8. A pet food company has a business objective of expanding its product line beyond its current kidney- and shrimp-based cat foots. The company developed two new products, one based on chicken liver and the other based on salmon. The company conducted an experiment to compare the two new products with its two existing ones, as well as a generic beef-based product sold in supermarket chains.
For the experiment, a sample of 50 cats from the population at a local animal shelter was selected. Ten cats were randomly assigned to each of the five products being tested. Each of the cats was then presented with 3 ounces of the selected food in a dish at feeding time. The researchers defined the variable to be measured as the number of ounces of food that the cat consumed within a 5-minute period that began when the filled dish was presented to the cat. The results for this experiment are summarized in CatFood.
a. At the 0.05 level of significance, is there evidence of a differences in the mean amount of food eaten among the various products?
b. Does the result in (a) give you statistical permission to probe for individual differences between the food products?
| Kidney | Shrimp | Chicken Liver | Salmon | Beef |
| 3.00 | 0.25 | 2.61 | 0.63 | 2.97 |
| 3.00 | 0.34 | 3.00 | 1.37 | 2.85 |
| 1.47 | 0.16 | 3.00 | 3.00 | 0.44 |
| 2.62 | 0.72 | 2.43 | 0.54 | 0.90 |
| 1.51 | 3.00 | 3.00 | 3.00 | 3.00 |
| 3.00 | 3.00 | 3.00 | 2.55 | 3.00 |
| 3.00 | 0.29 | 2.85 | 2.93 | 0.48 |
| 3.00 | 3.00 | 0.18 | 2.73 | 0.45 |
| 0.74 | 1.99 | 0.98 | 3.00 | 3.00 |
| 2.21 | 2.30 | 1.51 | 0.96 | 0.05 |
In: Statistics and Probability
A pet food company has a business objective of expanding its product line beyond its current kidney- and shrimp-based cat foots. The company developed two new products, one based on chicken liver and the other based on salmon. The company conducted an experiment to compare the two new products with its two existing ones, as well as a generic beef-based product sold in supermarket chains.
For the experiment, a sample of 50 cats from the population at a local animal shelter was selected. Ten cats were randomly assigned to each of the five products being tested. Each of the cats was then presented with 3 ounces of the selected food in a dish at feeding time. The researchers defined the variable to be measured as the number of ounces of food that the cat consumed within a 10-minute period that began when the filled dish was presented to the cat. The results for this experiment are summarized in CatFood.
a. At the 0.05 level of significance, is there evidence of a differences in the mean amount of food eaten among the various products?
b. Does the result in (a) give you statistical permission to probe for individual differences between the food products?
Please show me how to do this in excel using the data analysis tab
| Kidney | Shrimp | Chicken Liver | Salmon | Beef |
| 2.37 | 2.26 | 2.29 | 1.79 | 2.09 |
| 2.62 | 2.69 | 2.23 | 2.33 | 1.87 |
| 2.31 | 2.25 | 2.41 | 1.96 | 1.67 |
| 2.47 | 2.45 | 2.68 | 2.05 | 1.64 |
| 2.59 | 2.34 | 2.25 | 2.26 | 2.16 |
| 2.62 | 2.37 | 2.17 | 2.24 | 1.75 |
| 2.34 | 2.22 | 2.37 | 1.96 | 1.18 |
| 2.47 | 2.56 | 2.26 | 1.58 | 1.92 |
| 2.45 | 2.36 | 2.45 | 2.18 | 1.32 |
| 2.32 | 2.59 | 2.57 | 1.93 | 1.94 |
In: Math
Synthesis of banana oil
this is my discussion and below it is the professors comments. Can you correct it for me?
Discussion:
The purpose of the experiment performed was to synthesize isopentyl acetate, or more commonly known as banana oil, from isopentyl alcohol and glacial acetic acid. Both liquids were combined and remained clear until the addition of concentrated sulfuric acid. The addition of an acid caused a reaction to occur that resulted in a polymer, which gave the mixture color. The liquid turned dark brown when the polymer formed. The polymer was removed via distillation.
After creating the ester, the biggest challenge was separating it from all the other chemicals in the flask, which include water, acetic acid, sulfuric acid, and isopentyl alcohol. The isopentyl acetate is not soluble in water; so two layers are created in the separatory funnel. While the product will not dissolve in water, both acetic acid and sulfuric acid are. Since the acids are also slightly in the organic layer, sodium bicarbonate is used to convert the acids into a salt, which is soluble in water, as seen in Figure 2. The sodium bicarbonate reaction also produces carbonic acid, which is unstable and will break down into water and CO2 as seen in Figure 3. The little amount of unreacted isopentyl alcohol is separated by removing the first ten drops of product during the distillation. This is possible because it has a lower boiling point then the ester that is produced.
This whole reaction was first done and called the Fischer esterification. The general reaction scheme can be seen above. In the experiment, isopentyl alcohol and acetic acid react in the presence of sulfuric acid to form isopentyl acetate. This reaction mechanism can be seen below in Figure 5.
Figure 5 – Fischer esterification mechanism
In the reaction above, Acetic acid takes a proton from concentrated sulfuric acid. Then it reacts with isopropentyl alcohol. Delocalization of electrons and protons in later steps leads to elimination of water molecule to form final product.
During the distillation, the temperature was recorded for the boiling point of isopentyl acetate. It was found to be at 129 degrees Celsius. This is low compared to the literature value of 142 degrees Celsius. This difference is believed to be due to the different typed of thermometers used to record the boiling point. The literature value most likely used a mercury thermometer, while the experiment performed used an alcohol thermometer. Alcohol thermometers are not as accurate as mercury thermometers, but have to be used due a law banning mercury thermometers in the state of New Jersey. Because of this, not much can be said about the purity of the substance obtained.
While an NMR was not taking during the experiment, nor was an IR spectrum, attached is both an NMR example and an IR example of isopentyl acetate. On the NMR sheet, all hydrogen peaks are labeled on a drawing of the molecule, and all the information is written in the chart. On the IR sheet, peaks above 1500 cm-1 are labeled for what they are believed to be. While the pictures were found from a reputable source, they were not from the experiment performed so one cannot be perfectly sure that the desired substance was obtained.
The last topic for the reaction was the product loss. Most organic reactions are not perfect and have relatively low yields. The 42 percent yield was most likely due to side reactions occurring in the flask. Since there were several chemicals in the flask together, side reactions are bound to occur, creating a lower yield. For example, a polymer was formed which changed the color of the flask. This was not intended to happen so this reaction lowered the yield of the experiment.
professors comments.
You need to explain what substances should have been in the flask at the end of refluxing. Show a flow
diagram of the purification process. You did an extraction, a drying and a distillation.
Alcohol thermometers are quite accurate in the range they are designed to function. This type of
alcohol thermometer was not designed to work around 142 degrees C.
Treat the NMR and IR spectra as if they were obtained by you for your product. You should have tables
in your Results Section for IR, NMR and GC. You should discuss these results in more detail in the
discussion. What do we learn from each measurement.
Give more details of the many causes for obtaining less than 100% Yield.
Discuss whether this experiment is a good example of Green Chemistry. Does the Atom efficiency make
it a good candidate. Does the Reaction efficiency make it a good example of Green chemistry. What
about other things.
In: Chemistry
Account Type: SAVING
Account Owner: Customer B
Interest Rate: 1.1
Balance: 500.0
Account Type: CHECKING
Account Owner: Customer A
Interest Rate: 1.2
Balance: 200.0
Cannot withdraw more than account balance
Account Type: SAVING
Account Owner: Customer B
Interest Rate: 1.1
Balance: 700.0
Account Type: CHECKING
Account Owner: Customer A
Interest Rate: 1.2
Balance: 200.0
solution provided:
package csci1011.csci1011.lab8;
import java.text.NumberFormat;
import java.text.DecimalFormat;
class Account {
enum ACCOUNT_TYPE
{
CHECKING,SAVINGS;
}
//create five variable
private ACCOUNT_TYPE aType;
private String accountOwner;
private double interestRate;
private double Balance;
//setter and getter methods
private ACCOUNT_TYPE getaType() {
return aType;
}
private void setaType(ACCOUNT_TYPE aType) {
this.aType = aType;
}
private String getAccountOwner() {
return accountOwner;
}
private void setAccountOwner(String accountOwner) {
this.accountOwner = accountOwner;
}
private double getInterestRate() {
return interestRate;
}
private void setInterestRate(double interestRate) {
this.interestRate = interestRate;
}
private double getBalance() {
return Balance;
}
private void setBalance(double Balance) {
this.Balance = Balance;
}
void initialize(ACCOUNT_TYPE atype,String name,double interestRate,double balance)
{
setaType(atype);
setAccountOwner(name);
setInterestRate(interestRate);
setBalance(balance);
}
void display()
{
System.out.println(" Account Type : "+aType.name());
System.out.println("Account Owner : "+getAccountOwner());
System.out.println("Interest Rate : "+getInterestRate());
System.out.println("Balance : "+getBalance());
}
//deposit to the account
void deposit(double amount)
{
double bal=getBalance();
setBalance(bal+amount);
System.out.println("Successfull Deposit ! ");
}
//withdraw from account
void withdraw(double amount)
{
//if balance is 0 or amount is greater than balance
if(getBalance()<=0 || amount>getBalance())
{
System.out.println("You don't have enough money to withdraw");
}
else
{
double bal=getBalance();
setBalance(bal-amount);
System.out.println("Successfully withdrawn ");
}
}
public static void main(String args[])
{
//two objects
Account ac=new Account();
Account ac1=new Account();
//initialize with Savings
ac.initialize(ACCOUNT_TYPE.SAVINGS, "Customer B ", 1.1, 500);
//initialize with Checking
ac1.initialize(ACCOUNT_TYPE.CHECKING, "Customer A ", 1.2, 200);
//display
ac.display();
ac1.display();
//deposit into account
ac.deposit(20);
//withdraw from account
ac.withdraw(60);
//display
ac.display();
}
}
In: Computer Science
Part D - Labeling the Spinal Anatomy
Drag the name of the nervous tissue to the proper spot
on the image.

Drag the name of the nervous tissue to the proper spot on the image. Drag the appropriate labels to their respective targets.
Spinal nerve
Posterior ramus
Motor nuclei
Anterior root
Posterior root
Anterior ramus
In: Other
Your company has created the table below: VENDOR (VENDOR#, VENDOR-NAME, VENDOR-ADDRESS) The company will add other secondary fields later, but no matter which secondary field it adds, which normal form will this table never violate? Why?
In: Economics
What does it mean to "make a name" for oneself? Does it always mean the same thing or not? Consider the example of Gilgamesh before he sets out to slay Humbaba in The Epic of Gilgamesh (p. 20) and the example of Genesis 11.4. What does it mean in each text, respectively, to make one's name?
In: Psychology
What is a specific, "real-life", example of a seller in the United States today that meets the definition of a "competitive price searcher". Your posting should be at least two paragraphs long and specifically identify the differentiated product (I am looking for a brand name this time!) that is sold by the firm you are describing (by name).
In: Operations Management
Payout policies of the firm should be aligned with the shareholders’ wealth maximization objective. In general, name at least three reasons why some companies should be paying their earnings out in dividends; alternatively, name at least three reasons when it might be optimal for companies to reduce dividends and retain more of the earnings.
In: Finance
Determine the pH of each solution.
Dissociation Constants at 25 ∘C
| Name | Formula | Ka |
| Formic acid | HCHO2 | 1.8×10−4 |
| Name | Formula | Kb |
| Methylamine | CH3NH2 | 4.4×10−4 |
a) 0.21 M KCHO2
b) 0.21 M CH3NH3I
c)0.21 M KI
In: Chemistry