Questions
Twenty shoppers were given a standard shopping list of a limited number of items (say, twelve) for the upscale clothing requirements of one of their school-going children for the coming school year at an expensive private school.

 

General Instructions:

If nothing is specified, use LS = 5% and you may use MiniTab (or Excel) to perform the hypothesis test.

Question 2:

Twenty shoppers were given a standard shopping list of a limited number of items (say, twelve) for the upscale clothing requirements of one of their school-going children for the coming school year at an expensive private school. They were given the money by an independent firm called Market Research Inc. (MRI) to purchase the items for one child, from the standard list, from 4 different clothing chain stores. The dollar amount the shoppers spent on their clothing for each child, are given under the columns specifying which chain store they bought their clothing from. The MRI wanted only to compare the mean amount of money the various shoppers had spent in the 4 chain stores.

a. Clearly specify what hypothesis the MRI should test? Conduct the 4 step Hypothesis test at 1% level of significance (LS) and reach the appropriate conclusion regarding mean amounts spent in the 4 stores, by using the critical value of the statistic. You may use “SS” given by MiniTab.

b. Explain in words why, you can block the ‘Shopper’ variable. What is this method called?

c. Use the MiniTab approach to show how this can be demonstrated with appropriate analysis. Use 1% Level of Significance. (Hint: Think of ‘Shoppers’ and ‘Stores’ as the two factors.)

d. Which analysis is more appropriate? The one you did in Qu.#2 ‘c’ above or the one you did in Qu.#2 ‘a’? Explain with some specific numerical comparisons of relevant quality.

Data below..

Shopper Store 1 Store 2 Store 3 Store 4 Explanations            
1 1021.05 1086.66 1050.84 1115.64                
2 689.31 738.72 718.29 1096.02                
3 605.97 662.58 631.53 854.01                
4 1121.04 1172.79 1145.79 1153.17 Upscale School Clothing Prices at the 4 Chain Stores in $    
5 611.1 623.43 637.56 1193.94                
6 1211.04 1247.04 1240.56 1152.45 Column C1: Shopper (all shoppers have a standard list of Clothings to purchase)
7 801 885.42 830.25 1118.61 Column C2: Cost of Clothing on shopper's list at Store 1    
8 409.77 469.89 437.67 587.52 Column C3: Cost of Clothing on shopper's list at Store 2    
9 985.05 1061.82 1009.53 1263.51 Column C4: Cost of Clothing on shopper's list at Store 3    
10 301.05 341.82 327.42 1171.26 Column C5: Cost of Clothing on shopper's list at Store 4    
11 1605.24 1625.13 1631.97 960.84                
12 250.2 347.4 275.85 1111.77 Suggestion#1: Stack the Data in C2 to C5 in C9 and "ID" it in C10 for Qu.#1
13 558.72 625.68 584.73 676.08 Suggestion#2: In C11 properly identify the "Which Shopper" for Qu.#2  
14 232.11 280.17 260.55 777.51                
15 800.1 867.96 827.28 1313.01                
16 431.1 443.97 457.2 1053.54                
17 1004.13 1097.37 1029.96 945.09                
18 919.98 922.86 950.04 1309.77                
19 800.1 842.85 828.99 666.18                
20 830.97 977.67 858.78 1227.42

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(a) 120
(b) 29
(c) 56
(d) 58
(e) 59

(Please show work or explain. I already have the answer. just need to know how to solve it)

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Amos pays $1,200 (ck # 1013) for a one-year liability insurance policy. The policy coverage takes effect on August 1.

What will the adjusted entry for trial balance for September be???

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The City Council has gathered data on the number of minor traffic accidents and the number...

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X (Soccer Games) 20 30 10 12 15 25 24

Y (minor accdnt) . 6 9 4 5 7 8 9

Plot the data

Develop the estimating equation that describes the data

Predict the number of minor traffic accidents that will occur on a weekend during which 33 soccer games takes place

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  • Benefits of this form of implementation
  • Costs associated with the implementation of each solution
  • A summary of 2–3 paragraphs stating which solution you have decided to implement and what motivated the decision

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Multiple Choice

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There is a limitation to using this method and, statistically, this notion refers to the "power" of a test.

First, let's suppose that you are a disease outbreak coordinator for the Center for Disease Control and Prevention. A recent flu outbreak has led to a successful recovery without long-term problems with probability 93%. Your team runs a test in a small town and determines that, in 20 people, 19 successfully recovered. If you hypothesize that this small town has a higher recover rate, will you be able to reject the null hypothesis with alpha = 0.05? What if 20 successfully recovered? Provide your alpha-observed in both cases.

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