Financing Deficit
Garlington Technologies Inc.'s 2016 financial statements are shown below:
Balance Sheet as of December 31, 2016
| Cash | $ 180,000 | Accounts payable | $ 360,000 | |
| Receivables | 360,000 | Notes payable | 156,000 | |
| Inventories | 720,000 | Line of credit | 0 | |
| Total current assets | $1,260,000 | Accruals | 180,000 | |
| Fixed assets | 1,440,000 | Total current liabilities | $ 696,000 | |
| Common stock | 1,800,000 | |||
| Retained earnings | 204,000 | |||
| Total assets | $2,700,000 | Total liabilities and equity | $2,700,000 |
Income Statement for December 31, 2016
| Sales | $3,600,000 |
| Operating costs | 3,279,720 |
| EBIT | $ 320,280 |
| Interest | 18,280 |
| Pre-tax earnings | $ 302,000 |
| Taxes (40%) | 120,800 |
| Net income | 181,200 |
| Dividends | $ 108,000 |
Suppose that in 2017 sales increase by 20% over 2016 sales and that 2017 dividends will increase to $132,000. Forecast the financial statements using the forecasted financial statement method. Assume the firm operated at full capacity in 2016. Use an interest rate of 9%, and assume that any new debt will be added at the end of the year (so forecast the interest expense based on the debt balance at the beginning of the year). Cash does not earn any interest income. Assume that the all new-debt will be in the form of a line of credit. Round your answers to the nearest dollar. Do not round intermediate calculations.
| Garlington Technologies Inc. Pro Forma Income Statement December 31, 2017 |
|||
| Sales | $ | ||
| Operating costs | $ | ||
| EBIT | $ | ||
| Interest | $ | ||
| Pre-tax earnings | $ | ||
| Taxes (40%) | $ | ||
| Net income | $ | ||
| Dividends: | $ | ||
| Addition to RE: | $ | ||
| Garlington Technologies Inc. Pro Forma Balance Statement December 31, 2017 |
|||
| Cash | $ | ||
| Receivables | $ | ||
| Inventories | $ | ||
| Total current assets | $ | ||
| Fixed assets | $ | ||
| Total assets | $ | ||
| Accounts payable | $ | ||
| Notes payable | $ | ||
| Accruals | $ | ||
| Total current liabilities | $ | ||
| Common stock | $ | ||
| Retained earnings | $ | ||
| Total liabilities and equity | $ | ||
In: Finance
Minerals question i have named all 16 minerals already i just need the function Major or trace ,Food Source,Name of deficiency or symptoms of deficiency,and toxicity and yes or No answer.
There will be a total of 16 minerals (7 major & 9 trace) Minerals
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Name – both name and number if given |
Function Major or trace if minerals |
4 food sources |
Name of deficiency or symptoms of deficiency |
Toxicity Yes or no |
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1.Calcium |
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2.Magnesium |
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3.Potassium |
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4.Sodium |
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5.Sulfer |
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6.Phosphorous |
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7.Chloride |
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8.Zinc |
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9.Iron |
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10.Copper |
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11.Iodine |
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12.Selenium |
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13.Manganese |
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14.Chromium |
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15.Floride |
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16.Molybdenum |
In: Nursing
1.) According to the UML Class Diagram, these are the mutator and accessor methods that you need to define:
1a.) +setName(value:String):void
1b.) +setGPA(value:double):void
1c.) +setID(value: String):void
1d.) +getName(): String
1e.) +getLastName():String
2.) Working with constructors
2a.) +Student() : This is the default constuctor. For the Strings properties, initialize them to null. The order is String ID, String name, String lastName, and double GPA.
2b.) +Student(value:String) - This constructor receives just the ID.
2c.) +Student(value:String, var: String) - This constructor receives the ID and name in that order.
2d.) +Student(value:String, var: String, change: String) - This constructor receives the ID, name, and last name in that order.
In: Computer Science
Please write in Python 3.7.4 or Higher.
The Payroll Department keeps a list of employee information for each pay period in a text file. The format of each line of the file is the following: <last name> <hours worked> <hourly wage>
Write a program that inputs a filename from the user and prints to the terminal a report of the wages paid to the employees for the given period.
An example of the program input and output is shown below:
Enter the file name: data.txt Name Hours Total Pay Lambert 34 357.00 Osborne 22 137.50 Giacometti 5 503.50
In: Computer Science
Create a Database from blank (scratch) for a manager and name it. Create and design a table and name it. For each fields click and choose proper a data type such as short text and name the field. Make at least three fields. Enter your records. Make sure to add your name as a record.
Similarly create two more tables. By design tool, make a relationship between each of two tables at a time and drag a primary key one table to a secondary key of another table. For example one to one, one to many, many to one or many to many)
Run at least 5 queries of different important tasks on the data base
For this question I was given no data
In: Computer Science
In: Computer Science
When a user signs in for the first time to a website, the user must submit personal information, such as last name, first name, email address, and so on. Typically, there are two fields for passwords, requiring the user to enter the password twice, to ensure that the user did not make a typo in the first password field.
Write a class encapsulating user with the following attributes:
UserID
Password
Reentered password
Email address
Last Name
First Name
Zip
You will store these values as strings.
Write the following methods in your class:
1. A constructor which will initialize the 7 attributes listed above.
2. Accessor, mutator, toString methods
3. A method returning the user id consisting of the first letter of the first name, last two letters of the last name and the first three nambers of the zip code and a random number (between 0 and 999)
4.. A method checking if the two Strings representing the password fields are the same, if they are return true, otherwise false.
Write a test class to create 2 user objects (using your constructor) and test all the methods in your class.
Remember to submit all your .java files, .class files and screenshots of your code and output and psuedocode
In: Computer Science
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In: Accounting
Program in C
Make both a SOURCE AND HEADER FILE WITH FUNCTIONS to run the program. Input data from csv file. Two files. grades.c and grades.h Thank you
data.csv file
Mark Prest,37468,36,113,In Person
Andy Joe,6785923,19,98,Online
Caden Miller,237741,20,70.1,In Person
Luke Jr,2347878,18,45.9,In Online
Ally Rogers,8467483,30,89.99,Online
Maya Jank,5674930,30,90,In Person
Expected output
Name: Mark Prest
ID: 37468
Age: 36
Grade: 113.00
Attending: In Person
Name: Andy Joe
ID: 6785923
Age: 19
Grade: 98.00
Attending: Online
Name: Caden Miller
ID: 237741
Age: 20
Grade: 70.10
Attending: In Person
Name: Luke Jr
ID: 2347878
Age: 18
Grade: 45.90
Attending: Online
Name: Ally Rogers
ID: 8467483
Age: 30
Grade: 89.99
Attending: Online
Name: Maya Jank
NUID: 5674930
Age: 30
Grade: 90.00
Attending: In Person
--------------
2
---- Grade Stats ----
A's: 3
B's: 1
C's: 1
D's: 0
F's: 1
Avg grade: 84.50
---- Enrollment Statistics ----
Number of in person: 5
Number of online: 1
Average age: 25.50
In: Computer Science
Implement a Composite Design Pattern for the code below that creates a family tree
MAIN:
public class Main {
public static void main(String[] args) {
/* Let's create a family tree (for instance like one used on
genealogy sites).
For the sake of simplicity, assume an individual can have at most
two children.
If an individual has 1-2 children, they are considered a "tree". If
an individual
does not have children, they are considered a "person".
With that in mind, let's populate a family tree with some data.
*/
Person p1 = new Person(1);
Person p2 = new Person(2);
Person p3 = new Person(3);
Person p4 = new Person(4);
Tree t1 = new Tree(p1, 1);
Tree t2 = new Tree(p2, p3, 2);
Tree t3 = new Tree(t1, p4, 3);
Tree t4 = new Tree(t3, t2, 4);
t4.print();
}
}
PERSON:
public class Person {
String name;
public Person(int num) {
name = "person" + num;
}
public void print() {
System.out.println(name);
}
}
TREE:
public class Tree {
private String name;
private Tree tree1;
private Tree tree2;
private Person person1;
private Person person2;
public Tree(Person p1, int num) {
tree1 = null;
tree2 = null;
person1 = p1;
person2 = null;
name = "tree" + num;
}
public Tree(Tree t1, int num) {
tree1 = t1;
tree2 = null;
person1 = null;
person2 = null;
name = "tree" + num;
}
public Tree(Tree t1, Tree t2, int num){
tree1 = t1;
tree2 = t2;
person1 = null;
person2 = null;
name = "tree" + num;
}
public Tree(Tree t1, Person p2, int num){
tree1 = t1;
tree2 = null;
person1 = null;
person2 = p2;
name = "tree" + num;
}
public Tree(Person p1, Person p2, int num){
tree1 = null;
tree2 = null;
person1 = p1;
person2 = p2;
name = "tree" + num;
}
public void print() {
System.out.println(name);
if (tree1 != null) {
tree1.print();
}
if (tree2 != null) {
tree2.print();
}
if (person1 != null) {
person1.print();
}
if (person2 != null) {
person2.print();
}
}
}
In: Computer Science