Find the relative frequency for the class with lower class limit 19

Relative Frequency = %

Give your answer as a percent, rounded to two decimal places

A Frequency Distribution Table using data
This list of 16 random numbers has been sorted:

Fill in this table with the frequencies as whole numbers and the relative frequencies as decimals with 4 decimal places for the relative frequencies. Remember: relative frequencies are between 0.0 and 1.0

(This problem does not accept fractions.)

Complete the table.

In a student survey, fifty-two part-time students were asked how many courses they were taking this term. The (incomplete) results are shown below:

Please round your answer to 4 decimal places for the Relative Frequency if possible.

What percent of students take exactly one courses? %

50 part-time students were asked how many courses they were taking this term. The (incomplete) results are shown below:

a. Complete the table.

b. What percent of students take exactly two courses? %

70 adults with gum disease were asked the number of times per week they used to floss before their diagnoses. The (incomplete) results are shown below:

a. Complete the table (Use 4 decimal places when applicable)

b. What is the cumulative relative frequency for flossing 1 time per week? %

Susan is a 67-year-old white female who works part-time at the library and volunteers at least 10 hours per week. She and her husband live in a two-story home; her children and grandchildren visit every 6 months. She and her husband travel at least twice per year. She participates in water aerobics and yoga 4 days per week for 1 hour each. She will eat lunch at casual dining restaurants at least four times per week. She consumes three meals per day but is not eating as much due to recovering from a wrist fracture from a fall that happened 2 months ago. For breakfast, she will have ¾ cup of high-fiber cereal with ½ cup skim milk. For lunch, a heavy salad (chicken, cheese, romaine lettuce, vegetables) with light dressing, 1 slice of bread or a roll, and 4 ounces of wine. At dinner, she will have a big bowl of thickened soup/stew with bread or 2–3 ounces of fatty fish or meat, 1 cup of salad with light dressing, vegetables, and 4 ounces of wine. She tries to avoid milk-based foods due to the gas and bloating it causes and also tries to eat low-fat/low-salt to avoid gaining weight and increasing her blood pressure. She has no issues with chewing/swallowing or bowels aside from when eating milk-based foods. From her fall, the doctors performed a bone mineral density exam, in which her T-scores are as follows: for the hip: 1.7 (normal is > –1.0); for a vertebra: –2.6 (normal is > –2.5). Susan’s serum vitamin D level is 23 nmol/L. Her doctor has placed her on an over-the-counter 500-mg calcium with vitamin D supplement. She has prehypertension (average blood pressure of 128/92) and refuses to take any hypertension medications. She has lost 5 pounds over the past 2 months.

Height: 5’6”, weight: 122 pounds, weight history: 127 pounds (2 months ago)

Questions

1. What do her lab values lead you to believe about her bone status?
2. What is her BMI? What is her BMI classification?
3. Is her weight loss a concern to you? Why or why not?
4. What additional questions would you ask Susan regarding her nutritional intake?
5. What are Susan’s calorie, macronutrient, and micronutrient needs?
6. What are your diet recommendations for Susan?
7. What are your nutritional goals for Susan?

Smoky Mountain Corporation makes two types of hiking boots—Xtreme and the Pathfinder. Data concerning these two product lines appear below:   

The company has a traditional costing system in which manufacturing overhead is applied to units based on direct labor-hours. Data concerning manufacturing overhead and direct labor-hours for the upcoming year appear below:    

Required:

1. Compute the product margins for the Xtreme and the Pathfinder products under the company’s traditional costing system. (Do not round your intermediate calculations.)

2. The company is considering replacing its traditional costing system with an activity-based costing system that would assign its manufacturing overhead to the following four activity cost pools (the Other cost pool includes organization-sustaining costs and idle capacity costs):   
   .

Compute the product margins for the Xtreme and the Pathfinder products under the activity-based costing system. (Negative product margins should be indicated with a minus sign. Round your intermediate calculations to 2 decimal places.)

3. Prepare a quantitative comparison of the traditional and activity-based cost assignments. (Do not round intermediate calculations. Round your "Percentage" answer to 1 decimal place. (i.e. .1234 should be entered as 12.3))

Smoky Mountain Corporation makes two types of hiking boots—the Xtreme and the Pathfinder. Data concerning these two product lines appear below:

The company has a traditional costing system in which manufacturing overhead is applied to units based on direct labor-hours. Data concerning manufacturing overhead and direct labor-hours for the upcoming year appear below:

Required:

1. Compute the product margins for the Xtreme and the Pathfinder products under the company’s traditional costing system. (Round your intermediate calculations to 2 decimal places and final answers to the nearest whole dollar amount.)

2. The company is considering replacing its traditional costing system with an activity-based costing system that would assign its manufacturing overhead to the following four activity cost pools (the Other cost pool includes organization-sustaining costs and idle capacity costs):

2. Compute the product margins for the Xtreme and the Pathfinder products under the activity-based costing system. (Round your intermediate calculations to 2 decimal places.)

3. Prepare a quantitative comparison of the traditional and activity-based cost assignments.

Prepare a quantitative comparison of the traditional and activity-based cost assignments. (Round your intermediate calculations to 2 decimal places.)

A diet doctor claims Australians are, on average, overweight by more than 10kg. To test this claim, a random sample of 100 Australians were weighed, and the difference between their actual weight and their ideal weight was calculated and recorded.

The data are contained in the Excel file Weights.xlsx.

Use these data to test the doctor's claim at the 5% level of significance.

Question 10

(Part B)

In this question, we let μ represent

Question 11

(Part B)

The null hypothesis is

Question 12

(Part B)

The alternative hypothesis is

Question 13

(Part B)

The value of the t-statistic is

Question 14

(Part B)

The decision rule is

Question 15

(Part B)

The p-value is

The following data represent petal lengths (in cm) for independent random samples of two species of Iris. Petal length (in cm) of Iris virginica: x1; n1 = 35 5.1 5.6 6.2 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.7 5.1 Petal length (in cm) of Iris setosa: x2; n2 = 38 1.6 1.9 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.5 (a) Use a calculator with mean and standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.) x1 = s1 = x2 = s2 = (b) Let μ1 be the population mean for x1 and let μ2 be the population mean for x2. Find a 99% confidence interval for μ1 − μ2. (Round your answers to two decimal places.) lower limit upper limit (c) Explain what the confidence interval means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 99% level of confidence, is the population mean petal length of Iris virginica longer than that of Iris setosa? Because the interval contains only positive numbers, we can say that the mean petal length of Iris virginica is longer. Because the interval contains only negative numbers, we can say that the mean petal length of Iris virginica is shorter. Because the interval contains both positive and negative numbers, we cannot say that the mean petal length of Iris virginica is longer. (d) Which distribution did you use? Why? The Student's t-distribution was used because σ1 and σ2 are unknown. The standard normal distribution was used because σ1 and σ2 are known. The standard normal distribution was used because σ1 and σ2 are unknown. The Student's t-distribution was used because σ1 and σ2 are known. Do you need information about the petal length distributions? Explain. Both samples are large, so information about the distributions is needed. Both samples are large, so information about the distributions is not needed. Both samples are small, so information about the distributions is needed. Both samples are small, so information about the distributions is not needed.

The following data represent petal lengths (in cm) for independent random samples of two species of Iris. Petal length (in cm) of Iris virginica: x1; n1 =

35 5.1 5.8 6.5 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.9 5.1

Petal length (in cm) of Iris setosa: x2; n2 =

38 1.6 1.8 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.6

(a) Use a calculator with mean and standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.)

x1 =

s1 =

x2 =

s2 =

(b) Let μ1 be the population mean for x1 and let μ2 be the population mean for x2. Find a 99% confidence interval for μ1 − μ2. (Round your answers to two decimal places.)

lower limit

upper limit

(c) Explain what the confidence interval means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 99% level of confidence, is the population mean petal length of Iris virginica longer than that of Iris setosa?

Because the interval contains only positive numbers, we can say that the mean petal length of Iris virginica is longer.

Because the interval contains only negative numbers, we can say that the mean petal length of Iris virginica is shorter.   

Because the interval contains both positive and negative numbers, we cannot say that the mean petal length of Iris virginica is longer.

(d) Which distribution did you use? Why?

The Student's t-distribution was used because σ₁ and σ₂ are unknown.

The standard normal distribution was used because σ₁ and σ₂ are unknown.

The Student's t-distribution was used because σ₁ and σ₂ are known.

The standard normal distribution was used because σ₁ and σ₂ are known.

Do you need information about the petal length distributions? Explain.

Both samples are large, so information about the distributions is not needed

.Both samples are large, so information about the distributions is needed.

Both samples are small, so information about the distributions is needed.

Both samples are small, so information about the distributions is not needed.

Consider the following information on Huntington Power Co.

Debt: 4,000, 7% semiannual coupon bonds outstanding, $1,000 par value, 18 years to maturity, selling for 102 percent of par; the bonds make semiannual payments.

Preferred Stock: 10,000 outstanding with par value of $100 and a market value of 105 and $10 annual dividend.

Common Stock: 84,000 shares outstanding, selling for $56 per share, the beta is 2.08

The market risk premium is 5.5%, the risk free rate is 3.5% and Huntington’s tax rate is 32%.

Huntington Power Co. is evaluating two mutually exclusive project that is somewhat riskier than the usual project the firm undertakes; management uses the subjective approach and decided to apply an adjustment factor of +2.1% to the cost of capital for both projects.

Project A is a five-year project that requires an initial fixed asset investment of $2.4 million. The fixed asset falls into the five-year MACRS class. The project is estimated to generate $2,050,000 in annual sales, with costs of $950,000. The project requires an initial investment in net working capital of $285,000 and the fixed asset will have a market value of $225,000 at the end of five years when the project is terminated.

Project B requires an initial fixed asset investment of $1.0 million. The marketing department predicts that sales related to the project will be $920,000 per year for the next five years, after which the market will cease to exist. The machine will be depreciated down to zero over four-year using the straight-line method (depreciable life 4 years while economic life 5 years). Cost of goods sold and operating expenses related to the project are predicted to be 25 percent of sales. The project will also require an addition to net working capital of $150,000 immediately. The asset is expected to have a market value of $120,000 at the end of five years when the project is terminated.

Use the following rates for 5-year MACRS: 20%, 32%, 19.2%, 11.52%, 11.52%, and 5.76%

1. Calculate WACC for the firm.
2. What is the appropriate discount rate for project A and project B (Risk adjusted rate)?
3. Calculate project A’s cash flows for years 0-5
4. Calculate NPV, IRR and PI for project A
5. Calculate project B’s cash flows for year 0-5
6. Calculate NPV, IRR and PI for project B
7. Which project should be accepted if any and why?
8. What is the exact NPV profile’s crossover rate (incremental IRR)?

For this assignment you will write a class that transforms a Postfix expression (interpreted as a sequence of method calls) into an expression tree, and provides methods that process the tree in different ways.

We will test this using our own program that instantiates your class and calls the expected methods. Do not use another class besides the tester and the ExpressionTree class. All work must be done in the class ExpressionTree. Your class must be called ExpressionTree and have the following public methods:

public class ExpressionTree {

    public void pushNumber(double d);
    public void pushAdd();
    public void pushMultiply();
    public void pushSubtract();
    public void pushDivide();

    public double evaluate();
    public String infixString();

    public int height();        
    public void clear();

    // For bonus:
    // public void pushVariable();
    // public void evaluate(double variableVal);

}

Required methods

The methods should behave as follows:

1. pushNumber(double d) should push a node containing a number to the internal stack.
2. push (Add,Multiply,Subtract,Divide) should push a node representing the corresponding operation.
3. infixString() should return a String containing a parenthesized inorder traversal of the expression tree. Note: this should interpret the top of the internal stack as the root of the tree.
4. evaluate() should return the numeric value associated with the tree. This must operate recursively on the expression tree. Note: this should interpret the top of the internal stack as the root of the tree.
5. height() should return the height of the expression tree (distance in edges between the root and the farthest leaf). Note: this should interpret the top of the internal stack as the root of the tree.
6. clear() should reset the internal Stack

//////////TESTER CLASS THAT THE EXPRESSION TREE CODE MUST WORK WITH/////////////

public class ETreeValidator {
    public static void main(String[] args) 
    {
        ExpressionTree etree = new ExpressionTree();

        etree.pushNumber(10);
        etree.pushNumber(20);
        etree.pushOp("+");

        System.out.println("Expecting (10.0 + 20.0): " + etree.infixString());
        System.out.println("Expecting 30.0: " + etree.evaluate());
        System.out.println(("Expecting 1: " + etree.height()));

        etree.clear();

        
        etree.pushNumber(10);
        etree.pushNumber(20);
        etree.pushOp("+");
        etree.pushNumber(5);
        etree.pushNumber(3);
        etree.pushNumber(1);
        etree.pushOp("*");
        etree.pushOp("-");
        etree.pushOp("/");

        
        System.out.println("Expecting ((10.0 + 20.0) / (5.0 - (3.0 * 1.0))): " + etree.infixString());
        System.out.println("Expecting 15.0: " + etree.evaluate());
        System.out.println(("Expecting 3: " + etree.height()));
        etree.clear();
        
        // Uncomment this if you did the bonus
        etree.pushNumber(1.5);
        etree.pushNumber(12);
        etree.pushVariable();
        etree.pushOp("/");
        etree.pushOp("*");
        etree.pushVariable();
        etree.pushOp("-");
        System.out.println("Expecting ((1.5 * (12.0 / VAR)) - VAR): " + etree.infixString());
        System.out.println("Expecting 7: " + etree.evaluate(2));
        System.out.println(("Expecting 3: " + etree.height()));
        


    }
}

Write three functions that compute the square root of an argument x using three different methods. The methods are increasingly sophisticated, and increasingly efficient. The square root of a real number x is the value s such that s*s == x. For us, the values will be double precision variables and so may not be perfectly accurate. Also, for us, assume that x is in the range 0.0 to 100.0. You program should have a main() that asks the user for x and an accuracy bound, and then prints out the approximate square root for each of the three methods. If x is negative write an error message and exit. One. Write a pure function double sqrtLS(x, accuracy) that computes the square root of x using Linear Search. Do this in a loop that starts s at 0.0 and bestError at x. Each iteration of the loop computes error = |x-s*s|. If error< bestError, set bestError to error, and bestS to the current s. Then increment s by accuracy and move on. At the end of the loop, return bestS. This method is linear search, it searches along the number line for the best s that is within accuracy of the true value. Use the function double fabs(double) from the math library to compute absolute value. Two. Write a pure function double sqrtBS(x,accuracy) that computes the square root of x using Binary Search. (This method is also called bisection.) Start a variable low at 0.0 and a variable high at 10.0. This assumes that x will be no larger than 100.0 In a while loop do this: Compute the midpoint mid=(low+high)/2. If |x-mid*mid| ≤ accuracy return mid. If mid*mid < x set low = mid. Else set high = mid. Three. Write a pure function double sqrtNM(x, accuracy) that computes the square root of x using Newton’s Method. Recall the method: Start out an initial guess s=1.0 (or any value). Now repeatedly improve the guess: s = (s + x/s)/2 When the guess meets the ending condition |x-s*s| is ≤ bound return s. M:\ClassApps>gcc -lm squareRoot.c M:\ClassApps>.\a Enter x --> 47.5 Enter error bound --> 1e-5 sqrtLS(47.500)= 6.892020; s*s = 47.499940 sqrtBS(47.500)= 6.892024; s*s = 47.499999 sqrtNM(47.500)= 6.892024; s*s = 47.500001 Use ANSI-C syntax. Do not mix tabs and spaces. Do not use break or continue.