the company sells a brand of low-fat shakes that appeal to people of all age groups and both genders. The company advertises this shake in a variety of 30-second television ads, and these ads can be placed in a variety of television shows. The ads in different shows vary by cost – some 30-second slots are much more expensive than others – and by the types of viewers they are likely to reach.
The company has segmented the potential viewers into six mutually exclusive categories: males age 18 to 35, males age 36 to 55, males over 55, females age 18 to 35, females age 36 to 55, and females over 55. A rating service can supply data on the numbers of viewers in each of these categories who will watch a 30-second ad on any particular television show. Each such viewer is called an exposure. The company has determined the required number of exposures it wants to obtain for each group. It wants to know how many ads to place on each of several television shows to obtain these required exposures at minimum cost.
The data on costs per ad, numbers of exposures per ad, and minimal required exposures are listed below, where numbers of exposures are expressed in millions, and costs are in thousands of dollars.
What should the company do?
|
TV Shows |
||||||||||
|
Viewer Group |
Game of Thrones |
Walking Dead |
Homeland |
Westworld |
Lifetime Evening Movie |
The Voice |
ESPN |
CNN |
Minimal Required Exposure |
|
|
Young Men |
3.0 |
5.0 |
6.0 |
5.0 |
0.1 |
0.7 |
0.5 |
0.1 |
60 |
|
|
Mid-age Men |
5.0 |
3.0 |
5.0 |
2.0 |
0.1 |
0.2 |
0.5 |
0.2 |
60 |
|
|
Senior Men |
4.0 |
1.0 |
3.0 |
0.0 |
0.0 |
0.0 |
0.3 |
0.3 |
28 |
|
|
Young Women |
3.0 |
6.0 |
1.0 |
4.0 |
0.6 |
0.9 |
0.1 |
0.1 |
60 |
|
|
Mid-age Women |
5.0 |
4.0 |
1.0 |
2.0 |
1.3 |
0.1 |
0.1 |
0.2 |
60 |
|
|
Senior Women |
4.0 |
2.0 |
1.0 |
0.0 |
0.4 |
0.0 |
0.0 |
0.3 |
28 |
|
|
Cost per Ad |
150.0 |
140.0 |
100.0 |
80.0 |
15.0 |
13.0 |
9.0 |
8.0 |
||
How would you address the fact that multiple ads per show do not translate to multiple exposures for the show?
In: Accounting
A. Christy is considering investing in the ordinary shares of BlueSteel and Ranco. The following data are available for these two securities:
BlueSteel Ranco
Expected return 9.2% 19.1%
Standard deviation of returns 7.8% 14.3% Using these two shares undertake calculations of the expected return and standard deviation of the portfolio, for
: a) A portfolio of 30% Heico, and correlation coefficients of either -0.2 or 0.8 between the two assets
b) A portfolio of 70% Heico, and correlation coefficients of either -0.2 or 0.8 between the two assets Explain using these calculations how diversifying a portfolio benefits an investor, and what key factors contribute to the extent of benefit involved.
In: Finance
Asset A pays $1,500 with certainty, while asset B pays $2,000 with probability 0.8 or $100 with probability 0.2. If offered the choice between assets A and B, a particular decision maker would choose asset A. Asset C pays $1,500 with probability 0.25 or $100 with probability 0.75, while asset D pays $2,000 with probability 0.2 or $100 with probability 0.8. If offered the choice between assets C and D, the decision maker would choose asset D. Show that the decision maker's preferences violate the independence axiom.
PLEASE HELP SHOW WORK PLEASE!!
In: Statistics and Probability
How does the Company Amazon relates to the Miles and Snow strategy and also how does it relate to the Porter Generic strategy?
In: Operations Management
In: Civil Engineering
Simulate 100 observations from an ARMA(1,1) model and another 30 observations from an ARMA(1,1) model both with = 0.8 and = 0.3.
please use Rstudio and provide the codes.
In: Statistics and Probability
In: Computer Science
We know the following expected returns for stocks A and B, given different states of the economy:
| State (s) | Probability | E(rA,s) | E(rB,s) |
| Recession | 0.3 | -0.01 | 0.04 |
| Normal | 0.5 | 0.14 | 0.07 |
| Expansion | 0.2 | 0.22 | 0.11 |
Note: If you can, it is much faster to solve these problems in a spreadsheet. However, the answer cannot be had simply by using the built-in AVERAGE() or STDEV() functions. If you are somewhat familiar with Excel, you might look into the SUMPRODUCT() function which is widely used to calculate weighted sums.
A: What is the expected return for stock A? 3+ Decimals
B: What is the expected return for stock B? 3+ Decimals
C:What is the standard deviation of returns for stock A? 3+ Decimals
D: What is the standard deviation of returns for stock B? 4+3+ Decimals
In: Finance
The drive-up window at a local bank is searching for ways to improve service. One of the tellers has decided to keep a control chart for the service time in minutes for the first four customers driving up to her window each hour for a three-day period. The results for her data collection appear below:
|
Customer |
TIME |
||||||||
|
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
|
1 |
1.4 |
3.8 |
3.6 |
4.3 |
4.0 |
1.3 |
0.9 |
4.7 |
|
|
2 |
2.3 |
5.2 |
2.5 |
1.2 |
5.2 |
1.1 |
4.4 |
5.1 |
|
|
3 |
1.9 |
1.9 |
0.8 |
3.0 |
2.7 |
4.9 |
5.1 |
0.9 |
|
|
4 |
5.1 |
4.8 |
2.9 |
1.5 |
0.3 |
2.3 |
4.6 |
4.7 |
|
|
Customer |
TIME |
||||||||
|
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
|
1 |
2.8 |
0.5 |
4.5 |
0.6 |
4.8 |
2.7 |
4.2 |
0.9 |
|
|
2 |
3.0 |
2.7 |
1.9 |
1.2 |
2.8 |
2.0 |
1.1 |
4.4 |
|
|
3 |
4.1 |
4.7 |
4.2 |
2.7 |
1.1 |
2.6 |
4.4 |
0.6 |
|
|
4 |
4.8 |
3.6 |
0.4 |
2.5 |
0.4 |
2.6 |
3.1 |
0.4 |
|
|
Customer |
TIME |
||||||||
|
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
|
1 |
0.3 |
3.5 |
5.2 |
2.9 |
3.3 |
4.0 |
2.8 |
0.6 |
|
|
2 |
2.4 |
3.4 |
0.3 |
1.9 |
3.7 |
3.3 |
0.7 |
2.1 |
|
|
3 |
5.0 |
4.6 |
2.4 |
0.8 |
3.8 |
5.0 |
1.6 |
3.3 |
|
|
4 |
0.9 |
3.3 |
3.9 |
0.3 |
2.1 |
2.8 |
4.6 |
2.7 |
|
Using Minitab:
if it's possible i need the minitab file or link for it
In: Statistics and Probability
Suppose X has probability distribution
x: 0 1 2 3 4
P(X = x) 0.2 0.1 0.2 0.2 0.3
Find the following probabilities:
a. P(X < 2)
b. P(X ≤ 2 and X < 4)
c. P(X ≤ 2 and X ≥ 1)
d. P(X = 1 or X ≤ 3)
e. P(X = 2 given X ≤ 2)
In: Statistics and Probability