Consider a stationary solution of the Schrodinger Equation with positive energy E for a particle with mass m in the following one-dimensional potential: V (x) = 0 for |x| > a and V (x) = −V0 for |x| ≤ a with V0 > 0. (a) Calculate the transmission and reflection probabilities. (b) Show that the transmission probability is unity for some values of the energy.
In: Physics
Suppose that you are designing a parachute so that the terminal velocity using the parachute will be the same as the velocity at the end of a normal (frictionless) jump from a height of 2.80 m. If the parachute exerts a drag force of - b v where v is in meters per second and if the parachute is designed for an 70.0 kg person, what is b?
In: Physics
1. Consider a charge of -1 nC at (-1,0) m, and a charge of +1 nC at (1,0). Calculate the electric potential everywhere in the plane.
2. For the same geometry as in the first problem, calculate the electric field everywhere, using -?V =E. In 2 dimensions, ?V= (?subxV, ?subyV) = ?subxV x^ + ?suby Vy^
In: Physics
For the 2 × 2 game, find the optimal strategy for each player. Be sure to check for saddle points before using the formulas.
3 −3 2 3
For row player R:
r1 =
r2 =
For column player C:
c1 =
c2=
Find the value v of the game for row player R.
v =
In: Math
A 15.2% (m/v) solution of sodium chloride (NaCl) is used to prepare 25.0 L of a physiological saline solution with a concentration of 0.154 M NaCl. What volume of the 15.2% (m/V) solution of sodium chloride would be required to make 25.0 L of the physiological saline solution ( 0.154 M NaCl) ?
In: Chemistry
For the following reaction: NiO2(s) + 4 H+(aq) + 2 Ag(s) → Ni2+(aq) + 2 H2O(l) + 2 Ag+(aq) script E° = 2.48 V Calculate the pH of the solution if script E = 2.32 V and [Ag+] = [Ni2+] = 0.012 M. Use the Standard Reduction Table.
In: Chemistry
Complete P9-3 using the template provided here.
| P9-3 Perform ratio analysis, and discuss change in financial position and operating results | |||||||||
| Condensed balance sheet and income statement data for Jergan Corporation are presented here. | |||||||||
| JERGAN CORPORATION | |||||||||
| Balance Sheet | |||||||||
| December 31 | |||||||||
| 2017 | 2016 | 2015 | |||||||
| Cash | $30,000 | $20,000 | $18,000 | ||||||
| Accounts receivable (net) | 50,000 | 45,000 | 48,000 | ||||||
| Other current assets | 90,000 | 95,000 | 64,000 | ||||||
| Investments | 55,000 | 70,000 | 45,000 | ||||||
| Plant and equipment (net) | 500,000 | 370,000 | 358,000 | ||||||
| $725,000 | $600,000 | $533,000 | |||||||
| Current liabilities | $85,000 | $80,000 | $70,000 | ||||||
| Long-term debt | 145,000 | 85,000 | 50,000 | ||||||
| Common stock, $10 par | 320,000 | 310,000 | 300,000 | ||||||
| Retained Earnings | 175,000 | 125,000 | 113,000 | ||||||
| $725,000 | $600,000 | $533,000 | |||||||
| JERGAN CORPORATION | |||||||||
| Income Statement | |||||||||
| For the Year Ended December 31 | |||||||||
| 2017 | 2016 | ||||||||
| Sales revenue | $740,000 | $600,000 | |||||||
| Less: Sales return and allowances | 40,000 | 30,000 | |||||||
| Net sales | 700,000 | 570,000 | |||||||
| Cost of goods sold | 425,000 | 350,000 | |||||||
| Gross profit | 275,000 | 220,000 | |||||||
| Operating expenses (including income taxes) | 180,000 | 150,000 | |||||||
| Net income | 95,000 | 70,000 | |||||||
| Additional information: | |||||||||
| 1. | The market price of Jergan's common stock was $7.00, $7.50, and $8.50 for 2015, | ||||||||
| 2016, and 2017, respectively. | |||||||||
| 2. | You must compute dividends paid. All dividends were paid in cash. | ||||||||
| Instructions | |||||||||
| (a) | Compute the following ratios for 2016 and 2017. | ||||||||
| (1) Profit margin. | 5. Price-earnings ratio. | ||||||||
| (2) Gross profit rate. | 6. Payout ratio. | ||||||||
| (3) Asset turnover. | 7. Debt to assets ratio. | ||||||||
| (4) Earnings per share. | |||||||||
| (b) | Based on the ratios calculated, discuss briefly the improvement or lack thereof in the | ||||||||
| financial position and operating results from 2016 to 2017 of Jergan Corporation. | |||||||||
| NOTE: Enter a number in cells requesting a value; enter either a number or a formula in cells with a "?" . | |||||||||
| (a)(1) | Profit margin | ||||||||
| 2017 | 2016 | ||||||||
| Net income | Value | Value | |||||||
| Net sales | Value | Value | |||||||
| Profit margin | ? | ? | |||||||
| (a)(2) | Gross profit rate | ||||||||
| 2017 | 2016 | ||||||||
| Gross profit | Value | Value | |||||||
| Net sales | Value | Value | |||||||
| Gross profit rate | ? | ? | |||||||
| (a)(3) | Asset turnover | ||||||||
| 2017 | 2016 | ||||||||
| Total assets, 2017 | Value | ||||||||
| Total assets, 2016 | Value | Value | |||||||
| Total assets, 2015 | Value | ||||||||
| Average total assets | ? | ? | |||||||
| 2017 | 2016 | ||||||||
| Net sales | Value | Value | |||||||
| Average total assets | Value | Value | |||||||
| Asset turnover | ? | ? | |||||||
| (a)(4) | Earnings per share | ||||||||
| 2017 | 2016 | ||||||||
| Common shares outstanding, 2017 | Value | ||||||||
| Common shares outstanding, 2016 | Value | Value | |||||||
| Common shares outstanding, 2015 | Value | ||||||||
| Average common shares outstanding | ? | ? | |||||||
| 2017 | 2016 | ||||||||
| Net income - Pfd. Dividends | Value | Value | |||||||
| Average common shares outstanding | Value | Value | |||||||
| Earnings per share | ? | ? | |||||||
| (a)(5) | Price-earnings ratio | ||||||||
| 2017 | 2016 | ||||||||
| Stock price per share | Value | Value | |||||||
| Earnings per share | Value | Value | |||||||
| Price-earnings ratio | ? | ? | |||||||
| (a)(6) | Payout ratio | ||||||||
| 2017 | 2016 | ||||||||
| Prior year's retained earnings | Value | Value | |||||||
| Plus: current year net income | Value | Value | |||||||
| Less: current year's retained earnings | Value | Value | |||||||
| Cash dividends declared | ? | ? | |||||||
| 2017 | 2016 | ||||||||
| Cash dividends declared (common) | Value | Value | |||||||
| Net income | Value | Value | |||||||
| Payout ratio | ? | ? | |||||||
| (a)(7) | Debt to assets ratio | ||||||||
| 2017 | 2016 | ||||||||
| Current Liabilities | Value | Value | |||||||
| Long-term debt | Value | Value | |||||||
| Total liabilities | ? | ? | |||||||
| Total assets | Value | Value | |||||||
| Debt to assets ratio | ? | ? | |||||||
| After you have completed P9-3, consider the additional question. | |||||||||
| 1. | Assume that 2017 net income and total assets changed to $87,000 and total assets to | ||||||||
| $700,000. Show the impact of these changes on the ratios. | |||||||||
In: Accounting
a.A method that accepts no parameters and returns the length of the name, i.e., the sum of the lengths of the three parts of the name.
b.A method that accepts no parameters and returns a String consisting of the three initials IN UPPERCASE.
c.A method that accepts an integer n and returns the nth character in the full three part name.
d.A method that accepts no parameters and returns a String consisting of the last name followed by a comma followed by the first name followed by the middle name. Remember to put spaces between the names.
e.A method that accepts a String and returns true if the String is equal to the first name (use the equals method in the String class!). This is not quite the proper way to define an equals method, as we will learn later.
f.A method that accepts a Name object and returns true if the three parts of the name object are the same as the three parts of “this” Name object.
Create a class called NameDriverwhich contains a main method. Inside the main method, instantiate a Name object using your name and test your methods to make sure they work.Does it work for all name
In: Computer Science
jgrasp environment, java
write a complete program that prompts the user to enter their first name, middle name, and last name (separately). print out thier name and initials, exactly as shown:
your name is: John Paul Chavez
your initials are: J. P. C.
use string method chartAt() to extract the first (zero-th) character from a name(the name is a string type): username.charAt(0).
thank you.
In: Computer Science
CO2(g) + C(s) = 2 CO(g) a) Using the Bouduard reaction, calculate gas composition in a furnace under 1 atm total pressure and 1100 K. b) Under the same furnace conditions, is it possible to reduce VO to V by CO? ( VO + CO = V + CO2 ) C(s) + O2(g) = CO2(g) o GT = - 394100 – 0.84 T J/mol C(s) + ½ O2(g) = CO(g) o GT = - 111700 – 87.65 T J/mol V(s) + ½ O2(g) = VO (s) o GT = - 424700 + 80.04 T J/mol
In: Other