A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. SUVs equipped with tires using compound 1 have a mean braking distance of 76 feet and a standard deviation of 8.9 feet. SUVs equipped with tires using compound 2 have a mean braking distance of 80 feet and a standard deviation of 14.6 feet. Suppose that a sample of 45 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1 be the true mean braking distance corresponding to compound 1 and μ2 be the true mean braking distance corresponding to compound 2. Use the 0.1 level of significance.
Step 1 of 4: State the null and alternative hypotheses for the test.
Step 2 of 4: Compute the value of the test statistic. Round your answer to two decimal places.
Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round the numerical portion of your answer to two decimal places.
Step 4 of 4: Make the decision for the hypothesis test. Fail or reject to fail.
In: Statistics and Probability
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. SUVs equipped with tires using compound 1 have a mean braking distance of 5050 feet and a standard deviation of 12.112.1 feet. SUVs equipped with tires using compound 2 have a mean braking distance of 5555 feet and a standard deviation of 9.39.3 feet. Suppose that a sample of 8383 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1μ1 be the true mean braking distance corresponding to compound 1 and μ2μ2 be the true mean braking distance corresponding to compound 2. Use the 0.050.05 level of significance.
Step 1 of 4:
State the null and alternative hypotheses for the test.
Step 2 of 4:
Compute the value of the test statistic. Round your answer to two decimal places.
Step 3 of 4:
Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to three decimal places.
Step 4 of 4:
Make the decision for the hypothesis test.
In: Statistics and Probability
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. SUVs equipped with tires using compound 1 have a mean braking distance of 62 feet and a standard deviation of 10.6 feet. SUVs equipped with tires using compound 2 have a mean braking distance of 68 feet and a standard deviation of 13.9 feet. Suppose that a sample of 77 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1 be the true mean braking distance corresponding to compound 1 and μ2 be the true mean braking distance corresponding to compound 2. Use the 0.05 level of significance.
Step 1 of 4: State the null and alternative hypotheses for the test.
Step 2 of 4: Compute the value of the test statistic. Round your answer to two decimal places.
Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to three decimal places.
Step 4 of 4: Make the decision for the hypothesis test.
In: Statistics and Probability
6. Aminoacyl-tRNA synthetases catalyses _____ 1. DNA replication 2. transcriptional termination 3. the attachment of amino acids to the tRNA molecules. 4. the binding of mRNA to the 30S subunit. 5. the removal of the polypeptide from tRNA in the P site and transferal to the amino acid at the A site 7. If the strand “5'-TACGCCT-3'” is a template strand, what would the mRNA strand look like? 1. 5'-AGGCGUA-3' 2. 3'-AUGCGGA-5' 3. 3'-ATGCGGA-5' 4. 5'-AGGCGTA-3' 5. 5'-UGGCGTU-3' 8. A repressor is a______. 1. regulatory protein that increases the rate of transcription 2. regulatory protein that binds to DNA and inhibits transcription 3. form of positive control. 4. small effector molecule that causes transcription to increase 5. enzyme that converts lactose to allolactose 9. Complete the following statement: When there is lactose in the medium and no glucose, the cAMP concentration is _____. 1. low 2. medium 3. high 4. inhibited by negative feedback 5. negatively regulated 10. Antisense RNA________ 1. carries a codon during translation 2. is a strand of RNA, complementary to a specific mRNA strand. 3. cleaves RNA into fragments 4. functions in the translation of proteins 5. are sequences that increase gene expression
In: Biology
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. SUVs equipped with tires using compound 1 have a mean braking distance of 56 feet and a standard deviation of 6.4 feet. SUVs equipped with tires using compound 2 have a mean braking distance of 58 feet and a standard deviation of 6.6 feet. Suppose that a sample of 80 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1 be the true mean braking distance corresponding to compound 1 and μ2 be the true mean braking distance corresponding to compound 2. Use the 0.05 level of significance.
Step 1 of 4:
State the null and alternative hypotheses for the test.
Step 2 of 4:
Compute the value of the test statistic. Round your answer to two decimal places.
Step 3 of 4:
Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to three decimal places.
Step 4 of 4:
Make the decision for the hypothesis test.
In: Statistics and Probability
Record of product launch success/failure over the last 25 years: COMPANY A
|
Record of product launch success/failure over the last 25 years: COMPANY B
|
1. On an average, how many products are launched successfully by Company A in a given year? Similarly, on an average how many products are launched successfully by Company B in a given year? (4 points)
2. Let us assume that we employ a few different sets of standards for measuring success 3(or failure). Instead of using averages, we use the following alternate benchmarks:
a. Let’s assume that we measure the likelihood of 6 or more successful product launches in any given year by these firms. The underlying idea is that a successful firm should get a majority of its products, if not all, to succeed in any given year. And ‘6’ is a number just past the halfway mark and can be used as a reasonable proxy for ‘majority’ of products (out of 10)
Using this measure of likelihood of at least SIX products succeeding in a given year, which company has a better success rate? (2.5 Points)
In: Statistics and Probability
question 2 when considering the net cash inflows resulting from a capital budgeting decision taxes will:
1-increase the amount of the cash saving by tax rate
2-reduce the amount of the cash savings by (1-tax rate)
3-increase the amount of the cash savings by (1-tax rate)
4- reduce the amount of the cash saving by the (1+tax rate)
5- increase the amount of the cash savings by (1+tax rate)
question 3
opportunity cost is a cost of capital for which of the following sources of funds ?
1-long term debt
2-preferred shares
3-short term debt sold at a discount
4-common shares
5-internally generated cash flow
question 5
comparison of the actual results for a project to the costs and benefits expected at the time the project was selected is referred to as :
1-a cost benefit analysis
2-management control
3-the audit trail
4-capital budgeting
5-a post investment audit
question 6
the net present value method is better than the internal rate of return because
1-it considers the source of cash flows
2-the NPV of different projects can be added together and investment may have multiple required rates of return
3-managers generally find the npv method easier to understand
4-IRR focuses more on accounting income
5-it always yields the same result as IRR
question 8
the time value of money
1-is the opportunity cost of not having the money today
2-is equal to the bank prime rate
3-includes the rate of inflation
4-is the same value for all companies
5-is equal to the rate of inflation
In: Accounting
For any sequence, S[1…n], of length n, a basement is defined as a contiguous subsequence of S, which we denote by S[ i, i + 1, ..., j – 1, j ], with 1 £ i < i + 1 < j – 1 < j £ n, satisfying the following conditions:
The length of a basement is defined as the count of the elements that make up the basement sequence. As an example, for the sequence
S = [3, 2, 0, 0, 0, 0, 4, 4, 6, 5, 5, 5, 3, 7, 7, 7, 7]
We note that [2, 0, 0, 0, 0, 4,] is a basement (which you can verify, using the definition of a basement), and the length of the basement [2, 0, 0, 0, 0, 4,] is 6. The starting index for this basement is 2 and the ending index for this basement is 7. We also note that [6, 5, 5, 5, 3] is NOT a basement.
|
S[ i ] > S[ i + 1] |
HOLDS / FAILS |
1 £ i < i + 1 < j – 1 < j £ n |
HOLDS / FAILS |
|
S[ j – 1] < S[ j ] |
HOLDS / FAILS |
S[ r ] = S[ t ] for all i < r, t < j |
HOLDS / FAILS |
|
S[ i ] > S[ i + 1] |
HOLDS / FAILS |
1 £ i < i + 1 < j – 1 < j £ n |
HOLDS / FAILS |
|
S[ j – 1] < S[ j ] |
HOLDS / FAILS |
S[ r ] = S[ t ] for all i < r, t < j |
HOLDS / FAILS |
S = [2, 1, 4, 1, 1, 0, 6, 6, 6, 5, 5, 5, 10, 3, 3, 3, 3, 3, 3, 6, 6, 4, 0, 10, 0]
Determine an efficient algorithm to find the starting and ending indices of a basement in a sequence, S, whose length is maximal (in the event that there are multiple basements whose length is maximal, return the starting and indices of ONE of them). (10 points total: Full points given for a linear algorithm).
In: Computer Science
BACHELOR OF TECHNOLOGY: MARINE ENGINEERING
IAA520S: Instrumentation & Automation – Laboratory 1
Student’s Full Name:
-------------------------------------------
Student’s No: -------------------------------
Bench No: ------------------------------
Date: ---------------------------
STEP AND IMPULSE RESPONSE OF FIRST AND SECOND ORDER
SYSTEMS
OBJECTIVES
To determine:
1. Step response of 1st order system
2. Impulse response of 1st order system
3. Step response of 2nd order system
4. Impulse response of 2nd order system
EQUIPMENT:
Computer with Matlab software
MARKS OBTAINED:
Marks
% weight
Part 1 16 25
Part 2 20 60
Part 4+ Report 12 15
TOTAL MARKS 48 100
Part 1: (16)
Pre-Lab Exercise
Obtain step and impulse response of the following systems with
unity feedback connection:
1. G(S) = 1 S+11
2. G(S) = 1 S+2
NB: The prelab must be typed and equations written using the
in-built MS equation.
Part
2:
(20) Lab Exercise
Obtain step and impulse response of the following systems with
unity feedback connection
1. G(S) = 1 S2+3S+4
2. G(S) = 19 (S+4)(S+8)
Part 3:Post-Lab
1. What do you mean by rise time? (2)
2. Why is less overshoot desired for practical systems?
(2)
Part 4: Report Prepare your Lab report according to the following
general format: (8) Cover Page (Make the Lab manual cover page your
cover page).
I. Objectives of the Lab
II. Introduction to the Lab by giving a brief theory about the Lab
III. Give a list of equipment used
IV. Outline the procedure followed during the execution of the lab
V. Present your results (give appropriate tables and diagrams)
VI. Give an analysis of your
VII. Give a concise conclusion
In: Electrical Engineering
Dealing Cards
Write a program that deals a deck of card into 4 hands – Each hand having 13 cards.
Hints – Import below java utility to use the random function.
import java.util.*;
Random rand = new Random();
int r = rand.nextInt(52); // this will generate random numbers between 0-52
to get a value between 1-13, use the mod function and get the remainder
if your number is 15, 15%13 has a remainder of 2. 2 is your face card.
---------------------------------------------------------------------------
11 = jack
12= Queen
13= King
Card is a CLUB - If your generated number is between (1-13)
Card is a Diamond - If your generated number is between (14-26)
Card is a Spade - If your generated number is between (27-39)
Card is a Heart - If your generated number is between (40-52)
Your program output should look like this below
----------------------------------------------------------------------------------------------------------------------------------
Deck of cards shuffled into 4 hands
8 1 7 18 43 26 31 2 12 3 40 22 4
29 9 10 11 5 35 47 36 25 14 17 39 23
21 52 6 46 38 48 24 16 27 32 13 45 42
49 44 50 20 37 34 51 15 28 30 19 33 41
Face of cards in each Hand
Hand 1:
Clubs: 8 1 7 2 Q 3 4
Diamonds: 5 K 9
Spades: 5
Heart: 4 1
Hand 2:
Clubs: 4 9 10 J 5
Diamonds: Q 1 4
Spades: 3 9 10 K
Heart: 8
Hand 3:
Clubs: 6 K
Diamonds: 10 8 J 3
Spades: K Q 1 6
Heart: K 7 9
Hand 4:
Clubs: K
Diamonds: 7 2
Spades: J 8 2 4
Heart: 6 3 10 5 J Q
In: Computer Science