Here is the ORIGINAL data of the Sport Hotel project: 1. Projected outflows First year (Purchase Right, Land, and Permits) $1,000,000 Second Year (Construct building shell $2,000,000 Third Year: (Finish interior and furnishings) $2,000,000 TOTAL $5,000,000 2. Projected inflows If the franchise is granted hotel will be worth: $8,000,000 when it opened If the franchise is denied hotel will be worth: $2,000,000 when it opened. The probability of the city being awarded the franchise is 50%. Suppose that everything is the same as in that problem except TWO things: the worth of the hotel, should the city be awarded the franchise, is not $8 million but some unknown smaller number; and the probability of getting the franchise is NOT 50% but is upgraded to 80%. What must the new worth of the hotel when the franchise is granted be in order for the NPV of the Sporthotel project to be equal to exactly zero?
In: Finance
Since 1970, Super Rise, Inc., has provided maintenance services for elevators. On January 1, 2018, Super Rise obtains a contract to maintain an elevator in a 90-story building in New York City for 10 months and receives a fixed payment of $96,000. The contract specifies that Super Rise will receive an additional $48,000 at the end of the 10 months if there is no unexpected delay, stoppage, or accident during the year. At the beginning of the contract, Super Rise estimates there is a 25% chance of earning the bonus. On June 30, 2018, Super Rise changes the estimate to reflect a 65% chance of earning the bonus. Super Rise prepares financial statements monthly.
If super Rise estimates variable consideration using the expected value approach, what amount of revenue related to the contract will be reported on 6/30/2018, and 7/31/2018?
|
6/30/2018 |
7/31/2018 |
|
|
a. |
14,400 |
9,600 |
|
b. |
22,320 |
12,720 |
|
c. |
38,400 |
14,400 |
|
d. |
24,000 |
12,000 |
|
e. |
None of the above. |
|
In: Accounting
High-speed elevators function under two limitations: (1) the maximum magnitude of vertical acceleration that a typical human body can experience without discomfort is about 1.2 m/s2, and (2) the typical maximum speed attainable is about 9.1 m/s . You board an elevator on a skyscraper's ground floor and are transported 230 mabove the ground level in three steps: acceleration of magnitude 1.2 m/s2 from rest to 9.1 m/s , followed by constant upward velocity of 9.1 m/s , then deceleration of magnitude 1.2 m/s2 from 9.1 m/s to rest.
A)
determine the elapsed time for each of these 3 stages.
Express your answers using two significant figures separated by commas.
|
|
||||
|
tacc,tconstant,tdec |
B)Determine the change in the magnitude of the normal force, expressed as a % of your normal weight during each stage.
Express your answers using two significant figures separated by commas.
|
|
||||
| ΔFN,accFN,ΔFN,constantFN,ΔFN,decFN |
In: Physics
In: Psychology
One of the large photocopiers used by a printing company has a
number of special functions unique to that particular model. This
photocopier generally performs well but, because of the complexity
of its design and the frequency of usage, it occasionally breaks
down. The department has kept records of the number of breakdowns
per month over the last fifty months. The data is summarized in the
table below:
|
Number of Breakdowns |
Probability |
|
0 |
0.12 |
|
1 |
0.32 |
|
2 |
0.24 |
|
3 |
0.20 |
|
4 |
0.08 |
|
5 |
0.04 |
The cost of a repair depends mainly on the time taken, the level of
expertise required and the cost of any spare parts. There are four
levels of repair. The cost per repair for each level and
probabilities for different levels of repair are shown in table
below:
|
Repair Category |
Repair Cost |
Probability |
|
1 |
$35 |
0.50 |
|
2 |
$75 |
0.30 |
|
3 |
$150 |
0.16 |
|
4 |
$350 |
0.04 |
Based on the probabilities given in the two tables and using the
random number streams given below, simulate for each of 12
consecutive months the number of breakdowns and the repair cost of
each breakdown. Note that for each month you must compute both the
number of breakdowns, the repair cost for each breakdown (if any)
and the total monthly repair cost as well as the total annual
repair cost to answer the following questions.
Use the following random numbers in order (from left to right) for
the simulation of number of breakdowns per month:
|
Jan |
Feb |
Mar |
Apr |
May |
Jun |
Jul |
Aug |
Sep |
Oct |
Nov |
Dec |
|
0.13 |
0.21 |
0.08 |
0.09 |
0.89 |
0.26 |
0.65 |
0.28 |
0.97 |
0.24 |
0.10 |
0.90 |
Use the following random numbers in order (from left to right,
first row first - as you need them) for the simulation of repair
cost for each breakdown.
|
0.19 |
0.39 |
0.07 |
0.42 |
0.65 |
0.61 |
0.85 |
0.40 |
0.75 |
0.73 |
0.16 |
0.64 |
|
0.38 |
0.05 |
0.91 |
0.97 |
0.24 |
0.01 |
0.27 |
0.69 |
0.18 |
0.06 |
0.53 |
0.97 |
What is the average repair cost in this 12-month simulation?
In: Statistics and Probability
One of the large photocopiers used by a printing company has a
number of special functions unique to that particular model. This
photocopier generally performs well but, because of the complexity
of its design and the frequency of usage, it occasionally breaks
down. The department has kept records of the number of breakdowns
per month over the last fifty months. The data is summarized in the
table below:
|
Number of Breakdowns |
Probability |
|
0 |
0.12 |
|
1 |
0.32 |
|
2 |
0.24 |
|
3 |
0.20 |
|
4 |
0.08 |
|
5 |
0.04 |
The cost of a repair depends mainly on the time taken, the level of
expertise required and the cost of any spare parts. There are four
levels of repair. The cost per repair for each level and
probabilities for different levels of repair are shown in table
below:
|
Repair Category |
Repair Cost |
Probability |
|
1 |
$35 |
0.50 |
|
2 |
$75 |
0.30 |
|
3 |
$150 |
0.16 |
|
4 |
$350 |
0.04 |
Based on the probabilities given in the two tables and using the
random number streams given below, simulate for each of 12
consecutive months the number of breakdowns and the repair cost of
each breakdown. Note that for each month you must compute both the
number of breakdowns, the repair cost for each breakdown (if any)
and the total monthly repair cost as well as the total annual
repair cost to answer the following questions.
Use the following random numbers in order (from left to right) for
the simulation of number of breakdowns per month:
|
Jan |
Feb |
Mar |
Apr |
May |
Jun |
Jul |
Aug |
Sep |
Oct |
Nov |
Dec |
|
0.13 |
0.21 |
0.08 |
0.09 |
0.89 |
0.26 |
0.65 |
0.28 |
0.97 |
0.24 |
0.10 |
0.90 |
Use the following random numbers in order (from left to right,
first row first - as you need them) for the simulation of repair
cost for each breakdown.
|
0.19 |
0.39 |
0.07 |
0.42 |
0.65 |
0.61 |
0.85 |
0.40 |
0.75 |
0.73 |
0.16 |
0.64 |
|
0.38 |
0.05 |
0.91 |
0.97 |
0.24 |
0.01 |
0.27 |
0.69 |
0.18 |
0.06 |
0.53 |
0.97 |
What was the total monthly repair cost in May?
| A. |
$220 |
|
| B. |
$35 |
|
| C. |
$300 |
|
| D. |
$75 |
|
| E. |
$140 |
In: Statistics and Probability
This is a code for a bouncing ball on an 8X8 LED. How can i change the code to make it a ping pong game against AI by adding 1 potentionmeter to control it?
#include <TimerOne.h>//this is a library that uses timer 1 of the arduino to trigger interrupts in certain time intervals
//This defines a matrix defining a smiley face for the 8x8 LED
matrix display
#define BALL { \
{1, 0, 0, 0, 0, 0, 0, 0}, \
{0, 0, 0, 0, 0, 0, 0, 0}, \
{0, 0, 0, 0, 0, 0, 0, 0}, \
{0, 0, 0, 0, 0, 0, 0, 0}, \
{0, 0, 0, 0, 0, 0, 0, 0}, \
{0, 0, 0, 0, 0, 0, 0, 0}, \
{0, 0, 0, 0, 0, 0, 0, 0}, \
{0, 0, 0, 0, 0, 0, 0, 0} \
}
/*Arduino pin --> Display pin----->8x8 matrix row and column
coordinates (1;1) origin
D2-------------->9---------------------->row 1
D3-------------->10-------------------->col 4
D4-------------->11-------------------->col 6
D5-------------->12--------------------->row 4
D6-------------->13-------------------->col 1
D7-------------->14--------------------->row 2
D8-------------->15-------------------->col 7
D9-------------->16-------------------->col 8
D10------------->4--------------------->col 3
D11------------->3--------------------->col 2
D12------------->2---------------------->row 7
D13------------->1---------------------->row 5
A0 (D14)-------->5---------------------->row 8
A1 (D15)-------->6--------------------->col 5
A2 (D16)-------->7---------------------->row 6
A3 (D17)-------->8---------------------->row 3
*/
//rows:
const int col[8] = {
2,7,17,5,13,16,12,14 };//these are the Arduino pins that connect to
the anodes (1-8) of the LEDs
//columns:
const int row[8] = {
6,11,10,3,15,4,8,9 };//these are the Arduino pins that connect to
the cathodes (1-8) of the LEDs
int x = 0;
int y = 0;
int dx = 1;
int dy = 1;
volatile byte c,r,flag,counter;//interrupt routine variables, they need to be specified as 'volatile'
// 2-dimensional array that contains the currently 'ON' LEDs in
the matrix ('1'='ON'); this is used in the refreshScreen() ISR
below:
byte pattern[8][8] = BALL;
unsigned long previousMillis = 0; //last time we switched
patterns [ms]
unsigned long interval = 1000; //time between switching [ms]
int currentPattern = 0; //0 for "Ball", 1 for "Ball2", 2 for
"Ball3", 3 for "Ball4"
void setup() {
// initialize the row and column pins as outputs
// iterate through the pins:
for (int pin = 0; pin < 8; pin++) {
// initialize the output pins:
pinMode(col[pin], OUTPUT);
digitalWrite(col[pin], HIGH);
pinMode(row[pin], OUTPUT);
digitalWrite(row[pin], LOW);
// take the col pins (i.e. the cathodes) high and the row pins
(anodes) low to ensure that
// the LEDS are off:
}
Timer1.initialize(100); // initialize timer1, and set a 100 us
second period for the interrupt interval (i.e. the ISR will be
called
//every 100 us - this seems to be a good frequency to achieve a
flicker-free LED display.
//experiment with this parameter. If it gets too small the ISR
starts 'eating up' all the processor time, and the main loop
becomes very slow
Timer1.attachInterrupt(refreshScreen); // attaches the
refreshScreen() function as 'Interrupt Service Routine' (ISR) to
the interrupt
//this means that every time 100 us have passed, the
refreshScreen() routine will be called.
}
//main loop...here we can simply busy ourselves with changing
the pattern[][] array; nothing deals with the LED display.
//this is all handled via the ISR
void loop() {
if (x>=7)
{ dx = -1;
dy = random(-1,1);
}
if(x<=0)
{
dx = 1;
dy = random(-1,1);
}
if (y>=7)
{dy = -1;
dx = random(-1,1);
}
if (y<=0)
{ dy = 1;
dx = random(-1,1);
}
pattern[x][y] = 0;
pattern[x+dx][y+dy]=1;
x=x+dx;
y=y+dy;
delay(50);
In: Electrical Engineering
Visit the NASDAQ historical prices weblink. First, set the date range to be for exactly 1 year ending on the Monday that this course started. For example, if the current term started on April 1, 2018, then use April 1, 2017 – March 31, 2018. (Do NOT use these dates. Use the dates that match up with the current term.) MY DATES ARE MARCH 18 2018 - MARCH 19 2019 Do this by clicking on the blue dates after “Time Period”. Next, click the “Apply” button. Next, click the link on the right side of the page that says “Download Data” to save the file to your computer.
This project will only use the Close values. Assume that the closing prices of the stock form a normally distributed data set. This means that you need to use Excel to find the mean and standard deviation. Then, use those numbers and the methods you learned in sections 6.1-6.3 of the course textbook for normal distributions to answer the questions. Do NOT count the number of data points.
Complete this portion of the assignment within a single Excel file. Show your work or explain how you obtained each of your answers. Answers with no work and no explanation will receive no credit.
b) What the mean and Standard Deviation (SD) of the Close column in your data set?
c) If a person bought 1 share of Google stock within the last year, what is the probability that the stock on that day closed at less than the mean for that year? Hint: You do not want to calculate the mean to answer this one. The probability would be the same for any normal distribution. (5 points)
There are also 5 points for miscellaneous items like correct date range, correct mean, correct SD, etc.
Project 3 is due by 11:59 p.m. (ET) on Monday of Module/Week 5.
In: Statistics and Probability
The number of chocolate chips in an 18-ounce bag of
chocolate chip cookies is approximately normally distributed with a
mean of 1252 chips and standard deviation of 129
chips.
a. What is the probability that a randomly selected bag contains
between 1000 and 1400 chocolate chips?
b. What is the probability that a randomly selected bag contains more than 1225 chocolate chips?
c. What is the percentile rank of a bag that contains 1425 chocolate chips
Suppose the lengths of pregnancies of a certain animal are approximately normally distributed with mean ? = 240 days and ? = 18 days.
a. What is the probability that a randomly selected pregnancy lasts less than 233 days?
b. Suppose a random sample of 17 pregnancies is obtained. Describe the mean and standard deviation of the distribution of the sample mean length of pregnancies.
c. What is the probability that a random sample of 17 pregnancies has a mean pregnancy of less than 233 days?
According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A random sample of 1200 Americans results in 108 indicating that they are afraid to fly.
a. What is the sampling distribution of the proportion of Americans who are afraid to fly?
b. What is the point estimate of the sample (?̂)?
c. What is the probability that 108 or fewer out of 1200 Americans are afraid to fly?
d. Is this evidence that the proportion of Americans who are afraid to fly is decreasing? Why or why not?
Please show all work for the following problems. If a calculator is used, include the calculator function used as well as the values entered. (Example: normalcdf
In: Statistics and Probability
Assume that IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.. If 25 people are randomly selected, find the probability that their mean IQ score is less than 103. (a) .1587 (b) .8413 (c) 1.000 (d) .9938 23 Refer to question 19 above. If 100 people are randomly selected, find the probability that their mean IQ is greater than 103. (a) .8413 (b) 2.000 (c) .9772 (d) .0228 24 True or False. Because the total area under the normal standard distribution is equal to 1, there is a correspondence between area and probability. (a) True (b) False 25 True of False. A Z-score must be negative whenever it is located in the left half of the normal distribution. (a) True (b) False 26. The World Health Organization states that tobacco is the second leading cause of death in the world. Every year, a mean of 5 million people die of tobacco-related causes. Assume that the distribution is normal with µ = 5 (in millions) and ơ = 2 (in millions). Find the probability that more than 4 million people will die of tobacco-related causes in a particular year. (a) .3085 (b) .5000 (c) .6915 (d) -.5000 (e) .9772 27. Refer to question 26. What is the probability that the number of people who will die from tobacco-related deaths will fall between 3 million and 7 million in a particular year? (a) .1587 (b) .8413 (c) 1.000 (d) -1.000 (e) .6826 SHOW WORK
In: Statistics and Probability