Questions
The average final exam score for the statistics course is 76%. A professor wants to see...

The average final exam score for the statistics course is 76%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is higher. The final exam scores for the 16 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal.

86, 97, 69, 93, 85, 88, 99, 67, 91, 85, 73, 66, 100, 90, 71, 82

What can be concluded at the the αα = 0.05 level of significance level of significance?

  1. For this study, we should use Select an answer z-test for a population proportion t-test for a population mean
  2. The null and alternative hypotheses would be:

H0:H0:  ? μ p  ? > = < ≠       

H1:H1:  ? p μ  ? < = ≠ >    

  1. The test statistic ? z t  =  (please show your answer to 3 decimal places.)
  2. The p-value =  (Please show your answer to 4 decimal places.)
  3. The p-value is ? > ≤  αα
  4. Based on this, we should Select an answer accept reject fail to reject  the null hypothesis.
  5. Thus, the final conclusion is that ...
    • The data suggest that the population mean final exam score for students who are given colored pens at the beginning of class is not significantly higher than 76 at αα = 0.05, so there is statistically insignificant evidence to conclude that the population mean final exam score for students who are given colored pens at the beginning of class is higher than 76.
    • The data suggest the populaton mean is significantly higher than 76 at αα = 0.05, so there is statistically significant evidence to conclude that the population mean final exam score for students who are given colored pens at the beginning of class is higher than 76.
    • The data suggest the population mean is not significantly higher than 76 at αα = 0.05, so there is statistically insignificant evidence to conclude that the population mean final exam score for students who are given colored pens at the beginning of class is equal to 76.

In: Statistics and Probability

The average final exam score for the statistics course is 74%. A professor wants to see...

The average final exam score for the statistics course is 74%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is lower. The final exam scores for the 12 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal.

79, 60, 52, 72, 67, 47, 54, 79, 61, 80, 80, 47

What can be concluded at the the αα = 0.10 level of significance level of significance?

For this study, we should use Select an answer t-test for a population mean z-test for a population proportion

The null and alternative hypotheses would be:

H0:H0:  ? p μ  Select an answer ≠ > = <       

H1:H1:  ? μ p  Select an answer ≠ > = <    

The test statistic ? t z  =  (please show your answer to 3 decimal places.)

The p-value =  (Please show your answer to 4 decimal places.)

The p-value is ? > ≤  αα

Based on this, we should Select an answer accept reject fail to reject  the null hypothesis.

Thus, the final conclusion is that ...

The data suggest that the population mean final exam score for students who are given colored pens at the beginning of class is not significantly lower than 74 at αα = 0.10, so there is statistically insignificant evidence to conclude that the population mean final exam score for students who are given colored pens at the beginning of class is lower than 74.

The data suggest the population mean is not significantly lower than 74 at αα = 0.10, so there is statistically insignificant evidence to conclude that the population mean final exam score for students who are given colored pens at the beginning of class is equal to 74.

The data suggest the populaton mean is significantly lower than 74 at αα = 0.10, so there is statistically significant evidence to conclude that the population mean final exam score for students who are given colored pens at the beginning of class is lower than 74.

In: Statistics and Probability

1. The null and alternative hypotheses are given. Determine whether the parameter that is being tested....

1. The null and alternative hypotheses are given. Determine whether the parameter that is being tested.

Parameter: (Population mean, Population proportion, Sample mean, Sample proportion)

a. H0: μ = 9.5
H1: μ ≠ 9.5   

b. H0: p =0.05
H1: p < 0.05

1.B) A referendum for an upcoming election is favored by more than half of the voters.

1. Is this about a mean or a proportion?

a. proportion

b. mean

2. Identify the null hypothesis, the alternative hypothesis for a hypothesis test of this statement.

Ho: p

a. = 0.50

b. < 0.50

c. > 0.50

H1: p

a. > 0.50

b. = 0.50

c. < 0.50

Save your answers for the next question.

1.C) The dean of a major university claims that the mean number of hours students study at her University (per day) is 3.2 hours. If a hypothesis test is performed, how should you interpret a decision that rejects the null hypothesis?

*In the last question I gave you the null and alternative hypotheses, write the correct hypotheses in this question and then answer appropriately.

a. There is not sufficient evidence to reject the claim μ = 3.2.

b. There is not sufficient evidence to support the claim μ ≤ 3.2.

c. There is sufficient evidence to reject the claim μ = 3.2.

d. There is sufficient evidence to support the claim μ = 3.2.

1.D) A 4-year college claims that the percentage of their students that graduate on time is 91.3%.

A student decides to test this claim with the following hypothesis test.

Ho: p = 0.913

H1: p ≠0.913

With respect to the situation described in this problem, what is a type 1 error?

a. The evidence suggests that the percentage of students that graduate on time is 91.3%, but in fact the percentage is equal to 91.3%

b. The evidence suggests that the percentage of students that graduate on time is equal to 91.3%, but in fact it is different than 91.3%.

c. The evidence suggests that the percentage of students that graduate on time is different than 91.3%, but in fact it is less than 91.3%.

d. The evidence suggests that the percentage of students that graduate on time is equal to 91.3%, but in fact it is greater than 91.3%

In: Statistics and Probability

1. A trainer is studying the effects of vitamin D on his athletes. He has realized...

1. A trainer is studying the effects of vitamin D on his athletes. He has realized that there are many potential confounding factors, such as gender and age. To limit the effect of these confounding variables, he decided to first group two athletes together based on these variables (for example, two 21-year-old males). Then he randomly assigned one person to receive the vitamin D and the other to receive a sugar pill.

What type of experimental design does this situation demonstrate?

  • Matched-Pair Design

  • Randomized Block Design

  • Completely Randomized Design

  • Simple Random Design

2. Jay wants to study nutrition and performance in schools using available data.

Which of the scenarios below will provide Jay with available data?

  • Going to a local high school and asking the principal for information about students' previous grades, then interviewing a random selection of students about their eating habits.

  • Going to a local high school and asking the principal for information about students' current and previous grades, then asking the health teacher for the results from a survey students took in health class.

  • Going to a local high school and asking the principal for information about students' current and previous grades, then interviewing a random selection of students about their eating habits.

  • Going to a local college and asking current undergraduates to report their grades and eating habits from high school.

3. Dave drives to work. While driving the car over nine days, he observes his daily average speed and lists it in the table below.

Day Average Speed
(MPH)
1 45
2 62
3 44
4 70
5 59
6 66
7 54
8 63
9 67

The median speed at which Dave drove to work was __________.

  • 59 miles per hour

  • 63 miles per hour

  • 58.89 miles per hour

  • 62 miles per hour

In: Statistics and Probability

Question Set 1: Two Independent Proportions Reminder: The standard error is computed differently for a two-sample...

Question Set 1: Two Independent Proportions

Reminder: The standard error is computed differently for a two-sample proportion confidence interval and a two-sample proportion hypothesis test.

Researchers are comparing the proportion of University Park students who are Pennsylvania residents to the proportion of World Campus students who are Pennsylvania residents. Data from a sample are presented in the contingency table below.

Primary Campus

Total

University Park

World Campus

Pennsylvania Resident

Yes

115

70

185

No

86

104

190

Total

201

174

375

  1. Construct a 95% confidence interval to estimate the difference between the proportion of all University Park students who are Pennsylvania residents and the proportion of all World Campus students who are Pennsylvania residents. If assumptions are met, use the normal approximation method. Show how you checked assumptions. You should not need to do any hand calculations. Use Minitab Express to construct the confidence interval. Remember to copy+paste all relevant Minitab Express output and always clearly identify your final answer. [15 points]

B. Interpret the confidence interval that you computed in part A by completing the following sentence. [5 points]

I am 95% confident that…

C. Use the five-step hypothesis testing procedure given below to determine if there is evidence of a difference between the proportion of University Park students who are Pennsylvania residents and the proportion of World Campus students who are Pennsylvania residents. If assumptions are met, use the normal approximation method. Use Minitab Express. You should not need to do any hand calculations. Remember to copy+paste all relevant Minitab Express output. [30 points]

Step 1: Check assumptions and write hypotheses

Step 2: Calculate the test statistic

Step 3: Determine the p-value

Step 4: Decide to reject or fail to reject the null hypothesis

Step 5: State a real-world conclusion

In: Statistics and Probability

Directions Use the Chi-Square option in the Nonparametric Tests menu to answer the questions based on...

Directions Use the Chi-Square option in the Nonparametric Tests menu to answer the questions based on the following scenario. (Assume a level of significance of .05 and use information from the scenario to determine the expected frequencies for each category).

Scenario

During the analysis of the district data, it was determined that one high school had substantially higher Graduate Exit Exam scores than the state average and the averages of high schools in the surrounding districts. To better understand possible reasons for this difference, the superintendent conducted several analyses. One analysis examined the population of students who completed the exam. Specifically, the superintendent wanted to know if the distribution of special education, regular education, and gifted/talented test takers from the local high school differed from the statewide distribution. The obtained data are provided below.

Description

Number of students from local high school who took the graduate exam.

Special Education (10) Regular Education (104) Gifted/Talented (26)

Percent of test-taking students state wide who took the graduate exam

Special Education (7) Regular Education (77) Gifted/Talented (16)

1. If the student distribution for the local high school did not differ from the state, what would be the expected percentage of students in each category?

2. What were the actual percentages of local high school students in each category? (Report final answer to two decimal places)

3. State an appropriate null hypothesis for this analysis.

4. What is the value of the chi-square statistic?

5. What are the reported degrees of freedom?

6. What is the reported level of significance?

7. Based on the results of the one-sample chi-square test, was the population of test taking students at the local high school statistically significantly different from the statewide population?

8. Present the results as they might appear in an article. This must include a table and narrative statement that reports and interprets the results of the analysis.

In: Statistics and Probability

David Anderson has been working as a lecturer at Michigan State University for the last three...

David Anderson has been working as a lecturer at Michigan State University for the last three years. He teaches two large sections of introductory accounting every semester. While he uses the same lecture notes in both sections, his students in the first section outperform those in the second section. He believes that students in the first section not only tend to get higher scores, they also tend to have lower variability in scores. David decides to carry out a formal test to validate his hunch regarding the difference in average scores. In a random sample of 20 students in the first section, he computes a mean and a standard deviation of 85.2 and 25.9, respectively. In the second section, a random sample of 21 students results in a mean of 85.0 and a standard deviation of 1.18.

Sample 1 consists of students in the first section and Sample 2 represents students in the second section.

a.

Construct the null and the alternative hypotheses to test David’s hunch.

H0: μ1μ2 = 0; HA: μ1μ2 ≠ 0
H0: μ1μ2 ≥ 0; HA: μ1μ2 < 0
H0: μ1μ2 ≤ 0; HA: μ1μ2 > 0
b-1.

Calculate the value of the test statistic. (Round all intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)

  Test statistic   
b-2. What assumption regarding the population variances is used to conduct the test?
Known population standard deviations.
Unknown population standard deviations that are equal
Unknown population standard deviations that are not equal
c. Implement the test at α = 0.10 using the critical value approach.
Reject H0; there is evidence that scores are higher in the first section.
Reject H0; there is no evidence that scores are higher in the first section.
Do not reject H0; there is evidence that scores are higher in the first section.
Do not reject H0; there is no evidence that scores are higher in the first section.

In: Statistics and Probability

1. ) An instructor believes that students do not retain as much information from a lecture...

1. ) An instructor believes that students do not retain as much information from a lecture on a Friday compared to a Monday. To test this belief, the instructor teaches a small sample of college students some preselected material from a single topic on statistics on a Friday and on a Monday. All students received a test on the material. The differences in exam scores for material taught on Friday minus Monday are listed in the following table.

Difference Scores
(Friday − Monday)

+3.3

+4.5

+6.3

+1.1

−1.7

(a) Find the confidence limits at a 95% CI for these related samples. (Round your answers to two decimal places.)
to

(b) Can we conclude that students retained more of the material taught in the Friday class?

Yes, because 0 lies outside of the 95% CI.No, because 0 is contained within the 95% CI.    

2;) Listening to music has long been thought to enhance intelligence, especially during infancy and childhood. To test whether this is true, a researcher records the number of hours that eight high-performing students listened to music per day for 1 week. The data are listed in the table.

Music Listening Per
Day (in hours)
4.1
4.8
4.9
3.7
4.3
5.6
4.1
4.3

(a) Find the confidence limits at a 95% CI for this one-independent sample. (Round your answers to two decimal places.)
to  hours per day

(b) Suppose the null hypothesis states that students listen to 3.5 hours of music per day. What would the decision be for a two-tailed hypothesis test at a 0.05 level of significance?

Retain the null hypothesis because the value stated in the null hypothesis is within the limits for the 95% CI.Reject the null hypothesis because the value stated in the null hypothesis is outside the limits for the 95% CI.    Reject the null hypothesis because the value stated in the null hypothesis is within the limits for the 95% CI.Retain the null hypothesis because the value stated in the null hypothesis is outside the limits for the 95% CI.

In: Math

Journal entries The Research & Development Department of Large Mart is currently working on the development...

Journal entries

The Research & Development Department of Large Mart is currently working on the development of a “study pillow” that allows students to upload study material into their brain whilst sleeping. In order to complete this project, Large Mart has purchased the following items:

• A minibus (which is used to transport students participating in a trial of the study pillow to the laboratory)

• A video camera (which is used to record the feedback of students participating in the trial)

The minibus was purchased on credit on 10th April 201x. The list price of the minibus was $90,000, but Large Mart received a 10% loyalty discount because the company purchases all of its motor vehicles from this car dealer. The car dealer also charged $2,000 to deliver the minibus to the Large Mart Research & Development Department.

Large Mart received the minibus on 12th April, and Large Mart started to use the minibus on that day. The invoice (for the purchase price as well as the delivery charges) from the car dealer was paid on 1st May 201x and Large Mart received an early payment discount of 5% when the payment was made.

Large Mart expects to use the minibus for a period of 5 years. At the end of its useful life, the minibus is expected to have a residual value of $8,000. The depreciation method used for the minibus is identical to the method that Large Mart is using for other motor vehicles (straight-line depreciation).

On 1st July 201x, the accounting department of Large Mart decides to revalue the minibus to its fair value at that time of $75,000.

The video camera was purchased in a cash transaction on 1st May 201x. Large Mart paid a total of $3,000 for the camera. After unpacking the camera on 2nd May 201x, Large Mart noticed that the camera was broken. Large Mart returned the camera to the supplier and the supplier has promised to return the funds that were originally paid by Large Mart to Large Mart’s bank account on the following day.

Required:

1) (0.5 marks) – Provide all journal entries that are necessary in the books of Large Mart to account for the purchase of the video camera on 1st May 201x as well as the return of the camera to the supplier on 2nd May 201x.

2) (1 mark) – Provide all journal entries that are necessary in the books of Large Mart to account for the purchase of the minibus as well as its payment.

3) (1.5 marks) – Provide all journal entries that are necessary in the books of Large Mart to account for the revaluation of the minibus on 1st July 201x.

Please help me to solve this question. It's very urgent.

In: Accounting

The Research & Development Department of Large Mart is currently working on the development of a...

The Research & Development Department of Large Mart is currently working on the development of a “study pillow” that allows students to upload study material into their brain whilst sleeping. In order to complete this project, Large Mart has purchased the following items:

A car (which is used to transport students participating in a trial of the study pillow to the laboratory)

A notebook computer (which is used to record the feedback of students participating in the trial)

The car was purchased on credit on 11th May 201x. The cost of the car was $45,000. Large Mart received the car on 20th May but before Large Mart was able to start using the car, a special in car computer system that connects the car to the Large Mart server (called the intersect) was installed for a total cost of $2,000. After installing the special in car computer, Large Mart was able to start using the car on the 25th May. The car was paid on 31th May 201x and Large Mart received an early payment discount of 5% when the payment was made.

Large Mart expects to use the car for a period of 5 years. At the end of its useful life, the car is expected to have a residual value of $1,000. The depreciation method used for the car is the declining balance method of depreciation. Large Mart calculates the declining balance depreciation percentage of this car in the same way it calculates all of its declining balance percentages.

On 1st July 201x, the accounting department of Large Mart decides to revalue the car to its fair value of $49,000.

The notebook computer was purchased on credit (and received) on 1st May 201x. The computer had a list price of $5,000. However, because Large Mart purchases all of its notebook computers from this supplier, Large Mart was able to receive a “volume discount” of 10%. As a result, the supplier only sent Large Mart an invoice for $4,500. Large Mart paid the computer on 5th May after deducting an early payment discount of 5%.

Required:

1)     (0.5 marks) – Provide all journal entries that are necessary in the books of Large Mart to account for the purchase and payment of the notebook computer.

2)     (1 mark) – Provide all journal entries that are necessary in the books of Large Mart to account for the depreciation of the car for the month of May 201x AND provide a detailed outline of all required calculations

3)     (1.5 marks) – Provide all journal entries that are necessary in the books of Large Mart to account for the revaluation of the car on 1st July 201x AND provide a detailed outline of all required calculations.

In: Accounting