Questions
The market value of Owl Fund Industries common stock is $125 million and the market value...

The market value of Owl Fund Industries common stock is $125 million and the market value of its debt is $25 million. The beta of the company's common stock is 1.0 and the expected risk premium on the market portfolio is 6.5 percent. If the Treasury bill rate is 3 percent and the yield on its debt is 4%, what is the company's cost of capital assuming the tax rate is 0%.

In: Finance

What are the drift speeds of Li+, Na+, and K+ in water when a potential difference...

What are the drift speeds of Li+, Na+, and K+ in water when a potential difference of 10 V is applied across a 1.00 cm conductivity cell? How long would it take an ion to move from one electrode to the other? In conductivity measurements it is normal to use alternating current: what are the displacements of the ions in centimeters during a half cycle of 1.0 kHz applied potential.

In: Chemistry

Write a JAVA program that displays a table of the Celsius temperatures and their Fahrenheit equivalents....

Write a JAVA program that displays a table of the Celsius temperatures and their Fahrenheit
equivalents.
 The formula for converting a temperature from Celsius to Fahrenheit is
F = 9/ 5 C + 32
where F → Fahrenheit temperature
C → Celsius temperature.
 Allow the user to enter the range of temperatures in Celsius to be converted into Fahrenheit.
 Your program must use a loop to display the values of the temperature conversions (see sample
output).


Sample Output:
Welcome to the Temperature Converter!! Enter the range of temperatures in Celsius to be converted into
Fahrenheit
Enter minimum temperature in Celsius:
­5
Enter maximum temperature in Celsius:
7
The corresponding Fahrenheit equivalents are:
­5.0 C 23.0 F
­4.0 C 24.8 F
­3.0 C 26.6 F
­2.0 C 28.4 F
­1.0 C 30.2 F
0.0 C 32.0 F
1.0 C 33.8 F
2.0 C 35.6 F
3.0 C 37.4 F
4.0 C 39.2 F
5.0 C 41.0 F
6.0 C 42.8 F
7.0 C 44.6 F
Goodbye!

In: Computer Science

1.) Two securities have the following characteristics: E(Ra)= 0.06​ 0.04 E(Rb)= 0.08​ 0.10 A) Fill in...

1.) Two securities have the following characteristics:

E(Ra)= 0.06​ 0.04

E(Rb)= 0.08​ 0.10

A) Fill in the missing cells in the table.

For each of two correlation cases, corr. = -1 and corr. = 0, calculate the attainable portfolios' mean and standard deviation from combining the two assets together using weights in increments of 25% from 1 to 0. Also, calculate the minimum risk portfolio's weights, mean and standard deviation for each correlation case. Assume that the risk free rate is .04. Hint: in some of the cases, filling in the cells requires no calculations.

Corr = 0

Corr = -1

Weight in A

Weight in B

E(Rp)

E(Rp)

1.0

0.0

0.06

0.75

0.25

0.03905

0.005

0.50

0.50

0.07

0.05385

0.25

0.75

0.075

0.065

0.0

1.0

0.10

0.10

Minimum risk portfolio for corr=0

0.06275

NA

NA

Minimum risk portfolio for corr=-1

0.7143

0.2857

NA

NA

0.0657

NA = not applicable

E(Ra)= 0.06​ 0.04

E(Rb)= 0.08​ 0.10

In: Finance

1) For the following reaction, Kc = 255 at 1000 K. CO (g) + Cl2 (g)...

1) For the following reaction, Kc = 255 at 1000 K.
CO (g) + Cl2 (g) ⇌ COCl2 (g)
A reaction mixture initially contains a COconcentration of 0.1550 M and a Cl2concentration of 0.175 M at 1000 K.
1a)What is the equilibrium concentration of
CO at 1000 K?
1b)What is the equilibrium concentration of
Cl2 at 1000 K?
c)What is the equilibrium concentration of
COCl2 at 1000 K?
2) At 650 K, the reaction MgCO3(s)⇌MgO(s)+CO2(g) has Kp=0.026. A 12.5 L container at 650 K has 1.0 g of MgO(s) and CO2 at P = 0.0260 atm. The container is then compressed to a volume of 0.500 L .Find the mass of
MgCO3 that is formed.
3) Consider the following reaction:
A(g)⇌2B(g)
Find the equilibrium partial pressures of A and Bfor each of the following different values of Kp. Assume that the initial partial pressure of B in each case is 1.0 atm and that the initial partial pressure of A is 0.0 atm. Make any appropriate simplifying assumptions.
Kp= 1.2
Kp= 2.0×10−4
Kp= 2.0×105

In: Chemistry

Part A The aluminum cup inside your calorimeter weighs 42.95 g. You add 60.51 g of...

Part A The aluminum cup inside your calorimeter weighs 42.95 g. You add 60.51 g of 1.0 M acetic acid solution and 49.33 g of 1.0 M sodium hydroxide solution to the calorimeter. Both solutions have an initial temperature of 19.9 oC, and the final temperature after addition is 26.7 oC. What is the heat of neutralization for the amounts of reactants used, in units of J? Assume that: the calorimeter is completely insulated the heat capacity of the empty calorimeter is the heat capacity of the aluminum cup. the density of the two solutions is the same as that of water: 1.00 g/mL. the heat capacity of the two slutions is the same as that of water: 4.184 J g-1 oC-1. Perform all calculations without rounding, but then provide your answer to the correct number of significant figures. Part B What are the moles of the limiting reagent? Part C What is the molar enthalpy of neutralization determined from the calorimeter experiment, in units of kJ/mol? Use unrounded values in your calculation, but then provide your answer to the correct number of significant figures.

In: Chemistry

A 1000MVA, 20kV, 60 Hz three phase generator is connected to an infinite bus through a...

A 1000MVA, 20kV, 60 Hz three phase generator is connected to an infinite bus through a 1000MVA, 20kV? / 345kVY transformer to a 345kV circuit breaker and a 345kV transmission line. The generator reactances are X``d=0.17, X`d=0.30, and Xd=1.5 per unit on a 1000MVA, 20kV base. Generator time constants are T``d=0.05 seconds, T`d=1.0 seconds, and TA=0.10 seconds. The transformer series reactance is 0.10 per unit on the transformer ratings as a base. Neglect transformer losses, excitation current, and transformer time constants. The far end of the line is considered to be an infinite bus operating at 1.0 per unit voltage on the transformer ratings as a base. The line reactance is +j0.20 per unit on the same base as everything else. A three phase short circuit occurs on the line side of the transformer when the generator operates at no load. Breakers interrupt the fault three cycles after it begins. Determine the subtransient current through the transformer in per unit and the rms asymmetrical fault current that the breakers interrupt assuming maximum dc offset.

In: Electrical Engineering

A voltaic cell is assembled under standard conditions based on the following reaction : Ni(s) +...

A voltaic cell is assembled under standard conditions based on the following reaction :

Ni(s) + 2 Ag+(aq) → Ni+2(aq) + 2 Ag(s)

Indicate which statements, if any, about this voltaic cell are true by checking the box in front of each true statment. -

The voltaic cell will always produce a positive potential. If the [Ni2+] is doubled while [Ag+] remains standard, the intial potential produced by the voltaic cell will double.

If the [Ag+] is doubled while [Ni+2] remains standard, the intial potential produced by the voltaic cell will double.

If [Ni2+] less than 1.0 M is used while [Ag+] remains standard , the initial potential will be greater than the standard potential for the voltaic cell.

If [Ag+] less than 1.0 M is used while [Ni+2] remains standard , the initial potential will be greater than the standard potential for the voltaic cell.

The potential produced by the voltaic cell may be affected by temperature.

The value of K for the voltaic cell reaction is greater than 1.

The value of K for the voltaic cell reaction is less than 1.

In: Chemistry

Determine the batch weights needed for all materials for a 10 yd3 batch given the following...

Determine the batch weights needed for all materials for a 10 yd3 batch given the following information. Show all work for partial credit.

Slump = 4 inch maximum

w/cm = 0.45

Cementitious content = 525 lbs/yd3

Slag content = 30% by weight

Fly ash content = 30% by weight

CA (limestone) specific gravity (SSD) = 2.49

FA (sand) specific gravity (SSD) = 2.58

Cement (type I) specific gravity = 3.14

Slag (grade 100) specific gravity = 2.86

Fly ash (class C) specific gravity = 2.59

Air content = 1.0 percent (non-air entrained)

CA absorption = 1.0%

CA moisture content = 2.5%

FA absorption = 1.5%

FA moisture content = 3.3%

Aggregate Volume: 55% CA, 45% FA

Material

Uncorrected batch weights for 1 yd3

Corrected batch weights for 1 yd3

Batch weights for 10 yd3

Portland Cement

Slag

Fly Ash

Water

Coarse Aggregate

Fine Aggregate

In: Civil Engineering

The developer of a new filter for filter-tipped cigarettes claims that it leaves less nicotine in...

The developer of a new filter for filter-tipped cigarettes claims that it leaves less nicotine in the smoke than does the current filter. Because cigarette brands differ in a number of ways, he tests each filter on one cigarette of each of nine randomly selected brands and records the difference in nicotine content. His results are given in the table below.

Brand

A

B

C

D

E

F

G

H

J

Old Filter nicotine, mg

0.7

0.8

0.8

0.9

0.9

1.0

1.2

1.2

1.8

New Filter nicotine, mg

0.6

0.6

0.7

0.8

0.7

1.0

0.8

0.9

1.5

Does the data give convincing evidence that the filter tips leave less nicotine in the smoke? Follow the 4-step process.

old=c(.7, .8, .8, .9, .9, 1, 1.2, 1.2, 1.8)

new=c(.6, .6, .7, .8, .7, 1, .8, .9, 1.5)

YOU MUST FOLLOW THE 4-STEP PROCESS

STATE:

PLAN:

DO:

CONCLUSION:

Thank you!

In: Statistics and Probability