In: Physics
IV) Many enzymes obey simple Michaelis-Menten kinetics, which
are summarized
by the equation:
rate = (V max [S])/([S]+K m ); where V max = maximum velocity, [S]
= concentration
of substrate; and K m = the Michaelis constant.
It is instructive to plug in a few values of [S] into the equation
to see how rate is
affected. What are the rates for [S] equal to zero, equal to K m ,
and equal to infinite
concentration? Show all work.
In: Chemistry
using the Oyez audio file and transcript (Links to an external site.)Links to an external site. (go to "Opinion Announcement," which is a seven minute audio clip on the court's decision on the Snyder v. Phelps case), briefly summarize the facts of the Snyder v. Phelps (2011) case. By using facts presented, clearly explain why the Supreme Court ruled in favor of the Westboro Baptist Church. Then, tell us why you agree/disagree with the Court’s decision.
In: Psychology
Consider the following code:
values = [2, 5, 8, 12, 15]
values2 = {v % 3 for v in values}
What will be the length of values2?
Consider the following code:
values = ["moose", "giraffe", "antelope", "tortoise", "chinchilla"] values2 = [len(s) for s in values if "a" in s]
What will be the value of values2[1]?
Consider the following code:
numbers = [1, 2, 7, 9, 13] numbers2 = [n // 2 for n in numbers]
What will be the value of numbers2[2]?
In: Computer Science
Suppose that k is a field which is not algebraically closed. a. Show that if I ⊂ k[x1, . . . , xn ] is maximal, then V(I) is either empty or a point in kn . Hint: Examine the proof of Theorem 11. b. Show that there exists a maximal ideal I in k[x1, . . . , xn ] for which V(I) = ∅. Hint: See the previous exercise. c. Conclude that if k is not algebraically closed, there is always a maximal ideal of k[x1, . . . , xn ] which is not of the form <x1 − a1, . . . , xn − an >
In: Advanced Math
| Break-Even Point | ||||||||||||||||||||||
| Part a. | Part b. | Part c. | Part d. | |||||||||||||||||||
| Givens From Problem: | Costs | Dollars | No. | Dollars | No. | Dollars | No. | Dollars | No. | |||||||||||||
| A | ||||||||||||||||||||||
| B | ||||||||||||||||||||||
| C | ||||||||||||||||||||||
| D | ||||||||||||||||||||||
| E | ||||||||||||||||||||||
| F | ||||||||||||||||||||||
| G | ||||||||||||||||||||||
| H | ||||||||||||||||||||||
| I | ||||||||||||||||||||||
| A | B | C | D | |||||||||||||||||||
| Reimbursement | Reimbursement | Reimbursement | Reimbursement | |||||||||||||||||||
| Per Mammography (P) | ||||||||||||||||||||||
| 75 | ||||||||||||||||||||||
| Fixed Costs | Fixed Costs | Fixed Costs | Fixed Costs | |||||||||||||||||||
| Total Fixed Costs (TFC) | Total Fixed Costs (TFC) | Total Fixed Costs (TFC) | Total Fixed Costs (TFC) | |||||||||||||||||||
| Variable Costs | Variable Costs | Variable Costs | Variable Costs | |||||||||||||||||||
| Variables Costs based on Dollar Amount per Unit | Variables Costs based on Dollar Amount per Unit | Variables Costs based on Dollar Amount per Unit | Variables Costs based on Dollar Amount per Unit | |||||||||||||||||||
| Sum: | Sum: | Sum: | Sum: | |||||||||||||||||||
| Break-Even Point | Break-Even Point | Break-Even Point | Break-Even Point | |||||||||||||||||||
| Break-Even Units (X) | X = TFC / (P - V) | Break-Even Units (X) | X = TFC / (P - V) | Break-Even Units (X) | X = TFC / (P - V) | Break-Even Units (X) | X = TFC / (P - V) | |||||||||||||||
| Targeted Profit | Targeted Profit | Targeted Profit | Targeted Profit | |||||||||||||||||||
| Targeted Profit (TF) | Targeted Profit (TF) | Targeted Profit (TF) | Targeted Profit (TF) | |||||||||||||||||||
| Units required to reach targeted TF, X = (TFC + TF) / (P-V) | Units required to reach targeted TF, X = (TFC + TF) / (P-V) |
Units required to reach targeted TF, X = (TFC + TF) / (P-V) |
Units required to reach targeted TF, X = (TFC + TF) / (P-V) | |||||||||||||||||||
Scenario: Pacific Imaging Center is a small imaging center with
two analogue film or screen units. As the director of the center,
Juanita Hernandez has been asked to determine if the current
staffing is correct for her place or should she add another
technologist. She currently uses 2 mammography units, 2
technologists, and 1 aide. She has analyzed the current costs and
determined the following:
Reimbursement per screen $75 Equipment costs per month ($800 per
machine) $1,600 Technologists costs per mammography $20
Technologists aide per mammography $4 Variable cost per mammography
$10 Equipment maintenance per month per machine ($350 per machine)
$700
A. Solve for monthly volume to break even. B. Solve for monthly volume needed to break even at desired $5,000 per month profit level. C. Solve for volume needed to break even at new reimbursement of $112 per screen and no profit. D. Solve for volume needed to break even with an additional technologist
Expert Answer
In: Finance
PROMT: Climate Change Effects on Marine Iguana Mortality
QUESTION ----->>>>> Write a detailed summary
of what is wrong with the proposed study ^^^^^????
Your answer should use scientific vocabulary words and address the following questions.
In: Biology
Exercise 3
Step 1:
When you read Storing Data Using Sets, you learned that Python's set type allows us to create mutable collections of unordered distinct items. The items stored in a set must be immutable, so sets can contain values of type int, float or str, but we can't store lists or sets in sets. Tuples are immutable, so we can store tuples in sets. Try this experiment, which creates a set containing the points (1.0, 2.0), (4.0, 6.0) and (10.0, -2.0). What is displayed when points is evaluated? Write the question and the answer in lab11.py using python comments. >>> points = {(1.0, 2.0), (4.0, 6.0), (10.0, -2.0)} >>> points We can also initialize the set this way. Try this experiment. What is displayed when points is evaluated? Write the question and the answer in lab11.py using python comments. >>> point1 = (1.0, 2.0) >>> point2 = (4.0, 6.0) >>> point3 = (10.0, -2.0) >>> points = {point1, point2, point3} >>> points We could instead start with an empty set, and call the add method to initialize it, one point at a time. Try this experiment. What is displayed when points is evaluated? Write the question and the answer in lab11.py using python comments. >>> points = set() >>> points.add(point1) >>> points.add(point2) >>> points.add(point3) >>> points
Step 2:
What happens if we try to insert a point that is already in the set? Try this experiment: >>> points.add(point2) >>> points How many copies of point (4.0, 6.0) are in the set? Write the question and the answer in lab11.py using python comments.
Step 3:
Can individual points in the set be retrieved by specifying an index (position)? Try this experiment. What is displayed when points[0] is evaluated? Write the question and the answer in lab11.py using python comments. >>> points[0]
Step 4:
We can use a for loop to iterate over all the points in the set. What is displayed when this loop is executed? Write the question and the answer in lab11.py using python comments. >>> for point in points: ... print(point) ...
In: Computer Science
Which firms ( at least 3) have consitently reported a strong return to its shareholders? Identify firms with the most favorable earning trend?
| Data Year - Fiscal | Company Name | Standard Industry Classification Code | Assets - Total | AVG assets | Cash and Short-Term Investments | Current Liabilities - Total | AVG current Liab. | Liabilities and Stockholders Equity - Total | Liabilities - Total | Stock -Total | Net Income (Loss) | Operating Activities - Net Cash Flow | Receivables - Total | Sales/Turnover (Net) | Interest and Related Expense - Total |
| 2014 | SHAKE SHACK INC | 5812 | 82.9620 | 2.6770 | 48.1770 | 82.9620 | 70.3620 | 12.6000 | 2.1180 | 13.5840 | 3.2780 | 118.5300 | 0.3630 | ||
| 2015 | SHAKE SHACK INC | 5812 | 379.5470 | 71.1240 | 24.0050 | 379.5470 | 222.5280 | 157.0190 | -8.7760 | 41.2580 | 4.2170 | 190.5920 | 0.4400 | ||
| 2016 | SHAKE SHACK INC | 5812 | 538.1940 | 73.6470 | 31.7160 | 538.1940 | 336.8410 | 201.3530 | 12.4460 | 54.2850 | 6.0170 | 268.4750 | 0.3740 | ||
| 2017 | SHAKE SHACK INC | 5812 | 470.6060 | 367.8273 | 84.5430 | 34.0240 | 34.4805 | 470.6060 | 246.1270 | 224.4790 | -0.3200 | 70.8780 | 5.6590 | 358.8100 | 1.8070 |
| 2014 | BOJANGLES' INC | 5812 | 552.6430 | 13.2010 | 40.1380 | 552.6430 | 414.8910 | 137.7520 | 26.1200 | 41.6430 | 5.8760 | 430.4720 | 9.8560 | ||
| 2015 | BOJANGLES' INC | 5812 | 560.7650 | 14.2630 | 45.1020 | 560.7650 | 393.6410 | 167.1240 | 26.5260 | 45.5260 | 8.0260 | 488.2020 | 9.1350 | ||
| 2016 | BOJANGLES' INC | 5812 | 559.7720 | 13.8980 | 48.5790 | 559.7720 | 348.9820 | 210.7900 | 37.7160 | 54.3000 | 7.3120 | 531.8810 | 8.2520 | ||
| 2017 | BOJANGLES' INC | 5812 | 555.4680 | 557.1620 | 14.0520 | 39.9060 | 43.4313 | 555.4680 | 270.3640 | 285.1040 | 72.0060 | 49.7450 | 8.0090 | 547.4380 | 7.0770 |
| 2014 | STARBUCKS CORP | 5812 | 10752.9000 | 1843.8000 | 3038.7000 | 10752.9000 | 5479.2000 | 5273.7000 | 2068.1000 | 607.8000 | 631.0000 | 16447.8000 | 70.3000 | ||
| 2015 | STARBUCKS CORP | 5812 | 12446.1000 | 1611.4000 | 3653.5000 | 12446.1000 | 6626.3000 | 5819.8000 | 2757.4000 | 3749.1000 | 719.0000 | 19162.7000 | 74.1000 | ||
| 2016 | STARBUCKS CORP | 5812 | 14329.5000 | 2263.2000 | 4546.9000 | 14329.5000 | 8438.8000 | 5890.7000 | 2817.7000 | 4575.1000 | 768.8000 | 21315.9000 | 82.2000 | ||
| 2017 | STARBUCKS CORP | 5812 | 14365.6000 | 12973.5250 | 2690.9000 | 4220.7000 | 3864.9500 | 14365.6000 | 8908.6000 | 5457.0000 | 2884.7000 | 4174.3000 | 938.4000 | 22386.8000 | 93.6000 |
| 2014 | DAVE & BUSTER'S ENTMT INC | 5810 | 950.6890 | 70.8760 | 126.1400 | 950.6890 | 691.9920 | 258.6970 | 7.6360 | 86.7150 | 9.2600 | 746.7510 | 35.6530 | ||
| 2015 | DAVE & BUSTER'S ENTMT INC | 5810 | 1004.5350 | 25.4950 | 156.6470 | 1004.5350 | 658.1970 | 346.3380 | 59.6190 | 186.9830 | 18.1690 | 866.9820 | 12.8240 | ||
| 2016 | DAVE & BUSTER'S ENTMT INC | 5810 | 1052.7330 | 20.0830 | 177.7970 | 1052.7330 | 613.2810 | 439.4520 | 90.7950 | 231.3290 | 14.1000 | 1005.1580 | 7.7180 | ||
| 2017 | DAVE & BUSTER'S ENTMT INC | 5810 | 1197.0300 | 1051.2468 | 18.7950 | 207.8250 | 167.1023 | 1197.0300 | 775.3840 | 421.6460 | 120.9490 | 264.6720 | 19.8080 | 1139.7910 | 9.6750 |
| 2014 | RCI HOSPITALITY HLDGS INC | 5810 | 239.1420 | 10.5600 | 39.1940 | 239.1420 | 125.8430 | 113.2990 | 11.2400 | 20.4350 | 1.7450 | 129.1740 | 7.7520 | ||
| 2015 | RCI HOSPITALITY HLDGS INC | 5810 | 270.8120 | 8.6340 | 22.8540 | 270.8120 | 142.3260 | 128.4860 | 9.3120 | 16.3640 | 2.1540 | 144.6670 | 6.9690 | ||
| 2016 | RCI HOSPITALITY HLDGS INC | 5810 | 276.4880 | 11.3270 | 24.4570 | 276.4880 | 146.3460 | 130.1420 | 11.0890 | 23.0310 | 4.3650 | 134.8600 | 7.9820 | ||
| 2017 | RCI HOSPITALITY HLDGS INC | 5810 | 299.8840 | 271.5815 | 9.9220 | 31.1110 | 29.4040 | 299.8840 | 164.6590 | 135.2250 | 8.2590 | 21.0940 | 3.1870 | 144.8960 | 8.7320 |
In: Accounting
Write a Java program to read in the 10 numbers in the example file Book1.csv provided above. The program should sum all the numbers, find the lowest number, find the highest number, and computer the average. Upon completion of the processing, the program should write a new text file named stats.txt with the information found in the following format where xxx represents a number calculated above.
The sum of the numbers is: xxx The lowest number is: xxx The highest number is : xxx The average of the numbers is : xxx
Using the class Poem below. Write a complete Java program that creates three different objects of type Poem. The program shall then open a text file named poems.txt for writing and write the information about each poem to the text file. The program shall NOT write the toString() version of the object to the file, but write first the poem name on a line and then the poet name on a second line for each poem.
/**
* Poem.java
*
* A class representing information about a poem for use in Chapter 5 Exercise 2
*
*/
public class Poem
{
private String name;
private String poet;
/**
* no-arg constructor
*/
public Poem()
{
// initialize attributes
name = "unknown";
poet = "unknown";
}
/**
* @return the name
*/
public String getName()
{
return name;
}
/**
* @param name the name to set
*/
public void setName(String name)
{
this.name = name;
}
/**
* @return the poet
*/
public String getPoet()
{
return poet;
}
/**
* @param poet the poet to set
*/
public void setPoet(String poet)
{
this.poet = poet;
}
@Override
public String toString()
{
return "Poem [name=" + name + ", poet=" + poet + "]";
}
}
===Exercise 3 Using the Poem class given in exercise 2, write a Java program to read from a text file named poem2.txt provided before. The program shall read the name and poet of each poem, create an object of type Poem for each name/poet pair and print all the read poem infor to the console.
We Real Cool Gwendolyn Brooks I Know Why the Caged Bird Sings Maya Angelou Hope is the Thing with Feathers Emily Dickinson The Road Not Taken Robert Frost
In: Computer Science