1.
Superior Paver sued homeowners Pamela and Mark for $14,350 it claimed was still owed as extra work incurred in installing concreate pavers in the driveway of their residence. Pamela and Mark had previously paid the $45,000 contract price, and they counterclaimed for $60,500 for the reasonable cost of making the contractor’s work conform to the contract. The evidence established that Superior did not install a proper base of 3” to 4” of crushed limestone before installing the pavers as required by the contract, which caused the pavers to move creating gaps between the pavers and causing water to flow into the garage. To correct the problem the pavers needed to be removed and the area excavated and replaced with a crushed limestone base before, again, installing the pavers. Superior claimed it had substantially performed the contract as their performance resulted in a fully usable driveway, and, the proper remedy, if any, was the reduction of the market value of Pamela and Mark’s property due to any defective performance. Superior further asserted that the cost of redoing the entire job would be economic waste.
The result?
2.
A franchisee owner (Owner) of a popular hotel chain was bound by their franchise agreement with Mega Hotel Inc (Mega). Part of Owner’s obligations included that Owner maintain their 60 room hotel to at least minimum quality assurance standards. Owner’s hotel failed five consecutive quality inspections over two years, with the inspector noting damaged guest rooms, burns in the bedding, and severely stained carpets. Mega canceled the franchise agreement. Owner sued Mega for wrongfully canceling the agreement (breach of contract).
Owner’s defense against Mega cancelling the franchise was the following. The bridge repairs on the road leading to the hotel had adversely affected the hotels ability to live up to the franchise agreement. Further, the repairs made it commercially impractical for Owner to live up to the franchise agreement. For reasons such as the inability of hotel staff to arrive on time and properly clean the rooms. Will Owner’s defense prevail?
In: Accounting
In a survey of 3,827 travelers, 1,459 said that location was very important for choosing a hotel and 1,175 said that reputation was very important in choosing an airline. Complete parts (a) through (c) below.
a. Construct a 95% confidence interval estimate for the population proportion of travelers who said that location was very important for choosing a hotel.
b. Construct a 95% confidence interval estimate for the population proportion of travelers who said that reputation was very important in choosing an airline.
c. Write a short summary of the information derived from (a) and (b) Which of the following is the best summary of the information derived from (a)?
A.One can be 95% confident that the sample proportion of all travelers who said that location was very important for choosing a hotel lies within the interval in (a).
B.One can be 95% confident that the population proportion of all travelers who said that location was very important for choosing a hotel lies within the interval in (a).
C.There is a 95% probability that the sample proportion of all travelers who said that location was very important for choosing a hotel lies within the interval in (a).
D.There is a 95% probability that the population proportion of all travelers who said that location was very important for choosing a hotel lies within the interval in (a).
Which of the following is the best summary of the information derived from (b)?
A.One can be 95% confident that the population proportion of all travelers who said that reputation was very important in choosing an airline lies within the interval in (b).
B.One can be 95% confident that the sample proportion of all travelers who said that reputation was very important in choosing an airline lies within the interval in (b).
C.There is a 95% probability that the sample proportion of all travelers who said that reputation was very important in choosing an airline lies within the interval in (b).
D.There is a 95% probability that the population proportion of all travelers who said that reputation was very important in choosing an airline lies within the interval in (b).
In: Statistics and Probability
The mean area of homes in a certain city built in 2009 was 2438 square feet. Assume that a simple random sample of 11 homes in the same city in 2010 had a mean area of 2,295 squarefeet, with a deviation of 225 square feet. An insurance company wants to know if the mean area of homes built in 2010 is less than that of homes built in 2009.
In: Statistics and Probability
In: Operations Management
You are trying to develop a strategy for investing in two different stocks. The anticipated annual return for a $1,000 investment in each stock under four different economic conditions has the following probability distribution:
Probability : 0.1 , 0.3, 0.3 , 0.3 .
Economic Condition: Recession, slow growth, moderate growth, fast growth.
Return} -Stock X: -100 , 0 , 80 , 150 .
- Stock Y: 50 , 150 , -20 , -100 .
a) Covariance of stock X and Y
In: Statistics and Probability
Conduct a financial analysis of water system operation for the City of Smallville over the next ten years. Use the data below. If you lack data, make assumptions or ask for it. Analyze O&M, capital costs and cash flows. The water system currently serves 100,000 people and is to be expanded to handle a population influx of 5% per year for the next ten years. Land use is mixed residential and commercial, but no industry. Base your estimates on residential demands and assume that commercial water use adds 15% to the residential use. You expand the system to accommodate growth and simultaneously maintain and renew the existing system during the period. The system is currently 15 years old and has depreciated on a 30-year depreciation cycle at 3.33% per year on a straight-line basis.
Your system expansion will be staged so that half is built now and half in five years. When you also invest in system renewal to overcome depreciation, the investments would be added to the costs of system expansion. System renewal is governed by the rule that current system value must not fall below 50% of replacement value.
You will take a loan for the first part of the construction and issue bonds for the next increment (in five years). You may vary from this if you choose different capital financing vehicles. Loans are “revolving loans” and come from an infrastructure bank. Annual loan payments begin in one year and continue for ten years. Recommend how to finance the expansion and renewal with funding from plant investment fees, water use fees, sales tax revenues, and property tax revenues. Commercial property has 25% of the assessed valuation of the residential property.
|
Current population |
100,000 (33,333 households) |
|
Rate of population growth |
5% per year for ten years; 0% after that. |
|
Per capita water usage (average) |
150 gpcd |
|
Land Use |
Mixed residential and commercial. |
|
Planning horizon for capital improvements |
10 years to meet demands; 30 yrs for system life |
|
Plant investment fee |
$5,000 per house connection |
|
Current water fees |
$2.50/1000 gal |
|
Property tax dedicated to water system improvements |
0.8 mills |
|
Assessed valuation residential (market value * 0.2) |
$980 million |
|
Sales tax dedicated to water system |
0.8% |
|
Current anticipated taxable sales |
$800 million per year |
|
Interest rate on loan (due in ten years) |
8% |
|
Interest rate on bonds (use 20 year life) |
6% |
|
Projected inflation rate |
0% |
|
Capital cost of new or replacement system |
$3,000 for each new person |
|
Current value of existing system (average age15 years) |
Replacement value less 15 years depreciation |
|
Capital improvement goal |
System value not below 50% of replacement |
|
Depreciation of assets |
3.33% per year |
|
O&M cost |
$50 per capita per year |
1. Set up a spreadsheet and forecast cash flows for the next fifteen years.
2. Schedule for capital improvements (the capital improvement program)
In: Accounting
Reduce the following "top -b -n 1" output to its first, second, and last columns, and include only those processes belonging to "root". Use fscanf and strtok please. top - 05:00:58 up 543 days, 8:56, 1 user, load average: 0.11, 0.03, 0.01 Tasks: 112 total, 1 running, 111 sleeping, 0 stopped, 0 zombie %Cpu(s): 0.1 us, 0.1 sy, 0.0 ni, 99.8 id, 0.0 wa, 0.0 hi, 0.0 si, 0.0 st KiB Mem : 499976 total, 41456 free, 51636 used, 406884 buff/cache KiB Swap: 0 total, 0 free, 0 used. 392008 avail Mem 1 root 20 0 185324 4988 3032 S 0.0 1.0 7:08.14 systemd 2 root 20 0 0 0 0 S 0.0 0.0 0:00.06 kthreadd 3 root 20 0 0 0 0 S 0.0 0.0 3:19.04 ksoftirqd/0 5 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 kworker/0:0H 7 root 20 0 0 0 0 S 0.0 0.0 7:29.74 rcu_sched 8 root 20 0 0 0 0 S 0.0 0.0 0:00.00 rcu_bh 9 root rt 0 0 0 0 S 0.0 0.0 0:00.00 migration/0 10 root rt 0 0 0 0 S 0.0 0.0 4:36.48 watchdog/0 11 root 20 0 0 0 0 S 0.0 0.0 0:00.00 kdevtmpfs 12 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 netns 13 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 perf 14 root 20 0 0 0 0 S 0.0 0.0 0:13.48 khungtaskd 15 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 writeback 16 root 25 5 0 0 0 S 0.0 0.0 0:00.00 ksmd 17 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 crypto 18 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 kintegrityd 19 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 20 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 kblockd 21 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 ata_sff 22 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 md 23 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 devfreq_wq 27 root 20 0 0 0 0 S 0.0 0.0 22:01.55 kswapd0 28 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 vmstat 29 root 20 0 0 0 0 S 0.0 0.0 0:00.00 fsnotify_ma+ 30 root 20 0 0 0 0 S 0.0 0.0 0:00.00 ecryptfs-kt+ 46 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 kthrotld 47 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 acpi_therma+ 48 root 20 0 0 0 0 S 0.0 0.0 0:00.00 vballoon 49 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 50 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 51 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 52 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 53 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 54 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 55 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 56 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 57 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 58 root 20 0 0 0 0 S 0.0 0.0 0:00.00 scsi_eh_0 59 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 scsi_tmf_0 60 root 20 0 0 0 0 S 0.0 0.0 0:00.00 scsi_eh_1 61 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 scsi_tmf_1 67 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 ipv6_addrco+ 80 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 deferwq 81 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 charger_man+ 128 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 129 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 130 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 131 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 132 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 133 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 134 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 135 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 137 root 20 0 0 0 0 S 0.0 0.0 0:00.00 scsi_eh_2 138 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 scsi_tmf_2 145 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 kpsmoused 496 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 raid5wq 526 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 bioset 551 root 20 0 0 0 0 S 0.0 0.0 4:41.75 jbd2/vda1-8 552 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 ext4-rsv-co+ 614 root 20 0 27708 2248 1924 S 0.0 0.4 48:36.07 systemd-jou+ 621 root 0 -20 0 0 0 S 0.0 0.0 0:36.37 kworker/0:1H 632 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 iscsi_eh 648 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 ib_addr 651 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 ib_mcast 652 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 ib_nl_sa_wq 653 root 20 0 0 0 0 S 0.0 0.0 0:00.00 kauditd 654 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 ib_cm 657 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 iw_cm_wq 660 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 rdma_cm 689 root 20 0 102968 228 0 S 0.0 0.0 0:00.00 lvmetad 796 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 kvm-irqfd-c+ 1427 root 20 0 5220 116 0 S 0.0 0.0 25:47.02 iscsid 1428 root 10 -10 5720 3524 2436 S 0.0 0.7 123:01.13 iscsid 1449 message+ 20 0 42972 2008 1392 S 0.0 0.4 0:10.67 dbus-daemon 1455 syslog 20 0 256392 1564 0 S 0.0 0.3 13:44.06 rsyslogd 1459 root 20 0 28728 2752 2248 S 0.0 0.6 0:37.68 systemd-log+ 1462 root 20 0 653228 3996 1192 S 0.0 0.8 4:47.32 lxcfs 1469 root 20 0 4396 1156 1072 S 0.0 0.2 0:00.00 acpid 1471 root 20 0 274488 1016 212 S 0.0 0.2 27:45.06 accounts-da+ 1483 root 20 0 27728 2176 1896 S 0.0 0.4 1:34.16 cron 1490 daemon 20 0 26044 1724 1520 S 0.0 0.3 0:00.84 atd 1520 root 20 0 13372 192 52 S 0.0 0.0 0:04.41 mdadm 1594 root 20 0 14472 1588 1452 S 0.0 0.3 0:00.00 agetty 5845 root 20 0 0 0 0 S 0.0 0.0 0:00.00 kworker/0:0 5906 root 20 0 92832 6816 5884 S 0.0 1.4 0:00.04 sshd 5942 root 20 0 21428 5372 3368 S 0.0 1.1 0:00.06 bash 5958 root 20 0 0 0 0 S 0.0 0.0 0:00.01 kworker/u2:1 6134 root 20 0 65512 5844 5140 S 0.0 1.2 0:00.00 sshd 6135 sshd 20 0 65512 3200 2484 S 0.0 0.6 0:00.00 sshd 6141 root 20 0 65512 5784 5072 S 0.0 1.2 0:00.00 sshd 6142 sshd 20 0 65512 3208 2484 S 0.0 0.6 0:00.00 sshd 6147 root 20 0 40388 3492 2988 R 0.0 0.7 0:00.00 top 6433 root 20 0 277088 764 0 S 0.0 0.2 0:00.56 polkitd 8836 systemd+ 20 0 100324 1552 1312 S 0.0 0.3 0:10.54 systemd-tim+ 9724 root 20 0 42364 2344 1808 S 0.0 0.5 0:08.68 systemd-ude+ 14463 postgres 20 0 293408 14644 12936 S 0.0 2.9 0:23.56 postgres 14465 postgres 20 0 293408 1704 0 S 0.0 0.3 0:00.67 postgres 14466 postgres 20 0 293408 3408 1704 S 0.0 0.7 0:22.84 postgres 14467 postgres 20 0 293408 2076 372 S 0.0 0.4 0:22.46 postgres 14468 postgres 20 0 293792 3324 1328 S 0.0 0.7 0:13.53 postgres 14469 postgres 20 0 148392 1876 116 S 0.0 0.4 0:13.18 postgres 17737 www-data 20 0 819836 4652 1880 S 0.0 0.9 0:36.39 apache2 17738 www-data 20 0 819844 4948 2008 S 0.0 1.0 0:36.33 apache2 18046 root 20 0 36840 2220 1460 S 0.0 0.4 0:00.00 systemd 18051 root 20 0 209056 2344 0 S 0.0 0.5 0:00.00 (sd-pam) 20779 root 20 0 0 0 0 S 0.0 0.0 0:01.12 kworker/u2:0 25939 root 20 0 71584 4064 2876 S 0.0 0.8 0:17.42 apache2 27861 root 20 0 0 0 0 S 0.0 0.0 0:01.00 kworker/0:1 32109 root 20 0 14656 1328 1192 S 0.0 0.3 0:00.02 agetty 32497 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 xfsalloc 32498 root 0 -20 0 0 0 S 0.0 0.0 0:00.00 xfs_mru_cac+ 32699 root 20 0 65512 2516 1804 S 0.0 0.5 5:54.88 sshd
A start of this problem:
#include
#include
#include
int main()
{
FILE *myfile = fopen("out.top.txt","r");
char a[500] = "this is about as big as this line will be";
// top - 11:45:12 up 7 min, 2 users, load average: 0.34, 1.01, 0.66
// 8729 root 20 0 0 0 0 S 0.0 0.0 0:00.03 kworker/u8+
while (fscanf(myfile,"%[^\n]\n",a)==1) {
// printf("line in is %s\n",a);
char *b1 = strtok(a," "); // printf("first word is %s\n",b1);
if (atoi(b1) > 0) {
// printf("first word is a number\n");
char *b2 = strtok(NULL,", "); // printf("second word is %s\n",b2);
if (!strcmp(b2,"root")) printf("%s owner is %s\n",b1,b2);
}
}
}In: Computer Science
|
DataSpan, Inc., automated its plant at the start of the current year and installed a flexible manufacturing system. The company is also evaluating its suppliers and moving toward Lean Production. Many adjustment problems have been encountered, including problems relating to performance measurement. After much study, the company has decided to use the performance measures below, and it has gathered data relating to these measures for the first four months of operations. |
|
Month |
|||||
| 1 | 2 | 3 | 4 | ||
| Throughput time (days) | ? | ? | ? | ? | |
| Delivery cycle time (days) | ? | ? | ? | ? | |
| Manufacturing cycle efficiency (MCE) | ? | ? | ? | ? | |
| Percentage of on-time deliveries | 77% | 78% | 83% | 90% | |
| Total sales (units) | 10,530 | 10,550 | 10,540 | 10,550 | |
|
Management has asked for your help in computing throughput time, delivery cycle time, and MCE. The following average times have been logged over the last four months: |
|
Average per Month (in days) |
|||||||||
| 1 | 2 | 3 | 4 | ||||||
| Move time per unit | 0.5 | 0.6 | 0.7 | 0.5 | |||||
| Process time per unit | 0.3 | 0.5 | 0.5 | 0.7 | |||||
|
Wait time per order before start |
9.6 | 8.0 | 5.0 | 4.0 | |||||
| Queue time per unit | 4.1 | 3.7 | 2.7 | 1.7 | |||||
| Inspection time per unit | 0.6 | 0.3 | 0.6 | 0.4 | |||||
| Required: | |
| 1-a. | Compute the throughput time for each month. (Round your answers to 1 decimal place.) |
| 1-b. |
Compute the manufacturing cycle efficiency (MCE) for each month. (Round your answers to 1 decimal place (i.e., 0.123 should be entered as 12.3).) |
| 1-c. |
Compute the delivery cycle time for each month. (Round your answers to 1 decimal place.) |
| 3-a. |
Refer to the move time, process time, and so forth, given for month 4. Assume that in month 5 the move time, process time, and so forth, are the same as in month 4, except that through the use of Lean Production the company is able to completely eliminate the queue time during production. Compute the new throughput time and MCE. (Round your Throughput Time to 1 decimal place. Round your MCE percentage answer to 1 decimal place (i.e., 0.123 should be entered as 12.3).) |
| 3-b. |
Refer to the move time, process time, and so forth, given for month 4. Assume in month 6 that the move time, process time, and so forth, are again the same as in month 4, except that the company is able to completely eliminate both the queue time during production and the inspection time. Compute the new throughput time and MCE. (Round your Throughput Time to 1 decimal place. Round your MCE percentage answer to 1 decimal place (i.e., 0.123 should be entered as 12.3).) |
In: Accounting
A feedwater heater is a device to heat the feedwater before it goes into the boiler. This device receives one stream of saturated vapor at 0.8 MPa and another stream of compressed liquid at 0.8 MPa and 60 oC. These two streams combined to become saturated liquid at 0.8 MPa at the exit of the feedwater heater. The mass flow rate of the compressed liquid is 100 kg/s. Determine a) the mass flow rate of the saturated vapor, b) the exergy destroyed in the feedwater heater (To=300K, Po=0.1 MPa) (10)
In: Mechanical Engineering
Jennifer lifts a 2.4 kg carton of cat litter from the floor to a height of 0.81 m.
(a) How much total work is done on the carton during this operation?
___________J
b) Jennifer then pours 0.7 kg of the litter into the cat's litter box on the floor. How much work is done by gravity on the 0.7 kg of litter as it falls into the litter box?
____________J
In: Physics