
7 |
0.423 |
|
29 |
16 |
4.018 |
|
30 |
11 |
1.742 |
|
31 |
19 |
3.876 |
|
32 |
16 |
3.578 |
|
10. What is the estimated increase in number of fatal accidents per 1000 licenses due to a 1% increase in the percentage of drivers under 21 (ie. the slope)? |
|
|
11. What is the standard deviation of the estimated slope? |
|
|
12. What is the estimated number of fatal accidents per 1000 licenses if there were no drivers under the age of 21 (ie. the intercept)? |
In: Statistics and Probability
| F | G |
| 0 | 76.15 |
| 1 | 75.63 |
| 2 | 74.67 |
| 3 | 73.69 |
| 4 | 72.71 |
| 5 | 71.72 |
| 6 | 70.73 |
| 7 | 69.74 |
| 8 | 68.75 |
| 9 | 67.76 |
| 10 | 66.76 |
| 11 | 65.77 |
| 12 | 64.78 |
| 13 | 63.79 |
| 14 | 62.8 |
| 15 | 61.82 |
| 16 | 60.84 |
| 17 | 59.88 |
| 18 | 58.91 |
| 19 | 57.96 |
| 20 | 57.01 |
| 21 | 56.08 |
| 22 | 55.14 |
| 23 | 54.22 |
| 24 | 53.29 |
| 25 | 52.37 |
| 26 | 51.44 |
| 27 | 50.52 |
| 28 | 49.59 |
| 29 | 48.67 |
| 30 | 47.75 |
| 31 | 46.82 |
| 32 | 45.9 |
| 33 | 44.98 |
| 34 | 44.06 |
| 35 | 43.14 |
| 36 | 42.22 |
| 37 | 41.3 |
| 38 | 40.38 |
| 39 | 39.46 |
| 40 | 38.54 |
| 41 | 37.63 |
| 42 | 36.72 |
| 43 | 35.81 |
| 44 | 34.9 |
| 45 | 34 |
| 46 | 33.11 |
| 47 | 32.22 |
| 48 | 31.34 |
| 49 | 30.46 |
| 50 | 29.6 |
| 51 | 28.75 |
| 52 | 27.9 |
| 53 | 27.07 |
| 54 | 26.25 |
| 55 | 25.43 |
| 56 | 24.63 |
| 57 | 23.83 |
| 58 | 23.05 |
| 59 | 22.27 |
| 60 | 21.51 |
| 61 | 20.75 |
| 62 | 20 |
| 63 | 19.27 |
| 64 | 18.53 |
| 65 | 17.81 |
| 66 | 17.09 |
| 67 | 16.38 |
| 68 | 15.68 |
| 69 | 14.98 |
| 70 | 14.3 |
| 71 | 13.63 |
| 72 | 12.97 |
| 73 | 12.33 |
| 74 | 11.7 |
| 75 | 11.08 |
| 76 | 10.48 |
| 77 | 9.89 |
| 78 | 9.33 |
| 79 | 8.77 |
| 80 | 8.24 |
| 81 | 7.72 |
| 82 | 7.23 |
| 83 | 6.75 |
| 84 | 6.3 |
| 85 | 5.87 |
| 86 | 5.45 |
| 87 | 5.06 |
| 88 | 4.69 |
| 89 | 4.35 |
| 90 | 4.03 |
| 91 | 3.73 |
| 92 | 3.46 |
| 93 | 3.21 |
| 94 | 2.99 |
| 95 | 2.8 |
| 96 | 2.63 |
| 97 | 2.48 |
| 98 | 2.34 |
| 99 | 2.22 |
| 100 | 2.11 |
|
Flavor |
Cherry |
Strawberry |
Chocolate |
Orange |
Lime |
|
Expected % |
30% |
20% |
20% |
15% |
15% |
A bag bought at random has the following number of mints in it.
|
Flavor |
Cherry |
Strawberry |
Chocolate |
Orange |
Lime |
|
Observed |
67 |
50 |
54 |
29 |
25 |
Determine whether this distribution is consistent with company’s stated proportions.
3. This problem is the check to see whether you understand the X-squared test. There are only 2 test columns, so you cannot use the X-squared Goodness of Fit applet from the previous problem as it requires 3 or more test intervals.
You are told that a genetics theory says the ratio of tall:short plants is 3:1. You test this claim by growing 200 plants. You obtain 160 tall plants and 40 short plants. Using a X-squared test, determine whether or not your results supports the tall:short = 3:1 claim.
|
Card Color |
Observed |
Expected |
(O – E) |
(O-E)2 |
(O-E)2/E |
|
Red |
160 |
||||
|
Black |
40 |
||||
|
Sum |
200 |
200 |
0 |
n/a |
In: Statistics and Probability
|
Obs |
Income |
GPA |
|
1 |
1.51 |
3.18 |
|
2 |
3.31 |
2.85 |
|
3 |
1.81 |
1.84 |
|
4 |
2.42 |
4.61 |
|
5 |
1.72 |
3.18 |
|
6 |
1.63 |
3.98 |
|
7 |
0.98 |
1.35 |
|
8 |
1.04 |
2.78 |
|
9 |
1.55 |
3.74 |
|
10 |
2.75 |
2.87 |
Now calculate whether the result obtained is statistically significant
6. Are the results significant at the 5% level and explain what it means in terms of the Null hypothesis? (20 points)
In: Statistics and Probability
| Individual | Television | Radio |
| 1 | 22 | 25 |
| 2 | 8 | 10 |
| 3 | 22 | 21 |
| 4 | 22 | 18 |
| 5 | 25 | 29 |
| 6 | 13 | 10 |
| 7 | 29 | 10 |
| 8 | 26 | 25 |
| 9 | 33 | 21 |
| 10 | 16 | 15 |
| 11 | 10 | 33 |
| 12 | 30 | 12 |
| 13 | 40 | 33 |
| 14 | 16 | 38 |
| 15 | 41 | 30 |
| In recent years, a growing array of entertainment options competes for consumer time. By 2004, cable television and radio surpassed broadcast television, recorded music, and the daily newspaper to become the two entertainment media with the greatest usage (The Wall Street Journal, January 26, 2004). Researchers used a sample of 15 individuals and collected data on the hours per week spent watching cable television and hours per week spent listening to the radio. |
| a. Use a .05 level of significance and test for a difference between the population mean usage for cable television and radio. What is the p-value? |
| b. What is the sample mean number of hours per week spent watching cable television? What is the sample mean number of hours per week spent listening to radio? Which medium has the greater usage? |
In: Statistics and Probability
| Time | 0 | 1 | 2 | 3 | 4 | 5 |
| Cash flows | -800 | 80 | 100 | 300 | 500 | 500 |
| Financing rate=15% | ||||||
| Reinvestment rate=20% | ||||||
| a) Write the excel command to calculate the NPV: | ||||||
| b) Write the NPV numerical value: | ||||||
| c) Write the excel command to calculate the IRR: | ||||||
| d) Write the IRR numerical value: | ||||||
| e) Write the excel command to calculate the MIRR: | ||||||
| f) Write the MIRR numerical value: | ||||||
| h) Write the excel command to calculate the PI: | ||||||
| i) Write the PI numerical value: |
In: Finance
E19-4. (Three Differences, Compute Taxable Income, Entry for Taxes) (LO 1, 2) Zurich Company reports pretax financial income of $70,000 for 2017. The following items cause taxable income to be different than pretax financial income. 1.Depreciation on the tax return is greater than depreciation on the income statement by $16,000. 2.Rent collected on the tax return is greater than rent recognized on the income statement by $22,000. 3.Fines for pollution appear as an expense of $11,000 on the income statement. Zurich's tax rate is 30% for all years, and the company expects to report taxable income in all future years. There are no deferred taxes at the beginning of 2017
. Instructions
(a) Compute taxable income and income taxes payable for 2017.
(b) Prepare the journal entry to record income tax expense, deferred income taxes, and income taxes payable for 2017.
(c) Prepare the income tax expense section of the income statement for 2017, beginning with the line “Income before income taxes.”
In: Accounting