A factorial experiment was designed to test for any significant differences in the time needed to perform English to foreign language translations with two computerized language translators. Because the type of language translated was also considered a significant factor, translations were made with both systems for three different languages: Spanish, French, and German. Use the following data for translation time in hours.
| Language | |||
| Spanish | French | German | |
| System 1 | 6 | 13 | 11 |
| 10 | 17 | 15 | |
| System 2 | 4 | 16 | 15 |
| 8 | 18 | 21 | |
Test for any significant differences due to language translator system (Factor A), type of language (Factor B), and interaction. Use .
Complete the following ANOVA table (to 2 decimals, if necessary). Round your p-value to 4 decimal places.
| Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | -value | |
| Factor A | |||||
| Factor B | |||||
| Interaction | |||||
| Error | |||||
| Total |
The p-value for Factor A is - Select your answer -less than .005between .005 and .0125between .0125 and .025between .025 and .05greater than .05Item 21
What is your conclusion with respect to Factor A?
- Select your answer -Factor A is not significantFactor A is significantItem 22
The p-value for Factor B is - Select your answer -less than .005between .005 and .0125between .0125 and .025between .025 and .05greater than .05Item 23
What is your conclusion with respect to Factor B?
- Select your answer -Factor B is not significantFactor B is significantItem 24
The p-value for the interaction of factors A and B is - Select your answer -less than .005between .005 and .0125between .0125 and .025between .025 and .05greater than .05Item 25
What is your conclusion with respect to the interaction of Factors A and B?
- Select your answer -The interaction of factors A and B is not significantThe interaction of factors A and B is significant
In: Statistics and Probability
In an experiment to determine the effects of conventional and reduced tillage agriculture on crop yield for oats, 3 varieties of oats and two levels of fertilization (0.5 and 1 kg/ acre) were examined using conventional and reduce tillage techniques. Twenty 20 x 60m plots were each partitioned into 6 -10 x 20m subplots and subplots assigned at random to receive a combination of oat variety and fertilizer treatment. Ten of these plots were subjected to conventional tillage practices and 10 were subjected to reduced tillage practices. Each subplot was harvested at seasons' end and crop yield is expressed in bushels/acre. Examine the data provided in the data file oats.csv. Report hypothesis tests for all possible effects.
Data provided in the data file oats.csv. :
| tr | fert1v1 | fert1v2 | fert1v3 | fert2v1 | fert2v2 | fert2v3 | |
| 1 | 1 | 55.59555 | 62.28367 | 54.02856 | 52.3082 | 66.11916 | 47.28625 |
| 2 | 1 | 54.83042 | 66.4528 | 58.34965 | 51.20269 | 70.35817 | 59.59235 |
| 3 | 1 | 47.17417 | 53.11721 | 48.0996 | 42.20308 | 56.72854 | 49.01972 |
| 4 | 1 | 49.92158 | 59.02375 | 51.37804 | 47.1327 | 63.70916 | 51.65932 |
| 5 | 1 | 63.2877 | 69.37552 | 67.33111 | 60.75426 | 76.44359 | 64.48788 |
| 6 | 1 | 43.26808 | 51.84271 | 43.80456 | 43.46588 | 58.33783 | 41.24954 |
| 7 | 1 | 53.43448 | 61.23901 | 56.50824 | 55.53189 | 66.73144 | 54.54501 |
| 8 | 1 | 52.09698 | 59.69132 | 56.43002 | 46.99428 | 67.06747 | 57.05954 |
| 9 | 1 | 53.23395 | 59.83314 | 57.81001 | 54.74937 | 64.69777 | 57.40591 |
| 10 | 1 | 43.52501 | 48.36869 | 43.50235 | 40.54583 | 53.5147 | 45.39921 |
| 11 | 2 | 49.76705 | 52.92597 | 51.92696 | 48.5611 | 58.35346 | 48.73186 |
| 12 | 2 | 57.11089 | 60.52846 | 55.08849 | 52.75431 | 63.08562 | 58.9274 |
| 13 | 2 | 57.08448 | 69.46167 | 59.38628 | 59.41141 | 77.39677 | 59.74098 |
| 14 | 2 | 55.65932 | 64.41633 | 55.02598 | 55.76469 | 72.4667 | 56.30465 |
| 15 | 2 | 67.73778 | 72.19191 | 67.87371 | 67.11457 | 77.51533 | 64.34463 |
| 16 | 2 | 63.81949 | 66.31592 | 59.74957 | 63.24728 | 70.01633 | 61.11576 |
| 17 | 2 | 59.57243 | 63.58954 | 59.51328 | 60.33233 | 68.53625 | 59.57449 |
| 18 | 2 | 53.61506 | 60.7735 | 56.80479 | 47.1538 | 64.1669 | 59.46785 |
| 19 | 2 | 61.84216 | 67.61936 | 64.58683 | 57.77677 | 75.37341 | 63.0163 |
| 20 | 2 | 60.88292 | 67.25251 | 60.19583 | 58.40519 | 72.17987 | 57.51454 |
In: Statistics and Probability
Fertilizer: In an agricultural experiment, the effects of two fertilizers on the production of oranges were measured. Thirteen randomly selected plots of land were treated with fertilizer A, and
10
randomly selected plots were treated with fertilizer B. The number of pounds of harvested fruit was measured from each plot. Following are the results.
| Fertilizer A | ||||||
| 523 | 464 | 483 | 460 | 491 | 403 | 484 |
| 448 | 457 | 437 | 516 | 417 | 420 | |
| Fertilizer B | ||||
|
362 |
414 |
408 |
398 |
382 |
|
368 |
393 |
437 |
387 |
373 |
|
Part 1 of 3
Your Answer is correct
Explain why it is necessary to check whether the populations are
approximately normal before constructing a confidence
interval.
Since the sample size is ▼small, it is necessary to check that the populations are approximately normal.
Part 2 of 3
Your Answer is correct
Following are boxplots of these data. Is it reasonable to assume
that the populations are approximately normal?
400 420 440 460 480 500 520 540
360 370 380 390 400 410 420 430 440 450
It ▼is reasonable to assume that the populations are approximately normal.
Part 3 of 3
Construct a 95% confidence interval for the difference
between the mean yields for the two types of fertilizer. Let
μ1 denote the mean yield for fertilizer A. Use the TI-84 Plus
calculator. Round the answers to one decimal place.
| The 95% confidence interval for the
difference between the mean yields for the two types of fertilizer
is
< μ1 - μ2< . |
In: Statistics and Probability
Fertilizer: In an agricultural experiment, the effects of two fertilizers on the production of oranges were measured. Thirteen randomly selected plots of land were treated with fertilizer A, and
10
randomly selected plots were treated with fertilizer B. The number of pounds of harvested fruit was measured from each plot. Following are the results.
| Fertilizer A | ||||||
| 523 | 464 | 483 | 460 | 491 | 403 | 484 |
| 448 | 457 | 437 | 516 | 417 | 420 | |
| Fertilizer B | ||||
|
362 |
414 |
408 |
398 |
382 |
|
368 |
393 |
437 |
387 |
373 |
|
Part 1 of 3
Your Answer is correct
Explain why it is necessary to check whether the populations are
approximately normal before constructing a confidence
interval.
Since the sample size is ▼small, it is necessary to check that the populations are approximately normal.
Part 2 of 3
Your Answer is correct
Following are boxplots of these data. Is it reasonable to assume
that the populations are approximately normal?
400 420 440 460 480 500 520 540
360 370 380 390 400 410 420 430 440 450
It ▼is reasonable to assume that the populations are approximately normal.
Part 3 of 3
Construct a 95% confidence interval for the difference
between the mean yields for the two types of fertilizer. Let
μ1 denote the mean yield for fertilizer A. Use the TI-84 Plus
calculator. Round the answers to one decimal place.
| The 95% confidence interval for the
difference between the mean yields for the two types of fertilizer
is
< μ1 - μ2< . |
In: Statistics and Probability
An experiment consists of randomly rearranging the 10 letters of
the word QUARANTINE
into a sequence of 10 letters, where all possible orders of these
10 letters are equally likely. Find the probability of each of the
following events:
(1) the first three letters include no A’s;
(2) the first three letters or the last three letters (or both) include no A’s;
(3) the fourth letter is the first A;
(4) the first letter and the last letter are the same;
(5) the word ‘QUARANTINE’ is obtained;
(6) the sequence contains the word ‘RAN’.
In: Statistics and Probability
A student attempted to identify an unknown compound by the method described in this experiment. When he heated a sample weighing 1.031 g the mass went down to 0.688 g. When the product was converted to a chloride the mass went up to 0.748 g. (Answers I got are in bold)
1.Explain if you believe the sample to be a carbonate or hydrogen carbonate. (I said it is a hydrogen carbonate due to the loss of mass)
2.Write the two possible chemical equations for the reaction that that you believe occurred; one for sodium and one for potassium (carbonate or hydrogen carbonate). (we are supposed to use these two formulas but I am not sure how: 2XHCO3→ X2CO3 + H2O + CO2 this is hydrogen carbonate X2CO3 + 2 H+ + 2 Cl-→ 2 XCl + H2O + CO2 This one is for the hydrochloric acid being added)
3.Show by calculation how many moles of the chloride salt would be produced from one mole of original compound; one for sodium and one for potassium (carbonate or hydrogen carbonate).
4.Fill out the following information to help you determine how many grams of the chloride salt would be produced from one molar mass of original compound?
If NaHCO3 ____________ g original compound → ____________ g chloride
If KHCO3 ____________ g original compound → ____________ g chloride
If Na2CO3 ____________ g original compound → ____________ g chloride
If K2CO3 ____________ g original compound → ____________ g chloride
5.Calculate the theoretical value of Q for all 4 compounds
6.What was the student’s observed value of Q? ( I got 1.378 since this is calculated by original mass divided by final mass)
7.Which compound did the student have as their unknown?
In: Chemistry
In: Chemistry
Let EE and FF be events of an experiment. Select all of the sentences below that are correct. Marks will be deducted for selecting options that are incorrect.
Select one or more:
a. If EE and FF are mutually exclusive then they must also be
independent.
b. If EE and FF are independent then
Pr(E∩F)=Pr(E)Pr(F)Pr(E∩F)=Pr(E)Pr(F).
c. If EE and FF are mutually exclusive then EE and FF can't
occur at the same time.
d. It is possible for EE and FF to be neither mutually exclusive
nor independent.
e. If EE and FF are mutually exclusive then Pr(E∪F)=0Pr(E∪F)=0.
In: Statistics and Probability
In an experiment involving the breaking strength of a certain type of thread used in personal flotation devices, one batch of thread was subjected to a heat treatment for 60 seconds and another batch was treated for 120 seconds. The breaking strengths (in N) of ten threads in each batch were measured. The results were
60 seconds: 43 52 52 58 49 52 41 52 56 50 120
seconds: 59 55 59 66 62 55 57 66 66 51
Let μX represent the population mean for threads treated for 120 seconds and let μY represent the population mean for threads treated for 60 seconds. Find a 99% confidence interval for the difference μX−μY . Round down the degrees of freedom to the nearest integer and round the answers to three decimal places.
The 99% confidence interval is ( , ).
In: Statistics and Probability
What Lewis acid is used in the acetylation reaction of ferrocene?
In the experiment of acetylation of ferrocene, what will be the ordering of elution? How will you explain the observed ordering?
A mixture of cis and trans isomers of [Cr(CO)4(PPh3)2] is loaded onto a column and eluted with 10:90 ethyl acetate : petroleum ether solvent mixture. Which isomer will elute first? Why?
What two acetylated products are isolated from the acetylation of ferrocene? Which of the products is the minor product and how will you explain the poor yield of the minor product?
In: Chemistry