Questions
(A) How many moles (of molecules or formula units) are in each sample? And please explain...

(A) How many moles (of molecules or formula units) are in each sample? And please explain how the answer is found.

1) 20.0 g NO2

2) 1.35 kg CO2

3) 40.4 g KNO3

4) 102.3 kg Na2SO4

(B) How many molecules (or formula units) are in each sample? And please show how to find answer

1) 52.03 g CCl4
2) 73.85 kg NaHCO3

3) 123.22 g C4H10

4) 3.15×104 g Na3PO4

In: Chemistry

The Four Loves by C.S Lewis 1. Define “gift-love” and “need-love” (1). Which is more like...

The Four Loves by C.S Lewis

1. Define “gift-love” and “need-love” (1). Which is more like God? What problem does Lewis run into when he tries to determine which is best? (2-4)

2. Explain the difference between ‘nearness-by-likeness’ and ‘by- approach’ (4-5). How does the distinction guard help us guard against the tendency of “every human love, at its highest ... to claim for itself a divine authority” (7-8)?

In: Psychology

Given the following Hypothetical Example and the base year is 2017, answer the questions that follow...

Given the following Hypothetical Example and the base year is 2017, answer the questions that follow

Given the following Hypothetical Example and the base year is 2017, answer the questions that follow

Year

X

Y

Z

Nominal

GDP

Real

GDP

GDP

Deflator

Real GDP

Growth

Inflation

Rate

Q

P

Q

P

Q

P

2017

2

2

1

4

4

2

2018

3

3

2

5

5

3

2019

4

4

3

6

6

4

  1. Calculate the nominal GDP in the three years

  2. Calculate the real GDP in the three years.

  3. Calculate the GDP deflator in the three years

  4. Calculate the real GDP growth between 2018 and 2019

  5. Calculate the rate of inflation in 2019

In: Economics

Number of nonconformities in a process detected by inspection of sample size 50 are: 3, 2,...

Number of nonconformities in a process detected by inspection of sample size 50 are: 3, 2, 3, 1, 4, 0, 2, 3, 4, and 5. For sigma = 3:

a. Construct a control chart for the fraction of nonconformities.

b. Construct a control chart for the number of nonconformities.

c. Can you conclude that this process is in statistical control? Why?

In: Statistics and Probability

A die is weighted so that rolling a 1 is two times as likely as rolling...

A die is weighted so that rolling a 1 is two times as likely as rolling a 2, a 2 is two times likely as rolling a 3, a 3 is two times as likely as rolling a 4, a 4 is two times a likely as rolling a 5, and a 5 is two times as likely as rolling a 6. What is the probability of rolling an even number?

In: Math

Which of the following electronic transitions in a hydrogen atom will be accompanied by the absorption...

Which of the following electronic transitions in a hydrogen atom will be accompanied by the absorption of electromagnetic radiation of the longest wavelength?

Group of answer choices

A. n = 3 → n = 4

B. n = 6 → n = 5

C. n = 3 → n = 2

D. n = 1 → n = 2

E. n = 4 → n = 5

In: Chemistry

v To illustrate how to conduct rate-of-change calculations, we will use the following example. Note that...

v

To illustrate how to conduct rate-of-change calculations, we will use the following example. Note that this is just an example; the data in the table below do not match the data collected in this experiment.

Fossil Stickleback Pelvic Phenotype Totals
Layer 1
Layer 2
Layer 3
Layer 4
Layer 5
Layer 6
Complete: 20 8 3 1 3 0
Reduced: 0 5 16 19 5 16
Absent: 0 7 1 0 12 4

Using these numbers, you need to calculate the rate of change in the relative frequency of stickleback with a complete pelvis per 1,000 years.

Step 1. Calculate the relative frequency of stickleback with a complete pelvis in each layer using this formula:

Relative frequency =

stickleback with a complete pelvis
total number of stickleback analyzed in the layer


In this example, layer 1 had a total of 20 fish and 15 had a complete pelvis; the relative frequency of fish with a complete pelvis is 15/20 = 0.75. In other words, 75% of fish in that layer had a complete pelvis.

For layer 2 the relative frequency of fish with a complete pelvis is 0.5.

Step 2. Calculate the rate of change in relative frequencies between layer 1 and layer 2—a span of 3,000 years.

To do that, you subtract the number of the older layer (layer 1) from that of the more recent neighboring layer (layer 2).

Thus, the change in relative frequency of stickleback with a complete pelvis between layer 1 and layer 2 = 0.5-0.75 = -0.25. (Note that it is a negative number because the relative

frequency of fish with a complete pelvis decreased.)

Step 3. Calculate the rate of change for 1,000-year increments. To do this, you must divide each rate of change by 3 because there are 3 1,000-year increments between layers 1 and 2, and between layers 2 and 3, and so on.

So, the rate of change in relative frequency of stickleback with a complete pelvis between layer 1 and layer 2 per 1,000 years = -0.25/3 = -0.083. In other words, for every thousand years between layer 1 and layer 2 there is an average 8.3% decrease in the relative frequency of fish with the complete pelvis.

First 3,000 years
(From layer 1 to layer 2)

?

Next 3,000 years
(From layer 2 to layer 3)

?

Next 3,000 years
(From layer 3 to layer 4)

Next 3,000 years
(From layer 4 to layer 5)

?

Next 3,000 years
(From layer 5 to layer 6)

?

Rate of change per
thousand years

?

In: Advanced Math

ECON 1150 chap 17

The following graph shows the current short-run Phillips curve for a hypothetical economy; the point on the graph shows the initial unemployment rate and inflation rate. Assume that the economy is currently in long-run equilibrium.

Suppose the central bank of the hypothetical economy decides to increase the money supply.

On the following graph, shift the short-run (SR) Phillips curve or drag the blue point along the curve, or do both, to show the short-run effects of this policy.

Hint: You may assume that the central bank's move was unanticipated.

SR Phillips Curve01234566543210INFLATION RATE (Percent)UNEMPLOYMENT RATE (Percent)SR Phillips Curve   

In the short run, an unexpected increase in the money supply results in    in the inflation rate and    in the unemployment rate.

On the following graph, shift the curve or drag the blue point along the curve, or do both, to show the long-run effects of the increase in the money supply.

01234566543210INFLATION RATE (Percent)UNEMPLOYMENT RATE (Percent)   

In the long run, the increase in the money supply results in    in the inflation rate and    in the unemployment rate (relative to the economy's initial equilibrium).



In: Other

Given the following sample information, test the hypothesis that the treatment means are equal at the...

Given the following sample information, test the hypothesis that the treatment means are equal at the 0.01 significance level:

Treatment 1 Treatment 2 Treatment 3
3 9 6
2 6 3
5 5 5
1 6 5
3 8 5
1 5 4
4 1
7 5
6
4

a. State the null hypothesis and the alternative hypothesis.

H0 : μ1  (select one)  = / > / <

μ2    (select one)   = / > / < μ3

H1 : Treatment means  (select one)  are not / are all the same.

b. What is the decision rule? (Round the final answer to 2 decimal places.)

Reject H0 if F >:   

c. Compute SST, SSE, and SS total. (Round the final answers to 2 decimal places.)

SST =                

SSE =                

SS total =                  


d. Complete the ANOVA table. (Round the SS, MS, and F values to 2 decimal places.)

  Source SS DF MS F
  Factor               
  Error            
  Total        

e. State your decision regarding the null hypothesis.

Decision:  (select one)  Reject / Do not reject  H0.

f.Find the 95% confidence interval for the difference between treatment 2 and 3. (Round the final answers to 2 decimal places.)

95% confidence interval is: _ ± _  

We can conclude that the treatments 2 and 3 are  (select one)  different / the same

In: Statistics and Probability

Given the following sample information, test the hypothesis that the treatment means are equal at the...

Given the following sample information, test the hypothesis that the treatment means are equal at the 0.10 significance level:

Treatment 1 Treatment 2 Treatment 3
3 9 6
2 6 3
5 5 5
1 6 5
3 8 5
1 5 4
4 1
7 5
6
4

a. State the null hypothesis and the alternative hypothesis.

H0 : μ1  (Click to select)  =  >  <  μ2    (Click to select)  =  >  <  μ3

H1 : Treatment means  (Click to select)  are not  are   all the same.

b. What is the decision rule? (Round the final answer to 2 decimal places.)

Reject H0 if F >                 .

c. Compute SST, SSE, and SS total. (Round the final answers to 2 decimal places.)

SST =                

SSE =                

SS total =                  


d. Complete the ANOVA table. (Round the SS, MS, and F values to 2 decimal places.)

  Source SS DF MS F
  Factor               
  Error            
  Total        

e. State your decision regarding the null hypothesis.

Decision:  (Click to select)  Reject  Do not reject  H0.

f.Find the 95% confidence interval for the difference between treatment 2 and 3. (Round the final answers to 2 decimal places.)

95% confidence interval is:    ±     

We can conclude that the treatments 2 and 3 are  (Click to select)  different  the same   .

In: Statistics and Probability