Questions
Consider an electrochemical cell involving the overall reaction 2 AgBr(s) + Pb(s) → Pb2+(aq) + 2...

Consider an electrochemical cell involving the overall reaction

2 AgBr(s) + Pb(s) → Pb2+(aq) + 2 Ag(s) + 2 Br–(aq)


Each half-reaction is carried out in a separate compartment. The anion included in the lead half-cell is NO3–. The cation in the silver half-cell is K+. The two half-cells are connected by a KNO3 salt bridge. If [Pb2+] = 1.0 M and [Br-] = 0.14 M, what is the emf of the cell at 298 K?
Given:

AgBr(s) + e– → Ag(s) + Br–(aq)              E° = +0.07 V.

Pb+2 + 2e– → Pb(s)                                E° = - 0.13 V.

In: Chemistry

Cyphers are hundred of years old. Using pseudo code and the a substitution cypher write a...

  1. Cyphers are hundred of years old. Using pseudo code and the a substitution cypher write a function to decode the following message and give the expected solution for the this message

            IUHHKIN NAHKK KBNHT VUOYNG

T

Z

I

J

K

M

W

A

O

P

Q

R

S

Y

U

V

L

H

G

N

E

C

D

B

F

X

A

B

C

D

E

F

G

H

I

J

K

L

M

N

O

P

Q

R

S

T

U

V

W

X

Y

Z

In: Computer Science

There is a region with a constant magnetic field 6.31T . The magnetic field is directed...

There is a region with a constant magnetic field 6.31T . The magnetic field is directed out of the page. A conducting rod moves with a velocity of 1.58m/s , along a V shaped wire that is in the shape of a right triangle. At time = 0 s the rod is at the vertex of the triangle where the angle at the vertex is 19degrees . The right angle is where the conducting rod is. This means the rod is moving along the x axis and the rod is the y axis.

What is the emf induced in the rod after it has moved from the vertex for a time of 10.9s ?

emf = V

What is the current induced in the rod if the resistance is 5.31ohms ?

i = A

What is the power in the rod?

P = W

In: Physics

Below are the control strategy of hydraulic hybrid vehicle. How can I modify code below to...

Below are the control strategy of hydraulic hybrid vehicle. How can I modify code below to include the torque of motor of hydraulic hybrid vehicle? and How can I improve this

function [SOC,k,T_engine,S_engine,T_brake,T_pump] = strategy(duration,gamma,P,V,Pmin,Pmax,Vmin,Vmax,SOC,Disp,T_wheel,S_wheel,gearratio,S_map,Te_max,T_engine,S_engine,T_pm,k,eff_mech,eff_hyd)

S_flywheel = S_wheel*gearratio;
T_flywheel = T_wheel/gearratio;
T_brake = 0;

if SOC < 0.1
k=1; %Engine on
elseif SOC > 0.7
k=0; %Engine off
end

%T_pump +ve = charging
%T-pump -ve = discharging
if k==1
if T_engine*eff_mech < T_flywheel
  
%Engine provides full torque when hydraulic is insufficient to support
if SOC < 0.1
T_engine = T_flywheel/eff_mech;
Tmax = interp1(S_map,Te_max,S_engine);
if T_engine > Tmax
T_engine = Tmax;
end
end
  
T_pump = T_engine*eff_mech-T_flywheel;
  
elseif T_engine*eff_mech >= T_flywheel && T_flywheel >= 0
T_pump = T_engine-T_flywheel/eff_mech;
  
elseif T_engine*eff_mech >= T_flywheel && T_flywheel < 0
T_pump = T_engine-T_flywheel;
end
  
elseif k==0
T_pump = -T_flywheel;
T_engine = 0;
S_engine = 0;
end

%Stop charging when accumulator is full
if SOC >= 1 && T_pump > 0
T_pump = 0;
T_brake = -T_wheel;
end

%Including hydraulic efficiency
if T_pump > 0 %Charging thus real torque is smaller
T_pump = T_pump*eff_hyd;
elseif T_pump < 0 %Discharging thus requires higher real torque
T_pump = T_pump/eff_hyd;
end

%Torque of pump does not exceed its limit
if T_pump >= T_pm
T_brake = (T_pump-T_pm)*gearratio/eff_hyd;
T_pump = T_pm;
elseif T_pump <= -T_pm
T_pump = -T_pm;
T_brake = nan;
end

%Accumulator will charge to full
if SOC > 0.6
Qmax = (V-Vmin)/duration;
x_max = Qmax/(S_flywheel*Disp);
Tmax = P*Disp*x_max;
if T_pump > Tmax
T_pump = Tmax;
if T_brake == 0
T_brake = (T_engine*eff_hyd-T_pump)*gearratio/eff_hyd-T_wheel;
elseif T_brake > 0
T_brake = T_brake+(T_engine*eff_hyd-T_pump)*gearratio/eff_hyd-T_wheel;
end
end
end

x = T_pump/(P*Disp);
Q = S_flywheel*Disp*x*duration;

if Q == 0
SOC = SOC;
else
%V is volume of nitrogen gas; Q is rate of change of fluid pumped
V = V-Q;
SOC = (0.9*((Vmax/V)^gamma)-1)*Pmin/(Pmax-Pmin);
end

In: Mechanical Engineering

The following case study (Rinehart?Thompson) at hypothetical St. John Hospital illustrates numerous issues that the HIPAA...

The following case study (Rinehart?Thompson) at hypothetical St. John Hospital illustrates numerous
issues that the HIPAA privacy rule presents and which HIPAA?covered entities must address on a daily
basis. As you conclude Chapter 9 and the HIPAA privacy rule requirements, use this case study to
identify the issue(s) presented on each date, determining how each situation should be handled in order
to comply with the HIPAA privacy rule.
From May 26?30, Mary Jones was hospitalized in St. John Hospital, located in Johnson County, with
depression and a drug overdose (documented by the physician as possible suicide attempt). She also
had Type I diabetes and a previous above?knee amputation of the right leg, with prosthesis. During her
hospital stay, she had several sessions with her psychiatrist, Dr. Bridges.
On July 18, Ms. Jones contacted the HIM Department at St. John Hospital to request a copy of her
medical records from her May hospital admission. The chart was copied for her by ReadyChart, the
record?copying service utilized by St. John Hospital.
On August 7, Ms. Jones returned to the HIM Department at St. John Hospital, extremely upset that her
May records indicated a possible suicide attempt. She wanted Dr. Bridges to change the incorrect
records to reflect that the overdose was accidental. Dr. Bridges refused, stating that Ms. Jones didn’t
know what she was talking about.
On September 14, Ms. Jones was readmitted to St. John Hospital with an infection of the prosthetic site.
She was treated with an antibiotic regimen.
On October 5, St. John Hospital received a call from Mercy Hospital. Ms. Jones was in the emergency
department there, with a severe infection of her prosthetic site. The nurse in the Mercy Hospital
emergency department asked for faxed copies of medical records from Ms. Jones’ September admission
at St. John, as she was being prepared for immediate surgery.
On October 15, Ms. Jones decided to go to another psychiatrist. She called St. John Hospital HIM
Department and asked that her medical records from her May hospital admission be mailed to Dr. Lyon,
as she has an appointment scheduled with him this coming January. Ms. Jones stated that she had also
changed jobs in September, and her new health insurer was Liberty Life and Health.
On October 30, Ms. Jones requested a copy of her medical records from her September admission. The
new HIM manager in charge of correspondence, Don Day, stated that he was aware of a state statute
that prohibited the release of medical records to patients without prior written approval of their
attending physician. This has not been the practice at St. John Hospital. Mr. Day was concerned about
the hospital’s longstanding violation of state law. He suggested that correspondence requests (in which
records would be released directly to patients) be suspended until the state law could be researched
further.
On November 10, Ms. Jones received a brochure and samples from Comfort Healthcare, a
pharmaceutical company that manufactures ointment for patients with prostheses. Ms. Jones called the
St. John Hospital registration desk to complain. Jessica Carter, a candystriper, took Ms. Jones’ call.
On November 12, Liberty Life and Health submitted a request to Dr. Lyon’s office for copies of Ms.
Jones’ medical records from her May St. John Hospital admission and from Dr. Lyon’s office.
On November 17, A case worker from the Johnson County Children’s Services called the HIM
Department at St. John and requested Ms. Jones’ medical records from her May hospitalization.
Children’s Services had received a complaint that Ms. Jones had an “episode” on May 26 and there was
concern that her children were being subjected to ongoing abuse. As a result, it was initiating an
investigation.
On November 20, the physical therapy department at St. John Hospital is performing a correlational
study to determine the effects of two different types of treatment that the physical therapy department
has used with its above?knee amputation patients during the past two years. Ms. Jones received
treatment from the St. John physical therapy department during her September admission.
On November 21, Dr. King, an orthopedic surgeon, presented a seminar to the state association of
orthopedic surgeons on above?knee amputation techniques. He had performed Ms. Jones’ procedure
one year ago, and he showed slides that compared her condition before the procedure, immediately
after, six months later, and one year later.


Based on the HIPAA privacy rule issues discussed in Chapter 9, identify the issue or issues presented on
each date in the above case study.

In: Nursing

Consider the circuit shown in (Figure 1). Suppose that E = 7.0 V.

Consider the circuit shown in (Figure 1). Suppose that E = 7.0 V .

For the steps and strategies involved in solving a similar problem.

Figure < 1 of 1 5.00 5.00 www. 135.00


Part A 

Find the current through the resistor a 


Part B Find the potential difference across the resistor a 


Part C Find the current through the resistor b. 


Part D Find the potential difference across the resistor b. 


Part E Find the current through the resistor c 


Part F Find the potential difference across the resistor c.


Part G Find the current through the resistor d 


Part H Find the potential difference across the resistor d. 

In: Physics

Total volume of H2 produced, V= Partial Pressure of dry H2=

 

Determination of an Equivalent Mass by Electrolysis

Data

Identity of metal = Copper

Mass of metal anode = 11.167 g

Mass of anode after electrolysis = 10.930 g

Initial buret reading =50 mL

Buret reading after first electrolysis =49.2 mL

Buret reading after refilling = 50 mL

Buret reading after second electrolysis =47.2

Barometric pressure
(1 atm = 1013.25 mbar)

Temperature, T = 328 K


Vapor pressure of H2O at T=

Calculations (show work) Total volume of H2 produced, V=

Partial Pressure of dry H2=

(ignore any pressure effect due to liquid levels in buret)PH2= barometric pressure- PH2O

No. moles H2 produced, n=

Faradays passed (no. of moles of electrons)=

Loss in mass by anode=

Equivalent mass of metal=

mass lost/faradays passed

Molar mass of metal =

Charge, n, on cation=

In: Chemistry

The weight of a 0.6 kg object at the surface of Planet V is 20 N....

The weight of a 0.6 kg object at the surface of Planet V is 20 N. The radius of the planet is 4 X 106 m. Find the gravitational acceleration at a distance of 2.0 X 106 m from the surface of this planet.

9 m/s2

13 m/s2

14.8 m/s2

11 m/s2

In: Physics

How are antibodies unique? Please discuss the structure of an antibody. What are the V and...

How are antibodies unique? Please discuss the structure of an antibody. What are the V and C regions? Discuss how the few hundred genes involved are capable of making endless amounts of antibodies. Besides medical treatment what is another way antibodies can be used?

In: Biology

How are antibodies unique? Please discuss the structure of an antibody. What are the V and...

How are antibodies unique? Please discuss the structure of an antibody. What are the V and C regions? Discuss how the few hundred genes involved are capable of making endless amounts of antibodies. Besides medical treatment what is another way antibodies can be used?

In: Biology