Questions
An investment advisor claimed that BIT return is 2%. Do you agree? Justify your reasoning using...

An investment advisor claimed that BIT return is 2%. Do you agree? Justify your reasoning using a two-tailed hypothesis test approach at the significance level of 5% in Excel.

Date Weekly Return BIT
11/3/13 -46.16
18/3/13 -0.01
25/3/13 39.23
1/4/13 13.07
8/4/13 23.93
15/4/13 41.36
22/4/13 26.5
29/4/13 20.39
6/5/13 25.5
13/5/13 42.52
20/5/13 37.88001
27/5/13 15.66
3/6/13 20.98
10/6/13 25.28
17/6/13 11.97
24/6/13 -2.46
1/7/13 14.95
8/7/13 -3.5
15/7/13 -8
22/7/13 -0.05
29/7/13 25.49
5/8/13 4.099998
12/8/13 9.529999
19/8/13 58.75
26/8/13 36.12
2/9/13 47.87
9/9/13 43.09
16/9/13 42.08
23/9/13 40.24001
30/9/13 51.77
7/10/13 93.52
14/10/13 113.89
21/10/13 133.5
28/10/13 231.05
4/11/13 447.08
11/11/13 874.55
18/11/13 1091.99
25/11/13 916.27
2/12/13 927.8199
9/12/13 681.78
16/12/13 789.11
23/12/13 899
30/12/13 937.92
6/1/14 877.1
13/1/14 900
20/1/14 828.99
27/1/14 750
3/2/14 640
10/2/14 628.37
17/2/14 550
24/2/14 574.73
3/3/14 569.53
10/3/14 546.83
17/3/14 460
24/3/14 418.31
31/3/14 375
7/4/14 467.54
14/4/14 369
21/4/14 402.16
28/4/14 356
5/5/14 410.9
12/5/14 548.66
19/5/14 652.71
26/5/14 650
2/6/14 571.71
9/6/14 590
16/6/14 565
23/6/14 561.2
30/6/14 592.14
7/7/14 514.12
14/7/14 500.84
21/7/14 565.93
28/7/14 587.76
4/8/14 484.97
11/8/14 443
18/8/14 410.53
25/8/14 437.92
1/9/14 462.43
8/9/14 324.44
15/9/14 360.15
22/9/14 253.36
29/9/14 381.64
6/10/14 385.55
13/10/14 349.98
20/10/14 319.9
27/10/14 340.98
3/11/14 363.96
10/11/14 348.09
17/11/14 371.5
24/11/14 376
1/12/14 319.55
8/12/14 334.97
15/12/14 343.46
22/12/14 262.8
29/12/14 250.09
5/1/15 190.02
12/1/15 380.51
19/1/15 189.48
26/1/15 209.59
2/2/15 223.9
9/2/15 223.5
16/2/15 254.85
23/2/15 251.34
2/3/15 305.86
9/3/15 249.82
16/3/15 280
23/3/15 220.56
30/3/15 279.94
6/4/15 265
13/4/15 200
20/4/15 224.68
27/4/15 195.91
4/5/15 245.03
11/5/15 227.36
18/5/15 269.69
25/5/15 228.8
1/6/15 220.5
8/6/15 212.87
15/6/15 225.62
22/6/15 262.18
29/6/15 343.58
6/7/15 312.15
13/7/15 301.96
20/7/15 315
27/7/15 262.04
3/8/15 229.08
10/8/15 257.53
17/8/15 220.4
24/8/15 249.46
31/8/15 230.8
7/9/15 223.27
14/9/15 246.48
21/9/15 250.66
28/9/15 239.59
5/10/15 273.53
12/10/15 300.01
19/10/15 377.69
26/10/15 451.39
2/11/15 371.79
9/11/15 376.89
16/11/15 418.39
23/11/15 440.58
30/11/15 505.46
7/12/15 516.24
14/12/15 481.21
21/12/15 482.38
28/12/15 542.2
4/1/16 454.28
11/1/16 473.92
18/1/16 432.58
25/1/16 429.39
1/2/16 467.05
8/2/16 509.61
15/2/16 506.68
22/2/16 448.07
29/2/16 443.69
7/3/16 484.58
14/3/16 489.97
21/3/16 485.82
28/3/16 455.66
4/4/16 474.93
11/4/16 516.19
18/4/16 488.28
25/4/16 555.87
2/5/16 542.67
9/5/16 512.75
16/5/16 601.27
23/5/16 688.69
30/5/16 803.09
6/6/16 953.05
13/6/16 805.65
20/6/16 797.08
27/6/16 771.54
4/7/16 795.01
11/7/16 793.52
18/7/16 723.18
25/7/16 687.93
1/8/16 650.5
8/8/16 660
15/8/16 670
22/8/16 715.6
29/8/16 714
5/9/16 734.99
12/9/16 686.2
19/9/16 719.42
26/9/16 715.57
3/10/16 754
10/10/16 761.02
17/10/16 825
24/10/16 825.83
31/10/16 831.9
7/11/16 900.52
14/11/16 902.97
21/11/16 924.27
28/11/16 975.2
5/12/16 1006.2
12/12/16 1135.94
19/12/16 1281.4
26/12/16 1144.41
2/1/17 995.16
9/1/17 1123.2
16/1/17 1138.34
23/1/17 1247.74
30/1/17 1241.48
6/2/17 1275.95
13/2/17 1453.46
20/2/17 1590.27
27/2/17 1549.1
6/3/17 1262.27
13/3/17 1177.61
20/3/17 1372.88
27/3/17 1512.83
3/4/17 1488.75
10/4/17 1583.46
17/4/17 1681.71
24/4/17 2096.67
1/5/17 2495.07
8/5/17 2760.85
15/5/17 2994.79
22/5/17 3393.27
29/5/17 3789.46
5/6/17 3488.86
12/6/17 3403.31
19/6/17 3242.76
26/6/17 3315.51
3/7/17 2410
10/7/17 3441.5
17/7/17 3429.74
24/7/17 3960.53
31/7/17 5218.14
7/8/17 5198.76
14/8/17 5520
21/8/17 5918.4
28/8/17 5219.46
4/9/17 4493.05
11/9/17 4525.38
18/9/17 5465.36
25/9/17 5787.35
2/10/17 7126.76
9/10/17 7613.93
16/10/17 7918.65
23/10/17 9592.39
30/10/17 7824.89
6/11/17 10593.55
13/11/17 12197.99
20/11/17 14924.19
27/11/17 21084.87
4/12/17 25886.55
11/12/17 18839.79
18/12/17 18950.74
25/12/17 22762.21
1/1/18 18941.51
8/1/18 15048.37
15/1/18 14345.12
22/1/18 10125.82
29/1/18 10282.72
5/2/18 13238.45
12/2/18 12200.72
19/2/18 14663.94
26/2/18 12043.73
5/3/18 10546.88
12/3/18 10939.19
19/3/18 8735.98
26/3/18 9030.39
2/4/18 10554.32
9/4/18 11257.21
16/4/18 12332.76
23/4/18 12582.62
30/4/18 11460.03
7/5/18 11218.46
14/5/18 9652.02
21/5/18 10133.1
28/5/18 8856.31
4/6/18 8617.19
11/6/18 8152.91
18/6/18 8389.05
25/6/18 8853.63
2/7/18 8455.52
9/7/18 9847.28
16/7/18 11014.06
23/7/18 9459.81
30/7/18 8619.77
6/8/18 8820.44
13/8/18 9072.49
20/8/18 9981.22
27/8/18 8702.43
3/9/18 8958.83
10/9/18 9018.22
17/9/18 9039.68
24/9/18 9164.69
1/10/18 8635.74
8/10/18 8905.48
15/10/18 8919.61
22/10/18 8808.97
29/10/18 8741.39
5/11/18 7479.24
12/11/18 5335.57
19/11/18 5486.65
26/11/18 4814.89
3/12/18 4340.44
10/12/18 5496.18
17/12/18 5356.26
24/12/18 5586.6
31/12/18 4808.14
7/1/19 4862.34
14/1/19 4842.09
21/1/19 4634.24
28/1/19 5032.33
4/2/19 4983.2
11/2/19 5113.99
18/2/19 5240.09
25/2/19 5455.14
4/3/19 5526.45
11/3/19 5517.53
18/3/19 5638.09
25/3/19 7153.71
1/4/19 7114.66
8/4/19 7337.26
15/4/19 7305.25
22/4/19 8020.41
29/4/19 9862.31
6/5/19 11784.94
13/5/19 12517.35
20/5/19 12506.94
27/5/19 10883.83
3/6/19 12861.26
10/6/19 15472.87
17/6/19 15080.16
24/6/19 16268.05
1/7/19 14557.08
8/7/19 14957.73
15/7/19 13791.59
22/7/19 16032.89
29/7/19 16937.56
5/8/19 15248.79
12/8/19

In: Math

Question 24 Part A Each of the following sets of quantum numbers is supposed to specify...

Question 24

Part A

Each of the following sets of quantum numbers is supposed to specify an orbital. Choose the one set of quantum numbers that does not contain an error.

n = 3, l = 2, ml =+3
n = 4, l = 4, ml =0
n = 4, l = 0, ml =-1
n = 5, l = 3, ml =-3
n = 3, l = 1, ml = -2

In: Chemistry

Find the absolute maximum and minimum values of the function f(x, y) = x^2 + ((4/3)...

Find the absolute maximum and minimum values of the function f(x, y) = x^2 + ((4/3) y^3) − 1 on the disk x^2 + y^21.

In: Math

The joint probability distribution of random variables, X and Y, is shown in the following table:...

The joint probability distribution of random variables, X and Y, is shown in the following table: X 2 4 6 Y 1 0.10 0.20 0.08 2 0.06 0.12 0.16 3 0.15 0.04 0.09

(a) Calculate P ( X=4 | Y=1)

(b) Calculate V (Y | X=2) .

(c) Calculate V (3Y-X ) .

In: Statistics and Probability

Curve Fitting and Linear Regression a) Determine the linear regression equation for the measured values in...

Curve Fitting and Linear Regression

a) Determine the linear regression equation for the measured values in the table above.

??

1

2

3

4

Value 1 (????)

0

3

7

10

Value 2 (????)

2

4

9

11

b) Plot the points and the linear regression curve.

c) Determine the Linear Correlation Coefficient (i.e., Pearson’s r) for the dataset in the table above.

In: Statistics and Probability

Stairs Jumping One day, Jojo takes a vacation to the mountains to get away from the...

Stairs Jumping

One day, Jojo takes a vacation to the mountains to get away from the cities. While climbing the mountain, Jojo came to an area filled with thousands of stairs to get to the top. However, there was a rule in the mountain which stated that Jojo had to jump over the stairs with same height to get to the top of the mountain. Listening to these rules, Jojo wanted to know what is the minimum required height he should jump and the minimum number of jumps to reach the top of the mountain. Note: Jojo is on the first stair and the top of the mountain is on the last stair. Jojo can jump several stairs as long as the difference of the height of the steps does not exceed the height of Jojo’s jump.

Format Input:

There are T test cases. Each testcase contains an integer N which represents numbers of stairs that Jojo had to jump. On the next line there are N numbers where each number represents the height of the stair.

Format Output Output:

T line with format “Case # X: Y Z”, where X represents the testcase number, Y represents minimal height Jojo has to jump, and Z represents minimal number of jumps to reach the top of the mountain.

Constraints

1 ≤ T ≤ 50

2 ≤ N ≤ 10000

• 0 ≤ Ai ≤ 109 , where Ai represents i-th height of the stair. • Ai < Aj for every index i < j

Sample Input (standard input):

2

5

1 2 3 4 5

5

1 2 3 4 6

Sample Output (standard output):

Case #1: 1 4

Case #2: 2 3

Explanation In case 1, Jojo will jump 1 unit high because the biggest difference between adjacent stairs is 1. Then Jojo will jump 4 times to reach the top.

In case 2, Jojo will jump 2 units high because the biggest difference between adjacent stairs is 2 on the 4-th and 5-th stairs. Then Jojo made 3 jumps to reach the top with the following simulation.

• In jump 1, Jojo will jump from stair 1 to 3, because the height difference between the 1st and 3rd stairs is still less equal than 2.

• On jump 2, Jojo will jump from stair 3 to 4, with a height difference of 1. Jojo cannot jump directly to stair 5 because the difference in height exceeds the height of Jojo’s jump.

• On jump 3, Jojo will jump from stair 4 to 5, with a height difference of 2

NOTE: USE C LANGUAGE, DONT USE FUNCTION(RESULT,RETURN),VOID,RECURSIVE, USE BASIC CODE AND CODE IT UNDER int main (){, constraint must be the same

In: Computer Science

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the given sample data....

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the given sample data.

An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Listed below are the phenotype codes where

1 equals smooth dash yellow1=smooth-yellow​,

2 equals smooth dash green2=smooth-green​,

3 equals wrinkled dash yellow3=wrinkled-yellow​,

and

4 equals wrinkled dash green4=wrinkled-green.

Do the results make​ sense?

2

1

1

4

1

1

3

4

2

2

2

1

4

1

​(a) The mean phenotype code is?

​(b) The median phenotype code is?

​(c) Select the correct choice below and fill in any answer boxes within your choice

A.The mode phenotype code is?

B.There is no mode.

​(d) The midrange of the phenotype codes is?

Do the measures of center make​ sense

A.Only the​ mean, median, and midrange make sense since the data is nominal.

B.Only the mode makes sense since the data is nominal.

C.All the measures of center make sense since the data is numerical

D.Only the​ mean, median, and mode make sense since the data is numerical.

In: Statistics and Probability

Arguments around the legality and morality of medically assisted suicide have come to light within the...

Arguments around the legality and morality of medically assisted suicide have come to light within the last 2 decades. Opponents of such legislation state that its passing would unfairly promote an ideology that dictates one’s life-worth is based on how much of a burden they become to others. Proponents of such legislation claim that it is an individual’s right to decide when to end their own life. A medical sociologist suggests that one’s state impacts their support for such legislation. The sociologist surveys groups of 3 people from four different states to determine support for legislation based on a scale of 1 to 5 where 1 represents no support and 5 represents complete support.---ANOVA method---

California Oregon Montana Missouri
3 5 2 1
5 4 2 3
1 4 4 2

In: Statistics and Probability

Given the following sample information, test the hypothesis that the treatment means are equal at the...

Given the following sample information, test the hypothesis that the treatment means are equal at the 0.10 significance level:

Treatment 1 Treatment 2

Treatment 3

3 9 6
2 6 3
5 5 5
1 6 5
3 8 5
1 5 4
4 1
7 5
6
4

Complete the ANOVA table. (Round the SS, MS, and F values to 2 decimal places.)

  Source SS DF MS F
  Factor 46.96 Incorrect    2 Correct   23.48 Incorrect    9.30 Incorrect   
  Error 53 Incorrect    21 Correct   2.52 Incorrect   
  Total Not attempted   23 Correct  

Please explain how you got your answer. I am very new to statistics so the clearer the better.

In: Statistics and Probability

The following is a cross-tabulation of the variables gender and units (the number of units in...

The following is a cross-tabulation of the variables gender and units (the number of units in which a student has enrolled) from a recent class survey. Number of Units Gender 1 2 3 4 5 female 4 11 60 191 3 male 2 10 28 86 1 Note that χ 2 tests require all expected frequencies to be at least 5. To ensure this you may need to combine columns in a way that makes sense in the context of a test for association. That is, you could combine columns 1 and 2, but not columns 1 and 4. Assuming the data come from randomly-selected Murdoch University students, test for an association between gender and unit load in the Murdoch University student population. If you find an association, describe it.

In: Math