PA3-1 Preparing a Process Costing Production Report (Weighted-Average Method) [LO 3-2, 3-3, 3-4]

Sandia Corporation manufactures metal toolboxes. It adds all materials at the beginning of the manufacturing process. The company has provided the following information:

Required:
1 & 2. Using the weighted-average method of process costing, complete each of the following steps:

a. Reconcile the number of physical units worked on during the period.  



b. Calculate the number of equivalent units.



c. Calculate the cost per equivalent unit. (Round cost per Equivalent Unit to 5 decimal places.)  



d. Reconcile the total cost of work in process.(Use Cost per Equivalent Unit rounded to 5 decimal places and round your final answers to the nearest whole dollar amount.)

PA3-1 Preparing a Process Costing Production Report (Weighted-Average Method) [LO 3-2, 3-3, 3-4]

Sandia Corporation manufactures metal toolboxes. It adds all materials at the beginning of the manufacturing process. The company has provided the following information:

Required:
1 & 2. Using the weighted-average method of process costing, complete each of the following steps:

a. Reconcile the number of physical units worked on during the period.  



b. Calculate the number of equivalent units.



c. Calculate the cost per equivalent unit. (Round cost per Equivalent Unit to 5 decimal places.)  



d. Reconcile the total cost of work in process.(Use Cost per Equivalent Unit rounded to 5 decimal places and round your final answers to the nearest whole dollar amount.)

International Trade Practice exam
Explain key terms:
1) counter sample
2)FCL
3)FPA
4)INCOTERMS
5)Standby L/C

Problem 10A-10 Comprehensive Standard Cost Variances [LO10-1, LO10-2, LO10-3, LO10-4] "Wonderful! Not only did our salespeople do a good job in meeting the sales budget this year, but our production people did a good job in controlling costs as well,” said Kim Clark, president of Martell Company. “Our $20,825 overall manufacturing cost variance is only .5% of the $4,165,000 standard cost of products made during the year. That's well within the 3% parameter set by management for acceptable variances. It looks like everyone will be in line for a bonus this year." The company produces and sells a single product. The standard cost card for the product follows: Inputs (1) Standard Quantity or Hours (2) Standard Price or Rate Standard Cost (1) × (2) Direct materials 3.50 feet $ 4.30 per foot $ 15.05 Direct labor 2.2 hours $ 9 per hour 19.80 Variable overhead 2.2 hours $ 2.20 per hour 4.84 Fixed overhead 2.2 hours $ 4.50 per hour 9.90 Total standard cost per unit $ 49.59 The following additional information is available for the year just completed: The company manufactured 20,000 units of product during the year. A total of 69,000 feet of material was purchased during the year at a cost of $4.50 per foot. All of this material was used to manufacture the 20,000 units produced. There were no beginning or ending inventories for the year. The company worked 45,500 direct labor-hours during the year at a direct labor cost of $8.85 per hour. Overhead is applied to products on the basis of standard direct labor-hours. Data relating to manufacturing overhead costs follow: Denominator activity level (direct labor-hours) 40,000 Budgeted fixed overhead costs $ 180,000 Actual variable overhead costs incurred $ 113,750 Actual fixed overhead costs incurred $ 177,100 Required: 1. Compute the materials price and quantity variances for the year. 2. Compute the labor rate and efficiency variances for the year. 3. For manufacturing overhead compute: a. The variable overhead rate and efficiency variances for the year. b. The fixed overhead budget and volume variances for the year. (For all requirements, indicate the effect of each variance by selecting "F" for favorable, "U" for unfavorable, and "None" for no effect (i.e., zero variance). Input all amounts as positive values.)

# columns are [0]title [1]year [2]rating [3]length(min) [4]genre [5]budget($mil) [6]box_office_gross($mil)
oscar_data = [
["The Shape of Water", 2017, 6.914, 123, ['sci-fi', 'drama'], 19.4, 195.243464],
["Moonlight", 2016, 6.151, 110, ['drama'], 1.5, 65.046687],
["Spotlight", 2015, 7.489, 129, ['drama', 'crime', 'history'], 20.0, 88.346473],
["Birdman", 2014, 7.604, 119, ['drama', 'comedy'], 18.0, 103.215094],
["12 Years a Slave", 2013, 7.71, 133, ['drama', 'biography', 'history'], 20.0, 178.371993],
["Argo", 2012, 7.517, 120, ['thriller', 'drama', 'biography'], 44.5, 232.324128],
["The Artist", 2011, 7.942, 96, ['drama', 'melodrama', 'comedy'], 15.0, 133.432856],
["The King\'s Speech", 2010, 7.977, 118, ['drama', 'biography', 'history'], 15.0, 414.211549],
["The Hurt Locker", 2008, 7.298, 126, ['thriller', 'drama', 'war', 'history'], 15.0, 49.230772],
["Slumdog Millionaire", 2008, 7.724, 120, ['drama', 'melodrama'], 15.0, 377.910544],
["No Country for Old Men", 2007, 7.726, 122, ['thriller', 'drama', 'crime'], 25.0, 171.627166],
["The Departed", 2006, 8.456, 151, ['thriller', 'drama', 'crime'], 90.0, 289.847354],
["Crash", 2004, 7.896, 108, ['thriller', 'drama', 'crime'], 6.5, 98.410061],
["Million Dollar Baby", 2004, 8.075, 132, ['drama', 'sport'], 30.0, 216.763646],
["The Lord of the Rings: Return of the King", 2003, 8.617, 201, ['fantasy', 'drama', 'adventure'], 94.0, 1119.110941],
["Chicago", 2002, 7.669, 113, ['musical', 'comedy', 'crime'], 45.0, 306.776732],
['A Beautiful Mind', 2001, 8.557, 135, ['drama', 'biography', 'melodrama'], 58.0, 313.542341],
["Gladiator", 2000, 8.585, 155, ['action', 'drama', 'adventure'], 103.0, 457.640427],
["American Beauty", 1999, 7.965, 122, ['drama'], 15.0, 356.296601],
["Shakespeare in Love", 1998, 7.452, 123, ['drama', 'melodrama', 'comedy', 'history'], 25.0, 289.317794],
["Titanic", 1997, 8.369, 194, ['drama', 'melodrama'], 200.0, 2185.372302],
["The English Patient", 1996, 7.849, 155, ['drama', 'melodrama', 'war'], 27.0, 231.976425],
["Braveheart", 1995, 8.283, 178, ['drama', 'war', 'biography', 'history'], 72.0, 210.409945],
["Forrest Gump", 1994, 8.915, 142, ['drama', 'melodrama'], 55.0, 677.386686],
["Schindler\'s List", 1993, 8.819, 195, ['drama', 'biography', 'history'], 22.0, 321.265768],
["Unforgiven", 1992, 7.858, 131, ['drama', 'western'], 14.4, 159.157447],
["Silence of the Lambs", 1990, 8.335, 114, ['thriller', 'crime', 'mystery', 'drama', 'horror'], 19.0, 272.742922],
["Dances with Wolves", 1990, 8.112, 181, ['drama', 'adventure', 'western'], 22.0, 424.208848],
["Driving Miss Daisy", 1989, 7.645, 99, ['drama'], 7.5, 145.793296],
["Rain Man", 1988, 8.25, 133, ['drama'], 25.0, 354.825435],
]

def column_sum(data, column):
result = 0
for row in data:
result += row[column]
return result

def column_mean(data, column):
total = column_sum(oscar_data, 6)
mean = total / len(data)
return mean

# < write code here >
  

mean_score = column_mean(oscar_data, 2)
print('Average rating: {:.2f}'.format(mean_score))

mean_length = column_mean(oscar_data, 3)
print('Average length: {:.2f} min.'.format(mean_length))

mean_budget = column_mean(oscar_data, 5)
print('Average budget: ${:.2f} mil.'.format(mean_budget))

mean_gross = column_mean(oscar_data, 6)
print('Average revenue: ${:.2f} mil.'.format(mean_gross))

Define

1- Obligate anaerobes

2- Obligate aerobes

3- Mesophilic

4- Thermophiles

5-Coenzyme

6-Chemoautotrophs

7-Ribozyme

8-Proton motive force

Dice Game

Rules:

2 - 4 players

Each player has 5 Dice. The dice have 6 sides.

Each player rolls their dice, and the dice statistics are reported:

Sum, number of pairs (and of what), and "straights" - (all dice in order - e.g. 1,2,3,4,5 or 2,3,4,5,6)

Player 1 might roll 2,2,3,4,4 so the results would be:
Sum: 15, 1 pair (2), 1 pair (4)

Player 2 might roll 1, 1, 4, 6, 6 so the results would be:

Sum: 18, 1 pair (1), 1 pair (6)

Player 3 might roll 3, 3, 3, 5, 6 so the results would be:

Sum: 20, 1 triple (3)

Player 4 might roll 1, 2, 3, 5, 6

Sum: 17

Only one player wins per turn. Points are awarded as follows (only the highest possible point, not a sum of possibles):

The higher pairs beat the lower pairs. (If no other winner, then player 2 beats player 1 because a pair of 6 beats a pair of 4).

Ties re-roll between themselves.

First player to 50 points wins.

If you have built your program properly, you should be able to change the number of players, the number of dice sides, the number of dice, and the win point condition (50 points to something higher) and no changes should be needed to any of the rest of your code.

PS: NetBeans/Java Pls.

There is a 95.05% chance the project below can be completed in X days or less. What is X? In the space provided below type in the values for each activity’s expected time, variance, list of critical activities, Project duration and value of X. Draw the network diagram (diagram required only in the pdf file). Activity ----- Predecessors----------- Optimistic (days)----------- Most likely (days) ------------pessimistic(days) ------A ------------none ---------------------------1 --------------------------------4 --------------------------------------- 7 ------B------------none ----------------------------2 --------------------------------2 --------------------------------------- 2 ------C---------------A-------------------------------2 --------------------------------5 --------------------------------------- 8 ------D---------------A-------------------------------3 --------------------------------4 --------------------------------------- 5 ------E--------------B,C -----------------------------4 --------------------------------6 --------------------------------------- 8 ------F--------------B,C------------------------------0---------------------------------0 --------------------------------------- 6 ------G--------------D,E -----------------------------3 --------------------------------6 --------------------------------------- 9

1. Expected value for each activity: BLANK-1

2. Variance for each activity: BLANK-2

3. Critical activities: BLANK-3

4. Project duration: BLANK-4

5. X = BLANK-5

Refer to a duopoly market in which the inverse demand function is given by P = 96 − Q. Firm 1's cost function is c(q₁) = 6q₁ + 0.5q₁², and firm 2's cost function is c(q₂) = 6q₂ + 0.5q₂² (such that each firm has MC = 6 + q).

Q1: The Cournot best-response function for firm 1 will be:

1) q₁ = 22.5 − q₂/4

2) q₁ = 30 − q₂/3

3) q₁ = 45 − q₂/2

4) q₁ = 30 − q₂/2

5) None of the other answers is correct.

Q2: The outputs of the two firms in Cournot-Nash equilibrium will be:

1) q₁ = q₂ = 45

2) q₁ = q₂ = 22.5

3) q₁ = q₂ = 18

4) q₁ = q₂ = 30

5) None of the other answers is correct.

Q3: The profits of the two firms in Cournot-Nash equilibrium will be:

1) π₁ = π₂ = 759.4 (to 1 dp)

2) π₁ = π₂ = 450

3) π₁ = π₂ = 1012.5

4) π₁ = π₂ = 900

5) None of the other answers is correct.

Programming Language: C++

Overview

For this assignment, write a program that will simulate a single game of Craps.

Craps is a game of chance where a player (the shooter) will roll 2 six-sided dice. The sum of the dice will determine whether the player (and anyone that has placed a bet) wins immediately, loses immediately, or if the game continues.

If the sum of the first roll of the dice is equal to 7 or 11, the player wins immediately.

If the sum of the first roll of the dice is equal to 2, 3, or 12, the player has rolled "craps" and loses immediately.

If the sum of the first roll of the dice is equal to 4, 5, 6, 8, 9, or 10, the game will continue with the sum becoming the "point." The object of the game is now for the player to continue rolling the dice until they either roll a sum that equals the point or they roll a 7. If the player "makes their point" (ie. rolls a sum that equals the point), they win. If they roll a 7, they lose.

Random Number Generation

The random number generator will be used to "roll" the dice.

If a reminder is needed about how to use the random number generator and how to limit the values that are produced, refer back to program 4:

Link to Program 4

Basic Program Logic

Seed the random number generator with a value of 22. Note: other seed values may be used to produce different results. However, the version that is handed in for grading MUST use a seed value of 22.

Next, roll the dice by generating two random numbers between 1 and 6. The two numbers should be added together and then displayed along with the sum.

If the sum of the dice is equal to 7 or 11, the game is over and the player has won. Display a congratulatory message.

If the sum of the dice is equal to 2, 3, or 12, the game is over and the player has lost. Display a message indicating the player has lost because they rolled craps.

For any other sum, the sum is now the point and the game should continue until the user rolls the point again or rolls a 7. To do this:

Save the sum (the point) in a variable so it can be used for a later comparison

Display the point

Create a boolean variable and initialize it to a value of true to indicate that the game should continue.

In a loop that executes as long as the game should continue:

roll the dice and display the two values along with the sum

if the sum of the dice is the same as the point, display a congratulatory message indicating the player has made their point and they won the game. Also change the boolean variable that controls the loop to false to indicate the game should no longer continue.

otherwise, if the sum of the dice is 7, display a message that the player has lost the game and change the variable that controls the loop to false to indicate the game should no longer continue.

Symbolic Constants

The program MUST use at least three symbolic constants. Some options are:

an integer for each of the values (2, 3, and 12) that represents craps on the first roll of the die

an integer that represents the value 7

an integer that represents the value 11

Program Requirements

Include line documentation. There is no need to document every single line, but logical "chunks" of code should be preceded by a line or two that describes what the "chunk" of code does. This will be a part of every program that is submitted during the semester and this will be the last reminder in the program write-ups.

Make sure to actually use the symbolic constants that are created.

Be sure to #include

Make sure that the copy of the program that is handed in uses srand(22); to set the seed value for the random number generator.

Hand in a copy of the source code (CPP file) using Blackboard.

Output

Some runs of the program follow. Each one is marked with the srand value that produced the result.

Run 1 using srand(11); on Windows PC

Roll: 3 + 1 = 4 The point is 4 Roll: 5 + 4 = 9 Roll: 6 + 6 = 12 Roll: 1 + 2 = 3 Roll: 3 + 2 = 5 Roll: 3 + 2 = 5 Roll: 1 + 1 = 2 Roll: 6 + 1 = 7 Seven'd out! You lost!

Run 2 using srand(14); on Windows PC

Roll: 1 + 6 = 7 You won! Congratulations!

Run 3 using srand(22); on Windows PC

Roll: 3 + 1 = 4 The point is 4 Roll: 5 + 1 = 6 Roll: 4 + 4 = 8 Roll: 6 + 6 = 12 Roll: 4 + 4 = 8 Roll: 2 + 1 = 3 Roll: 5 + 1 = 6 Roll: 2 + 4 = 6 Roll: 3 + 5 = 8 Roll: 5 + 3 = 8 Roll: 2 + 1 = 3 Roll: 2 + 2 = 4 The point was made! You won!

Run 4 using srand(1); on Windows PC

Roll: 6 + 6 = 12 Craps! You lost!

Run 1 using srand(11); on Mac

Roll: 6 + 5 = 11 You won! Congratulations!

Run 2 using srand(22); on Mac

Roll: 5 + 3 = 8 The point is 8 Roll: 5 + 5 = 10 Roll: 6 + 5 = 11 Roll: 6 + 1 = 7 Seven'd out! You lost!

Run 3 using srand(1); on Mac

Roll: 2 + 2 = 4 The point is 4 Roll: 6 + 3 = 9 Roll: 5 + 3 = 8 Roll: 1 + 3 = 4 The point was made! You won!

Run 4 using srand(5); on Mac

Roll: 6 + 6 = 12 Craps! You lost!

Extra Credit 1

For up to 5 points of extra credit, add code that will allow the user to wager that the game will be won.

Before the dice are rolled, the user should be prompted for how much they would like to wager on the game. This initial wager is known as the pass line bet. It's a wager that the shooter will win the game (ie. the initial roll is 7 or 11, or the shooter makes their point) (Note: the game of craps also allows the user to wager that the shooter will lose, but we'll leave that out of this implementation.)

This wager pays 1/1 or even money. This means that if the user wagers $1, they'll win $1 if the game is won. In other words, if the game is won, the user will win the amount that they wagered plus their original wager. So if the wager amount was $10 and the game is won, the user will win $10 plus get their original wager amount for a total of $20.

Like a casino, this implementation of craps will have a minimum wager. Use a value of $5. Make sure to check the user's wager amount and to prompt them for a new value if they enter an amount less than the minimum. This should continue until the user wagers a value greater than or equal to the minimum.

Also like a casino, the wager amount must not contain cents. So a wager of $5.25 should not be allowed. If the user adds cents to their wager amount, "return" the cents to the user and use the remaining amount as the wager amount. So if the user tries to wager, $5.25 the $0.25 should be "returned" and the wager amount adjusted to $5. There are a number of ways to check for digits after the decimal point (cents). One way is to take the original wager amount and subtract the integer portion of the wager amount.

Note about extra credit: the points will ONLY be awarded if the required portions of the assignment work correctly. In other words, don't take short cuts in the rest of the program because it is assumed that 5 extra points will be awarded.

Extra Credit 1 Output 1 using srand(11); on Windows PC

How much would you like to wager (no cents allowed) (minimum: 5.00)? 10.00 Roll: 3 + 1 = 4 The point is 4 Roll: 5 + 4 = 9 Roll: 6 + 6 = 12 Roll: 1 + 2 = 3 Roll: 3 + 2 = 5 Roll: 3 + 2 = 5 Roll: 1 + 1 = 2 Roll: 6 + 1 = 7 Seven'd out! You lost! You lost $10.00

Extra Credit 1 Output 2 using srand(22); on Windows PC

How much would you like to wager (no cents allowed) (minimum: 5.00)? 10.00 Roll: 3 + 1 = 4 The point is 4 Roll: 5 + 1 = 6 Roll: 4 + 4 = 8 Roll: 6 + 6 = 12 Roll: 4 + 4 = 8 Roll: 2 + 1 = 3 Roll: 5 + 1 = 6 Roll: 2 + 4 = 6 Roll: 3 + 5 = 8 Roll: 5 + 3 = 8 Roll: 2 + 1 = 3 Roll: 2 + 2 = 4 The point was made! You won! You won $20.00

Extra Credit 1 Output 3 using srand(15); on Windows PC

How much would you like to wager (no cents allowed) (minimum: 5.00)? 2.50 You can't bet $2.50. The minimum bet is 5.00. Please try again: 1.00 You can't bet $1.00. The minimum bet is 5.00. Please try again: 5.36 You can have 0.36 back. The wager cannot have cents. Your wager is now 5.00 Roll: 4 + 6 = 10 The point is 10 Roll: 3 + 5 = 8 Roll: 6 + 3 = 9 Roll: 1 + 1 = 2 Roll: 3 + 4 = 7 Seven'd out! You lost! You lost $5.00

Extra Credit 1 Output 1 using srand(1); on Mac

How much would you like to wager (no cents allowed) (minimum: 5.00)? 5.00 Roll: 2 + 2 = 4 The point is 4 Roll: 6 + 3 = 9 Roll: 5 + 3 = 8 Roll: 1 + 3 = 4 The point was made! You won! You won $10.00

Extra Credit 1 Output 2 using srand(5); on Mac

How much would you like to wager (no cents allowed) (minimum: 5.00)? 5 Roll: 6 + 6 = 12 Craps! You lost! You lost $5.00

Extra Credit 1 Output 3 using srand(22); on Mac

How much would you like to wager (no cents allowed) (minimum: 5.00)? 5.00 Roll: 5 + 3 = 8 The point is 8 Roll: 5 + 5 = 10 Roll: 6 + 5 = 11 Roll: 6 + 1 = 7 Seven'd out! You lost! You lost $5.00

Extra Credit 2

For up to an additional 5 points of extra credit, add code that will allow the user to wager on odds for the pass line wager. This is an additional wager that if a point has been established, the shooter will make the point.

After a point has been established but before the dice are rolled to try to make the point, the user should be prompted for how much they would like to wager on the odds that the shooter will make the point.

Like extra credit 1, the minimum wager on odds is $5. Make sure to check the user's wager amount and to prompt them for a new value if they enter an amount less than the minimum. This should continue until the user wagers a value greater than or equal to the minimum.

Also make sure that the wager amount does not contain cents. If it does, "return" the cents and adjust the wager amount to remove the cents.

The payouts for wagering on the odds is based upon the point value. Points of 4 and 10 pay 2/1 (if $1 is bet, then the player wins $2 if the 4 or 10 is rolled). Points 5 and 9 pay 3/2 (if $2 is bet, then the player wins $3 if the 5 or 9 is rolled). Points 6 and 8 pay 6/5 (if $5 is bet, then the player wins $6 if the 6 or 8 is rolled).

If the point is made, the payout for wagering on the odds is added to the payout for wagering on the pass line (the value from extra credit 1).

Use the following formula to calculate the payout for wagering on odds:

wager amount + ( wager amount * odds )

For example, if the point is 8 and user wagered $15 on the odds, the user ends up with $33 for wagering on the odds.

wager amount + ( wager amount * odds ) = 15 + ( 15 * 6/5 ) = 15 + ( 90 / 5 ) = 15 + ( 18 ) = 33

If the user wagered $5 on the pass line, then the total payout is $43. $5 from pass line wager plus $5 for making the point plus $15 from wagering on the odds plus $18 for making the point with the odds wager.

Note about extra credit 2: the points will ONLY be awarded if the required portions of the assignment work correctly AND extra credit 1 works correctly.

Extra Credit 2 Output 1 using srand(22); on Windows PC

How much would you like to wager (no cents allowed) (minimum: 5.00)? 10.00 Roll: 3 + 1 = 4 The point is 4 How much would you like to wager on the odds? 30.00 Roll: 5 + 1 = 6 Roll: 4 + 4 = 8 Roll: 6 + 6 = 12 Roll: 4 + 4 = 8 Roll: 2 + 1 = 3 Roll: 5 + 1 = 6 Roll: 2 + 4 = 6 Roll: 3 + 5 = 8 Roll: 5 + 3 = 8 Roll: 2 + 1 = 3 Roll: 2 + 2 = 4 The point was made! You won! Pass Line Win: $20.00 Odds Payout: $90.00 You won $110.00

Extra Credit 2 Output 2 using srand(4); on Windows PC

How much would you like to wager (no cents allowed) (minimum: 5.00)? 5.00 Roll: 4 + 6 = 10 The point is 10 How much would you like to wager on the odds? 1.25 You can't bet $1.25. The minimum bet is 5.00. Please try again: 10.36 You can have 0.36 back. The wager cannot have cents. Your wager is now 10.00 Roll: 4 + 3 = 7 Seven'd out! You lost! You lost $15.00

Extra Credit 2 Output 1 using srand(1); on Mac

How much would you like to wager (no cents allowed) (minimum: 5.00)? 5.00 Roll: 2 + 2 = 4 The point is 4 How much would you like to wager on the odds? 10.00 Roll: 6 + 3 = 9 Roll: 5 + 3 = 8 Roll: 1 + 3 = 4 The point was made! You won! Pass Line Win: $10.00 Odds Payout: $30.00 You won $40.00

Depreciation by Three Methods; Partial Years Perdue Company purchased equipment on April 1 for $49,950. The equipment was expected to have a useful life of three years, or 5,400 operating hours, and a residual value of $1,350. The equipment was used for 1,000 hours during Year 1, 1,900 hours in Year 2, 1,600 hours in Year 3, and 900 hours in Year 4. Required: Determine the amount of depreciation expense for the years ended December 31, Year 1, Year 2, Year 3, and Year 4, by (a) the straight-line method, (b) units-of-activity method, and (c) the double-declining-balance method. Note: FOR DECLINING BALANCE ONLY, round the multiplier to four decimal places. Then round the answer for each year to the nearest whole dollar. a. Straight-line method Year Amount Year 1 $ Year 2 $ Year 3 $ Year 4 $ b. Units-of-activity method Year Amount Year 1 $ Year 2 $ Year 3 $ Year 4 $ c. Double-declining-balance method Year Amount Year 1 $ Year 2 $ Year 3 $ Year 4 $