Two teaching methods and their effects on science test scores are being reviewed. A random sample of 9 students, taught in traditional lab sessions, had a mean test score of 71.5 with a standard deviation of 4.1. A random sample of 6 students, taught using interactive simulation software, had a mean test score of 77.9 with a standard deviation of 4.7. Do these results support the claim that the mean science test score is lower for students taught in traditional lab sessions than it is for students taught using interactive simulation software? Let μ1 be the mean test score for the students taught in traditional lab sessions and μ2 be the mean test score for students taught using interactive simulation software. Use a significance level of α=0.05
for the test. Assume that the population variances are equal and that the two populations are normally distributed.
Step 3 of 4 :
Determine the decision rule for rejecting the null hypothesis H0
. Round your answer to three decimal places.
Reject H0 if t/or |t|, (<, or >) _________
In: Math
a) Treisa needs to score at the 95% percentile on an economics knowledge test to earn college credits forher job. All students tend to score 85 on average with a σx of 4.9. What z-score does she need to be atthe 95% percentile?
b) Treisa needs to score at the 95% percentile on an economics knowledge test to earn college credits forher job. All students tend to score 85 on average with a σx of 4.9. What raw score does she need to beat the 95% percentile?
c) As an instructor, I want to get a “normal” selection of current Psychology 10 students to speak to anew in-coming group on the importance of getting homework completed on time, coming to classregularly, and asking questions in class. Thus, I plan to select the most typical Psych 10 student in thecurrent semester to represent Psych 10 students. To do this, I will select those who score the middle 50% on a Psychology 10 exam. What range of raw scores do students have to achieve in order to beselected in this “typical” group of Psych 10 students when students in general tend to score 57 on thistest with a σx of 6.8 ?
In: Statistics and Probability
I want to provide this solution for other students to see.
A university financial aid office polled a random sample of 591 male undergraduate students and 484 female undergraduate students. Each of the students was asked whether or not they were employed during the previous summer. 424424 of the male students and 385 of the female students said that they had worked during the previous summer. Give a 95% confidence interval for the difference between the proportions of male and female students who were employed during the summer. Find the point estimate. Then, the margin of error. Finally, construct the 95% confidence interval. Round your answers to three decimal places.
Explaination: In the previous steps, we determined that the point estimate for the given information is pˆ1−pˆ2=−0.078p^1−p^2=−0.078 and the margin of error is E=0.051113E=0.051113. To determine the confidence interval, we must find the lower endpoint and the upper endpoint, rounding the values to three decimal places.
Lower endpoint: pˆ1−pˆ2−E=−0.078−0.051113≈−0.129Upper endpoint: pˆ1−pˆ2+E=−0.078+0.051113≈−0.027
ANSWERS
Point Estimate = −0.078
Margin of Error = 0.051113
Lower endpoint: −0.129, Upper endpoint: −0.027
In: Statistics and Probability
A group of nursing students is sitting in the cafeteria between classes. Nearby, a group of education students discusses how the field of education is a true profession as opposed to nursing, which one of the students describes as a field in which "nurses think just because they say they're professionals, they automatically become professionals." One of the other students adds, "Nurses work shifts, they are paid on an hourly basis, they can't decide on the level of education for entry, and they have an organization for everything. How does that make nursing a profession?" The nursing students discuss how to address the issue in a constructive manner. During the conversation, one of the nursing students questions the professionalism of nursing, asking, "Is that true? Is that how the public views nursing? Do they see us as a group that can't make up our minds or that we are just fooling ourselves about being a profession?"
In: Nursing
A group of nursing students is sitting in the cafeteria between classes. Nearby, a group of education students discusses how the field of education is a true profession as opposed to nursing, which one of the students describes as a field in which "nurses think just because they say they're professionals, they automatically become professionals." One of the other students adds, "Nurses work shifts, they are paid on an hourly basis, they can't decide on the level of education for entry, and they have an organization for everything. How does that make nursing a profession?" The nursing students discuss how to address the issue in a constructive manner. During the conversation, one of the nursing students questions the professionalism of nursing, asking, "Is that true? Is that how the public views nursing? Do they see us as a group that can't make up our minds or that we are just fooling ourselves about being a profession?"
In: Nursing
One of the authors came across an article (USA Today, 2008) that said that on average Americans have visited 16 states in the United States. In a survey of 50 students in her introductory statistics class, she found the average number of states the students had visited to be 9.48 and the standard deviation to be 7.13. The data were not strongly skewed.
1. Identify the observational unit for this study.
a. students
b. Americans
c. number of states
2. Identify the variable of interest and whether it is categorical or quantitative.
a. number of U.S. states visited, categorial
b. number of students, quantitative
c. number of students, categorial
d. number of U.S. states visited, quantitative
3. Regardless of your answer to part (c), state the null and the alternative hypotheses in symbols, to test whether the average number of states all students at the author’s school have visited is different from 16.
a. H0: mu = 16, Ha: mu ≠ 16
b. H0: mu = 16, Ha: mu > 16
c. H0: mu = 16, Ha: mu < 16
4. Using the 2SD approach to find a 95% confidence interval for the average number of states all students at the author’s school have visited. Round to two decimal places
In: Statistics and Probability
You are studying the affect of financial means on students'
average hours of sleep. You have found a reliable study indicating
that students that have a job and do not receive financial support
from their parents or guardians sleep an average of 5.8 hours per
night (excluding weekends) on average (population average).
You decide to test whether or not students who do not work get more
sleep per week night on average. You take a sample of 63 students
that do not work and live with parents or guardians then you record
the number of hours per week night they sleep for a period of 15
weeks (1 semester). You find that the average (mean) hours slept
per week night in your sample is 7.2 hours and the standard
deviation is 3.9 hours. Assume that average sleeping hours on week
nights is normally distributed across students.
Remember to define the null and alternative hypotheses to help you
answer the question.
What does your data indicate? (Based on a hypothesis test at the 1%
significance level)
Select one:
a. Reject the null hypothesis, students that do not work and live with parents or guardians sleep less hours per week night on average.
b. Fail to reject the null hypothesis, students that do not work and live with parents or guardians sleep less hours per week night on average.
c. Fail to reject the null hypothesis, students that do not work and live with parents or guardians sleep more hours per week night on average.
d. Reject the null hypothesis, students that do not work and live with parents or guardians sleep more hours per week night on average.
In: Statistics and Probability
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 35 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.1 hours with a standard deviation of 0.97 hours. You want to construct a 99% confidence interval for the mean nightly hours of sleep for all college students.
(a) What is the point estimate for the mean nightly hours of
sleep for all college students?
hours
(b) Construct the 99% confidence interval for the mean nightly
hours of sleep for all college students. Round your answers
to 1 decimal place.
< μ <
(c) Are you 99% confident that the mean nightly hours of sleep for
all college students is below the average for all people of 7 hours
per night? Why or why not?
Yes, because 7 is above the upper limit of the confidence interval for college students.No, because 7 is below the upper limit of the confidence interval for college students. Yes, because 7 is below the upper limit of the confidence interval for college students.No, because 7 is above the upper limit of the confidence interval for college students.
(d) We are never told whether or not the parent population is
normally distributed. Why could we use the above method to find the
confidence interval?
Because the margin of error is less than 30.Because the margin of error is positive. Because the sample size is less than 100.Because the sample size is greater than 30.
In: Statistics and Probability
A researcher is interested in whether college students get
enough sleep. She suspects
that they get less than 8 hours of sleep on average. The sample
mean (x ̄) for 65 students
was 7.08 hours. The standard deviation of number of hours students
slept is s=1.8.
(a) Determine the null and alternative hypothesis for the test.
What is the parameter
in this study?
(b) The p-value for the test is <0.0001. Using a significance
level of .05, write a one or
two sentence conclusion in context of the problem.
(c) Calculate 95% confidence interval for μ, the mean number of
hours college students
sleep per night. Interpret the confidence interval. Be sure to use
the word mean or average in your interpretation and don’t forget
units. If you are doing the calculations by hand use t* =
1.998.
(d) Does your confidence interval support the results of the hypothesis test? Explain.
2. The College Board reported that the mean SAT score in 2009
was 540 for all US High
School students that took the SAT. A teacher believes that the mean
score for his
students is greater than 540. He takes a random sample of 50 of his
students and
the sample mean score for the 25 students is 565 with a sample
standard deviation of
100. Does he have evidence that his students, on average, do better
than the national
average?
(a) State the null and alternative hypotheses.
(b) The p-value for the above test was 0.1117. State a
conclusion in context of the
problem. Use a significance level of 0.05.
(c) A 95% confidence interval for μ is (523.7,606.3). Interpret
the confidence interval
in context of the problem.
(d) Does your confidence interval support the results of the hypothesis test? Explain.
In: Statistics and Probability
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LESSON PLAN TEMPLATE Topic: ……………………………… Objective of the Lesson: …………………………. Learning Outcomes: ………………. Duration: ………………………………………… Background of students:…………………………. Prior knowledge of students on the topic: …………… Equipment & Facilities: ………………………………… Procedure:
Closure: …………………………………………………… Evaluation [Do students understand?] |
[NOTE: Make sure you provide links to these resources and show how you intend to use them]
In: Psychology