The local convection coefficient on a plate decreases as the thickness of the boundary layer grows along the plate. After transition from laminar to turbulent flow, the local convection coefficient becomes much larger, even though the boundary layer is much thicker. Explain why this is so.
Explain with a paragraph in a clear and straightforward manner, please.
In: Physics
In Surveying in the PLSS:
Match which method to use to set the lost corner type:
1 .Land Grant Corner
[ Choose One ] 2 point control, Grant boundary method, Single point control, Double proportion, Modified single proportion, Single proportion with curve adjustment , 3 point control, Single proportion
2. 1/4 corner
[ Choose One ] 2 point control, Grant boundary method, Single point control, Double proportion, Modified single proportion, Single proportion with curve adjustment , 3 point control, Single proportion
3. Section Corner interior of a township
[ Choose One ] 2 point control, Grant boundary method, Single point control, Double proportion, Modified single proportion, Single proportion with curve adjustment , 3 point control, Single proportion
4. Corner on the baseline
[ Choose One ] 2 point control, Grant boundary method, Single point control, Double proportion, Modified single proportion, Single proportion with curve adjustment , 3 point control, Single proportion
5. Township corner common to two townships
[ Choose One ] 2 point control, Grant boundary method, Single point control, Double proportion, Modified single proportion, Single proportion with curve adjustment , 3 point control, Single proportion
6. Meander corner where measure terminated
[ Choose One ] 2 point control, Grant boundary method, Single point control, Double proportion, Modified single proportion, Single proportion with curve adjustment , 3 point control, Single proportion
7. Section corner common to only one section
[ Choose One ] 2 point control, Grant boundary method, Single point control, Double proportion, Modified single proportion, Single proportion with curve adjustment , 3 point control, Single proportion
8. Corner on range line with angle point in the record
[ Choose One ] 2 point control, Grant boundary method, Single point control, Double proportion, Modified single proportion, Single proportion with curve adjustment , 3 point control, Single proportion
In: Civil Engineering
Write a program that displays all the cars in the given file (no sorting). Each car property is separated by a tab character: \t
Given file:
cars.txt
make model year Ford Expedition 2003 Mazda B-Series 1989 Ford Freestar 2003 Hyundai Elantra 2001 Hyundai Entourage 2008 Chevrolet Camaro 2011 Chevrolet Monte Carlo 2006 Chevrolet Blazer 1996 Chevrolet Aveo 2005 Chevrolet Corvette 1999 Mercedes-Benz E-Class 2006 Dodge Avenger 1995 Pontiac Grand Prix 1973 Mitsubishi Outlander 2011 MINI Clubman 2011 Suzuki Aerio 2007 Dodge Dakota Club 1992 Chevrolet Astro 2002 Chevrolet Tahoe 1996 Mitsubishi Mirage 1994 Porsche 944 1991 Hyundai Elantra 1994 Mercury Grand Marquis 1998 Volkswagen Golf 2001 Jaguar XJ Series 2005 Toyota Echo 2005 GMC Safari 2002 GMC Sierra 1500 2000 Chevrolet Cobalt 2005 Jeep Patriot 2008 Mazda Navajo 1991 Chevrolet Malibu 2001 Saab 900 1990 Mercury Grand Marquis 1998 Hummer H1 2004 Subaru Loyale 1993 Jeep Wrangler 1999 Ford Mustang 1994 Austin Mini Cooper S 1963 Mercedes-Benz M-Class 1998 Jeep Wrangler 2006 Honda Civic 1997 Plymouth Voyager 1994 Ford Club Wagon 1997 Audi 5000S 1984 Saturn VUE 2003 Oldsmobile Achieva 1994 Mercedes-Benz G55 AMG 2006 Chevrolet Express 3500 1997 Lexus ES 1992 Cadillac Allante 1992 Hyundai Tiburon 1997 Pontiac Grand Prix 1965 Ford Focus 2000 Mitsubishi Chariot 1987 Chrysler Prowler 2001 Land Rover Discovery 2012 Volkswagen Scirocco 1984 Ford Bronco 1984 Hyundai Accent 1996 Volkswagen Routan 2012 Volkswagen Golf 2003 GMC Terrain 2010 Ford F150 2009 GMC Sierra 2011 Dodge Ram Van 1500 2000 Chrysler 300 2009 Oldsmobile Achieva 1997 Land Rover Discovery 2008 Toyota 4Runner 2002 Porsche 911 1995 Toyota Land Cruiser 2002 Land Rover Defender 1994 Chevrolet Lumina 1997 Audi TT 2002 Chrysler Town & Country 2009 Nissan Frontier 2000 Toyota Tercel 1997 Buick Riviera 1997
Output needed:
Required Output
Ford Expedition 2003\n
Mazda B-Series 1989\n
Ford Freestar 2003\n
Hyundai Elantra 2001\n
Hyundai Entourage 2008\n
Chevrolet Camaro 2011\n
Chevrolet Monte Carlo 2006\n
Chevrolet Blazer 1996\n
Chevrolet Aveo 2005\n
Chevrolet Corvette 1999\n
Mercedes-Benz E-Class 2006\n
Dodge Avenger 1995\n
Pontiac Grand Prix 1973\n
Mitsubishi Outlander 2011\n
MINI Clubman 2011\n
Suzuki Aerio 2007\n
Dodge Dakota Club 1992\n
Chevrolet Astro 2002\n
Chevrolet Tahoe 1996\n
Mitsubishi Mirage 1994\n
Porsche 944 1991\n
Hyundai Elantra 1994\n
Mercury Grand Marquis 1998\n
Volkswagen Golf 2001\n
Jaguar XJ Series 2005\n
Toyota Echo 2005\n
GMC Safari 2002\n
GMC Sierra 1500 2000\n
Chevrolet Cobalt 2005\n
Jeep Patriot 2008\n
Mazda Navajo 1991\n
Chevrolet Malibu 2001\n
Saab 900 1990\n
Mercury Grand Marquis 1998\n
Hummer H1 2004\n
Subaru Loyale 1993\n
Jeep Wrangler 1999\n
Ford Mustang 1994\n
Austin Mini Cooper S 1963\n
Mercedes-Benz M-Class 1998\n
Jeep Wrangler 2006\n
Honda Civic 1997\n
Plymouth Voyager 1994\n
Ford Club Wagon 1997\n
Audi 5000S 1984\n
Saturn VUE 2003\n
Oldsmobile Achieva 1994\n
Mercedes-Benz G55 AMG 2006\n
Chevrolet Express 3500 1997\n
Lexus ES 1992\n
Cadillac Allante 1992\n
Hyundai Tiburon 1997\n
Pontiac Grand Prix 1965\n
Ford Focus 2000\n
Mitsubishi Chariot 1987\n
Chrysler Prowler 2001\n
Land Rover Discovery 2012\n
Volkswagen Scirocco 1984\n
Ford Bronco 1984\n
Hyundai Accent 1996\n
Volkswagen Routan 2012\n
Volkswagen Golf 2003\n
GMC Terrain 2010\n
Ford F150 2009\n
GMC Sierra 2011\n
Dodge Ram Van 1500 2000\n
Chrysler 300 2009\n
Oldsmobile Achieva 1997\n
Land Rover Discovery 2008\n
Toyota 4Runner 2002\n
Porsche 911 1995\n
Toyota Land Cruiser 2002\n
Land Rover Defender 1994\n
Chevrolet Lumina 1997\n
Audi TT 2002\n
Chrysler Town & Country 2009\n
Nissan Frontier 2000\n
Toyota Tercel 1997\n
Buick Riviera 1997\n
My program so far:
import java.io.*;
import java.util.Scanner;
public class PS1{
public static void main(String[] args) {
try{
Scanner scnr = new Scanner(new File("cars.txt"));
String headings = scnr.nextLine();
String line;
String make;
StringBuilder model;
String temp;
int year=0;
while(scnr.hasNext()){
line = scnr.nextLine();
Scanner scnr2 = new Scanner(line);
make = scnr2.next();
model = new StringBuilder(scnr2.next());
while(scnr2.hasNext()){
temp = scnr2.next();
if(scnr2.hasNext())
model.append(" ").append(temp);
else
year = Integer.parseInt(temp);
}
System.out.printf("%15s%25s%5s\n", make, model.toString(), year);
}
scnr.close();
}catch(FileNotFoundException e){
System.out.println(e.getMessage());
}
}
}
My output:
Your Program's Output
Ford Expedition 2003\n
Mazda B-Series 1989\n
Ford Freestar 2003\n
Hyundai Elantra 2001\n
Hyundai Entourage 2008\n
Chevrolet Camaro 2011\n
Chevrolet Monte Carlo 2006\n
Chevrolet Blazer 1996\n
Chevrolet Aveo 2005\n
Chevrolet Corvette 1999\n
Mercedes-Benz E-Class 2006\n
Dodge Avenger 1995\n
Pontiac Grand Prix 1973\n
Mitsubishi Outlander 2011\n
MINI Clubman 2011\n
Suzuki Aerio 2007\n
Dodge Dakota Club 1992\n
Chevrolet Astro 2002\n
Chevrolet Tahoe 1996\n
Mitsubishi Mirage 1994\n
Porsche 944 1991\n
Hyundai Elantra 1994\n
Mercury Grand Marquis 1998\n
Volkswagen Golf 2001\n
Jaguar XJ Series 2005\n
Toyota Echo 2005\n
GMC Safari 2002\n
GMC Sierra 1500 2000\n
Chevrolet Cobalt 2005\n
Jeep Patriot 2008\n
Mazda Navajo 1991\n
Chevrolet Malibu 2001\n
Saab 900 1990\n
Mercury Grand Marquis 1998\n
Hummer H1 2004\n
Subaru Loyale 1993\n
Jeep Wrangler 1999\n
Ford Mustang 1994\n
Austin Mini Cooper S 1963\n
Mercedes-Benz M-Class 1998\n
Jeep Wrangler 2006\n
Honda Civic 1997\n
Plymouth Voyager 1994\n
Ford Club Wagon 1997\n
Audi 5000S 1984\n
Saturn VUE 2003\n
Oldsmobile Achieva 1994\n
Mercedes-Benz G55 AMG 2006\n
Chevrolet Express 3500 1997\n
Lexus ES 1992\n
Cadillac Allante 1992\n
Hyundai Tiburon 1997\n
Pontiac Grand Prix 1965\n
Ford Focus 2000\n
Mitsubishi Chariot 1987\n
Chrysler Prowler 2001\n
Land Rover Discovery 2012\n
Volkswagen Scirocco 1984\n
Ford Bronco 1984\n
Hyundai Accent 1996\n
Volkswagen Routan 2012\n
Volkswagen Golf 2003\n
GMC Terrain 2010\n
Ford F150 2009\n
GMC Sierra 2011\n
Dodge Ram Van 1500 2000\n
Chrysler 300 2009\n
Oldsmobile Achieva 1997\n
Land Rover Discovery 2008\n
Toyota 4Runner 2002\n
Porsche 911 1995\n
Toyota Land Cruiser 2002\n
Land Rover Defender 1994\n
Chevrolet Lumina 1997\n
Audi TT 2002\n
Chrysler Town & Country 2009\n
Nissan Frontier 2000\n
Toyota Tercel 1997\n
Buick Riviera 1997\n
When mine outputs Land Rover is separated and Rover is put with the model, can someone help me fix this, thank you. Keep this in Java.
In: Computer Science
When finding the minimum positive subsequence sum (mpss) for an
array a = a0, a1, . . . , an−1 of integers, one can use the
following divide-and-conquer algorithm. Divide the array into two
equal subarrays aleft and aright, and recursively compute the mpss
of both subarrays. Then compute the mpss, call if mpssmid, of any
subsequence that crosses the boundary between aleft and aright.
Finally, take the minimum positive value of the three answers.
Answer the following questions pertaining to how mpssmid is
computed.
5a. Step 1: compute the leftward (respectively rightward) sums of
aleft (respectively, aright). For k = 1, . . . , n/2 provide an
expression that gives the k th leftward sum LSk of aleft. Hint: LS1
= an/2.
5b. If every leftward sum is added to every rightward sum to form a
boundary-crossing sum, then exactly how many boundary-crosing sums
are formed? State the resulting running-time recurrence and running
time, according to the Master Theorem.
5c. On the other hand, if the leftward and rightward sums are first sorted, then what is the most number of boundary-crossing sums that must be computed? Determine the boundary-crossing sums that are computed for the array a = 12, 43, −65, 76, −32, 81, 19, −95, 27, −43.
In: Computer Science
Alternative-Fueled Vehicles The table shows the numbers (in thousands) of alternative-fueled
vehicles A in use in the United States from 1995 to 2011. (Source: U.S. Energy Information Administration)
|
Year |
Number of vehicles, A |
|
1995 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 |
246.9 265.0 280.2 295.0 322.3 394.7 425.5 471.1 534.0 565.5 592.1 634.6 695.8 775.7 826.3 938.6 1191.8 |
(a) Use a graphing utility to plot the data. Let t represent the year, with t = 5 corresponding to 1995. (b) A model for the data is
4615.36t − 8726.7
1 + 15.01t − 0.542t2, 5 ≤ t ≤ 21
where t = 5 corresponds to 1995. Use the model to estimate the numbers of alternative-fueled vehicles in 1996, 2006, and 2011. How do your answers compare to the original data?
(f ) Use the model to predict the numbers of alternative-fueled vehicles in 2016 and 2017
* Need help to understand F . Should I be using a particular formula
In: Advanced Math
1. Use the data below to find the linear regression equation that best represents the given data and predict the revenue in 2013 (Copy data to Excel)
2. Then create Two new columns that represent the predication y =mx+b for each year and percent of growth for each year = (Revenue/Predication)*100
3. Use Excel to graph the linear model (x-axis years, y-axis revenue) and the linear equation of best fit.
| Year | Revenue | Predication | Percent of growth (%) |
| 2001 | 3665 | ||
| 2002 | 4163 | ||
| 2003 | 4750 | ||
| 2004 | 5287 | ||
| 2005 | 5825 | ||
| 2006 | 6395 | ||
| 2007 | 6834 | ||
| 2008 | 6994 | ||
| 2009 | 7401 | ||
| 2010 | 7867 | ||
| 2011 | 8548 | ||
| 2012 | 9331 |
In: Statistics and Probability
For this submission, you will be given a series of scenarios and small collections of data. You should plot the data or calculate probabilities using excel. Then, you will create your own real or hypothetical scenario to graph and explain.
Answer the following:
The mean temperature for the month of July in Boston, Massachusetts is 73 degrees Fahrenheit. Plot the following data, which represent the observed mean temperature in Boston over the last 20 years:
| 1998 | 72 |
| 1999 | 69 |
| 2000 | 78 |
| 2001 | 70 |
| 2002 | 67 |
| 2003 | 74 |
| 2004 | 73 |
| 2005 | 65 |
| 2006 | 77 |
| 2007 | 71 |
| 2008 | 75 |
| 2009 | 68 |
| 2010 | 72 |
| 2011 | 77 |
| 2012 | 65 |
| 2013 | 79 |
| 2014 | 77 |
| 2015 | 78 |
| 2016 | 72 |
| 2017 | 74 |
Is this a normal distribution? Explain your reasoning.
What is an outlier? Are there any outliers in this distribution? Explain your reasoning fully.
Using the above data, what is the probability that the mean will be over 76 in any given July?
Using the above data, what is the probability that the mean will be over 80 in any given July?
In: Statistics and Probability
1). Grouse in Russia show a recessive mutation “short-tail” that causes problems in the control of direction when flying. In 2002 a survey of a large, freely interbreeding, population of 1,856 grouse revealed 142 with short tail feathers.
a) What proportion of the grouse population would you expect to be heterozygous at the short-tail locus ?
b) Where there is no mutation, migration or selection what percentage of the next generation would be homozygous dominants, heterozygotes and homozygous recessives?
c) Due to rising affluence there was an increase in recreational grouse hunting. In a later survey of the grouse over some years it was found that a significant decrease had taken place in the population. In 2003 there were 2,861 grouse and in 2004 there were only 2,369 and all the surviving grouse had long tails. Support by calculation that this change would reflect greater vulnerability of short tail grouse to killing by hunters.
d) After further random mating of survivors what would be the percentage of homozygous dominants, heterozygotes and homozygous recessives expected in the next generation in the absence of any further hunting?
In: Biology
The general fund budget (in billions of dollars) for a U.S. state for 1988 (period 1) to 2011 (period 24) follows.
| Year | Period | Budget ($ billions) |
|---|---|---|
| 1988 | 1 | 3.03 |
| 1989 | 2 | 3.29 |
| 1990 | 3 | 3.56 |
| 1991 | 4 | 4.31 |
| 1992 | 5 | 4.46 |
| 1993 | 6 | 4.61 |
| 1994 | 7 | 4.65 |
| 1995 | 8 | 5.15 |
| 1996 | 9 | 5.34 |
| 1997 | 10 | 5.66 |
| 1998 | 11 | 6.11 |
| 1999 | 12 | 6.20 |
| 2000 | 13 | 6.58 |
| 2001 | 14 | 6.75 |
| 2002 | 15 | 6.56 |
| 2003 | 16 | 6.88 |
| 2004 | 17 | 7.08 |
| 2005 | 18 | 7.65 |
| 2006 | 19 | 8.38 |
| 2007 | 20 | 8.57 |
| 2008 | 21 | 8.76 |
| 2009 | 22 | 8.43 |
| 2010 | 23 | 8.33 |
| 2011 | 24 | 8.76 |
(b)Develop a linear trend equation for this time series to forecast the budget (in billions of dollars). (Round your numerical values to three decimal places.)
Tt = ____?______
(c)What is the forecast (in billions of dollars) for period 25? (Round your answer to two decimal places.)
$___?_____ billion
In: Statistics and Probability
6. Recently, fixed mortgage rates have been at historical lows due to the housing slowdown. The data table linked below shows the 30-year fixed average mortgage rate for the month of December every year between 1987 and 2010.
Year Rate_(%)
1987 11.09
1988 11.04
1989 10.17
1990 9.93
1991 8.57
1992 8.3
1993 7.25
1994 9.04
1995 7.21
1996 7.06
1997 7.07
1998 6.84
1999 7.65
2000 7.74
2001 7.07
2002 6.84
2003 6.94
2004 6.79
2005 7.02
2006 6.82
2007 6.63
2008 5.88
2009 5.64
2010 5.4
b. Forecast the average December mortgage rate in 2011 using a trend projection (Round to two decimal places as needed.)
c. Calculate the MAD for this forecast. (Round to two decimal places as needed.)
d. Determine the Durbin–Watson statistic (Round to two decimal places as needed.)
e. Identify the critical values. (Round to two decimal places as needed.)
In: Statistics and Probability