(A) How many moles (of molecules or formula units) are in each sample? And please explain how the answer is found.
1) 20.0 g NO2
2) 1.35 kg CO2
3) 40.4 g KNO3
4) 102.3 kg Na2SO4
(B) How many molecules (or formula units) are in each sample? And please show how to find answer
1) 52.03 g CCl4
2) 73.85 kg NaHCO3
3) 123.22 g C4H10
4) 3.15×104 g Na3PO4
In: Chemistry
The Four Loves by C.S Lewis
1. Define “gift-love” and “need-love” (1). Which is more like God? What problem does Lewis run into when he tries to determine which is best? (2-4)
2. Explain the difference between ‘nearness-by-likeness’ and ‘by- approach’ (4-5). How does the distinction guard help us guard against the tendency of “every human love, at its highest ... to claim for itself a divine authority” (7-8)?
In: Psychology
Given the following Hypothetical Example and the base year is 2017, answer the questions that follow
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Given the following Hypothetical Example and the base year is 2017, answer the questions that follow
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In: Economics
Number of nonconformities in a process detected by inspection of sample size 50 are: 3, 2, 3, 1, 4, 0, 2, 3, 4, and 5. For sigma = 3:
a. Construct a control chart for the fraction of nonconformities.
b. Construct a control chart for the number of nonconformities.
c. Can you conclude that this process is in statistical control? Why?
In: Statistics and Probability
A die is weighted so that rolling a 1 is two times as likely as rolling a 2, a 2 is two times likely as rolling a 3, a 3 is two times as likely as rolling a 4, a 4 is two times a likely as rolling a 5, and a 5 is two times as likely as rolling a 6. What is the probability of rolling an even number?
In: Math
Which of the following electronic transitions in a hydrogen atom will be accompanied by the absorption of electromagnetic radiation of the longest wavelength?
Group of answer choices
A. n = 3 → n = 4
B. n = 6 → n = 5
C. n = 3 → n = 2
D. n = 1 → n = 2
E. n = 4 → n = 5
In: Chemistry
v
To illustrate how to conduct rate-of-change calculations, we
will use the following example. Note that this is just an example;
the data in the table below do not match the data collected in this
experiment.
| Fossil Stickleback Pelvic Phenotype Totals | |||||||||||||
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|
|
|
|
|
|
|
|||||||
| Complete: | 20 | 8 | 3 | 1 | 3 | 0 | |||||||
| Reduced: | 0 | 5 | 16 | 19 | 5 | 16 | |||||||
| Absent: | 0 | 7 | 1 | 0 | 12 | 4 | |||||||
Using these numbers, you need to calculate the rate of change in
the relative frequency of stickleback with a complete pelvis
per 1,000 years.
Step 1. Calculate the relative frequency of stickleback with a
complete pelvis in each layer using this formula:
|
Relative frequency = |
stickleback with a complete pelvis |
In this example, layer 1 had a total of 20 fish and 15 had a
complete pelvis; the relative frequency of fish with a complete
pelvis is 15/20 = 0.75. In other words, 75% of fish in that layer
had a complete pelvis.
For layer 2 the relative frequency of fish with a complete pelvis
is 0.5.
Step 2. Calculate the rate of change in relative frequencies
between layer 1 and layer 2—a span of 3,000 years.
To do that, you subtract the number of the older layer (layer 1)
from that of the more recent neighboring layer (layer 2).
Thus, the change in relative frequency of stickleback with a
complete pelvis between layer 1 and layer 2 = 0.5-0.75 = -0.25.
(Note that it is a negative number because the relative
frequency of fish with a complete pelvis decreased.)
Step 3. Calculate the rate of change for 1,000-year increments. To
do this, you must divide each rate of change by 3 because there are
3 1,000-year increments between layers 1 and 2, and between layers
2 and 3, and so on.
So, the rate of change in relative frequency of stickleback with a
complete pelvis between layer 1 and layer 2 per 1,000 years =
-0.25/3 = -0.083. In other words, for every thousand years between
layer 1 and layer 2 there is an average 8.3% decrease in the
relative frequency of fish with the complete pelvis.
First 3,000 years
(From layer 1 to layer 2)
?
Next 3,000 years
(From layer 2 to layer 3)
?
Next 3,000 years
(From layer 3 to layer 4)
Next 3,000 years
(From layer 4 to layer 5)
?
Next 3,000 years
(From layer 5 to layer 6)
?
Rate of change per
thousand years
?
In: Advanced Math
The following graph shows the current short-run Phillips curve for a hypothetical economy; the point on the graph shows the initial unemployment rate and inflation rate. Assume that the economy is currently in long-run equilibrium.
Suppose the central bank of the hypothetical economy decides to increase the money supply.
On the following graph, shift the short-run (SR) Phillips curve or drag the blue point along the curve, or do both, to show the short-run effects of this policy.
Hint: You may assume that the central bank's move was unanticipated.
In the short run, an unexpected increase in the money supply results in in the inflation rate and
in the unemployment rate.
On the following graph, shift the curve or drag the blue point along the curve, or do both, to show the long-run effects of the increase in the money supply.
In the long run, the increase in the money supply results in in the inflation rate and
in the unemployment rate (relative to the economy's initial equilibrium).
In: Other
Given the following sample information, test the hypothesis that the treatment means are equal at the 0.01 significance level:
| Treatment 1 | Treatment 2 | Treatment 3 |
| 3 | 9 | 6 |
| 2 | 6 | 3 |
| 5 | 5 | 5 |
| 1 | 6 | 5 |
| 3 | 8 | 5 |
| 1 | 5 | 4 |
| 4 | 1 | |
| 7 | 5 | |
| 6 | ||
| 4 | ||
a. State the null hypothesis and the alternative hypothesis.
H0 : μ1 (select one) = / > / <
μ2 (select one) = / > / < μ3
H1 : Treatment means (select one) are not / are all the same.
b. What is the decision rule? (Round the final answer to 2 decimal places.)
Reject H0 if F >:
c. Compute SST, SSE, and SS total. (Round the final answers to 2 decimal places.)
SST =
SSE =
SS total =
d. Complete the ANOVA table. (Round the
SS, MS, and F values to 2 decimal places.)
| Source | SS | DF | MS | F | ||
| Factor | ||||||
| Error | ||||||
| Total | ||||||
e. State your decision regarding the null hypothesis.
Decision: (select one) Reject / Do not reject H0.
f.Find the 95% confidence interval for the difference between treatment 2 and 3. (Round the final answers to 2 decimal places.)
95% confidence interval is: _ ± _
We can conclude that the treatments 2 and 3 are (select one) different / the same
In: Statistics and Probability
Given the following sample information, test the hypothesis that the treatment means are equal at the 0.10 significance level:
| Treatment 1 | Treatment 2 | Treatment 3 |
| 3 | 9 | 6 |
| 2 | 6 | 3 |
| 5 | 5 | 5 |
| 1 | 6 | 5 |
| 3 | 8 | 5 |
| 1 | 5 | 4 |
| 4 | 1 | |
| 7 | 5 | |
| 6 | ||
| 4 | ||
a. State the null hypothesis and the alternative hypothesis.
H0 : μ1 (Click to select) = > < μ2 (Click to select) = > < μ3
H1 : Treatment means (Click to select) are not are all the same.
b. What is the decision rule? (Round the final answer to 2 decimal places.)
Reject H0 if F > .
c. Compute SST, SSE, and SS total. (Round the final answers to 2 decimal places.)
SST =
SSE =
SS total =
d. Complete the ANOVA table. (Round the
SS, MS, and F values to 2 decimal places.)
| Source | SS | DF | MS | F | ||
| Factor | ||||||
| Error | ||||||
| Total | ||||||
e. State your decision regarding the null hypothesis.
Decision: (Click to select) Reject Do not reject H0.
f.Find the 95% confidence interval for the difference between treatment 2 and 3. (Round the final answers to 2 decimal places.)
95% confidence interval is: ±
We can conclude that the treatments 2 and 3 are (Click to select) different the same .
In: Statistics and Probability