1. CPK and SGOT tests are used in the diagnosis of myocardial infarction (MI). When the CPK test is given to a patient who does not have a MI, the probability of a negative finding (i.e. its specificity) is 0.6. The probability that the SGOT test will be negative for a non-MI patient is 0.7. When both tests are given to a non-MI patient the probability that at least one is negative is 0.9. For a non-MI patient who has both tests:
Hints: (1) Answer is not 0.12 -- tests are not to be assumed to be independent.
(2) Using 2-by-2 table to structure your calculations can help.
In: Math
An uninsulated steam pipe with a wall temperature of 140 °C passes through a room of quiescent air of 14 °C. The pipe is horizontal and has an outer diameter of 20 cm. Find the following (include units if needed):
a) The temperature to evaluate properties = __________
b) The Rayleigh number, _____________
c) The heat transfer coefficient, h = ____________
d) q’ along the pipe = ________________
e) The pipe diameter is decreased by 50%. If all other parameters remain the same, will the heat transfer coefficient increase, decrease or stay the same? ___________. Justify your answer mathematically. For air: ν = 20.92 x 10-6 m2/s, α = 29.9 x 10-6 m2/s, 30 x 10-3 W/m·K, Pr = 0.7
In: Mechanical Engineering
Batch and continuous biomass production Pseudomonas methylotrophus is used to produce single cell protein from methanol in a 1000-m pressure-cycle airlift fermenter. The biomass yield from substrate is 0.41 gg-, Ks is 0.7 mg 1", and the maximum specific growth rate is 0.44 h. The medium contains 4% (w/v) methanol. A substrate conversion of 98% is desirable. The reactor may be operated in either batch or continuous mode. If operated in batch, an inoculum of 0.01% (w/v) is used and the downtime between batches is 20 h. If continuous operations are used at steady state, a downtime of 25 days is expected per year. Neglecting maintenance requirements, compare the annual biomass production achieved using batch and continuous reactor
In: Other
(1 point) A manufacturer of electronic kits has found that the mean time required for novices to assemble its new circuit tester is 2.9 hours, with a standard deviation of 0.7 hours. A consultant has developed a new instructional booklet intended to reduce the time an inexperienced kit builder will need to assemble the device and the manufacturer needs to decide whether or not to send out the new booklet.
The testable hypotheses in this situation are
H0:μ=2.9
vs HA:μ<2.9
.
1. Identify the consequences of making a Type I error.
A. The manufacturer sends out a helpful
instructional booklet.
B. The manufacturer does not send out a helpful
instructional booklet.
C. The manufacturer does not send out an unhelpful
instructional booklet.
D. The manufacturer sends out an unhelpful
instructional booklet.
2. Identify the consequences of making a Type II error.
A. The manufacturer does not send out a helpful
instructional booklet.
B. The manufacturer sends out a helpful
instructional booklet.
C. The manufacturer does not send out an unhelpful
instructional booklet.
D. The manufacturer sends out an unhelpful
instructional booklet.
To monitor the assembly time of inexperienced kit builders using the booklet, the manufacturer is going to take a random sample of 14 novices and calculate the mean time to assemble the circuit tester. If it is less than 2.7, they will send out the new instructional booklet. Assume the population standard deviation is 0.7 hours.
3. What is the probability that the manufacturer will make a Type I error using this decision rule? Round your answer to four decimal places.
4. Using this decision rule, what is the power of the test if the actual mean time to assemble the circuit tester is 2.75 hours? That is, what is the probability they will reject H0 when the actual average time is 2.75 hours? Round your answer to four decimal places.
In: Statistics and Probability
Assume that the differences are normally distributed. Complete parts (a) through (d) below.
|
Observation |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
|
|||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
Upper X Subscript iXi |
46.746.7 |
47.747.7 |
45.645.6 |
50.250.2 |
48.448.4 |
50.850.8 |
47.847.8 |
48.648.6 |
||||||||||||||||
|
Upper Y Subscript iYi |
50.150.1 |
48.448.4 |
47.347.3 |
54.554.5 |
47.947.9 |
50.950.9 |
49.649.6 |
50.350.3 |
||||||||||||||||
(a) Determine
d Subscript i Baseline equals Upper X Subscript i Baseline minus Upper Y Subscript idi=Xi−Yi
for each pair of data.
|
Observation |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
|---|---|---|---|---|---|---|---|---|
|
di |
negative 3.4 −3.4 |
negative 0.7 −0.7 |
negative 1.7 −1.7 |
negative 4.3 −4.3 |
0.5 0.5 |
negative 0.1 −0.1 |
negative 1.8 −1.8 |
negative 1.7 −1.7 |
(Type integers or decimals.)
(b) Compute
d overbard
and
s Subscript dsd.
d overbardequals=negative 1.650 −1.650
(Round to three decimal places as needed.)
s Subscript dsdequals=1.605 1.605
(Round to three decimal places as needed.)(c) Test if
mu Subscript dμdless than<0
at the
alphaαequals=0.05
level of significance.
What are the correct null and alternative hypotheses?
A.
Upper H 0H0:
mu Subscript dμdless than<0
Upper H 1H1:
mu Subscript dμdequals=0
B.
Upper H 0H0:
mu Subscript dμdgreater than>0
Upper H 1H1:
mu Subscript dμdless than<0
C.
Upper H 0H0:
mu Subscript dμdless than<0
Upper H 1H1:
mu Subscript dμdgreater than>0
D.
Upper H 0H0:
mu Subscript dμdequals=0
Upper H 1H1:
mu Subscript dμdless than<0
In: Math
Fixed acidity - Volatile acidity - Citric acid - Residual sugar -Chlorides
7.4 0.7 0 1.9 0.076
7.8 0.88 0 2.6 0.098
7.8 0.76 0.04 2.3 0.092
11.2 0.28 0.56 1.9 0.075
7.4 0.7 0 1.9 0.076
7.4 0.66 0 1.8 0.075
7.9 0.6 0.06 1.6 0.069
7.3 0.65 0 1.2 0.065
7.8 0.58 0.02 2 0.073
7.5 0.5 0.36 6.1 0.071
6.7 0.58 0.08 1.8 0.097
7.5 0.5 0.36 6.1 0.071
5.6 0.615 0 1.6 0.089
7.8 0.61 0.29 1.6 0.114
8.9 0.62 0.18 3.8 0.176
8.9 0.62 0.19 3.9 0.17
8.5 0.28 0.56 1.8 0.092
8.1 0.56 0.28 1.7 0.368
7.4 0.59 0.08 4.4 0.086
7.9 0.32 0.51 1.8 0.341
8.9 0.22 0.48 1.8 0.077
7.6 0.39 0.31 2.3 0.082
7.9 0.43 0.21 1.6 0.106
8.5 0.49 0.11 2.3 0.084
6.9 0.4 0.14 2.4 0.085
6.3 0.39 0.16 1.4 0.08
1. For the data on 26 red wines given above, conduct the following analysis:
i. Provide five-number summary i.e. the minimum, 1st quartile, median, 3rd quartile, and maximum value for fixed acidity. Arrange them in increasing order on a straight line, draw a box plot and interpret what it means.
ii. Calculate the correlation coefficient between fixed acidity and volatile acidity and between residual sugar and chlorides. Comment on the strength and direction of association for the two variable pairs.
iii. What can be stated about the cause-effect relationship between fixed acidity and volatile acidity, based on the correlation coefficient score?
In: Math
A power plant that supplies a community with electricity costs $1 billion to build, lasts 25 years, and has an annual operating cost of $0.2 billion; it costs $0.1 billion to decommission the plant at the end of its lifetime (25 years). (Assume that the construction costs and the operating costs are paid at the beginning of the period, and that the decommissioning cost is paid at the end of the life of the plant.) The annual discount rate is r, with discount factor ρ = 1 1+r . Write the formula for the present value of the cost of providing this community with electricity for 100 years, including the decommissioning costs. (Hint: First find the present value of providing one unit of electricity for 25 years. Denote this magnitude as Z. Then find the present value of incurring this cost, Z, 4 times: in periods 0, 25, 50, and 75.)
In: Finance
Modify model for projection of free cash flows from the Home Net project along the following dimensions:
5-year MACRS:
Year 0: 20%
Year 1: 32.0%
Year 2: 19.2%
Year 3: 11.52%
Year 4: 11.52%
Year 5: 5.76%
Data for the question:
| Year | 0 | 1 | 2 | 3 | 4 | 5 | |
| Price per unit | 260 | 260 | 260 | 260 | 260 | 260 | |
| # of units | 0 | 100,000.00 | 100,000.00 | 100,000.00 | 100,000.00 | 0 | |
| Expected loss in sales of routers (%%) | 0 | 0.25 | 0.25 | 0.25 | 0.25 | 0.25 | |
| Price per unit (router) | 100 | 100 | 100 | 100 | 100 | 100 | |
| Cost of Goods Sold Router/unit | 60 | 60 | 60 | 60 | 60 | 60 | |
| Cost of Goods Sold/unit | 110 | 110 | 110 | 110 | 110 | 110 | |
| Marketing Costs/year | 0 | 2,800,000.00 | 2,800,000.00 | 2,800,000.00 | 2,800,000.00 | 0 | |
| Opportunity Cost (Lab) | 0 | 200,000.00 | 200,000.00 | 200,000.00 | 200,000.00 | 0 | |
| New Equipment/year | 7,500,000.00 | 0 | 0 | 0 | 0 | 0 | |
| Depreciation schedule | 0 | 0.2 | 0.2 | 0.2 | 0.2 | 0.2 | |
| Software Development: | |||||||
| Engineers | 50 | 0 | 0 | 0 | 0 | 0 | |
| Cost/engineer | 200,000.00 | 0 | 0 | 0 | 0 | 0 | |
| Design and Engineering | 5,000,000.00 | 0 | 0 | 0 | 0 | 0 | |
| Tax Rate | 0.4 | 0.4 | 0.4 | 0.4 | 0.4 | 0.4 | |
| HomeNet's Net Working Capital Requirements | |||||||
| Cash | 0 | 0 | 0 | 0 | 0 | 0 | |
| Inventory | 0 | 0 | 0 | 0 | 0 | 0 | |
| Receivables (15% Sales) | 0 | 3,525,000.00 | 3,525,000.00 | 3,525,000.00 | 3,525,000.00 | 0 | |
| Payables (15% COGS) | 0 | 1,425,000.00 | 1,425,000.00 | 1,425,000.00 | 1,425,000.00 | 0 | |
| NWC | 0 | 2,100,000.00 | 2,100,000.00 | 2,100,000.00 | 2,100,000.00 | 0 | |
| Change in NWC | 0 | 2,100,000.00 | 0 | 0 | 0 | -2,100,000.00 | |
| Sales | 0 | 23,500,000.00 | 23,500,000.00 | 23,500,000.00 | 23,500,000.00 | 0 | |
| COGS | 0 | 9,500,000.00 | 9,500,000.00 | 9,500,000.00 | 9,500,000.00 | 0 | |
| Gross Profit | 0 | 14,000,000.00 | 14,000,000.00 | 14,000,000.00 | 14,000,000.00 | 0 | |
| Selling, General, Admin. Expnenses | 0 | 3,000,000.00 | 3,000,000.00 | 3,000,000.00 | 3,000,000.00 | 0 | |
| Research and Development | 15,000,000.00 | 0 | 0 | 0 | 0 | 0 | |
| Depreciation | 0 | 1,500,000.00 | 1,500,000.00 | 1,500,000.00 | 1,500,000.00 | 1,500,000.00 | |
| EBIT | -15,000,000.00 | 9,500,000.00 | 9,500,000.00 | 9,500,000.00 | 9,500,000.00 | -1,500,000.00 | |
| Income Tax | -6,000,000.00 | 3,800,000.00 | 3,800,000.00 | 3,800,000.00 | 3,800,000.00 | -600,000.00 | |
| NI (Unlevered) | -9,000,000.00 | 5,700,000.00 | 5,700,000.00 | 5,700,000.00 | 5,700,000.00 | -900,000.00 | |
| Plus: Depreciation | 0 | 1,500,000.00 | 1,500,000.00 | 1,500,000.00 | 1,500,000.00 | 1,500,000.00 | |
| Less:Capital Expenditures (Equipm.) | 7,500,000.00 | 0 | 0 | 0 | 0 | 0 | |
| Less: change in NWC | 0 | 2,100,000.00 | 0 | 0 | 0 | -2,100,000.00 | |
| FCF | -16,500,000.00 | 5,100,000.00 | 7,200,000.00 | 7,200,000.00 | 7,200,000.00 | 2,700,000.00 | |
| Cost of capital | 0.12 | ||||||
| PV of CFS | -16,500,000.00 | 4,553,571.43 | 5,739,795.92 | 5,124,817.78 | 4,575,730.16 | 1,532,052.51 | |
| NPV | 5,025,967.81 |
In: Finance
SCENARIO 8-12
The Three Brothers Energy Drink Company bottles and distributes a
popular drink for athletes and exercise enthusiasts. Because of its
marketing successes the company has installed an additional filling
machine and the managers are eager to use it in daily operations.
The machine is set to fill bottles at 16 oz.
However, we know there is inherent machine variability and quality
control has determined through testing a mean of 16.2 oz. and a
standard deviation of 0.3 oz. using a 100 bottle sample.
Refer to Scenario 8-12.
Find a 90% confidence interval for the mean volume of the filled
bottle contents.
In: Economics
During a 5-week period in 2007, the stock of an insurance company and the stock of a small tech company showed the following weekly percentage changes.
| Company | Weekly Price Change (%) | ||||
| Insurance Stock | 2 | -1 | -1.7 | 0.6 | -0.3 |
| Tech Stock | 3 | 2.2 | 1.3 | -4.3 | 1.7 |
Find the variance of the weekly price changes of each. (Round your
answers to four decimal places.)
| insurance stock | ||
| tech stock |
Relate the two variances found to the riskiness of the two stocks.
The two stocks have the same riskiness.The insurance stock is riskier. No statement about the riskiness of these stocks can be made.The tech stock is riskier.
In: Statistics and Probability