Questions
Susan is a self-employed consultant, earning $80,000 annually. She does not have health insurance but knows...

Susan is a self-employed consultant, earning $80,000 annually. She does not have health insurance but knows that, in a given year, there is a 5 percent probability she will develop a serious illness. If so, she could expect medical bills to be as high as $25,000. Susan derives utility from her income according to the following formula:

U = Y^(0.3), (i.e. Y raised to the 0.3 power), where Y is annual income.

a) What is Susan's expected utility?

b) What is her maximum willingness to pay for health insurance?

In: Economics

A pharmaceutical manufacturer forms tablets by compressing a granular material that contains the active ingredient and...

A pharmaceutical manufacturer forms tablets by compressing a granular material that contains the active ingredient and various fillers. The force in kilograms (kg) applied to the tablets varies a bit, with the N(11.4, 0.3) distribution. The process specifications call for applying a force between 11.3 and 12.3 kg. (a) What percent of tablets are subject to a force that meets the specifications? % (b) The manufacturer adjusts the process so that the mean force is at the center of the specifications, μ = 11.8 kg. The standard deviation remains 0.3 kg. What percent now meet the specifications? %

In: Statistics and Probability

A pharmaceutical manufacturer forms tablets by compressing a granular material that contains the active ingredient and...

A pharmaceutical manufacturer forms tablets by compressing a granular material that contains the active ingredient and various fillers. The force in kilograms (kg) applied to the tablets varies a bit, with the N(11.4, 0.3) distribution. The process specifications call for applying a force between 11.3 and 12.3 kg. (a) What percent of tablets are subject to a force that meets the specifications? % (b) The manufacturer adjusts the process so that the mean force is at the center of the specifications, μ = 11.8 kg. The standard deviation remains 0.3 kg. What percent now meet the specifications? %

In: Statistics and Probability

A pharmaceutical manufacturer forms tablets by compressing a granular material that contains the active ingredient and...

A pharmaceutical manufacturer forms tablets by compressing a granular material that contains the active ingredient and various fillers. The force in kilograms (kg) applied to the tablets varies a bit, with the N(12, 0.3) distribution. The process specifications call for applying a force between 11.2 and 12.2 kg.

(a) What percent of tablets are subject to a force that meets the specifications? %

(b) The manufacturer adjusts the process so that the mean force is at the center of the specifications, μ = 11.7 kg. The standard deviation remains 0.3 kg. What percent now meet the specifications?

In: Statistics and Probability

How to compute the question (b)? And why it isn't 6C2·0.3^2·0.7^4? The probability that Jim goes...

How to compute the question (b)? And why it isn't 6C2·0.3^2·0.7^4?

The probability that Jim goes to work by taxi is 0.3. He works 6 days in a week.

(a) Find the probability that Jim goes to work by taxi in at least 3 days in a week given that
(i) he goes to work by taxi for at most 4 days,
(ii) he goes to work by taxi for more than 1 day.
(b) Find the probability that Jim goes to work by taxi in exactly 2 consecutive mornings.

In: Statistics and Probability

How to compute the question (b)? And why it isn't 6C2·0.3^2·0.7^4? The probability that Jim goes...

How to compute the question (b)? And why it isn't 6C2·0.3^2·0.7^4?

The probability that Jim goes to work by taxi is 0.3. He works 6 days in a week.

(a) Find the probability that Jim goes to work by taxi in at least 3 days in a week given that
(i) he goes to work by taxi for at most 4 days,
(ii) he goes to work by taxi for more than 1 day.
(b) Find the probability that Jim goes to work by taxi in exactly 2 consecutive mornings.

In: Statistics and Probability

A bottling machine can be regulated so that it discharges an average of μ ounces per...

A bottling machine can be regulated so that it discharges an average of μ ounces per bottle. It has been observed that the amount of fill dispensed by the machine has a normal distribution A sample of n= 16 filled bottles is randomly selected from the output of the machine on a given day and the ounces of fill measured for each. The sample variance is equal to one ounce. Find the probability: a) that each bottle filled will be within 0.3 ounce of the true mean? b) that the sample mean will be within 0.3 ounce of the true mean?

In: Statistics and Probability

Rand Inc. and McNally Corp. have the following probability distribution of returns: Probability Rand Returns McNally...

Rand Inc. and McNally Corp. have the following probability distribution of returns: Probability Rand Returns McNally Returns
0.3 15% 12% 0.4 9 5 0.3 18 20
Sudha Krishnaswami Lecture Notes
Page 1 of 3

Homework-6
a) Calculate the expected rates of return for the two stocks.
b) Calculate the standard deviation of returns for the two stocks.
c) Calculate the expected return and standard deviation on a portfolio P made up of 75%
invested in McNally stock and the remaining invested in Rand stock.

In: Finance

A student would like to determine whether the number of pages in a textbook can be...

A student would like to determine whether the number of pages in a textbook can be used to predict its price. She took a random sample of 30 textbooks from the campus bookstore and recorded the price (in $) and the number of pages in each book. The least squares regression line is calculated to be = 83 + 0.3x.

Question 21 (1 point)

One textbook in the sample costs $120 and has a residual value of -32. How many pages are in this textbook?

Question 21 options:

250

240

230

220

210

Question 22 (1 point)

Saved

Refer to the previous question. We conduct a hypothesis test to determine if there exists a positive linear relationship between number of pages and price of a textbook. The P-value is calculated to be 0.18.

What is the interpretation of this P-value?

Question 22 options:

The probability that there is a positive linear relationship between number of pages and price is 0.18.

If there was a positive linear relationship between number of pages and price, the probability of observing a value of b1 at least as high as 0.3 would be 0.18.

If there was a positive linear relationship between number of pages and price, the probability of observing a value of β1 at least as high as 0.3 would be 0.18.

If there was no linear relationship between number of pages and price, the probability of observing a value of b1 at least as high as 0.3 would be 0.18.

If there was no linear relationship between number of pages and price, the probability of observing a value of β1 at least as high as 0.3 would be 0.18.

In: Statistics and Probability

Please show all work, calculation, or explanation to receive full credit and circle the correct answer....

  • Please show all work, calculation, or explanation to receive full credit and circle the correct answer.

Use the following Information to Answer Problems 1 and 2

Bradford Services Inc. (BSI) is considering a project that has a cost of $10 million and an expected life of 3 years. There is a 30 percent probability of good conditions, in which case the project will provide a cash flow of $9 million at the end of each year for 3 years. There is a 40 percent probability of medium conditions, in which case the annual cash flows will be $4 million, and there is a 30 percent probability of bad conditions and a cash flow of -$1 million per year. BSI uses a 12 percent cost of capital to evaluate projects like this.

Problem 1: Find the project’s expected cashflow and NPV

Condition

Probability

Cash Flow

Prob.*Cash Flow

Good

0.3

$9

Medium

0.4

$4

Bad

0.3

-$1

Expected CF

Expected CF =

T=0

T=1

T=2

T=3

CF

NPV of Project =

What can you conclude regarding this project?

Problem 2: find the project’s standard deviation and coefficient variation?

Condition

Probability

NPV

Good

0.3

Medium

0.4

Bad

0.3

Expected NPV

NPV of Project in Good Condition =

NPV of Project in Average Condition =

NPV of Project in Bad Condition =

Variance           =

Coefficient Variation =

In: Finance