Brand Tar Nicotine CO
American_Filter 16 1.2 15
Benson_&_Hedges 16 1.2
15
Camel 16 1 17
Capri 9 0.8 6
Carlton 1 0.1 1
Cartier_Vendome 8 0.8 8
Chelsea 10 0.8 10
GPC_Approved 16 1 17
Hi-Lite 14 1 13
Kent 13 1 13
Lucky_Strike 13 1.1 13
Malibu 15 1.2 15
Marlboro 16 1.2 15
Merit 9 0.7 11
Newport_Stripe 11 0.9 15
Now 2 0.2 3
Old_Gold 18 1.4 18
Pall_Mall 15 1.2 15
Players 13 1.1 12
Raleigh 15 1 16
Richland 17 1.3 16
Rite 9 0.8 10
Silva_Thins 12 1 10
Tareyton 14 1 17
Triumph 5 0.5 7
True 6 0.6 7
Vantage 8 0.7 11
Viceroy 18 1.4 15
Winston 16 1.1 18
a) Find the regression equation that expresses the response variable (y) of nicotine amount in terms of the predictor variable (x) of the tar amount.
b) Find the regression equation that expresses the response variable (y) of nicotine amount in terms of the predictor variable (x) of the carbon monoxide amount.
c) Find the regression equation that expresses the response variable (y) of nicotine amount in terms of predictor variables (x) of tar amount and carbon monoxide amount.
d) For the regression equations found in parts (a), (b), and (c), which is the best equation for predicting the nicotine amount? Justify your answer.
e) Is the best regression equation identified in part (d) a good equation for predicting the nicotine amount? Why or why not?
In: Statistics and Probability
Eleven students and 14 professors took part in a study to find mean commuting distances. The mean number of miles traveled by students was 5.6 and the standard deviation was 2.8. The mean number of miles traveled by professors was 14.3 and the standard deviation was 9.1. Perform a test of the null hypothesis that the population variances are equal.
In: Statistics and Probability
Find (a) the angular velocity (rad/s) and (b) the linear velocity (miles/hour) of a person standing in Sylmar (latitude 34 degrees north on Earth). Take R of Earth to be 4000 miles.
Ans should be about (a) 7.27 X 10-5 rad/s (b) ~ 900 mi/hr
In: Physics
Q.5. From a sample of 100 tires the mean life time was 46000 miles with a standard deviation of 5500 miles. Test the hypothesis μ = 45000 against the alternate μ > 45000 at (i) 0.05 and (ii) 0.01 level of significance. ?
solve the above problem step by step in proper format
In: Statistics and Probability
Transformers Industry & Technology Inc. is a diversified industrial company. The Company owns businesses providing products & services to the energy, transportation, chemical, and construction sectors.
The energy segment operates as an oil and natural gas contract drilling company the United States. The energy segment acquires, explores, develops, and produces oil and natural gas properties primarily located in Oklahoma and Texas, as well as in Arkansas, Colorado, Kansas, Louisiana, Mississippi, Montana, New Mexico, North Dakota, Utah, and Wyoming. This segment generated over $10 billion of revenue in 2016.
The transportation segment is among the largest public railroad in North America. Operating on 12,000 miles of track in the western one thirds of the U.S., This segment generated over $20 billion of revenue in 2016 by hauling coal, industrial products, intermodal containers, agriculture goods, chemicals, and automotive goods.
The chemical segment sells value-added chemicals, thermoplastic polymers, and other chemical-based products worldwide. This segment develops, produces, and supplies specialty polymers for automotive and medical applications, as well as for use in industrial products and consumer electronics. This segment generated over $5 billion of revenue in 2016.
The Construction segment produces and sells specialty construction chemicals, specialty building materials, and packaging sealants and coatings. The Company operates through two segments: Specialty Construction Chemicals and Specialty Building Materials. The Specialty Construction Chemicals segment manufactures and markets products to manage performance of Portland cement, and materials based on Portland cement, such as concrete admixtures and cement additives, as well as concrete production management systems. The Specialty Building Materials segment manufactures and markets building envelope products, residential building products and specialty construction products. This segment generated over $5 billion of revenue in 2016.
During the last few years, Transformers Industry has been too constrained by the high cost of capital to make many capital investments. Recently, though, capital costs have been declining, and the company has decided to look seriously at a major expansion program that has been proposed by the marketing department. The expansion requires investment in eight projects from the four segments. Table-1 provides information about the projects.
Assume that you are an assistant to Jim Jones, the financial vice president. Your first task is to estimate Transformers cost of capital.
As a part of your analysis you have collected the following data:
The firm's tax rate is 40%.
The current price of Transformers 12% coupon, semiannual payment, non-callable bonds with 15 years remaining to maturity is $1,153.72. TPIT does not use short-term interest-bearing debt on a permanent basis. New bonds would be privately placed with no flotation cost.
The current price of the firm’s 10%, $100 par value, quarterly dividend, perpetual preferred stock is $116.95. Transformers would incur flotation costs equal to 5% of the proceeds on a new issue.
Transformers common stock is currently selling at $50 per share. Its last dividend was $3.12, and dividends are expected to grow at a constant rate of 5.8% in the foreseeable future. Transformers beta is 1.2, the yield on T-bonds is 5.6%, and the market risk premium is estimated to be 6%.
Suppose the firm has historically earned 15% on equity (ROE) and retained 35% of earnings, and investors expect this situation to continue in the future. How could you use this information to estimate the future dividend growth rate, and what growth rate would you get? Is this consistent with the 5.8% growth rate given earlier?
Transformers target capital structure is 30% long-term debt, 10% preferred stock, and 60% common equity.
Suggested questions
1) What sources of capital should be included when you estimate Transformers weighted average cost of capital (WACC)?
2) Should the component costs be figured on a before-tax or an after-tax basis?
3) Should the costs be historical (embedded) costs or new (marginal) costs? Explain?
4) Transformers preferred stock is riskier to investors than its debt, yet the preferred yield to investors is lower than the yield to maturity on the debt. Does this suggest that you have made a mistake? (Hint: Think about taxes.)
5) What is the market interest rate on Transformers debt and what is the component cost of this debt for WACC purposes?
6) What is the corporate cost of capital?
Part 2
1) Jim Jones was worried that whether the corporate cost of capital would be appropriate to evaluate the four segments’ project. His concern centered on whether the risk of the projects is reflected on the corporate cost of capital? What is the logical method of adjusting the cost of capital for risk? Is it wise to use the corporate cost of capital to evaluate the four segments’ projects?
2) Discuss the quantitative methods that are useful to evaluate the projects?
3) Discuss the strengths and weakness of each quantitative method you have selected to evaluate the projects?
4) Will all of the quantitative methods rank the projects identically? Why or why not?
5) Rank the projects on the basis of the measurements discussed above.
|
Annual cash flows: |
Annual cash flows: |
Annual cash flows: |
Annual cash flows: |
|||||
|
Energy |
Transportation |
Chemical |
Construction |
|||||
|
Year |
EA |
EB |
TC |
TD |
CHE |
CHF |
ConG |
ConF |
|
0 |
($1,500,000) |
($1,500,000) |
$ (650,000) |
($200,000) |
($350,000) |
($300,000) |
($200,000) |
($200,000) |
|
1 |
$450,000 |
$440,000 |
$ 210,000 |
$97,000 |
$144,000 |
$43,000 |
$88,500 |
$101,000 |
|
2 |
$650,000 |
$440,000 |
$ 210,000 |
$97,000 |
$144,000 |
$98,000 |
$91,000 |
$78,000 |
|
3 |
$650,000 |
$440,000 |
$ 210,000 |
$97,000 |
$144,000 |
$152,000 |
$88,000 |
$87,000 |
|
4 |
$440,000 |
$540,000 |
$ 210,000 |
$97,000 |
$144,000 |
$168,000 |
$88,000 |
$87,000 |
|
5 |
$330,000 |
$540,000 |
$ 210,000 |
$97,000 |
$144,000 |
$184,000 |
$88,000 |
$87,000 |
|
6 |
$250,000 |
$540,000 |
$ 210,000 |
$97,000 |
$144,000 |
$200,000 |
$88,000 |
$87,000 |
|
Comparable Companies- Energy |
Market Cap Mil |
Net Income Mil |
Interest Coverage |
D/E |
Equity Beta |
|
Unit Corp |
1,346 |
30 |
— |
0.6 |
1.2 |
|
Omv AG (USD,EUR) |
21,927 |
-151 |
-0.9 |
0.4 |
0.6 |
|
Omv AG (USD,EUR) |
21,927 |
-151 |
-0.9 |
0.4 |
0.6 |
|
Helmerich & Payne Inc (USD) |
7,725 |
-128 |
-8.3 |
0.1 |
0.4 |
|
RSP Permian Inc (USD) |
6,553 |
92 |
0.2 |
0.4 |
0.5 |
|
Patterson-UTI Energy Inc (USD) |
5,445 |
-267 |
-11.3 |
0.2 |
0.3 |
|
Transocean Ltd (USD) |
4,538 |
-2,773 |
3.3 |
0.5 |
0.5 |
|
Ensco PLC (USD) |
2,998 |
-57 |
5.4 |
0.6 |
0.8 |
|
Diamond Offshore Drilling Inc (USD) |
2,693 |
166 |
-4.2 |
0.5 |
1 |
|
Ocean Rig UDW Inc (USD) |
2,614 |
-3,809 |
-14.2 |
0.2 |
0.75 |
|
Nabors Industries Ltd (USD) |
2,581 |
-766 |
-5.5 |
1.4 |
1.3 |
|
Rowan Companies PLC (USD) |
2,009 |
-63 |
3.1 |
0.5 |
0.8 |
|
CES Energy Solutions Corp (USD,CAD) |
1,325 |
29 |
-1.6 |
0.7 |
0.9 |
|
Noble Corp PLC (USD) |
1,249 |
-1,794 |
-3.3 |
0.7 |
0.85 |
|
SONGA OFFSHORE SE (USD) |
1,062 |
-40 |
0.6 |
2.3 |
1.5 |
|
Ensign Energy Services Inc (USD,CAD) |
957 |
-146 |
-5.6 |
0.4 |
0.55 |
|
Sabine Royalty Trust (USD) |
708 |
33 |
— |
— |
0.3 |
|
Trinidad Drilling Ltd (USD,CAD) |
398 |
-73 |
-0.8 |
0.4 |
0.25 |
|
Seadrill Partners LLC (USD) |
346 |
216 |
4.5 |
2.5 |
1.8 |
|
Pioneer Energy Services Corp (USD) |
287 |
-98 |
-4.4 |
1.8 |
1.35 |
|
Archer Ltd (USD) |
219 |
-2 |
-1.6 |
2.9 |
1.8 |
|
Fred Olsen Energy ASA (USD) |
201 |
-185 |
-1.1 |
1 |
0.85 |
|
Fred Olsen Energy ASA (USD) |
201 |
-185 |
-1.1 |
1 |
0.75 |
|
Independence Contract Drilling Inc (USD) |
197 |
-28 |
-6.2 |
0.2 |
0.3 |
|
Pantheon Resources PLC (USD) |
171 |
-1 |
— |
— |
0.5 |
|
Xtreme Drilling Corp (USD,CAD) |
138 |
-82 |
-18 |
— |
0.5 |
|
Industry Average |
1,779 |
1 |
-522.2 |
0.6 |
|
Comparable Companies- Transportation |
Market Cap Mil |
Net Income Mil |
Interest Coverage |
D/E |
Equity Beta |
|
Union Pacific Corp |
110,542 |
4,578 |
10.7 |
0.8 |
1.06 |
|
Canadian National Railway Co (USD,CAD) |
60,016 |
3,891 |
11.3 |
0.6 |
0.85 |
|
CSX Corp (USD) |
51,880 |
1,789 |
5.7 |
1.1 |
1.33 |
|
Norfolk Southern Corp (USD) |
43,898 |
1,852 |
5.6 |
0.7 |
1.54 |
|
East Japan Railway Co (USD,JPY) |
39,937 |
291,733 |
6.8 |
0.9 |
0.9 |
|
Central Japan Railway Co (USD,JPY) |
37,319 |
398,785 |
10.3 |
1.5 |
0.43 |
|
Canadian Pacific Railway Ltd (USD,CAD) |
26,283 |
1,805 |
5.6 |
1.3 |
1.14 |
|
Kansas City Southern (USD) |
11,545 |
539 |
7.8 |
0.5 |
0.73 |
|
Westinghouse Air Brake Technologies Corp (USD) |
7,856 |
251 |
— |
0.7 |
0.92 |
|
Guangshen Railway Co Ltd (USD,CNY) |
5,652 |
952 |
— |
— |
1.37 |
|
Industry Average |
13,429 |
29,956 |
15.9 |
0.8 |
|
Comparable Companies- Chemical |
Market Cap Mil |
Net Income Mil |
Interest Coverage |
D/E |
Equity Beta |
|
Eastman Chemical Co |
13,917 |
1,009 |
4.7 |
1.3 |
1.21 |
|
A. Schulman Inc (USD) |
1,128 |
44 |
1.6 |
4.2 |
1.84 |
|
Asahi Kasei Corp (USD,JPY) |
18,510 |
132,954 |
36.5 |
0.2 |
0.3 |
|
Ashland Global Holdings Inc (USD) |
4,540 |
1 |
0.6 |
0.8 |
1.31 |
|
Balchem Corp (USD) |
2,583 |
64 |
12.4 |
0.4 |
0.5 |
|
Basf SE (USD,EUR) |
108,362 |
5,230 |
9.2 |
0.4 |
1.03 |
|
Bio-En Holdings Corp (USD) |
129 |
0 |
-27.9 |
— |
-0.63 |
|
BioAmber Inc (USD) |
23 |
-24 |
-8.8 |
0.2 |
3.16 |
|
Industry Average |
11,925 |
29,851 |
125.4 |
0.5 |
1.09 |
|
Market Cap Mil |
Net Income Mil |
Interest Coverage |
D/E |
Equity Beta |
|
|
Vulcan Materials Co |
17,862 |
386 |
5.1 |
0.6 |
0.91 |
|
Daikin Industries Ltd (USD,JPY) |
36,579 |
159,019 |
24.3 |
0.3 |
0.83 |
|
Compagnie de Saint-Gobain SA (USD,EUR) |
32,398 |
1,311 |
5.7 |
0.4 |
0.39 |
|
CRH PLC (USD,EUR) |
30,435 |
1,327 |
6.2 |
0.6 |
0.96 |
|
Masco Corp (USD) |
14,438 |
544 |
4.6 |
— |
1.45 |
|
Martin Marietta Materials Inc (USD) |
14,267 |
435 |
8.4 |
0.4 |
1.32 |
|
Cemex SAB de CV (USD,MXN) |
11,943 |
21,512 |
1.8 |
1.1 |
1.35 |
|
Owens-Corning Inc (USD) |
10,682 |
379 |
— |
0.6 |
0.73 |
|
Asahi Glass Co Ltd (USD,JPY) |
10,275 |
75,138 |
10.1 |
0.3 |
0.5 |
|
James Hardie Industries PLC (USD) |
9,465 |
256 |
13.9 |
— |
1.4 |
|
Industry Average |
18834.4 |
26030.7 |
8.9 |
0.5375 |
In: Finance
For a car that travels 70 mph for 60 miles and then 80 mph for 60 miles. The total time traveled is given by calculating the distance per rate traveled for each part and then summing the values. •Have the program in c++ that calculates the most appropriate mean rate of the two different rates and the two equal distances, and output the result to the text file. The “best” mean rate is the rate at which T=D/R is same as if you did it separately where D is the total distance. Output all the data to the text file (include expected results on the display screen).•Example: The program should print something like•A car travels 40mph for 10 miles and 50 mph for 10 miles.•The total time traveled given by T=D1/R1 + D2/R2 is [your answer].•The best mean rate R is [your answer].•The total time given by this mean and T=D/R is [your answer]
In: Computer Science
(in java) Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMiles. Sample output for the given program:
Min miles: -10
Max miles: 40
given code below (please bold the solution, thank you!)
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_ROWS = 2;
final int NUM_COLS = 2;
int [][] milesTracker = new int[NUM_ROWS][NUM_COLS];
int i;
int j;
int maxMiles; // Assign with first element in milesTracker before
loop
int minMiles; // Assign with first element in milesTracker before
loop
for (i = 0; i < milesTracker.length; i++){
for (j = 0; j < milesTracker[i].length; j++){
milesTracker[i][j] = scnr.nextInt();
}
}
/* Your solution goes here */
System.out.println("Min miles: " + minMiles);
System.out.println("Max miles: " + maxMiles);
}
}
In: Computer Science
Program 3.5 - Conversion Program - NOW using cin statements to gather input from user
Concepts Covered: Chapter 2 – cout , math, data types, Chapter 3 , gathering both numeric & string input from user
Programs 2-21, 2-22, 2-23, 2-28 should help with math and programs 3.5, 3.17 and 3.19 should help you with the new concepts introduced with this program.
Program Purpose: To help you understand the concept of using both proper numeric variables and string variables. To give you practice using the C++ math operators. To give you practice getting both numeric input and string input from a user. To give you practice overriding the default behavior of C++ for numeric formatting. Lastly, to appreciate the flexibility of the cout object by passing it string variables, string literals, and numeric variables.
Background: Your instructor is an avid (some would say obsessed) bicyclist. Rides of 40 to 50 miles are not uncommon. Your instructor also uses an indoor training program called Zwift. It uses the metric system which is kilometers biked (instead of miles), and meters climbed (instead of feet). You need to help out your metrically challenged professor and write a conversion program that converts kilometers to miles and meters to feet.
For example, if I told some of my non-biking friends that I rode 40 kilometers, many of them would be impressed. Well, in miles that is only 24.8 miles. Conversely, if I told them I climbed 1000 meters they may not be impressed. But, 1000 meters is 3,280 feet which is not too shabby here in the Midwest.
Oh, did I mention, this also applies to runners, especially in terms of kilometers.
So your job commission is to write a C++ program which will convert kilometers to miles and meters to feet.
PROGRAM SPECIFICATIONS:
Insert program heading with your name, course, section, program name, AS WELL AS brief documentation of program purpose at the top of your program.
Create your c++ code.
INPUT SECTION
Create 4 numeric variables to hold the following: meters, feet, kilometers, and miles.
Create 2 string variables: one to hold the activity type: biking or running and the other to hold a person’s name.
Prompt the user for their name. You should get the user's full name! Example Jimmy C or John Bonham
Prompt the user (using their name) for which activity they did. - biking or running
Prompt the user for how many kilometers
Prompt the user for how many meters they climbed
PROCESSING SECTION
Perform the necessary math operations to convert kilometers to miles and meters to feet.
Kilometers to miles formula:
1 kilometer is equal to 0.621371 miles (often shortened to .62). 1 mile is equal to 1.609344 kilometers. Thus, to convert kilometers to miles, simply multiply the number of kilometers by 0.62137.
Meters to feet formula:
Multiply any meter measurement by 3.28 to convert to feet. Since one meter = 3.28 feet, you can convert any meter measurement into feet by multiplying it by 3.28.
1 meter x 3.28 = 3.28 feet
5 meters x 3.28 = 16.4 feet
2.7 meters x 3.28 = 8.856 feet
OUTPUT SECTION
Using cout statements, display the output listing name, activity, kilometers, miles, meters and feet. For formatting of numeric variables, use 2 digits of precision to right of decimal point.with values shown above.
In: Computer Science
A research firm tests the miles-per-gallon characteristics of three brands of gasoline. Because of different gasoline performance characteristics in different brands of automobiles, five brands of automobiles are selected and treated as blocks in the experiment; that is, each brand of automobile is tested with each type of gasoline. The results of the experiment (in miles per gallon) follow.
| Gasoline Brands | ||||
|---|---|---|---|---|
| I | II | III | ||
| Automobiles | A | 18 | 21 | 20 |
| B | 24 | 26 | 27 | |
| C | 30 | 28 | 34 | |
| D | 22 | 25 | 24 | |
| E | 20 | 23 | 24 | |
(a)At α = 0.05, is there a significant difference in the mean miles-per-gallon characteristics of the three brands of gasoline?
State the null and alternative hypotheses.
H0: At least two of the population means are
equal.
Ha: At least two of the population means are
different.
H0: μI ≠
μII ≠ μIII
Ha: μI =
μII =
μIII
H0: μI =
μII = μIII
Ha: μI ≠
μII ≠ μIII
H0: Not all the population means are
equal.
Ha: μI =
μII = μIII
H0: μI =
μII = μIII
Ha: Not all the population means are equal.
Find the value of the test statistic. (Round your answer to two decimal places.)
=
Find the p-value. (Round your answer to three decimal places.)
p-value =
State your conclusion.
Do not reject H0. There is sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
Do not reject H0. There is not sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
Reject H0. There is not sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
Reject H0. There is sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
(b) Analyze the experimental data using the ANOVA procedure for completely randomized designs. (Use α = 0.05.)
Find the value of the test statistic. (Round your answer to two decimal places.)
=
Find the p-value. (Round your answer to three decimal places.)
p-value =
State your conclusion.
Do not reject H0. There is sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
Reject H0. There is not sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
Do not reject H0. There is not sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
Reject H0. There is sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
Compare your findings with those obtained in part (a).
The conclusion is the same as the conclusion in part (a).
The conclusion is different from the conclusion in part (a).
What is the advantage of attempting to remove the block effect?
There is no advantage to removing the block effect because the conclusion is the same in either case.
We must remove the block effect in order to detect that there is a significant difference due to the brand of gasoline.
We must remove the block effect in order to detect that there is no significant difference due to the brand of gasoline.
In: Statistics and Probability
A research firm tests the miles-per-gallon characteristics of three brands of gasoline. Because of different gasoline performance characteristics in different brands of automobiles, five brands of automobiles are selected and treated as blocks in the experiment; that is, each brand of automobile is tested with each type of gasoline. The results of the experiment (in miles per gallon) follow.
| Gasoline Brands | ||||
|---|---|---|---|---|
| I | II | III | ||
| Automobiles | A | 19 | 21 | 20 |
| B | 24 | 26 | 27 | |
| C | 30 | 29 | 34 | |
| D | 22 | 25 | 24 | |
| E | 20 | 23 | 24 | |
(a)
At α = 0.05, is there a significant difference in the mean miles-per-gallon characteristics of the three brands of gasoline?
State the null and alternative hypotheses.
H0: μI =
μII = μIII
Ha: Not all the population means are
equal.H0: At least two of the population means
are equal.
Ha: At least two of the population means are
different. H0:
μI = μII =
μIII
Ha: μI ≠
μII ≠
μIIIH0: Not all the
population means are equal.
Ha: μI =
μII =
μIIIH0:
μI ≠ μII ≠
μIII
Ha: μI =
μII = μIII
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to three decimal places.)
p-value =
State your conclusion.
Do not reject H0. There is not sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.Reject H0. There is sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal. Do not reject H0. There is sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.Reject H0. There is not sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
(b)
Analyze the experimental data using the ANOVA procedure for completely randomized designs. (Use α = 0.05.)
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to three decimal places.)
p-value =
State your conclusion.
Reject H0. There is sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.Reject H0. There is not sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal. Do not reject H0. There is sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.Do not reject H0. There is not sufficient evidence to conclude that the mean miles-per-gallon ratings for the three brands of gasoline are not all equal.
Compare your findings with those obtained in part (a).
The conclusion is the same as the conclusion in part (a).The conclusion is different from the conclusion in part (a).
What is the advantage of attempting to remove the block effect?
We must remove the block effect in order to detect that there is no significant difference due to the brand of gasoline.There is no advantage to removing the block effect because the conclusion is the same in either case. We must remove the block effect in order to detect that there is a significant difference due to the brand of gasoline.
In: Statistics and Probability