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Alternative Scenarios: |
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Coal (over 1000 miles, same land mass) |
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Human organs used for transplant within the same country/continent (over 1000 miles) |
|
Tens of thousands of pounds of grain used for production of beer (over 1000 miles) |
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5,000 lbs. (2271 kilos) specialized parts used in manufacturing equipment (average value) |
How does the availability of third-party providers influence your decision?
In: Operations Management
Consider the following information regarding the performance of a money manager in a recent month. The table represents the actual return of each sector of the manager’s portfolio in column 1, the fraction of the portfolio allocated to each sector in column 2, the benchmark or neutral sector allocations in column 3, and the returns of sector indices in column 4.
| Actual Return | Actual Weight | Benchmark Weight | Index Return | |||||||||
| Equity | 2.6 | % | 0.6 | 0.6 | 3.1% (S&P 500) | |||||||
| Bonds | 1.5 | 0.2 | 0.1 | 1.7 (Barclay’s Aggregate) | ||||||||
| Cash | 0.8 | 0.2 | 0.3 | 0.9 | ||||||||
a-1. What was the manager’s return in the month? (Do not round intermediate calculations. Input all amounts as positive values. Round your answer to 2 decimal places.)
a-2. What was her overperformance or underperformance? (Do not round intermediate calculations. Input all amounts as positive values. Round your answer to 2 decimal places.)
b. What was the contribution of security selection to relative performance? (Do not round intermediate calculations. Round your answer to 2 decimal places. Negative amount should be indicated by a minus sign.)
c. What was the contribution of asset allocation to relative performance? (Do not round intermediate calculations. Round your answer to 2 decimal places. Negative amount should be indicated by a minus sign.)
In: Finance
A researcher carried out an investigation of the extra sleep produced by drug A and drug B. The data from the experiment in hours are shown. Drug A 0.7 −1.6 −0.2 −1.2 −0.1 3.4 3.7 0.8 0.0 2.0 Drug B 1.9 0.8 1.1 0.1 −0.1 4.4 5.5 1.6 4.6 3.4 The data for both treatment groups are not normally distributed. To determine if the mean sleep response (extra hours of sleep produced) differs between drug A and drug B, a permutation test was performed. This was done by pooling both groups of data and randomly reassigning half the observations to the drug A group, and the other half to the drug B group. The difference of means for these two groups, ?⎯⎯⎯⎯?−?⎯⎯⎯⎯? , was then calculated and recorded. This permutation process was repeated a large number of times. The histogram shows the resulting distribution of values for the mean difference for all the permutations. Nearly symmetric histogram centered at 0 with vertical dashed lines at -1.8 and +1.8, separating the critical region from the non-critical region With a null hypothesis of no difference in the amount of extra sleep between the two drugs, and a two‑sided alternative hypothesis, determine if the actual observed difference is statistically significant. The dashed lines represent the critical values at −1.8 and 1.8, and the total area in the tails of the histogram is 0.05 , which represents the critical (rejection) region.
Compute the difference of the means of the two drugs for the observed data. Give your answer to two decimal places.
In: Statistics and Probability
The Super-Pop Popcorn Company requires a new popcorn plant in Asia. Management collects data related to each site as follows in the table below. Where the plant should be built?
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Section 2: The Super-Pop Popcorn Company requires a new popcorn plant in Asia. Management collects data related to each site as follows in the table below. Where the plant should be built?
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1. Calculate the weighted factor scores for each site.
2. Choose the best site and explain why.
In: Operations Management
IM GETTING A ERROR MESSAGE :
if rentalCode == 'W' and averageMiles <= 900:
mileCharge = weeksRented * 100.00
else:
Collect Customer Data - Part 2
Prompt: "Starting Odometer Reading:\n"
Variable: odoStart = ?
Prompt: "Ending Odometer Reading:\n"
Variable: odoEnd = ?
Add code to PRINT odoStart and odoEnd variables as well as the totalMiles to check your work.
The following data will be used as input in the test:
odoStart = 1234 odoEnd = 2222
Collect Customer Data - Part 2 - Feedback Link
IF you would like some constructive feedback on your assignment before you submit for a grade, press the Help Me! button below.
Help Me!
Customer Data Check 2
In your rental_car.py file, add code to print out the two new
variables you have collected input for:
odoStart
odoEnd
totalMiles
import sys
'''
Section 1: Collect customer input
'''
#Add customer input 1 here, rentalCode = ?
rentalCode = input("(B)udget, (D)aily, or (W)eekly
rental?\n")
print (rentalCode)
#Collect Customer Data - Part 2
#4)Collect Mileage information:
#a) Prompt the user to input the starting odometer
reading and store it as the variable odoStart
#Prompt -->"Starting Odometer Reading:\n"
# odoStart = ?
odoStart = input('Starting Odometer Reading: ')
#b) Prompt the user to input the ending odometer
reading and store it as the variable odoEnd
#Prompt -->"Ending Odometer Reading:"
# odoEnd = ?
odoEnd = input('Ending Odometer Reading: ')
#c) Calculate total miles
totalMiles = int(odoEnd) - int(odoStart)
#Print odoStart, odoEnd and totalMiles
print (odoStart)
print (odoEnd)
print (totalMiles)
# Calculate Charges 2
## Calculate the mileage charge and store it
as
# the variable mileCharge:
#a) Code 'B' (budget) mileage charge: $0.25 for each
mile driven
if rentalCode == "B":
mileCharge = totalMiles * 0.25
#b) Code 'D' (daily) mileage charge: no charge if the
average
# number of miles driven per day is 100 miles or less;
# i) Calculate the averageDayMiles
(totalMiles/rentalPeriod)
elif rentalCode == "D":
averageDayMiles = totalMiles/rentalPeriod
if averageDayMiles <= 100:
extraMiles == 0
# ii) If averageDayMiles is above the 100 mile per
day
# limit:
# (1) calculate extraMiles (averageDayMiles -
100)
if totalMiles >= 100 and rentalCode == 'D':
# (2) mileCharge is the charge for extraMiles,
mileCharge = totalMiles * int(rentalPeriod) *0.25
#c) Code 'W' (weekly) mileage charge: no charge if
the
# average number of miles driven per week is
# 900 miles or less;
if rentalCode == 'W' and averageMiles <= 900:
mileCharge = weeksRented * 100.00
else:
mileCharge = 0
# i) Calculate the averageWeekMiles (totalMiles/
rentalPeriod)
# ii) mileCharge is $100.00 per week if the average
number of miles driven per week exceeds 900 miles
if rentalCode == 'W' and averageMiles >= 900:
mileCharge = weeksRented * 100.00
else:
print('Charges : ${}'.format(mileCharge))
In: Computer Science
35) Calculate the contribution to total performance from currency, country, and stock selection for the manager in the example below. All exchange rates are expressed as units of foreign currency that can be purchased with 1 U.S. dollar. (Do not round intermediate calculations. Round your answers to 2 decimal places. Input all amounts as positive values.)
EAFE Weight Return on
Equity Index E1/E0 Manager's
Weight Manager's Return
Europe 0.6 18
% 1.2 0.7
17 %
Australasia 0.2 18
0.55 0.1
18
Far East 0.2 23
1.4 0.2
18
In: Finance
Calculate the contribution to total performance from currency,
country, and stock selection for the manager in the example below.
All exchange rates are expressed as units of foreign currency that
can be purchased with 1 U.S. dollar. (Do not round
intermediate calculations. Round your answers to 2 decimal places.
Input all amounts as positive values.)
| EAFE Weight | Return on Equity Index |
E1/E0 | Manager's Weight | Manager's Return | |||||||
| Europe | 0.6 | 18 | % | 1.2 | 0.7 | 17 | % | ||||
| Australasia | 0.2 | 18 | 0.55 | 0.1 | 18 | ||||||
| Far East | 0.2 | 23 | 1.4 | 0.2 | 18 | ||||||
In: Finance
Ebling Inc finances with 0.2 fraction debt, 0.1 fraction preferred and the remaining common stock. If Ebeling is subject to a 0.3 fraction corporate income tax, what is the company's Weighted Average Cost of Capital.
In: Finance
For a discrete random variable X, it is known that Pr[X = 1] = 0.15, Pr[X = 3] = 0.3, Pr [X = 5] = 0.35, and Pr[X = 7] = 0.2. Find Pr[X < 5].
In: Statistics and Probability
The average density of planet earth is 5.52 g/cm3. Knowing that Earth has a mass of 5.97*10^27g, determine the earth radius in miles. ( 1 mile = 1609 meters).
In: Chemistry