Scenario 8.2

The undergraduate grade point average (GPA) for students admitted to the top graduate business schools was 3.37. Assume this estimate was based on a sample of 90 students admitted to the top schools. Using past years' data, the population standard deviation can be assumed known as 0.30.  

1. Based on the information in Scenario 8.2, you are to construct a 95% confidence interval estimate of the mean undergraduate GPA for students admitted to the top graduate business schools, that is
[ Lower limit , Upper limit ].

The Lower limit of this 95% confidence interval is equal to ? (to 2 decimals)?

2. Based on the information in Scenario 8.2, you are to construct a 95% confidence interval estimate of the mean undergraduate GPA for students admitted to the top graduate business schools, that is
[ Lower limit , Upper limit ].

The Upper limit of this 95% confidence interval is equal to ? (to 2 decimals)?

You are interested in finding a 95% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 12 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 8 7 25 13 23 26 6 6 6 28 8 12 a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean commute for non-residential college students is between and miles. c. If many groups of 12 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of commute miles.

You are interested in finding a 90% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 11 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 25 21 26 6 25 14 26 24 7 10 14 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean commute for non-residential college students is between and miles. c. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of commute miles.

Let’s represent 61 students sitting in a row as a simple string, 61 characters long. Students not wearing a mask are represented by the space character. Students wearing a mask are represented by an asterisk (*). On the first day, only one student, sitting in the middle of the row is wearing a mask. Our initial string looks like this: " * " Students will decide whether to wear a mask the next day according to the following rule: If a student is sitting next to exactly one student wearing a mask (on the left or the right) then they will wear a mask to the next class. Otherwise they won’t wear a mask the next day. How does the mask-wearing behavior change over time. Generate the subsequent strings for 100 subsequent classes. Embed your output inside your code as a triple-quoted string. Here are the first few classes: " * " " * * " " * * " " * * * * " (should look like a pyramid with space in middle of third row)

Dr. Vegapunk thinks that watching anime (Japanese animated shows) decreases social skills in college students. To test this, Dr. Vegapunk randomly selected 30 brooklyn college students and assigned them to watch an episode of anime everyday for a week. After the week, each of the students answered a questionnaire about their social skills. The results showed that the sample had a mean social skills score of 7.3 and a standard deviation of 2.4. A previous study showed that the overall population of brooklyn college students had a mean social skills score of 6.2, but the standard deviation was not reported. Dr. Vegapunk decides to use an alpha level of 0.05.

a) what test should he use?

b) what is the alternative hypothesis?

c) what is the null hypothesis?

d) what is the critical value?

e) what is the obtained statistic?

f) what should he conclude?

You have been hired by the Pierce College Center for Academic Success. Your job is to go to student clubs and organizations and make a presentation on "Secrets to Succeed in College". Read Chapter 14 before you complete this assignment. Please

Think through the 3x3 process

Do some research and identify:

1. Habits of successful students
2. Strategies for Studying
3. Prepare for test
4. Common misconceptions and mistakes students make in classes
5. Time Management
6. Importance of connecting with students and faculty
7. Financial Aid

Now prepare a PowerPoint report that you would use to make your presentation to students.

• Remember the 7x7 rule
• Remember the outline (Tell them what you are going to tell them, tell them, tell them what you told them)
• Remember to include visual aids that augment your slide and help with understanding and retention
• Capture their attention in the first few slides

1. Scores on an MBA placement exam are reported to have a normal distribution with standard deviation 18. The exam officials stated that the average score for all students was 70. You take a random sample of 50 students and find their average score is 67. Use your data to estimate the mean score for all students taking the MBA placement exam -Verify your answer using calculations and show your work.

2. Students at the union want to estimate the average number of ounces of coffee in a cup. They take a random sample of 40 cups and find the mean is 5.2 ounces. Assume amount dispensed has a normal distribution and that the standard deviation is set at 0.24 ounces per cup. Find your best estimate for the average amount of coffee being dispensed by this machine. Verify your answer using calculations and show your work.

2. A night-club owner has both the student (S) and non-student (NS) customers. The demand for drinks by a typical student is QS = 18 - 3P. The demand for drinks by a typical non-student customer is QNS = 10 – 2P. There are equal number of students and non-students. The marginal cost of each drink is $2. If the club owner could easily identify the groups and can serve each group by offering an entry-fee to the club and number of drink tokens

(a) What would be the entry-fee and the number of drink tokens for each student.

(b) What would be the entry-fee and the number of drink tokens for non-each student.

(c) If there were 100 students and 100 non-students, what would the club owner’s profit be under this pricing regime?

(d) What would you call this pricing regime?

1. In C++, Mrs. Jones wishes to computerize her grading system. She gives 5 tests but only counts the 4 highest scores. Input the 5 test scores and output the average of the highest four. And using the following grading scale, 90-100 A, 80-89 B, 70-79 C, 60-69 D, and below 60 F, output the student’s letter grade. After creating this code, Modify the above to calculate the grade for all students in the class. The first input value will be the number of students in the class. You will then need to use a loop to input the students’ names as well as their 5 grades. Inside the loop (after calculating the average for the student) you will need to add each student’s average to a sum variable because at the end, you will need to print out the class average as well as each students’ names and letter grades.

A survey of undergraduate college students at a small university was recently done by an administrator in charge of residential life services. A random sample of 300 students was selected from each class level (freshman, sophomore, junior, senior). Each student was asked to complete and return a short questionnaire on quality of campus residence. Some students returned the questionnaire, and some didn't. This is summarized in the table below:

What percentage of seniors returned the questionnaire? a. 53%b. 47.5% c. 28% d. 25%

Of those that returned the survey, what percentage were seniors? a. 53%b. 47.5%c. 28%d. 13%

Which of the following conclusions seems to be supported by the data? a. Juniors and seniors appear to be more likely to return the survey than freshmen and sophomores. b. Juniors and seniors are happier with the quality of campus residences than freshmen and sophomores. c. Students that did not return the questionnaire are unhappy with the quality of campus residences. d. The percentage of students returning the questionnaire is the same for each class.