Questions
Given two dependent random samples with the following results: Population 1 20 22 44 42 28...

Given two dependent random samples with the following results:

Population 1 20 22 44 42 28 48 39
Population 2 30 30 32 45 18 43 32

Use this data to find the 99% confidence interval for the true difference between the population means. Assume that both populations are normally distributed.

Copy Data

Step 1 of 4 :  

Find the point estimate for the population mean of the paired differences. Let x1 be the value from Population 1 and x2 be the value from Population 2 and use the formula d=x2−x1 to calculate the paired differences. Round your answer to one decimal place.

Step 2 of 4:

Calculate the sample standard deviation of the paired differences. Round your answer to six decimal places.

Step 3 of 4:

Use the 99% confidence interval for the true difference between the population means. Assume that both populations are normally distributed.

Step 4 of 4:

Construct the 99% confidence interval. Round our answers to one decimal places.

In: Statistics and Probability

5) In order for the viruses to escape extinction, they have to keep evolving. Two different...

5) In order for the viruses to escape extinction, they have to keep evolving. Two different bacteriophages that infect two different bacteria had critical mutations. One mutation is at the OR2 region while the other one is at OL2.

A) What will happen when the mutation is at OR region and the bacteria is in a poor environmental condition? (7 pts)

B) What will happen when the mutation is at OL region and the bacteria is in a poor environmental condition? (7 pts)

In: Biology

Seasonal affective disorder (SAD) is a type of depression during seasons with less daylight (e.g., winter...

Seasonal affective disorder (SAD) is a type of depression during seasons with less daylight (e.g., winter months). One therapy for SAD is phototherapy, which is increased exposure to light used to improve mood. A researcher tests this therapy by exposing a sample of patients with SAD to different intensities of light (low, medium, high) in a light box, either in the morning or at night (these are the times thought to be most effective for light therapy). All participants rated their mood following this therapy on a scale from 1 (poor mood) to 9 (improved mood). The hypothetical results are given in the following table.

   Light Intensity
Low Medium High
Time of
Day
Morning 5 5 7
6 6 8
3 4 6
7 7 8
5 9 5
6 8 8
Night 5 6 8
8 8 7
6 7 6
7 5 8
4 9 7
3 8 6

(a) Complete the F-table and make a decision to retain or reject the null hypothesis for each hypothesis test. (Round your answers to two decimal places. Assume experimentwise alpha equal to 0.05.)

Source of
Variation
SS df MS F
Time of day
Intensity
Time of
day ×
Intensity
Error   
Total


State the decision for the main effect of the time of day.

Retain the null hypothesis.Reject the null hypothesis.     


State the decision for the main effect of intensity.

Retain the null hypothesis.Reject the null hypothesis.     


State the decision for the interaction effect.

Retain the null hypothesis.Reject the null hypothesis.     


(b) Compute Tukey's HSD to analyze the significant main effect.

The critical value is  for each pairwise comparison.

In: Statistics and Probability

Seasonal affective disorder (SAD) is a type of depression during seasons with less daylight (e.g., winter...

Seasonal affective disorder (SAD) is a type of depression during seasons with less daylight (e.g., winter months). One therapy for SAD is phototherapy, which is increased exposure to light used to improve mood. A researcher tests this therapy by exposing a sample of patients with SAD to different intensities of light (low, medium, high) in a light box, either in the morning or at night (these are the times thought to be most effective for light therapy). All participants rated their mood following this therapy on a scale from 1 (poor mood) to 9 (improved mood). The hypothetical results are given in the following table.

   Light Intensity
Low Medium High
Time of
Day
Morning 5 5 7
6 6 8
3 4 6
7 7 8
5 9 5
6 8 8
Night 5 6 8
8 8 7
6 7 6
7 5 8
4 9 7
3 8 6

(a) Complete the F-table and make a decision to retain or reject the null hypothesis for each hypothesis test. (Round your answers to two decimal places. Assume experimentwise alpha equal to 0.05.)

Source of
Variation
SS df MS F
Time of day
Intensity
Time of
day ×
Intensity
Error   
Total


State the decision for the main effect of the time of day.

Retain the null hypothesis.Reject the null hypothesis.     


State the decision for the main effect of intensity.

Retain the null hypothesis.Reject the null hypothesis.     


State the decision for the interaction effect.

Retain the null hypothesis.Reject the null hypothesis.     


(b) Compute Tukey's HSD to analyze the significant main effect.

The critical value is  for each pairwise comparison.

In: Statistics and Probability

A new car that is a gas- and electric-powered hybrid has recently hit the market. The...

A new car that is a gas- and electric-powered hybrid has recently hit the market. The distance travelled on 1 gallon of fuel is normally distributed with a mean of 50 miles and a standard deviation of 8 miles. Find the probability of the following events:

A. The car travels more than 54 miles per gallon.

Probability =  

B. The car travels less than 42 miles per gallon.

Probability =  

C. The car travels between 44 and 57 miles per gallon.

Probability =  

In: Statistics and Probability

1.-The following data were used in a regression study. Observation 1 2 3 4 5 6...

1.-The following data were used in a regression study.

Observation 1 2 3 4 5 6 7 8 9

xi

2 3 4 5 7 7 7 8 9

yi

4 5 4 7 4 6 9 6 11

(a)Develop an estimated regression equation for these data. (Round your numerical values to two decimal places.)

ŷ =______

2.-The following data show the brand, price ($), and the overall score for six stereo headphones that were tested by a certain magazine. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from 0 (lowest) to 100 (highest). The estimated regression equation for these data is

ŷ = 20.987 + 0.340x, where x = price ($) and y = overall score.

Brand Price ($) Score
A 180 78
B 150 73
C 95 59
D 70 54
E 70 40
F 35 26

(a)Compute SST, SSR, and SSE. (Round your answers to three decimal places.)

SST=___

SSR=___

SSE=___

(b)Compute the coefficient of determination r2.(Round your answer to three decimal places.)

r2=___

c)What is the value of the sample correlation coefficient? (Round your answer to three decimal places.)____

In: Statistics and Probability

There are 180 primary schools in a country area having an average of 30 or more...

There are 180 primary schools in a country area having an average of 30 or more people under the age of 21 per class. A sample of 30 schools drawn using systematic sampling with an interval of k = 6.

Serial number

1

2

3

4

5

6

   7

8

9

10

No. of students

60

200

45

50

40

79

35

41

30

120

Serial number

11

12

13

14

15

16

17

18

19

20

No. of students

300

65

111

120

200

42

51

67

32

40

Serial number

21

22

23

24

25

26

27

28

29

30

No. of students

46

55

250

100

63

90

47

82

31

50

  1. Estimate total number of students.
  2. Estimate average number of students per farm.
  3. The variance of the sample mean of students per farm.
  4. 95% confidence interval for the total number of students.

In: Statistics and Probability

Question 1: There are 180 primary schools in a country area having an average of 30...

Question 1:

There are 180 primary schools in a country area having an average of 30 or more people under the age of 21 per class. A sample of 30 schools drawn using systematic sampling with an interval of k = 6.

Serial number

1

2

3

4

5

6

   7

8

9

10

No. of students

60

200

45

50

40

79

35

41

30

120

Serial number

11

12

13

14

15

16

17

18

19

20

No. of students

300

65

111

120

200

42

51

67

32

40

Serial number

21

22

23

24

25

26

27

28

29

30

No. of students

46

55

250

100

63

90

47

82

31

50

  1. Estimate total number of students.
  2. Estimate average number of students per farm.
  3. The variance of the sample mean of students per farm.
  4. 95% confidence interval for the total number of students.

In: Advanced Math

Write a 200-250 word summary of this passage: The Government’s Position on Illegal Mining             Laws...

Write a 200-250 word summary of this passage:

The Government’s Position on Illegal Mining

            Laws in South Africa prohibit any one without a license to mine or process gold. However, local authorities lack the manpower needed to properly monitor the thousands of abandoned mine shafts. The South African government is concerned that the large number of “freelance” miners, coupled with a decline in some sectors (e.g. gold) is having a significant negative impact on tax revenues. South Africa’s Chamber of Mines, an industry association, estimates that South Africa loses about 5% of its potential annual mineral production to illegal mining. This lost production is valued at around $2 billion. The government estimated that in 2010, it had lost approximately $500 million in tax revenues and [lost] export revenue due to illegal mining 8). These lost funds could have been used to support much-needed social service programs for the country’s poor and unemployed.   

In: Economics

Delta, United, and American Airlines announced purchases of planes on July 18 (7/18), February 12 (2/12),...

Delta, United, and American Airlines announced purchases of planes on July 18 (7/18), February 12 (2/12), and October 7 (10/7), respectively.

  

              Delta              United          American
Date Market
Return
Company
Return
Date Market
Return
Company
Return
Date Market
Return
Company
Return
7/12 −.34 −.47    2/8 −.83     −1.06     10/1 .54    .27    
7/13 .00 .24      2/9 −.93 −1.06     10/2 .44    .67    
7/16 .54 .80      2/10 .44 .18     10/3 1.14    1.14    
7/17 −.54     −.28      2/11 .64     1.66     10/6 .14    −1.14    
7/18 −2.13     1.25    2/12 −.34     −.07 10/7 −2.24    −.28    
7/19 −.88     −.62      2/15 1.14 1.70     10/8 .54    .54    
7/20 −.93 −1.09    2/16 .54     .54     10/9 −.34    −.18    
7/23 .74     .47    2/17 −.34     −.18 10/10 .34    −.08    
7/24 .24     .09      2/18 .34     .17     10/13 .00    −.14

   

Given the above information, calculate the cumulative abnormal return (CAR) for these stocks as a group. (A negative answer should be indicated by a minus sign. Leave no cells blank - be certain to enter "0" wherever required. Do not round intermediate calculations and round your answers to 2 decimal places, e.g., 32.16.)

  

Abnormal returns (Ri – R­M)
Days from announcement Delta United American Sum Average abnormal return Cumulative abnormal return
−4                  
−3                  
−2                  
−1                  
  0                  
  1                  
  2                  
  3                  
  4                  

In: Finance