Prepare a Production Budget EcoBags manufactures cloth shopping bags. The controller is preparing a budget for the coming year and asks for your assistance. The following costs and other data apply to bag production:

Direct materials per bag

1.0 yard cotton at $4 per yard

0.2 yards canvas finish at $12 per yard

Direct labor per bag

0.5 hour at $18 per hour

Overhead per bag

Indirect labor …………………………………………… $0.60

Indirect materials ………………………………………. 0.20

Power …………………………………………………… 0.40

Equipment costs ………………………………………… 1.30

Building occupancy …………………………………….. 0.90

Total overhead per unit    $3.40

You learn that equipment costs and building occupancy are fixed and are based on a normal production of 600,000 units per year. Other overhead costs are variable. Plant capacity is sufficient to produce 750,000 units per year. Labor costs per hour are not expected to change during the year. However, the cotton supplier has informed EcoBags that it will impose a 20 percent price increase at the start of the coming budget period. No other costs are expected to change. During the coming budget period, EcoBags expects to sell 540,000 bags. Finished goods inventory is targeted to increase from the current balance of 120,000 units to 210,000 units to prepare for an expected sales increase the year after next as a result of legislation in several states regarding plastic bags. Production will occur evenly throughout the year. Inventory levels for cotton and canvas are expected to remain unchanged throughout the year. There is no work-in-process inventory. Required Prepare a production budget and estimate the materials, labor, and overhead costs for the coming year.

In this exercise, we examine the effect of combining investments with positively correlated risks, negatively correlated risks, and uncorrelated risks. A firm is considering a portfolio of assets. The
portfolio is comprised of two assets, which we will call ''A" and "B." Let X denote the annual rate of return from asset A in the following year, and let Y denote the annual rate of return from asset B in the following year. Suppose that
E(X) = 0.15 and E(Y) = 0.20,
SD(X) = 0.05 and SD(Y) = 0.06,
and CORR(X, Y) = 0.30.
(a) What is the expected return of investing 50% of the portfolio in asset A and 50% of the portfolio in asset B? What is the standard deviation of this return?
(b) Replace CORR(X, Y) = 0.30 by CORR(X, Y) = 0.60 and answer the questions in part (a). Do the same for CORR(X, Y) = 0.60, 0.30, and 0.0.
(c) (Spreadsheet Exercise). Use a spreadsheet to perform the following analysis. Suppose that the fraction of the portfolio that is invested in asset B is f, and so the fraction of the portfolio that is invested in asset A is (1 f). Letting f vary from f = 0.0 to f = 1.0 in increments of 5% (that is, f = 0.0, 0.05, 0.10, 0.15, . . . ), compute the mean and the standard deviation of the annual rate of return of the portfolio (using the original data for the problem). Notice that the expected return of the portfolio varies (linearly) from 0.15 to 0.20, and the standard deviation of the return varies (non-linearly) from 0.05 to 0.06. Construct a chart plotting the standard deviation as a function of the expected return.
(d) (Spreadsheet Exercise). Perform the same analysis as in part (c) with CORR (X, Y) = 0.30 replaced by CORR(X, Y) = 0.60, 0.0, 0.30, and 0.60.

you will develop a small XML.

XML is used for storing and exchanging information. XML is the most commonly used file format for e-business. It is important to have a grasp of XML.

In XML, you can choose your own tag names. For example, for representing name of a product, you can use <pname>, <prodName> or <productname> as you like. XML has to follow certain syntax rules.  Gentle Introduction to XML (External Link) provides more information about XML. Do the following:

• Do some research and find out what information must be obtained from customer for effective customer relationship management. (The information includes customer name, email, phone numbers etc.).   
• Decide on an XML file structure (also called schema) for storing all your order (products ordered + payment) information. No schema creation or validation is required.
• Create an XML file including payment data using a text editor like notepad.
• Syntax check your xml with an online validator (need to check for XML syntax only). XML Validator (External Link).
• Save your XML into a file and submit before the deadline. (By default, notepad stores files with extension .txt and that is fine. Although XML files usually have the extension .xml, you may want to save the file with .txt extension to upload

• Below is a sample XML file to start with:

  <?xml version="1.0"?>
  <crmDB>
  <customer>
  <customerName>John Doe</customerName>
  <phoneNumber>3092980000</phoneNumber>
  </customer>
  </crmDB>

    

  Obviously, you can choose whatever tag names you like and the information you choose to add for effective customer relationship management will be different as well.

1. three storey structure having a square footprint of 225 m² is constructed on a clayey deposit. The structure is planned to be supported by square isolated footings having a width of 2m and spaced at 5m center to center. typical borehole indicates that the soil consists of 2m fill layer at the top (g=17KN/m³) followed by a very stiff clay layer 2m thick (gsat=18.5KN/m³) underlain by a normally consolidated soft clay layer of 4.5m thickness (gsat=17KN/m³) followed by a rock layer extending down to the bottom of borehole. The foundations are laid on top of the stiff clay layer. Water table is located at the top of the stiff clay layer. Undisturbed samples were taken from the middle of each clay layer and consolidation tests done on undisturbed samples indicated the following:

 Stiff Clay: Cc=0.15; Cs = 0.02; P_c = 120 kPa; e₀=0.9

 Soft Normally Consolidated Clay: Cc=0.38; Cs = 0.06; e₀=1.0

a) The isolated foundations are subjected to a stress of 140 kPa. Calculate the consolidation settlement. Consider the very stiff clay as one layer and divide soft clay layer into two equal sub-layers. Calculate settlement under one typical foundation.

b) What would be the maximum additional stress applied on a central foundation from two neighboring foundations (situated at the left and right sides of the central foundation). Is it necessary to consider the additional stresses from neighboring foundations in the settlement calculations?

c) A concern is the differential settlement between isolated adjacent footings. It was decided to change the design to have the structure founded on a raft foundation subjected to a stress of 45 kPa. Compute the consolidation settlement and comment on the results.

QUIESTION 1
A three-phase synchronous generator is connected to an infinite bus. The infinite bus voltage and the generated voltage are o 1.0 pu ∠0 and o 1.0pu ∠42.84 , respectively. The synchronous reactance is 0.85 pu and resistances are neglected. a) Compute power angle (δ), armature current (Is), power factor (pf), real power (P), and reactive power (Q). Draw the phasor diagram. b) If the prime mover torque is kept constant at a value corresponding to P=0.8 pu, compute the required value of the generated voltage (E2) for the unity power factor condition (and constant power, P=0.8 pu). What is the new value of power angle (δ2)? Solution: δ= 42.84o , Is = 0.86pu ∠21.44o , pf=0.93, P=0.8 ph, Q= -0.314pu, δ2 = 34.2o , E2= 1.21pu

QUESTION 2
Two “three-phase Y-connected synchronous generators” have per phase generated voltages of o 1 E = 120 V∠10 and o 2 E = 120 V∠20 under no load, and resistance of X j5 Ω / phase 1 = and X j8 Ω / phase 2 = . They are connected in parallel to a load impedance of XL = 4 + j3 Ω / phase . Compute: a) Per phase terminal voltage Vt (both magnitude and phase angle). b) Armature currents for each generator ( a1 a2 I and I ). c) Power supplied by each generator (P1 and P2 ). d) The total output power (Pout ). Solution: Vt= 82 V ∠-5.94o , Ia1 = 9.36 A ∠-51.17o , Ia2 = 7.31 A ∠-32.06o , P1 = 1621 W, P2 = 1614.5 W, Pout = 3236 W.

Design and construct a computer program in one of the approved languages (C++) that will illustrate the use of a fourth-order explicit Runge-Kutta method of your own design. In other words, you will first have to solve the Runge-Kutta equations of condition for the coefficients of a fourth-order Runge-Kutta method. See the Mathematica notebook on solving the equations for 4th order RK method. That notebook can be found at rk4Solution.nb . PLEASE DO NOT USE a[1] = 1/2 or a[2] = 1/2. In general, you should pick a[1] and a[2] to be distinct values greater than zero and less than one. Then, you will use these coefficients in a computer program to solve the ordinary differential equation below. Be sure to follow the documentation and programming style policies of the Computer Science Department.

The initial value problem to be solved is the following: x'(t) = 3 x2 cos(5 t) subject to the initial condition: x(0) = 1.0 Obtain a numerical solution to this problem over the range from t=0.0 to t=2.0 for seven different values of the stepsize, h=0.1, 0.05 , 0.025 , 0.0125 , 0.00625 , 0.003125 , and 0.0015625 . In other words, make seven runs with 20, 40, 80, 160, 320, 640, and 1280 steps, respectively. For each run, print out the value of h, then a table of t and x, and then the error at t=2. You may use the following very precise value for your "true answer" in order to compute the error at t=2: 0.753913186469598763502963347. The true solution of this differential equation resembles the following plot of x(t) as a function of t.

Crude oil, products and merchandise inventories are carried at the lower of current market value or cost (generally determined under the last-in, first-out method – LIFO). Inventory costs include expenditures and other charges (including depreciation) directly and indirectly incurred in bringing the inventory to its existing condition and location.

In 2016, 2015 and 2014, net income included losses of $295 million and $186 million, and a gain of $187 million, respectively, attributable to the combined effects of LIFO inventory accumulations and drawdowns. The aggregate replacement cost of inventories was estimated to exceed their LIFO carrying values by $8.1 billion and $4.5 billion at December 31, 2016, and 2015, respectively.

Crude oil, products and merchandise as of year-end 2016 and 2015 consist of the following:

5.3 If ExxonMobil had used FIFO in 2016, what would be the value of the inventory?

ou plan to invest in the Kish Hedge Fund, which has total capital of $500 million invested in five stocks: