When bonding teeth, orthodontists must maintain a dry field. A new bonding adhesive has been developed to eliminate the necessity of a dry field. However, there is a concern that the new bonding adhesive is not as strong as the current standard, a composite adhesive. Tests on a sample of 26 extracted teeth bonded with the new adhesive resulted in a mean breaking strength (after 24 hours) of 2.33 MPa, and a standard deviation of 4 MPa. Orthodontists want to know if the true mean breaking strength is less than 4.06 MPa, the mean breaking strength of the composite adhesive. Assume normal distribution for breaking strength of the new adhesive.
1. What are the appropriate hypotheses one should test?
H0: μ = 4.06 against
Ha: μ > 4.06.
H0: μ = 4.06 against
Ha: μ ≠ 4.06.
H0: μ = 2.33 against
Ha: μ ≠ 2.33.
H0: μ = 2.33 against
Ha: μ > 2.33.
H0: μ = 2.33 against
Ha: μ < 2.33.
H0: μ = 4.06 against
Ha: μ < 4.06.
2. The formula of the test-statistic to use here is
\dfrac[(x)] − μ0σ/√n.
\dfrac[(x)] − μ0s/√n.
\dfrac[^(p)] −
p0√{p0(1−p0)/n}.
None of the above.
3. Rejection region: We should reject H0 at
2.5% level of significance if:
test statistic < −1.960.
|test statistic| > 2.241.
test statistic < −2.060.
test statistic > 1.960.
|test statistic| > 2.385.
test statistic > 2.060.
4. The value of the test-statistic is (answer to 3 decimal places):
5. If α = 0.025, what will be your conclusion?
Do not reject H0.
Reject H0.
There is not information to conclude.
6. The p-value of the test is (answer to 4 decimal places):
7. We should reject H0 for all significance
level which are
not equal to p-value.
larger than p-value.
smaller than p-value.
Are medical students more motivated than law students? A randomly selected group of each were administered a survey of attitudes toward Life, which measures motivation for upward mobility. The scores are summarized below. The researchers suggest that there are occupational differences in mean testosterone level. Medical doctors and university professors are two of the occupational groups for which means and standard deviations are recorded and listed in the following table.
| Group | Sample size | Mean | StDev |
|---|---|---|---|
| Medical | n1 = 7 | [(x)]1 = 81.59 | s1 = 4.36 |
| Law | n2 = 7 | [(x)]2 = 76.27 | s2 = 14.84 |
Let us denote:
1. If the researcher is interested to know whether the mean
testosterone level among medical doctors is higher than that among
university professors, what are the appropriate hypotheses he
should test?
H0: μ1 = μ2
against Ha: μ1
< μ2.
H0: μ1 = μ2
against Ha: μ1
> μ2.
H0: [(x)]1 =
[(x)]2 against
Ha:
[(x)]1 ≠ [(x)]2.
H0: [(x)]1 =
[(x)]2 against
Ha:
[(x)]1 > [(x)]2.
H0: [(x)]1 =
[(x)]2 against
Ha:
[(x)]1 < [(x)]2.
H0: μ1 = μ2
against Ha: μ1
≠ μ2.
Case 1: Assume that the population standard deviations
are unequal, i.e. σ1 ≠ σ2.
1. What is the standard error of the difference in sample mean
[(x)]1 − [(x)]2? i.e.
s.e.([(x)]1−[(x)]2)
= [answer to 4 decimal places]
2. Rejection region: We reject H0 at 10%
level of significance if:
t < −1.89.
t > 1.41.
t < −1.41.
|t| > 1.89.
t > 1.89.
None of the above.
3. The value of the test-statistic is: Answer to 3 decimal places.
4. If α = 0.1, and the p-value is 0.1965, what will be your
conclusion?
Do not reject H0.
Reject H0.
There is not enough information to conclude.
Case 2: Now assume that the population standard
deviations are equal, i.e. σ1 =
σ2.
1. Compute the pooled standard deviation,
spooled [answer to 4 decimal
places]
2. Rejection region: We reject H0 at 10%
level of significance if:
t > 1.78.
t < −1.36.
t > 1.36.
|t| > 1.78.
t < −1.78.
None of the above.
3. The value of the test-statistic is: Answer to 3 decimal places.
4. If α = 0.1, , and the p-value is 0.1904, what will be your
conclusion?
Reject H0.
There is not enough information to conclude.
Do not reject H0.
In: Statistics and Probability
|
The American Housing Survey reported the following data on the number of times that owner-occupied and renter-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months.
Do not round intermediate calculations. Round your answers to two decimal places. a. Define a random variable x = number of times that owner-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months and develop a probability distribution for the random variable. (Let x = 4 represent 4 or more times.)
b. Compute the expected value and variance for x.
c. Define a random variable y = number of times that renter-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months and develop a probability distribution for the random variable. (Let y = 4 represent 4 or more times.)
d. Compute the expected value and variance for y.
e. What observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units? The number of times of water supply stoppages in owner-occupied houses is Select greater/ less Item 17 than in renter-occupied houses, and the variability in the number of times is Select greater/less Item 18 for the owner-occupied houses |
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In: Statistics and Probability
|
Voltage Data |
Voltage Data |
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Sample # |
xi |
Sample # |
xi |
|
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1 |
6 |
11 |
8 |
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1 |
9 |
11 |
12 |
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1 |
10 |
11 |
14 |
|
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1 |
15 |
11 |
16 |
|
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2 |
10 |
12 |
6 |
|
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2 |
4 |
12 |
13 |
|
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2 |
6 |
12 |
9 |
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2 |
11 |
12 |
11 |
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3 |
7 |
13 |
16 |
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3 |
8 |
13 |
9 |
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3 |
10 |
13 |
13 |
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3 |
5 |
13 |
15 |
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4 |
8 |
14 |
7 |
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4 |
9 |
14 |
13 |
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4 |
6 |
14 |
10 |
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4 |
13 |
14 |
12 |
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5 |
9 |
15 |
11 |
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5 |
10 |
15 |
7 |
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5 |
7 |
15 |
10 |
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5 |
13 |
15 |
16 |
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6 |
12 |
16 |
15 |
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6 |
11 |
16 |
10 |
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6 |
10 |
16 |
11 |
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6 |
10 |
16 |
14 |
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7 |
16 |
17 |
9 |
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7 |
10 |
17 |
8 |
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7 |
8 |
17 |
12 |
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7 |
9 |
17 |
10 |
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8 |
7 |
18 |
15 |
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8 |
5 |
18 |
7 |
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8 |
10 |
18 |
10 |
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8 |
4 |
18 |
11 |
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9 |
9 |
19 |
8 |
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9 |
7 |
19 |
6 |
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9 |
8 |
19 |
9 |
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9 |
12 |
19 |
12 |
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10 |
15 |
20 |
13 |
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10 |
16 |
20 |
14 |
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10 |
10 |
20 |
11 |
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10 |
13 |
20 |
15 |
In: Statistics and Probability
Iterative Merge Sort is not working
#include
#include
#include
int* b;
void merge(int a[], int left, int mid, int right)
{
int i = left, j = mid + 1, k = left;
while (i <= mid && j <= right)
{
if (a[i] < a[j])
b[k++] =
a[i++];
else
b[k++] =
a[j++];
}
for (; i <= mid; i++)
{
b[k++] = a[i];
}
for (; j <= right; j++)
{
b[k++] = a[j];
}
for (int i = left; i <= right; i++)
{
a[i] = b[i];
}
}
void mergesort(int a[], int n)
{
int p, left, right, mid, i;
for (p = 2; p <= n; p = p * 2)
{
for (i = 0; i + p - 1 < n; i = i
+ p)
{
left = i;
right = i + p -
1;
mid = (left +
right) / 2;
merge(a, left,
mid, right);
}
}
if (p / 2 < n)
{
merge(a, 0, (p / 2) - 1, n -
1);
}
}
void main()
{
int max, * a;
scanf("%d", &max);
a = (int*)malloc(sizeof(int) * max);
b = (int*)malloc(sizeof(int) * max);
for (int i = 0; i < max; i++)
{
scanf("%d", &a[i]);
}
mergesort(a, max);
for (int i = 0; i < max; i++)
{
printf(" %d", a[i]);
}
}
input 50
50 49 48 47 46 45 ~ 5 4 3 2 1
output
3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 1 2 19 20 21 22 23 24 ~ 50
why 1,2 are between in 18 and 19?
please answer and correct code
In: Computer Science
Part 1
What does a stop order to sell at $2 mean? When might it be used?
Part 2
Six-month call options with strike prices of $35 and $40 cost $7 and $4, respectively. What is the maximum gain when a bull spread is created from the calls?
In: Finance
Strong acids and bases completely dissociate in water. classify the following chemical compounds as strong acids, weak acids, strong bases, and weak bases.
1. H2SO4
2. KOH
3. HI
4. HCN
5. H2S
6. KF
7. Be(OH)2
8. NH3
In: Chemistry
1. What do you understand about DRI's in the past and present?
2. What is the difference between RDA and AMDR?
3. What is a tertiary prevention example of type 2 DM?
4. Plant source of fats ( example of foods)?
5. Animal source of Fats (food examples)?
In: Nursing
Which of the following transitions in the Bohr hydrogen atom results in the emission of the shortest wavelength photon.
a. n = 2 → n = 5
b. n = 5 → n = 2
c. n = 6 → n = 3
d. n = 3 → n = 6
e. n = 4 → n = 1
In: Chemistry
determine the distances between the genes, coefficient of coincidence, and interference. Show all calculations. (create pairs eg wfm and +++ are a parental pair)
|
Phenotype |
Number of Individuals |
|
wfm |
5 |
|
+++ |
7 |
|
+fm |
4 |
|
w++ |
0 |
|
w+m |
2 |
|
+f+ |
1 |
|
wf+ |
0 |
|
++m |
2 |
In: Biology
1. What is the relationship that constitutes the foundation of the Capital Asset Pricing
Model?
2. What are the vital functions that this relationship serves?
3. List two (2) of the assumptions that lead to the basic version of the CAPM
4. Explain what the “Market Portfolio” is.
5. Explain what the Security Market Line is.
In: Finance