Questions
*ratings for typed answers ONLY* Answer the following question: How would your results differ if you...

*ratings for typed answers ONLY*

Answer the following question: How would your results differ if you performed the experiment on Mars? with the given information below!

Using the slope of your T2 versus L plot, determine the acceleration due to gravity.

The slope of the graph = 0.042924

Acceleration due to gravity 39.47/0.042924=939,761

Acceleration due to gravity = 9.39 m/s2

Based on your results, please answer the following questions:

  1. How close is your experimentally determined gravitational acceleration to 9.81 m/s2? What are potential sources for error in the experiment?

Based on our calculus, our result equals 9.39 m/s2 is close to the value of 9.81 m/s2. The explanation for the small difference is represented by potential errors that took place during the experiment. In most cases, this is due to human error. This can include parallax error that took place when the measurement of lengths was done or a mistake in recording the period of time.

  1. For small angles, does the pendulum's period of oscillation depend on the initial angular displacement from equilibrium? Explain.

It is important to understand that the period T is dependent on the length of the string. As we can see, the higher the length is, the longer the value of T is. Because of that, the period T won't be dependent on the mass of the initial angular displacement.

  1. Why is it a good idea to use a relatively heavy mass in this experiment? What would you say to a colleague that wanted to use only one washer as the pendulum mass?

An important thing during this experiment is to keep the string as straight as possible during the entire period of motion. In order to do that, it needs to use a relatively high mass to straighten the line. Using only one washer can lead to an incorrect result. This is because one washer represents a small weight, and the air resistance will be more effective.

In: Physics

Dataset #2 – Star War Film Data Description: Weekly domestic box office revenues for the 8...

Dataset #2 – Star War Film Data

Description: Weekly domestic box office revenues for the 8 Star War films

Research ‘Question’: Find a ‘best’ linear model to predict Star War revenue/day using the number of theaters, number of weeks since release, film number, and release year.

theaters weeknum film year revperday
3672 1 IV 1977 18498679.7
3672 2 IV 1977 9505314.86
3672 3 IV 1977 4127697.71
3672 4 IV 1977 2632591
3422 5 IV 1977 1950438.14
3311 6 IV 1977 2521766.29
3186 7 IV 1977 2831227.86
2681 8 IV 1977 1023363.71
2170 9 IV 1977 652710.714
1851 10 IV 1977 566439
1202 11 IV 1977 250623.714
907 12 IV 1977 179533.714
505 13 IV 1977 102494.857
311 14 IV 1977 74403.1429
206 15 IV 1977 44651.5714
215 16 IV 1977 46953.5714
228 17 IV 1977 54924.2857
172 18 IV 1977 29591.1429
291 19 IV 1977 76476.1429
270 20 IV 1977 59581
160 21 IV 1977 41030.1429
111 22 IV 1977 28579.4286
57 23 IV 1977 22707.5714
43 24 IV 1977 17242.4286
40 25 IV 1977 11668.7143
30 26 IV 1977 9229
3682 1 V 1980 15161652.6
3682 2 V 1980 8844278.29
3682 3 V 1980 5120454.57
3387 4 V 1980 1772898.57
3025 5 V 1980 1165040.57
2505 6 V 1980 1340427.71
2505 7 V 1980 1944470
2015 8 V 1980 799467
1550 9 V 1980 421755.857
1077 10 V 1980 303789.143
783 11 V 1980 142854.857
502 12 V 1980 85785.1429
352 13 V 1980 52545.1429
441 14 V 1980 70452.4286
388 15 V 1980 45788.2857
388 16 V 1980 41332.7143
360 17 V 1980 39414.5714
205 18 V 1980 24388.8571
151 19 V 1980 17734.5714
95 20 V 1980 14462.7143
80 21 V 1980 12256.4286
72 22 V 1980 4412
15 23 V 1980 786.285714
7 24 V 1980 455.285714
3855 1 VI 1983 17580664.1
3855 2 VI 1983 7119019.71
3805 3 VI 1983 3913192.71
3004 4 VI 1983 2412629
2725 5 VI 1983 1652119.43
2002 6 VI 1983 977608.429
1460 7 VI 1983 643752.429
1008 8 VI 1983 404027.429
605 9 VI 1983 240410.429
409 10 VI 1983 169831.286
310 11 VI 1983 107789.429
248 12 VI 1983 80801.4286
391 13 VI 1983 95609.8571
391 14 VI 1983 90454.4286
321 15 VI 1983 38485
228 16 VI 1983 29893
246 17 VI 1983 25054
164 18 VI 1983 11661.4286
119 19 VI 1983 9036
74 20 VI 1983 8862.57143
55 21 VI 1983 7250
55 22 VI 1983 5731.71429
3858 1 I 1999 20897581.3
3858 2 I 1999 9015073
3858 3 I 1999 3487897.43
3325 4 I 1999 1834563.57
2750 5 I 1999 1438515.14
2424 6 I 1999 1818900.29
2316 7 I 1999 1315771.29
1555 8 I 1999 510037.571
1003 9 I 1999 345916.714
560 10 I 1999 159016.429
340 11 I 1999 96117.5714
245 12 I 1999 69097
160 13 I 1999 49419.4286
441 14 I 1999 136217
422 15 I 1999 93123.1429
331 16 I 1999 57197.7143
231 17 I 1999 39329.1429
191 18 I 1999 29226.5714
140 19 I 1999 22458.7143
89 20 I 1999 14974.7143
4285 1 II 2002 19483946.1
4285 2 II 2002 7050087.71
4005 3 II 2002 3828435.43
3125 4 II 2002 2158583
2585 5 II 2002 1212925.71
1955 6 II 2002 817540.571
1322 7 II 2002 488799.571
1017 8 II 2002 417103.143
775 9 II 2002 193287.571
589 10 II 2002 143490.429
320 11 II 2002 59758.8571
241 12 II 2002 41315.4286
408 13 II 2002 74103.8571
377 14 II 2002 54086.4286
283 15 II 2002 38864.1429
225 16 II 2002 27574.1429
159 17 II 2002 18940
105 18 II 2002 14270.4286
90 19 II 2002 9984.85714
56 20 II 2002 8214.28571
52 21 II 2002 4788.28571
38 22 II 2002 2020.85714
4325 1 III 2005 21314847.9
4455 2 III 2005 6561318.43
4393 3 III 2005 3879632
3455 4 III 2005 1973952.71
2771 5 III 2005 1146060.29
1936 6 III 2005 718753.857
1508 7 III 2005 474352.286
1091 8 III 2005 403442.857
744 9 III 2005 173298.571
415 10 III 2005 78098.7143
301 11 III 2005 51525.8571
190 12 III 2005 33442.8571
505 13 III 2005 84180.1429
356 14 III 2005 51179.8571
245 15 III 2005 33814.8571
201 16 III 2005 21102
135 17 III 2005 17775.7143
95 18 III 2005 11938.8571
44 19 III 2005 7837.85714
44 20 III 2005 6345.28571
36 21 III 2005 3118.28571
23 22 III 2005 1052.42857
4125 1 VII 2015 24281289.7
4125 2 VII 2015 8218801.86
4125 3 VII 2015 3098252
3577 4 VII 2015 1644693.14
1840 5 VII 2015 1302432.86
1732 6 VII 2015 1294747
1732 7 VII 2015 918122.286
1507 8 VII 2015 442270.857
941 9 VII 2015 291175.571
725 10 VII 2015 168580.857
465 11 VII 2015 109324.714
365 12 VII 2015 71774.2857
409 13 VII 2015 93213.2857
321 14 VII 2015 77634.8571
303 15 VII 2015 45363.7143
208 16 VII 2015 30144.8571
122 17 VII 2015 20494.5714
94 18 VII 2015 14027.7143
85 19 VII 2015 12463.4286
66 20 VII 2015 8202.42857
4375 1 VIII 2017 32302438.4
4375 2 VIII 2017 10059634.3
4145 3 VIII 2017 4872357.86
3175 4 VIII 2017 2777846.71
2414 5 VIII 2017 1630078.29
1738 6 VIII 2017 963457.571
1328 7 VIII 2017 558613
1092 8 VIII 2017 564588.286
810 9 VIII 2017 196717.429
601 10 VIII 2017 136677.857
320 11 VIII 2017 76497
252 12 VIII 2017 53219.8571
407 13 VIII 2017 86566.5714
330 14 VIII 2017 57112.1429
240 15 VIII 2017 35131
163 16 VIII 2017 22387.2857
225 17 VIII 2017 21222.2857
85 18 VIII 2017 10420.1429
78 19 VIII 2017 5208.14286

In: Statistics and Probability

Question to answer after EXPERIMENT OF SPECTROPHOTOMETRIC DETERMINATION OF TRACE Fe Principles The purpose of this...

Question to answer after EXPERIMENT OF SPECTROPHOTOMETRIC DETERMINATION OF TRACE Fe

Principles The purpose of this experiment is to determine the concentration of iron present as a trace constituent (ppm) in an aqueous sample by a spectrophotometric method. One of the most sensitive methods for the determination of iron involves the formation of the orange-red iron (II) orthophenanthroline complex. This complex has an absorption maximum at 508 nm, is stable over a long period of time, and follows Beer's Law quite faithfully.

The chemistry involved is straightforward. Hydroxylamine hydrochloride is used to reduce all Fe3+ present to Fe2+. Since orthophenanthroline (abbreviated as phen) is a weak base and an acid medium must be used in order to prevent precipitation of the iron as Fe(OH)2, the principal complexing species is the phenanthrolium ion (phenH+ ). The complex formation reaction:

Fe2+ + 3phenH+  Fe(phen)3 2+ + 3H+

has an equilibrium constant of 2.5 x 106 , so complex formation may be considered quantitative. Although pH control is not essential, too high of an H+ concentration (pH<2) can inhibit formation of the complex, while too high of a pH can cause the loss of iron by precipitation. Thus, the solution is buffered to be to about a pH of 3.5.

Since the system obeys Beer's Law, above, a plot of absorbance at 508 nm versus iron concentration yields a straight line. Thus, one can prepare a set of standard solutions of known concentrations, establish a straight line, and prepare the unknown solution in exactly the same way. If the absorbance of the unknown solution is measured, the unknown concentration may be determined from the analytical curve generated with the standard solutions.

Questions:

1. The ferrous ammonium sulfate used as a standard in this experiment is not of primary standard quality, yet you were not instructed to standardize this reagent 81 before use. Why is it not necessary to standardize this analytical reagent before use in this experiment? Explain.

2. Describe two reasons why deviations to Beer's Law (i.e. nonlinearity) can occur.

3. The sensitivity of spectrophotometric methods can greatly exceed sensitivities attainable with classical wet chemical methods. How do the Fe concentrations analyzed in this spectrophotometric experiment compare with the Fe concentrations used in the redox titration experiment? Be quantitative!

In: Chemistry

Write a class encapsulating the concept of a corporate name (for example, IBM), assuming a corporate...

Write a class encapsulating the concept of a corporate name (for example, IBM), assuming a corporate name has the following attribute: the corporate name. Include a constructor, the accessors and mutators, and methods toString() and equals(). Also include and method that returns a potential domain name by adding a www. at the beginning and .com at the end of the corporate name (for instance, if the corporate name is IBM, that method should return www.ibm.com). Write a client class to test all the methods in your class.

In: Computer Science

Complete Answer Must Compile in Visual Code in template Form Code, Must Reflect in UI. 1.           ...

Complete Answer Must Compile in Visual Code in template Form Code, Must Reflect in UI.

1.            Add a new text box - Mavenlink Project Name

2.            Once we enter project name and project code , on tab change Mavenlink Project Name should be set as

Project Code - Project Name

Example :

Project Code =   T1002

Project Name =   TEST123

So in this case Mavenlink Project Name will be T1002 - TEST123

In: Computer Science

In an ADC, assume that Vref is connected to 2.3 V. Find the following. Assume an...

In an ADC, assume that Vref is connected to 2.3 V. Find the following. Assume an 9-bit option.

a-) Step Size = Answer mV (answer must have 3 digits after the decimal point, rounded).

b-) D8..D0 values if Vin = 1.39V Answer (answer should be rounded and then converted)

c-) D8..D0 values if Vin = 2.17V Answer (answer should be rounded and then converted)

d-) Vin if D8..D0 values are 001010101 => Answer V (answer must have 3 digits after the decimal point, rounded).

e-) Vin if D8..D0 values are 111011011 => Answer V (answer must have 3 digits after the decimal point, rounded).

In: Electrical Engineering

Using a light source with a power density of 500 W / m2 for a PV...

Using a light source with a power density of 500 W / m2 for a PV module with a surface area of 0.92 m2, the measured values at the Tcell = 55 ˚C are given as follows.
 The current and voltage value corresponding to the maximum power point is Vmpp = 30 V and Impp = 1.45.
 The open circuit voltage is Voc 38 V and the short circuit current is Isc 1.70.
 The temperature coefficient for this module Voc is 0.16 V / ° C (ignore for Isc).
According to this, calculate the following.
a) What is the efficiency of this module for the specified measurement conditions?
b) Calculate the Voc, Isc, Vm, Im, and Pmax values for this module in standard test measurement conditions (STC).
c) What is the efficiency of the module in STC?

In: Physics

(a) Find the equilibrium solution, or critical point, of the given system. (b) Use a computer...

(a) Find the equilibrium solution, or critical point, of the given system.

(b) Use a computer to draw a direction field and phase portrait centered at the critical point.

(c) Describe how solutions of the system behave in the vicinity of the critical point.

x′ =−0.25x−0.75y+8, y′ =0.5x+y−11.5

(d) Let x= xc+u and y= yc+v, where xc and yc give the critical point you found in (a). Plug these into the system and show that you obtain a homogeneous system u′ = Au for u = (u v)T .

(e) Solve the resulting homogeneous system for u and v, and show that the solutions you obtain match the phase portrait that you generated in (b).

In: Advanced Math

A ballistic pendulum consists of a large heavy mass, M on the end of a very...

A ballistic pendulum consists of a large heavy mass, M on the end of a very light rod of length L. The rod is free to pivot at the top and the mass is attached at the bottom, so it hangs like a pendulum. A second mass, m, is fired horizontally at speed v straight into the large mass, and they stick together. The pendulum swings to a maximum angle ?m.

a)Show that you can measure v by measuring ?m, that is obtain an expression for v in terms of M, m, L, g and ? m.

b)Look up the mass and speed of a bullet, and figure out how mass

ive M should be if L is about 0.25 m and we want a maximum angular displacement no greater than 45?.

In: Physics

We have to calculate the value of Power of an electric DC motor IN WATTS made...

We have to calculate the value of Power of an electric DC motor IN WATTS made from scratch. The only known values that we have are: The Voltage (V) which is 9V and the current (I) that we are using which is 3 A, also the value of "n" which is n= 90.16 m (the number of turns of the wire used in the motor)

I already asked here for this problem and someone answered this:

Voltage = 9 V, current = 3 A, number of turns = n = 90.16

Power of motor = n*V*I = 90.16*9*3=2434.32 Watt

But I don’t think this is correct since the motor has power in and power out. Can someone else help? Thank you!

In: Physics