The data in the table is the number of absences for 7 students and their corresponding grade. Number of Absences 1 2 3 4 6 7 8 Grade 5 4.5 4 3.5 2.5 2 1

Step 1 of 3: Calculate the correlation coefficient, r. Round your answer to six decimal places. Step 2 of 3: Determine if r is statistically significant at the 0.01 level. Step 3 of 3: Calculate the coefficient of determination, r2 . Round your answer to three decimal places.

The data in the table is the number of absences for 7 students and their corresponding grade. Number of Absences 2 3 3 5 5 6 6 Grade 3.8 3.6 3.2 2.5 2.1 2 1.7 Table

Step 1 of 5 : Calculate the sum of squared errors (SSE). Use the values b0=4.8669 and b1=−0.5056 for the calculations. Round your answer to three decimal places.

Step 2 of 5 : Calculate the estimated variance of errors, s2e. Round your answer to three decimal places.

Step 3 of 5 : Calculate the estimated variance of slope, s2b1. Round your answer to three decimal places.

Step 4 of 5 : Construct the 98% confidence interval for the slope. Round your answers to three decimal places.

Step 5 of 5 : Construct the 80% confidence interval for the slope. Round your answers to three decimal places.

The data in the table is the number of absences for 7 students and their corresponding grade.

Calculate the estimated variance of slope, s^2b1. Round your answer to three decimal places.

Construct the 90% confidence interval for the slope. Round your answers to three decimal places.

Construct the 90% confidence interval for the slope. Round your answers to three decimal places.

Construct the 95% confidence interval for the slope. Round your answers to three decimal places.

Construct the 99% confidence interval for the slope. Round your answers to three decimal places.

Construct the 80% confidence interval for the slope. Round your answers to three decimal places.

Construct the 85% confidence interval for the slope. Round your answers to three decimal places.

Students in a school were asked to participate in a study of the effects of a new teaching method on reading skills of 10th graders. To determine the effectiveness of the new method, a reading test was given to each student before applying the new method (pre-test). Another test was given to the same students after applying the new method (post-test). Experts consider that a good measure of improvement is given by the following formula: Improvement=20(Post-test score)- 10(Pre-test score). That is, improvement is 20 times the post-test score minus 10 times the pre-test score. An improvement ? 300 is considered good. It is known that the average score in the pre-test is 40, average score in the post-test is 40, standard deviation in the post-test is 6, standard deviation in the pre-test is 5, and correlation between the scores in the two tests is 0.5

What is the standard deviation of the improvement?

Write the Variance covariance matrix for the pre and post-test scores vector random variable.

The data in the table is the number of absences for 7 students and their corresponding grade.

Step 3 of 5 : Calculate the estimated variance of slope, s2b1. Round your answer to three decimal places.

The question was:

Finals are over and the marks are in. For all the students who have completed the introductory course to business statistics the distribution of the grades represented a bell-shaped distribution, symmetrical about the average which was 75.90 marks. The standard deviation was 1.40.

Given the information above, answer the following questions using the Empirical Rule.

For full marks your answer should be accurate to at least two decimal places.

a) Approximately what percentage of marks were above 77.30?

b) Approximately what percentage of marks were below 71.70?

c) Approximately what percentage of marks were between 71.70 and 80.10?

I don't want to get answers, I want method steps，Thanks!

The data in the table is the number of absences for 7 students and their corresponding grade. Number of Absences 0 1 2 3 5 6 7 Grade 4.5 4 3.5 3 2.5 2 1.5

Step 1 of 3: Calculate the correlation coefficient, r. Round your answer to six decimal places.

Calculate the coefficient of determination, r2r2. Round your answer to three decimal places.

Determine if r is statistically significant at the 0.050.05 level.

1.

In a certain school district, it was observed that 30% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 136 out of 392 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the α=0.02 level of significance.

What is the hypothesized population proportion for this test?
p=
(Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.)

Based on the statement of this problem, how many tails would this hypothesis test have?

• one-tailed test
• two-tailed test

Choose the correct pair of hypotheses for this situation:

Ha:p<0.3

Ha:p≠0.3

Ha:p>0.3

Ha:p<0.347

Ha:p≠0.347

Ha:p>0.347

(A)

(B)

(C)

(D)

(E)

(F)

Using the normal approximation for the binomial distribution (without the continuity correction), what is the test statistic for this sample based on the sample proportion?
z=
(Report answer as a decimal accurate to 3 decimal places.)

You are now ready to calculate the P-value for this sample.
P-value =
(Report answer as a decimal accurate to 4 decimal places.)

This P-value (and test statistic) leads to a decision to...

• reject the null
• accept the null
• fail to reject the null
• reject the alternative

As such, the final conclusion is that...

• There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program.
• There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program.
• The sample data support the assertion that there is a different proportion of only children in the G&T program.
• There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program.

2.

In a certain school district, it was observed that 29% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 122 out of 374 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the α=0.01 level of significance.

What is the hypothesized population proportion for this test?
p=

(Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.)

Based on the statement of this problem, how many tails would this hypothesis test have?

• one-tailed test
• two-tailed test

Choose the correct pair of hypotheses for this situation:

Ha:p<0.29

Ha:p≠0.29

Ha:p>0.29

Ha:p<0.326

Ha:p≠0.326

Ha:p>0.326

(A)

(B)

(C)

(D)

(E)

(F)

Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion?
z=
(Report answer as a decimal accurate to 3 decimal places.)

You are now ready to calculate the P-value for this sample.
P-value =
(Report answer as a decimal accurate to 4 decimal places.)

This P-value (and test statistic) leads to a decision to...

• reject the null
• accept the null
• fail to reject the null
• reject the alternative

As such, the final conclusion is that...

• There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program.
• There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program.
• The sample data support the assertion that there is a different proportion of only children in the G&T program.
• There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program.

The purpose of this assignment is to provide students with an opportunity to develop a framework for the development of a database that would support a Post-operative Follow-Up Module in an Ambulatory Surgery Center.

Please read the article contained in this link and answer the following questions: [Article about Structured Vs. Unstructured Data].

1. What are the critical issues that Post-Anesthesia Care Unit (PACU) staff must address when contemplating the development of a Post-operative Follow-Up Module?

2. When considering the issue of recording post-operative complications, should the clinical staff rely more on structure or unstructured data? Please provide a rationale for your answer. Please see Reading Assignment – Week 03 for a discussion on the merits of structured versus unstructured data.

3. What hesitations might IT Staff express when considering the prospect of developing a module for the collection of post-operative discharge follow-up data in an Ambulatory Surgical Center?   Might the anticipated replacement of the entire legacy EHR system in approximately 18 months factor into the decision of the IT staff with regard to this project?

The data in the table is the number of absences for 7 students and their corresponding grade.

Step 1 of 5: Calculate the sum of squared errors (SSE). Use the values b0=4.1440 and b1=−0.3047 for the calculations. Round your answer to three decimal places.

Step 2 of 5: Calculate the estimated variance of errors, Round your answer to three decimal places.

Step 3 of 5: Calculate the estimated variance of slope, . Round your answer to three decimal places.

Step 4 of 5: Construct the 95% confidence interval for the slope. Round your answers to three decimal places.

Step 5 of 5: Construct the 90% confidence interval for the slope. Round your answers to three decimal places.