An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more efficiently. Two alternative loading/unloading methods have been proposed. To account for potential differences due to the type of ride and the possible interaction between the method of loading and unloading and the type of ride, a factorial experiment was designed. Use the following data to test for any significant effect due to the loading and unloading method, the type of ride, and interaction. Use α = 0.05.
| Type of Ride | |||
|---|---|---|---|
| Roller Coaster | Screaming Demon | Log Flume | |
| Method 1 | 41 | 52 | 50 |
| 43 | 44 | 46 | |
| Method 2 | 49 | 50 | 48 |
| 51 | 46 | 44 | |
Find the value of the test statistic for method of loading and unloading.
_____________.
Find the p-value for method of loading and unloading. (Round your answer to three decimal places.)
p-value = _________.
Find the value of the test statistic for type of ride.
____________.
Find the p-value for type of ride. (Round your answer to three decimal places.)
p-value = __________.
Find the value of the test statistic for interaction between method of loading and unloading and type of ride.
____________.
Find the p-value for interaction between method of loading and unloading and type of ride. (Round your answer to three decimal places.)
p-value = _____________.
In: Statistics and Probability
An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more efficiently. Two alternative loading/unloading methods have been proposed. To account for potential differences due to the type of ride and the possible interaction between the method of loading and unloading and the type of ride, a factorial experiment was designed. Use the following data to test for any significant effect due to the loading and unloading method, the type of ride, and interaction. Use α = 0.05.
| Type of Ride | |||
|---|---|---|---|
| Roller Coaster | Screaming Demon | Log Flume | |
| Method 1 | 43 | 50 | 50 |
| 45 | 42 | 46 | |
| Method 2 | 47 | 52 | 48 |
| 49 | 48 | 44 | |
a) Find the value of the test statistic for method of loading and unloading.
Find the p-value for method of loading and unloading. (Round your answer to three decimal places.)
p-value =
b) Find the value of the test statistic for type of ride.
Find the p-value for type of ride. (Round your answer to three decimal places.)
p-value =
c) Find the value of the test statistic for interaction between method of loading and unloading and type of ride.
Find the p-value for interaction between method of loading and unloading and type of ride. (Round your answer to three decimal places.)
p-value =
In: Statistics and Probability
| Case | taste | Acetic | H2S | Lactic |
| 1 | 12.3 | 4.543 | 3.135 | 0.86 |
| 2 | 20.9 | 5.159 | 5.043 | 1.53 |
| 3 | 39 | 5.366 | 5.438 | 1.57 |
| 4 | 47.9 | 5.759 | 7.496 | 1.81 |
| 5 | 5.6 | 4.663 | 3.807 | 0.99 |
| 6 | 25.9 | 5.697 | 7.601 | 1.09 |
| 7 | 37.3 | 5.892 | 8.726 | 1.29 |
| 8 | 21.9 | 6.078 | 7.966 | 1.78 |
| 9 | 18.1 | 4.898 | 3.85 | 1.29 |
| 10 | 21 | 5.242 | 4.174 | 1.58 |
| 11 | 34.9 | 5.74 | 6.142 | 1.68 |
| 12 | 57.2 | 6.446 | 7.908 | 1.9 |
| 13 | 0.7 | 4.477 | 2.996 | 1.06 |
| 14 | 25.9 | 5.236 | 4.942 | 1.3 |
| 15 | 54.9 | 6.151 | 6.752 | 1.52 |
| 16 | 40.9 | 6.365 | 9.588 | 1.74 |
| 17 | 15.9 | 4.787 | 3.912 | 1.16 |
| 18 | 6.4 | 5.412 | 4.7 | 1.49 |
| 19 | 18 | 5.247 | 6.174 | 1.63 |
| 20 | 38.9 | 5.438 | 9.064 | 1.99 |
| 21 | 14 | 4.564 | 4.949 | 1.15 |
| 22 | 15.2 | 5.298 | 5.22 | 1.33 |
| 23 | 32 | 5.455 | 9.242 | 1.44 |
| 24 | 56.7 | 5.855 | 10.199 | 2.01 |
| 25 | 16.8 | 5.366 | 3.664 | 1.31 |
| 26 | 11.6 | 6.043 | 3.219 | 1.46 |
| 27 | 26.5 | 6.458 | 6.962 | 1.72 |
| 28 | 0.7 | 5.328 | 3.912 | 1.25 |
| 29 | 13.4 | 5.802 | 6.685 | 1.08 |
| 30 | 5.5 | 6.176 | 4.787 | 1.25 |
Please help me with activity 8, answer of 6 and 7 are below it
Activity 8: If you add the proportions of variability in taste that can explained by each variable individually (your results from Activity 6), you do not get the same result as the proportion of variability that can be explained by the combined model in Activity 7. Why is this? Look at the relationships that the predictor variables have with one another by constructing scatterplots and finding the correlations between hydrogen sulfide and lactic acid, between hydrogen sulfide and acetic acid, and between lactic acid and acetic acid.
Activity 6
What proportion of the variability in taste can be explained by hydrogen sulfide?
r^2 =0.7558*0.7558=0.5712
What proportion of the variability in taste can be explained by lactic acid?
r^2 =0.7042*0.7042=0.4959
What proportion of the variability in taste can be explained by acetic acid?
r^2 =0.5495*0.5495=0.3020
Activity 7
Estimate the equation of the regression line predicting taste score based on all three predictor variables in a single equation.
taste = -28.877 + 0.328 x Acetic +3.912 x H2S + 19.671 x Lactic
What taste score would you predict for a cheese whose hydrogen sulfide measurement was 5.0, whose acetic acid measurement was 6.1, and whose lactic acid measurement was 0.90?
taste = 10.39
What proportion of the variability in taste can be explained by the model using all three predictor variables?
R^2 = 0.6518
In: Statistics and Probability
| 1 | 1 | 111.5 |
| 1 | 2 | 97.7 |
| 1 | 3 | 126.1 |
| 2 | 1 | 94.4 |
| 2 | 2 | 70.5 |
| 2 | 3 | 93.1 |
| 3 | 1 | 73.9 |
| 3 | 2 | 56.2 |
| 3 | 3 | 84.6 |
In many agricultural and biological experiments, one may use a two‑way model with only one observation per cell. When one of the factors is related to the grouping of experimental units into more uniform groups, the design may be called a randomized complete block design (RCBD). The analysis is similar to a two‑way analysis of variance (question B) except that the model does not include an interaction term.
The specific leaf areas (area per unit mass) of three types of citrus each treated with one of three levels of shading are stored in Table C. The first column contains the code for the shading treatment, the second column contains the code for the citrus species, and the third column contains the specific leaf area. Assume that there is no interaction between citrus species and shading. Carry out a two‑way analysis of this data.
The shading treatment and citrus species are coded as follows:
Treatment Code Species Code
Full sun 1 Shamouti orange 1
Half shade 2 Marsh grapefruit 2
Full shade 3 Clementine mandarin 3
nCopy the treatment code, the species code, and the specific leaf area into the EXCEL worksheet, label the columns and look at the data.
{Example 1}
nPerform a two‑way (without interaction) analysis of this data and answer the following questions. Use a 5% significance level.
|
Source of variation |
Degrees of freedom |
Sum of squares |
Mean square |
F |
P |
||||
|
Shading treatment |
2 |
||||||||
|
Citrus species |
2 |
||||||||
|
Error |
4 |
|
24. Should the hypothesis that shading treatment has no effect on specific leaf area be rejected (1) or not (0)? |
|
25. Should the hypothesis that citrus species do not differ in specific leaf area be rejected (1) or not (0)? |
|
26. What is the estimate of the average (pooled) variance in this experiment (i.e. Error mean square)? |
|
27. What are the error degrees of freedom for the pooled variance? |
{Example 26}
Recall that the confidence interval for a difference between two means is based on a calculation of the margin of error of the estimated difference. With a common variance (Error MS) and the same number of observations in all shading treatments, the margin of error of an estimated difference will be the same whether we calculate it for treatments 1 and 2, 1 and 3, or 2 and 3. This margin of error of the difference between two means is sometimes referred as the least significant difference (LSD).
nCalculate the LSD for comparing shading treatments in this experiment.
LSD = critical tvalue ´standard error of difference.
Use the critical t value with 4 degrees of freedom is t 0.025,4= 2.776.
n is the number of times of times each treatment was tested (in this case n = 3 for the 3 species).
|
28. What is the least significant difference (a = 0.05) for comparing shading treatments in this experiment? |
In: Statistics and Probability
what are the ethical responsilities of a firm to its employees and customers.
In: Psychology
can selling and distribution expenses vary by customers & why
In: Accounting
Discuss in detail the motivators and determinants for customers of Ragdale Hall
In: Economics
Amicable Wireless, Inc. offers credit terms of 2/10, net 30 for its customers. Sixty percent of Amicable's customers take the 2% discount and pay on day 10. The remainder of Amicable's customers pay on day 30. How many days' sales are in Amicable's accounts receivable?
In: Accounting
The goal of customer relationship management is to: manage every customer relationship differently. manage every customer relationship to maximize short-term profitability. eliminate customers who are profitable, but not highly profitable. identify and build loyalty among a firm's most valued customers. generate relationships with competitor's customers.
In: Operations Management
Interpreting the Accounts Receivable Footnote
Hewlett-Packard Company reports the following in its 2015 10-K
report.
| October 31 (in millions) |
2015 |
2014 |
|---|---|---|
| Accounts receivable | $13,363 | $13,832 |
Footnotes to the company's 10-K provide the following additional
information relating to its allowance for doubtful accounts.
| For the fiscal years ended October
31 (in millions) |
2015 |
2014 |
2013 |
|---|---|---|---|
| Allowance for doubtful accounts-accounts receivable | |||
| Balance, beginning of period | $232 | $332 | $464 |
| Provision for doubtful accounts | 46 | 25 | 23 |
| Deductions, net of recoveries | (89) | (125) | (155) |
| Balance, end of period | $189 | $232 | $332 |
(a) What is the gross amount of accounts receivables for
Hewlett-Packard in fiscal 2015 and 2014?
| ($ millions) | 2015 | 2014 |
|---|---|---|
| Gross accounts receivable | Answer | Answer |
(b)What is the percentage of the allowance for doubtful accounts to
gross accounts receivable for 2015 and 2014? (Round your answers to
two decimal places.)
| ($ millions) | 2015 | 2014 | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Percentage of uncollectible accounts to gross accounts
receivable(d)Compute Hewlett-Packard's write-offs as a percentage
of the allowance account at the beginning of the year. (Round your answers to two decimal places) 2015 write-offs as a percentage of beginning of year allowance: Answer % 2014 write-offs as a percentage of beginning of year allowance: Answer % 2. Revenue Recognition: We generally recognize sales, net of estimated returns, at the time the member takes possession of merchandise or receives services. When we collect payment from customers prior to the transfer of ownership of merchandise or the performance of services, the amount recieved is generally recorded as deferred revenue on the consolidated balance sheets until the sales or service is completed. Membership fee revenue represents annual membership fees paid by our memberships. We account for membership fee revenue, net of estimated refunds, on a deferred basis, whereby revenue is recognized ratably over the one-year membership period.
(b) Use the balance sheet information on Costco's Deferred Membership Fees liability account and its income statement revenues related to Membership Fees earned during 2016 to compute the cash that Costco received during 2016 for membership fees. Total cash received (in $ millions) = $Answer
|
Answer % | Answer % | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
In: Accounting