In what follows use any of the following tests/procedures: Regression, confidence intervals, one-sided t-test, or two-sided t-test. All the procedures should be done with 5% P-value or 95% confidence interval.

Open Brain data. SETUP: It is believed that the person whose brain has larger surface area (i.e. TOTSA: Total Surface Area) that the person will have the larger brain volume as well. Given the data your job is to confirm or disprove this assertion.

1. What test/procedure did you perform?

• a. One-sided t-test
• b. Two-sided t-test
• c. Regression
• d. ​​Confidence interval

2. What is the P-value/margin of error?

• a. 0.248605264
• b. 0.005070081
• c. 3.44547E-20
• d. 5.27739E-08
• e. ​​None of these

3. Statistical interpretation

• a. Since P-value is very large we cannot confirm that the average of the first sample is larger than the other.
• b. Since P-value is very small we are very confident that the averages are different.
• c. Since P-value is very small we are confident that the slope of regression line is not zero.
• d. ​​None of these.

4. Conclusion

• a. Yes, I am confident that the above assertion is correct.
• b. No, we cannot claim that the above assertion is correct.

paste content below in a text document and then open the text document with excel

CCMIDSA: Corpus Collasum Surface Area (cm2)     FIQ: Full-Scale IQ      HC: Head Circumference (cm)     ORDER: Birth Order      PAIR: Pair ID (Genotype)        SEX: Sex (1=Male 2=Female)      TOTSA: Total Surface Area (cm2) TOTVOL: Total Brain Volume (cm3)        WEIGHT: Body Weight (kg)
8.42    96      57.2    1       6       1       1806.31 1079    61.236
7.44    88      57.2    1       7       1       2018.92 1104    79.38
6.84    85      57.2    1       8       1       2154.67 1439    99.792
6.48    97      57.2    1       9       1       1767.56 1029    81.648
6.43    124     58.5    1       10      1       1971.63 1160    72.576
7.62    101     57.2    2       6       1       1689.6  1173    61.236
6.03    93      57.2    2       7       1       2136.37 1067    83.916
6.59    94      55.8    2       8       1       1966.81 1347    97.524
7.52    114     56.5    2       9       1       1827.92 1100    88.452
7.67    113     59.2    2       10      1       1773.83 1204    79.38
6.08    96      54.7    1       1       2       1913.88 1005    57.607
5.73    87      53      1       2       2       1902.36 1035    64.184
6.22    101     57.8    1       3       2       2264.25 1281    63.958
5.8     103     56.6    1       4       2       1866.99 1051    133.358
7.99    127     53.1    1       5       2       1743.04 1034    62.143
7.99    89      54.2    2       1       2       1684.89 963     58.968
8.76    87      52.9    2       2       2       1860.24 1027    58.514
6.32    103     56.9    2       3       2       2216.4  1272    61.69
6.32    96      55.3    2       4       2       1850.64 1079    107.503
7.6     126     54.8    2       5       2       1709.3  1070    83.009

Which of the following are correct for P(x,y,z)= xyz + x(yz)' + x'(y + z) + (xyz)' ?

1) P(0, 0, 1) = 0

2) P(0, 1, 0) = 1

3) P(0, 0, 0) = 1

4) P(1, 1, 1) = 1

5) P(1, 0, 0) = 0

For this assignment, you are to use the business model canvas to create four (4) canvases on different business concepts

Make sure to include the following in the margins as per the video.

1)Key Trends

2) Industry Trends

3) Market Forces

4) Marco-economic forces

question 1 SWOT ANALYSIS OF STARBUCKS.

QUESTION 2 TOWS matrix of Starbucks
QUESTION 3 Starbucks mission, objectives, strategies and policies in terms of growth Strategies.
QUESTION 4 functional strategies of the Starbucks

For question o. 4 , I just need functional strategies.

x[n] is the input of an LTI system with the impulse response of h[n]. x[n] = [1, 2, 3] and h[n] = [4, 6]. Use 4-point DFT and IDFT and zero padding of x[n] and h[n] to find the output y[n].

JAVA write a code for Task 1 and Task 2 and pass the test cases.

Imagine you have a rotary combination lock with many dials. Each dial has the digits 0 - 9. At any point in time, one digit from each dial is visible. Each dial can be rotated up or down. For some dial, if a 4 is currently visible then rotating the dial up would make 5 visible; rotating the dial down would make 3 visible. When 0 is the visible digit then rotating down would make 9 visible. Similarly, when 9 is visible then rotating up would make 0 visible. We have devised a robotic finger to manipulate such combination systems. The robotic finger takes as input a String that indicates the operations to be performed. An L moves the finger one dial to the left, an R moves the finger one dial to the right, and a + rotates the dial that the finger is at up and a - rotates the dial that the finger is at down.

The robotic finger always starts at the leftmost dial.

Task 1

Given a sequence of operations in String form, as well as an initial arrangement of the dials, determine the digits that will be visible after the operations have been performed.

Task 2

Given an initial state of the dials and a final state, return a String that represents a sequence of operations of shortest length that transforms the initial state to the final state.

Task 1

 @param initialState represents the state of the combination dials and {@code 0 <= initialState[i] <= 9} for all {@code 0 <= i < initialState.length}.
 * @param ops          represents the operations to perform and only contains the characters 'L', 'R', '+' and '-' or {@code ops} is empty
 * @return the new state
 */
public int[] rotate(int[] initialState, String ops) {

//code in here

}

Test cases for task 1:

int[] initialState = {7, 0, 2, 9, 1, 5, 6};
String ops = "R-R++R+++R+RR--";
int[] expectedState = {7, 9, 4, 2, 2, 5, 4};

Task2

/**
 * Transform the initial state to a given new state using the shortest sequence of operations
 *
 * @param initialState represents the initial state of the dials, and {@code 0 < initialState.length <= 10}, and {@code 0 <= initialState[i] <= 9} for all {@code 0 <= i < initialState.length}.
 * @param newState     represents the new (desired) state of the dials, and {@code 0 < initialState.length <= 10}, and {@code 0 <= initialState[i] <= 9} for all {@code 0 <= i < initialState.length}. Also {@code newState.length() == initialState.length()}.
 * @return a representation of a shortest operation sequence that ensures that the initial state is transformed to the new state.
 */
public String getRotationSequence(int[] initialState, int[] newState) {
//code in here
    return null;
}

Test cases for task 2

int[] initialState = {1, 2, 4, 4, 4, 7};
int[] finalState = {2, 7, 3, 4, 8, 9};
int expectedLength = "+R+++++R-RR++++R++".length();

Use the following information to answer the question(s) below.

Kester Co. purchases a piece of equipment on May 1, 20xx, for $30,000. The equipment has an estimated life of eight years or 50,000 units of production and an estimated residual value of $3,000. Kester uses a calendar fiscal year.

----------

What is the amount of straight-line depreciation to be recorded in the first partial year? (Hint: use the nearest month and calculate a partial year.)

Question 20 options:

Question 21 (1 point)

Use the following information to answer the question(s) below.

Kester Co. purchases a piece of equipment on May 1, 20xx, for $30,000. The equipment has an estimated life of eight years or 50,000 units of production and an estimated residual value of $3,000. Kester uses a calendar fiscal year.

------------

The amount of depreciation to be recorded for the first partial year using the double-declining –balance method, is

Question 21 options:

Question 22 (1 point)

Use the following information to answer the question(s) below.

Kester Co. purchases a piece of equipment on May 1, 20xx, for $30,000. The equipment has an estimated life of eight years or 50,000 units of production and an estimated residual value of $3,000. Kester uses a calendar fiscal year.

------------------

The amount of depreciation to be recorded for the first partial year using the units of production method and assuming that 6,500 units are produced, is

Question 22 options:

Question 23 (1 point)

The primary difference between ordinary and extraordinary repairs is that extraordinary repairs

Question 23 options:

Question 1:  Windows’ Ping sends four echo requests (i.e., four ping requests) to a target by default. Based on what you did in Activity 1 of Lab 4 and/or some of the information available in the Appendix of the Lab 4 assignment (i.e., the last pages in the Lab 4 assignment), which of the following is the appropriate command for pinging target 172.217.4.36 by sending 4 echo requests without changing any of the default pinging options?

1. ping –l 4 172.217.4.36
2. ping –r 4 172.217.4.36
3. ping 172.217.4.36
4. None of the above

Question 2:  Based on what you did in Activity 1 of Lab 4 and/or some of the information available in the Appendix of the Lab 4 assignment (i.e., the last pages in the Lab 4 assignment), which of the following commands can you use to ping the target 172.217.4.36 repeatedly until you stop the pinging yourself?

1. ping –r 4 172.217.4.36
2. ping –repeat 4 172.217.4.36
3. ping –t 172.217.4.36
4. None of the above

Question 3: You start pinging with the option of repeatedly pinging a target. Based on what you did in Activity 1 of Lab 4 and/or some of the information available in the Appendix of the Lab 4 assignment (i.e., the last pages in the Lab 4 assignment), which of the following can you use to stop the pinging?

1. Press the Esc key on the keyboard
2. Press Shift-Esc
3. Type Quit
4. Type Stop
5. None of the above

QUESTION 1
On 1st October 2017, Sugar Limited acquired 90% of Salt limited by issuing 100 000 shares at an agreed value of N$1.60 per share and N$ 140 000 in cash.
At that time, the Statement of Financial Position of Salt Limited was as follows:
N$ 000
Property plant and equipment 190
Inventories 70
Trade receivables 30
Cash and cash equivalent 10
Trade payables (40)
260
The Consolidated Statements of Financial Position of Sugar Limited as at 31 December were as follows:
2017 2016
N$000 N$ 000
Non-current assets
Property, plant and equipment 2 500 2 300
Goodwill 66 0
2 566 2 300
Current assets
Inventories 1 450 1 200
Trade receivables 1 370 1 100
Cash and cash equivalents 16 50
2 836 2 350 Total Assets 5 402 4 650
13
Equity attributable to equity holders of the parent
Share capital (N$ 1 ordinary share) 1 150 1 000
Share premium account 590 500
Retained earnings 1 791 1 530 3 531 3 030
Non- controlling interest 31 0
3 562 3 030
Current liabilities
Trade payables 1 690 1 520
Income tax payable 150 100
1 840 1 620
Total equity and liabilities 5 402 4 650
The Consolidated Statement of Profit or Loss for the year ended 31 December 2017 was as follows:
Revenue 10 000
Cost of sales (7 500)
Gross profit 2 500
Administrative expenses (2 080)
Profit before tax 420
Income tax expense (150)
Profit for the period 270
Attributable to:
Equity holders of the parent 261
Non- controlling interest 9
270
You are also given the following information:
14
1. All the subsidiary are wholly owned
2. Depreciation charged to the consolidated income statement amounted to
N$210 000
3. There were no disposals of property, plant and equipment during the year
4. No dividend were paid by the parent company
Required
Prepare a Consolidated Statement of Cash flows for the year ended 31 December 2017 under the indirect method in accordance with IAS 7.