| Year | years since 1971 | number of new locations |
| 1971 | 0 | 1 |
| 1987 | 16 | 17 |
| 1988 | 17 | 33 |
| 1989 | 18 | 55 |
| 1990 | 19 | 84 |
| 1991 | 20 | 116 |
| 1992 | 21 | 165 |
| 1993 | 22 | 272 |
| 1994 | 23 | 425 |
| 1995 | 24 | 677 |
| 1996 | 25 | 1015 |
| 1997 | 26 | 1412 |
| 1998 | 27 | 1886 |
| 1999 | 28 | 2498 |
| 2000 | 29 | 3501 |
| 2001 | 30 | 4709 |
| 2002 | 31 | 5886 |
| 2003 | 32 | 7225 |
| 2004 | 33 | 8569 |
| 2005 | 34 | 10241 |
| 2006 | 35 | 12440 |
| 2007 | 36 | 15011 |
| 2008 | 37 | 16680 |
| 2009 | 38 | 16635 |
| 2010 | 39 | 16858 |
| 2011 | 40 | 17003 |
| 2012 | 41 | 18066 |
| 2013 | 42 | 19767 |
| 2014 | 43 | 21366 |
| 2015 | 44 | 22519 |
And now here we are…a Starbucks on nearly every corner. Even Homer Simpson had something to say about this in a recent episode! This is where I need your help. I would like you to perform a thorough analysis of the data involving the number of Starbucks locations. Our investors are interested to know about the rate of growth as well as to understand issues related to forecasting the number of Starbucks locations in the future. And specifically, we are wondering when the number of stores will reach 37,000 locations. You see, there are currently 37,000 McDonald’s restaurants worldwide, and we have set a goal to reach that number by the year 2020. Do you think we can do it?
In: Statistics and Probability
Could this be answered within excel + handwritten notes and thoroughly explained. Please and thank you
INTRODUCTION TO LINEAR CORRELATION AND REGRESSION ANALYSIS.
An economist with a major bank wants to learn, quantitatively, how much spending on luxury goods and services can be explained based on consumers’ perception about the current state of the economy and what do they expect in the near future (6 months ahead). Consumers, of all income and wealth classes, were surveyed. Every year, 1500 consumers were interviewed. The bank having all of the data from the 1500 consumers interviewed every year, computed the average level of consumer confidence (an index ranging from 0 to 100, 100 being absolutely optimistic) and computed the average dollar amount spent on luxuries annually. Below is the data shown for the last 24 years.
Date X Y (in thousands of dollars)
1994 79.1 55.6
1995 79 54.8
1996 80.2 55.4
1997 80.5 55.9
1998 81.2 56.4
1999 80.8 57.3
2000 81.2 57
2001 80.7 57.5
2002 80.3 56.9
2003 79.4 55.8
2004 78.6 56.1
2005 78.3 55.7
2006 78.3 55.7
2007 77.8 55
2008 77.7 54.4
2009 77.6 54
2010 77.6 56
2011 78.5 56.7
2012 78.3 56.3
2013 78.5 57.2
2014 78.9 57.8
2015 79.8 58.7
2016 80.4 59.3
2017 80.7 59.9
Questions:
In: Statistics and Probability
the table gives a total U.S expenditure for health services and supplies selected years from 2000 and projected to 2018.
year $(billion)
2000 1264
2002 1498
2004 1733
2006 1976
2008 2227
2010 2458
2012 2746
2014 3107
2016 3556
2018 4086
a. find an exponential function model to these data, with x equal to the number of years after 2000. b) use the model to estimate the U.S expenditure for health services and supplies in 2020.
2.The percent of boys age x or younger who have been seually active are given below.
Age cumulative percent seuual active girls cumulative percent sexual active boys
15 5.4 16.6
16 12.6 28.7
17 27.1 47.9
18 44.0 64.0
19 62.9 77.6
20 73.6 83.0
a). Creat a logarithmic function that model the data using an input equal to the age of the boys.
b) use the model to estimate the percent of boys age 17 or younger who have been seually active
c. compare the percent that are sexually active for the two genders, what do you conclude.
3). if $12000 is invested in an account that pays 8% interest, compounded quaterly, find the future value of this investment
a) after 2 year. b) after 10 years.
4).if $9000 is invested in an account that pays 8% interest, compounded quaterly . find the future value of this investment
a) after 0.5 year b)after 15 years
5. Grandparents decide to put a lump sum of money into a trust fund on their gtanddaughters 10th birthday so that she will have $1000000 on her 60th birthday. if the fund pays 11% compounded monthly. how much money must they put in the account.
6.At the end of t years the future value of an investment of $25000 in an account that pays 12% compounded quaterly is
S=25000(1+0.12 /4t )^4t dollars.. a) How many years will the investment amount to $60000.
In: Math
Because of high tuition costs at state and private universities, enrollments at community colleges have increased dramatically in recent years. The following data show the enrollment (in thousands) for Jefferson Community College for the nine most recent years.
Click on the datafile logo to reference the data.
Year |
Period (t) |
Enrollment (1,000s) |
| 2001 | 1 | 6.5 |
| 2002 | 2 | 8.1 |
| 2003 | 3 | 8.4 |
| 2004 | 4 | 10.2 |
| 2005 | 5 | 12.5 |
| 2006 | 6 | 13.3 |
| 2007 | 7 | 13.7 |
| 2008 | 8 | 17.2 |
| 2009 | 9 | 18.1 |
| (a) | Choose the correct time series plot. | ||||||||||||
|
|||||||||||||
| - Select your answer -Plot (i)Plot (ii)Plot (iii)Plot (iv)Item 1 | |||||||||||||
| What type of pattern "significantly" exists in the data? (Use 1% level of significance when needed) | |||||||||||||
| - Select your answer -Only randomnessRandomness & Linear trendRandomness & SeasonalityRandomness, Linear trend & SeasonalityItem 2 | |||||||||||||
| (b) | Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series. | ||||||||||||
| If required, round your answers to two decimal places. | |||||||||||||
| y-intercept, b0 = | |||||||||||||
| Slope, b1 = | |||||||||||||
| MSE = | |||||||||||||
| (c) | What is the forecast for year 10? | ||||||||||||
| Do not round your interim computations and round your final answer to two decimal places. | |||||||||||||
| (d) | Use the Holt's method with smoothing constants of 0.3 for alpha and 0.6 for gamma. Find the equation of the forecast line and the MSE for this method. | ||||||||||||
| If required, round your answers to two decimal places. | |||||||||||||
| y-intercept, b0 = | |||||||||||||
| Slope, b1 = | |||||||||||||
| MSE = | |||||||||||||
| (e) | What is the forecast for year 10? | ||||||||||||
| Do not round your interim computations and round your final answer to two decimal places. | |||||||||||||
| (f) | Which of the following methods perform better with respect to MSE? - Select your answer -RegressionHolt's with alpha=0.3, gamma=0.6Holt's with alpha=0.2, gamma=0.2 |
In: Statistics and Probability
SUBJECT: TAXATION OF INDIVIDUALS AND BUSINESS ENTITIES (Chapter 25)
Required information
Roland had a taxable estate of $5.5 milionwhen he died this year.
Calculate the amount of estate tax due (if any) under the following alternative. (Refer to EXHIBIT 25-1 AND EXHIBIT 25-2).
a. Roland's prior taxable gifts consist of a taxable gift of $1 million in 2005. Estate tax due?
b. Roland's prior taxable gifts consist of a taxable gift of $1.5 million in 2005. Estate tax due?
c. Roland made a $1 million taxable gift in the year prior to his death. Estate tax due?
EXHIBIT 25-1
|
TAX BASE EQUAL TO OR OVER |
NOT OVER | TENTATIVE TAX | PLUS |
OF AMOUNT OVER |
| $ 0 | $ 10,000 | $ 0 | 18% | $ 0 |
| 10,000 | 20,000 | 1,800 | 20 | 10,000 |
| 20,000 | 40,000 | 3,800 | 22 | 20,000 |
| 40,000 | 60,000 | 8,200 | 24 |
40,000 |
| 60,000 | 80,000 | 13,000 | 26 | 60,000 |
| 80,000 | 100,000 | 18,200 | 28 | 80,000 |
| 100,000 | 150,000 | 23,800 | 30 | 100,000 |
| 150,000 | 250,000 | 38,800 | 32 | 150,000 |
| 250,000 | 500,000 | 70,800 | 34 | 250,000 |
| 500,000 | 750,000 | 155,800 | 37 | 500,000 |
| 750,000 | 100,000 | 248,300 | 39 | 750,000 |
| 1,000,000 | 345,800 | 40 | 1,000,000 |
EXHIBIT 25-2 THE EXEMPTION EQUIVALENT
| YEAR OF TRANSFER | GIFT TAX | ESTATE TAX |
| 1986 | $ 500,000 | $ 500,000 |
| 1987-1997 | 600,000 | 600,000 |
| 1998 | 625,000 | 625,000 |
| 1999 | 650,000 | 650,000 |
| 2000-2001 | 675,000 | 675,000 |
| 2002-2003 | 1,000,000 | 1,000,000 |
| 2004-2005 | 1,000,000 | 1,500,000 |
| 2006-2008 | 1,000,000 | 2,000,000 |
| 2009-2010* | 1,000,000 | 3,500,000 |
| 2011 | 5,000,000 | 5,000,000 |
| 2012 | 5,120,000 | 5,120,000 |
| 2013 | 5,250,000 | 5,250,000 |
| 2014 | 5,340,000 | 5,340,000 |
| 2015 | 5,430,000 | 5,430,000 |
| 2016 | 5,450,000 | 5,450,000 |
| 2017 | 5,490,000 | 5,490,000 |
Please show the solution. Thank you
In: Accounting
Use the data and Excel to answer this question. It contains the United States Census Bureau’s estimates for World Population from 1950 to 2014. You will find a column of dates and a column of data on the World Population for these years. Generate the time variable t. Then run a regression with the Population data as a dependent variable and time as the dependent variable. Have Excel report the residuals.
(a) Based on the ANOVA table and t-statistics, does the regression appear significant?
(b) Calculate the Durbin-Watson Test statistic. Is there a serial correlation problem with the data? Explain.
(d) What affect might your answer in part (b) have on your conclusions in part (a)?
| Year | Population |
| 1950 | 2,557,628,654 |
| 1951 | 2,594,939,877 |
| 1952 | 2,636,772,306 |
| 1953 | 2,682,053,389 |
| 1954 | 2,730,228,104 |
| 1955 | 2,782,098,943 |
| 1956 | 2,835,299,673 |
| 1957 | 2,891,349,717 |
| 1958 | 2,948,137,248 |
| 1959 | 3,000,716,593 |
| 1960 | 3,043,001,508 |
| 1961 | 3,083,966,929 |
| 1962 | 3,140,093,217 |
| 1963 | 3,209,827,882 |
| 1964 | 3,281,201,306 |
| 1965 | 3,350,425,793 |
| 1966 | 3,420,677,923 |
| 1967 | 3,490,333,715 |
| 1968 | 3,562,313,822 |
| 1969 | 3,637,159,050 |
| 1970 | 3,712,697,742 |
| 1971 | 3,790,326,948 |
| 1972 | 3,866,568,653 |
| 1973 | 3,942,096,442 |
| 1974 | 4,016,608,813 |
| 1975 | 4,089,083,233 |
| 1976 | 4,160,185,010 |
| 1977 | 4,232,084,578 |
| 1978 | 4,304,105,753 |
| 1979 | 4,379,013,942 |
| 1980 | 4,451,362,735 |
| 1981 | 4,534,410,125 |
| 1982 | 4,614,566,561 |
| 1983 | 4,695,736,743 |
| 1984 | 4,774,569,391 |
| 1985 | 4,856,462,699 |
| 1986 | 4,940,571,232 |
| 1987 | 5,027,200,492 |
| 1988 | 5,114,557,167 |
| 1989 | 5,201,440,110 |
| 1990 | 5,288,955,934 |
| 1991 | 5,371,585,922 |
| 1992 | 5,456,136,278 |
| 1993 | 5,538,268,316 |
| 1994 | 5,618,682,132 |
| 1995 | 5,699,202,985 |
| 1996 | 5,779,440,593 |
| 1997 | 5,857,972,543 |
| 1998 | 5,935,213,248 |
| 1999 | 6,012,074,922 |
| 2000 | 6,088,571,383 |
| 2001 | 6,165,219,247 |
| 2002 | 6,242,016,348 |
| 2003 | 6,318,590,956 |
| 2004 | 6,395,699,509 |
| 2005 | 6,473,044,732 |
| 2006 | 6,551,263,534 |
| 2007 | 6,629,913,759 |
| 2008 | 6,709,049,780 |
| 2009 | 6,788,214,394 |
| 2010 | 6,858,584,755 |
| 2011 | 6,935,999,491 |
| 2012 | 7,013,871,313 |
| 2013 | 7,092,128,094 |
| 2014 | 7,169,968,185 |
Thanks id advance! Will try to rate the answer ASAP. Please show your process too :)
In: Statistics and Probability
NOTE THAT
((This should be done by R studio !))
Q: Upload your data as a CSV in R studio, then do
any
cleaning or convert needed for example convert the date in your
table
from character to date and NA identifiers . After
do all these, run a summary statistics
|
Year |
REX |
OilP |
Food exports (% of merchandise exports) |
Ores and metals exports (% of merchandise exports) |
|
1980 |
239.5433424 |
35.52 |
0.09638294 |
0.060083757 |
|
1981 |
240.3102173 |
34 |
0.094079554 |
0.024360528 |
|
1982 |
245.3895131 |
32.38 |
0.128489839 |
0.025668368 |
|
1983 |
242.8677506 |
29.04 |
.. |
.. |
|
1984 |
238.0284197 |
28.2 |
.. |
.. |
|
1985 |
221.878717 |
27.01 |
0.259787311 |
0.116943755 |
|
1986 |
169.6457184 |
13.53 |
.. |
.. |
|
1987 |
144.1934823 |
17.73 |
.. |
.. |
|
1988 |
134.5212315 |
14.24 |
1.371078529 |
0.732151804 |
|
1989 |
136.0536024 |
17.31 |
1.374888969 |
0.834330299 |
|
1990 |
125.5311345 |
22.26 |
0.713126234 |
0.491007478 |
|
1991 |
125.8812467 |
18.62 |
0.526384845 |
0.242750346 |
|
1992 |
118.7733668 |
18.44 |
1.074388363 |
0.548851562 |
|
1993 |
122.2521688 |
16.33 |
0.982275388 |
0.429968062 |
|
1994 |
117.8952881 |
15.53 |
0.673955645 |
0.346686956 |
|
1995 |
114.1213899 |
16.86 |
0.810242733 |
0.567217625 |
|
1996 |
116.3114665 |
20.29 |
0.632336949 |
0.304958406 |
|
1997 |
121.4661302 |
18.86 |
.. |
.. |
|
1998 |
127.1948915 |
12.28 |
1.114818605 |
0.507089276 |
|
1999 |
121.9490893 |
17.44 |
0.930990348 |
0.262574488 |
|
2000 |
123.200674 |
27.6 |
0.538501429 |
0.147164016 |
|
2001 |
125.2424379 |
23.12 |
0.558465111 |
0.201693533 |
|
2002 |
121.5455166 |
24.36 |
0.628539417 |
0.223275991 |
|
2003 |
111.1523893 |
28.1 |
0.835851768 |
0.182707717 |
|
2004 |
103.4682918 |
36.05 |
0.7405123 |
0.172800798 |
|
2005 |
100.5070052 |
50.59 |
0.620831971 |
0.137293785 |
|
2006 |
98.93290899 |
61 |
0.64203501 |
0.219532433 |
|
2007 |
95.96813741 |
69.04 |
0.838923226 |
0.283587719 |
|
2008 |
93.62494305 |
94.1 |
0.744029125 |
0.221986187 |
|
2009 |
100.1652448 |
60.86 |
1.407633083 |
0.232499732 |
|
2010 |
100 |
77.38 |
1.155876888 |
0.154654215 |
|
2011 |
96.57013945 |
107.46 |
0.898301922 |
0.122271232 |
|
2012 |
99.61967144 |
109.45 |
0.860627792 |
0.138455596 |
|
2013 |
102.3680362 |
105.87 |
0.878931429 |
0.403127249 |
|
2014 |
105.3894897 |
96.29 |
1.006265279 |
0.769034983 |
|
2015 |
118.5851177 |
49.49 |
1.798068624 |
1.307540253 |
R ONLY !!
In: Computer Science
Peak and off-peak times provide an obvious source of
equivalence classes for the start and duration of the call. A call
could start during peak or off-peak hours, and it could end in peak
or off-peak hours (because the maximum duration of a call is just
under an hour, a call can cross the peak/off-peak boundary once,
but not twice). A call could also cross over the boundary between
days, and this wrapping must be handled correctly.
A good set of boundaries for the start of the call
would be: 00:00, 06:00, 07:00, 18:00 and 19:00. A good set of
boundaries for the duration of the call would be the minimum and
maximum durations – 00:00 and 59:59. We don’t need to test every
combination of start time and duration – the duration of the call
is only really important if the call starts within an hour of the
peak/off-peak switch. We can test the remaining start times with a
single duration.
The other input values entered by the user are
boolean, so only a true value and a false value needs to be tested
for each. Again, we don’t need to test each boolean option with
every possible combination of the previous options – one or two
cases should be sufficient. code in python OOP.
In: Accounting
Consider a particle moving in two spatial dimensions,
subject to the following potential:
V (x, y) = (
0, 0 ≤ x ≤ L & 0 ≤ y ≤ H
∞, otherwise.
(a) Write down the time-independent Schr¨odinger equation for this
case, and motivate
its form. (2)
(b) Let k
2 = 2mE/~
2 and rewrite this equation in a simpler form. (2)
(c) Use the method of separation of variables and assume that ψ(x,
y) = X(x)Y (y).
Rewrite the equation in terms of X and Y . (2)
(d) Divide by XY and solve for X00/X.
(e) Define a separation constant λ and write down the general
solution for X(x). (2)
(f) Apply the boundary conditions in the x-dimension and obtain
Xn(x). (4)
(g) Write down the general solution for Y (y). (2)
(h) Apply the boundary conditions in the y-dimension and obtain
Ym(x). (3)
(i) Normalise ψnm(x, y). Make use of the fact that x and y are
independent and that
the two integrals may thus be solved independently. (2)
(j) From the definition of k and using λ, obtain the discrete
energies Enm. If we
define Enm ≡ Ex + Ey, write down expressions for the latter two
terms
In: Physics
During 2003, General Motors cut the prices of its car models. As a result, GM earned a profit of only $184 per car, compared to the profit of $555 per car it had earned in 2002. Does the decline in GM’s profits per car indicate that cutting prices was not a profit-maximizing strategy? Briefly explain.
In: Economics