1. Convert 101 from base-2 number system to base-10 number system
2. Convert 101 from base-2 number system to base-16 number system
3. Convert 100 from base-10 number system to base-2 number system
4. Convert 100 from base-10 number system to base-16 number system
5. Convert ef from base-16 number system to base-2 number system
6. Convert ef from base-16 number system to base-10 number system

  Ashcroft Airlines flies a six-passenger commuter flight once a day to Gainesville, Florida.         A non-refundable one-way fare with a reservation costs $129. The daily demand for this         flight is given in the table below, along with the probability distribution of no-shows. A         no-show has a reservation but does not arrive on time at the gate and forfeits the fare.         Ashcroft currently overbooks at most three passengers per flight. If there are not         enough seats for all the passengers at the gate, each passenger that cannot board the         flight is refunded the passenger’s fare and also $150 voucher good on any other trip.         The fixed cost for a flight is $450.

        i) Set up a flow chart showing the logical sequence of events for simulating Ashcroft’s              expected profit for this flight. Provide all the details of the formulas used for relevant         calculations.                                                                                         [20%]

        ii) Using the two-digit random numbers below (in the order as they appear),                         calculate Ashcroft’s profit per flight and replicate your calculations 10 times.                     Organise all your calculation in a table. Calculate the expected profit, the                           occupancy rate of the plane and the probability that Ashcroft profit per flight is                  higher than $400? Briefly comment on the reliability of your results.             [50%]

           Random number sequence: 69 56 30 32 66 79 55 24 80 35 10 98 92 92 88            82 13 04 86 31 12 23 40 93 13 42 51 16 17 29 62 08 59 41 47 72 25            96 58 14 68 15 18 99 13 05 03 83 34 78 50 89 98 93 70 11

        iii) Explain how you could use this model to investigate Ashroft’s overbooking strategy             (no calculations required).                                                                    [15%]

Question 3B

CWD Electronics sells Televisions (TV), which it orders from the USA. Because of shipping and handling costs, each order must be for 10 TVs. Because of the time it takes to receive an order, the company places an order every time the present stock drops to 5 TVs. It costs $50 to place an order. It costs the company $200 in lost sales when a customer asks for a TV and the warehouse is out of stock. It costs $50 to keep each TV stored in the warehouse. If a customer cannot purchase a TV when it is requested, the customer will not wait until one comes in but will go to a competitor. The following probability distribution for demand for TV has been and the time required to receive an order once it is placed (lead time) has the following probability distribution:

The company has 10 TVs in stock. Orders are always received at the beginning of the week.

Note that a lead time of 2 weeks imply that an order placed in week one will arrive in week 4.

Hint. No order is placed until the current order has arrived. Usage of all random numbers for lead time depend on stock arrivals in the model hence all numbers may not be used.

Required

a) Construct the appropriate random number mappings for the random variables starting with .00. (2.5 marks for demand and 1.5 mark for lead time)

b) Simulate CWD's ordering and sales policy for 20 weeks.

c) Compute the average cost of the policy ( 4 marks)

Use the following headings

In each of the following problems, identify a probability question and a statistics question associated with the given information.

(a) It has been reported that 81%81% of U.S. Americans have a social media profile. Consider a random sample of 100100 U.S. Americans.

1. How likely would it be to observe that less than 5050 of the sampled Americans have a social media profile?
2. Within the sample of 100100 Americans, only 5050 reported having a social media profile. What does this result suggest about the reported national percentage of social media users?

(b) In general, 36%36% of all people use the same password for everything. Consider a random sample of 50 people.50 people.

1. We observe that 2121 of the selected 5050 use the same password for everything. Does this suggest that the true percentage of people that use the same password for everything is actually different than 36%?than 36%?
2. What is the probability that exactly 2121 of the selected individuals use the same password for everything?

(c) In Norway, 52%52% of all passenger cars are plug‑in electric vehicles.

1. Suppose you walk through a parking lot in Norway. What is the probability that none of the first 1616 cars you observe are plug‑in electric?
2. Suppose you take a random sample of 3535 cars in Denmark and 1919 of them are plug‑in electric. Does this sample provide evidence to suggest that Denmark has a higher percentage of electric cars than Norway?

(d) Fifty‑four percent of all injuries due to snow shoveling fall into the category of pulled muscles.

1. Suppose an insurance agency sees an atypically large number of snow shoveling‑related insurance claims this winter, all from the same neighborhood. If they observe that 66 of the 1010 claims are not categorized as pulled muscles, do they have evidence to suggest that these claims may be fraudulent?
2. Suppose that 33 people in your neighborhood suffer from snow shoveling injuries this winter. What is the likelihood that all 33 injuries are categorized as pulled muscles?

WHICH OF THESE IS THE PROBABILITY QUESTIONS AND WHICH OF THESE IS THE STATISTICS QUESTIONS ? (IDENTIFY)

prob - stat -

Demand for walnut fudge ice cream at the Sweet Cream Dairy can be approximated by a normal distribution with a mean of 17 gallons per week and a standard deviation of 3.2 gallons per week. The new manager desires a service level of 90 percent. Lead time is two days, and the dairy is open seven days a week. (Hint: Work in terms of weeks.)

a-1. If an ROP model is used, what ROP would be consistent with the desired service level? (Do not round intermediate calculations. Round your final answer to 2 decimal places.)

ROP ______ gallons

a-2. How many days of supply are on hand at the ROP, assuming average demand? (Do not round intermediate calculations. Round your final answer to 2 decimal places.)

Days _______

b-1. If a fixed-interval model is used instead of an ROP model, what order size would be needed for the 90 percent service level with an order interval of 7 days and a supply of 8 gallons on hand at the order time? (Do not round intermediate calculations. Round your final answer to the nearest whole number.)

Order size _______ gallons

b-2. What is the probability of experiencing a stockout before this order arrives? (Do not round intermediate calculations. Round your final answer to the nearest whole percent. Omit the "%" sign in your response.)

Probability _________ %

c. Suppose the manager is using the ROP model described in part a. One day after placing an order with the supplier, the manager receives a call from the supplier that the order will be delayed because of problems at the supplier’s plant. The supplier promises to have the order there in two days. After hanging up, the manager checks the supply of walnut fudge ice cream and finds that 2 gallons have been sold since the order was placed. Assuming the supplier’s promise is valid, what is the probability that the dairy will run out of this flavor before the shipment arrives? (Do not round intermediate calculations. Round your final answer to the nearest whole percent. Omit the "%" sign in your response.)

Risk probability _________ %

Risk analysis is one way to monitor security in an organization. Risk analysis can be a time- consuming process; it involves a number
of steps, some of which require “educated guessing.” Nevertheless, the process alone raises awareness of security issues even if no immediate actions are taken as a result. The steps are:

i. Identify assets (infrastructure, people, hardware, software, reputation, etc.).

For the rest of this list, we’ll concentrate on a single asset.

ii. Determine vulnerability (what event or events might happen to the asset. For example, the building could catch fire, the website could be hacked, etc.).

For the rest of this list, we’ll concentrate on a single asset vulnerable to a single event.

ii. Estimate the probability per year of this event (based on past data, expert estimates, etc.). Take current security measures into account.

iv. Estimate the expected cost if this event occurs (cost to repair or replace, cost of lost business, etc.).

v. Compute risk exposure 5 cost estimate 3 probability estimate.

vi. Identify any additional security measure X that would help protect against this event, determine what it would cost, and do a calculation of the risk exposure with the additional security measure X in place.

vii. Do a cost-benefit analysis:
(Risk exposure without X – Risk exposure with X) − Cost of X

You have a small web-based business that uses a single server to manage your webpage and your customer information. Over the past four years, your website has been hacked and taken down twice. You estimate that the cost of this event is $600 to clean the server and reload the webpage and $12,000 in lost business while the server is down.

1. You could purchase a backup server for a cost of $3,000, which you estimate would reduce the probability per year of losing your website to 0.2. Would this be a cost- effective security measure?

2. What if you reevaluate the probability per year with the backup server to be 0.3. Does this change your answer?

Don't attempt if you can't attempt fully, i will dislike and negative comments would be given Please it's a request.

c++
We will read a CSV files of a data dump from the GoodReads 2 web site that contains information
about user-rated books (e.g., book title, publication year, ISBN number, average reader rating,
and cover image URL). The information will be stored and some simple statistics will be
calculated. Additionally, for extra credit, the program will create an HTML web page based on
the top n highest rated books. As is typical of many subject matter information sources, the data
in the file contains various errors. As such, we will track the errors and create an exceptions files
to track the lines with data errors.
Develop a class, bookDataType, to provide functionality for reading and storing book
information. The UML class specifications are provided below. A main will be provided that
uses the bookDataType class.
●
Book Data Type Class
The class will implement the functions.
bookDataType
-COL_LIMIT = 23: static constexpr unsigned int
-TOP_LIMIT = 20: static constexpr unsigned int
-booksFileName: string
-webPageFileName: string
-exceptionsFileName: string
-bookCount: unsigned int
1 For more information, refer to: https://en.wikipedia.org/wiki/Comma-separated_values
2 See: www.goodreads.com-topBooksLimit: unsigned int
-*topBooks: unsigned int
-struct bookErrsStruct
-bookIDErrors: unsigned int
-bookYearErrors: unsigned int
-AveRatingErrors: unsigned int
-duplicateDataErrors: unsigned int
-bookErrInfo: bookErrsStruct
-struct bookStruct
-bookTitle: string
-isbn: string
-pubYear: short
-aveRating: float
-imageURL: string
-bookID: unsigned int
-*bookInfo: bookStruct
+bookDataType()
+~bookDataType()
+getBookArguments(int, char *[], string &, bool &): bool
+getBookFileName() const: string
+getWebPageFileName() const: string
+getExceptionsFileName() const: string
+getReadBookIDErrors() const: unsigned int
+getReadBookYearErrors() const: unsigned int
+getReadBookAveRatingErrors() const: unsigned int
+getReadBookDuplicateErrors() const: unsigned int
+getTopBooksLimit() const: unsigned int
+showBookData(unsigned int) const: void
+getBookCount() const: unsigned int
+getAverageOverallRating() const: float
+showHighestRatedBooks() const: void
+readBookData(const string): bool
+buildWebPage(const string="CS 202 Top Books") const: bool
+findHighestRatedBooks(): void
+setWebPageFileName(const string): void
+setExceptionsFileName(const string): void
+setTopBooksLimit(unsigned int): void
-parseLine(string, string []) const: void
Note, points will be deducted for insufficient commenting, poor style, or inefficient coding. The
error messages should be prefixed with the function name (to help better identify the source of
the error). Refer to the sample execution for error message examples.Function Descriptions
•
The bookDataType() constructor should set the books filename to the empty string, the
bookCount to 0, the topLimit to a default value of 5, the error counts to 0, the web page
file name to a default value of “index.html”, and the exceptions file to a default value of
“errors.txt”, and the pointers to the nullptr.
•
The ~bookDataType() destructor should delete the dynamically allocated arrays, set the
other class variables to their default values (noted above).
•
The getBookArguments() function should read the command line qualifiers in the
required format ( -i <booksFileName> [<-show|-noshow>] ) to obtain the file
name and set the show extra information flag (true/false). The data file and show extra
flag may be in either order. The show extra flag is optional and the “-noshow” is the
default if not specified. This includes a usage message and error messages for both the
input file specifier and the input file name. The file name must be at least one letter and
include a “.csv” extension (thus, the minimum length is 5). If the file name is incorrect or
does not exist, an appropriate error message should be displayed, the class variable
should remain unchanged, and the function should return false. To determine if a file
exists (without opening it), you can use the access() function (i.e,
( access(fn.c_str(), F_OK) ) which returns a 0 if the file exists and returns a -1 if
the files does not exist. Note, the access() function requires the #include <unistd.h>
statement. If there is an error, the function should output one of the following error
messages:
cout
cout
cout
cout
cout
•
•
•
•
•
•
•
•
•
<<
<<
<<
<<
<<
"Usage:
"Error,
"Error,
"Error,
"Error,
./books -i <bookDataFileName> [<-show|-noshow>]" << endl;
invalid input file name specifier." << endl;
invalid command line options." << endl;
book data file name must be '.csv' extension." << endl;
invalid show extra information specifier." << endl;
based on the specific error.
The getBookFileName() function should return the current book file name.
The getWebPageFileName() function should return the current web page file name.
The getReadBookIDErrors(), getReadBookYearErrors(),
getReadBookAveRatingErrors(), and getReadBookDuplicateErrors() functions should
return the applicable structure field.
The getExceptonsFileName() function should return the current exceptions file name.
The setBookFileName() function should set the class variable for the books file name to
the passed file name. The file name must be at least one letter and include a “.csv”
extension (thus, the minimum length is 5). If the passed file name is correct and the file
exists, the class variable should be set and a true returned. If the file name is incorrect or
does not exist, an appropriate error message should be displayed, the class variable
should remain unchanged, and the function should return false. To determine if a file
exists (without opening it), you can use the access() function (i.e,
( access(fn.c_str(), F_OK) ) which returns a 0 if the file exists and returns a -1 if
the files does not exist..
The setWebPageFileName() function should set the class variable for the web page file
name to the passed file name. The file name must be at least one letter and include a
“.html” extension (thus, the minimum length is 6).
The setExceptonsFileName() function should set the class variable for the file name to
the passed file name. The file name must be at least one letter and include a “.txt”
extension (thus, the minimum length is 5).
The getTopBooksLimit() function should return the value for the current number of
highest rated books to be found.
The setTopBooksLimit() function should set the class variable for the current number of
highest rated books to be found. The value must not exceed the TOP_LIMIT constant. If
the passed value is out of range, nothing should be changed.•
•
•
The getBookCount() should return the current number of books in the data set.
The getAverageOverallRating() function should return the overall average of book rating
in the entire current data set.
The showBookData() function should display the formatted book information to the
screen in the specified format (see output example).
cout
cout
cout
cout
cout
cout
cout
•
•
•
•
•
<<
<<
<<
<<
<<
<<
<<
"Book Information:" <<
offset << "Title:
"
offset << "Book ID
"
offset << "ISBD:
"
offset << "Year:
"
offset << "Ave Rate: "
endl;
endl;
<< bookInfo[idx].bookTitle << endl;
<< bookInfo[idx].bookID << endl;
<< bookInfo[idx].isbn << endl;
<< bookInfo[idx].pubYear << endl;
<< bookInfo[idx].aveRating << endl;
The showHighestRatedBooks() function should show the topBooksLimit number of
highest rated books using the showBookData() function from the topBooks array. As
such, the findHighestRatedBooks() function must have been previously called.
The findHighestRatedBooks() function should find the topBooksLimit number of highest
rated books. This will require dynamic creation and population of the topBooks[] array
of topBooksLimit size. The array will hold the index of the book into the bookInfo[]
array. Due to the data size, a sort is not appropriate. The topBooksLimit number of
highest rated books should be determined with out performing a sort.
The parseLine() function will accept a string in comma-separated format and break the
string into its individual comma separated fields. This includes handling quoted fields
that may contain commas which are not field separators when inside quotes. The
function should populate the passed array with the COL_LIMIT fields in string format.
If the line contains more than COL_LIMIT fields, only the first COL_LIMIT should be
returned (thus, do not over-write the array).
The readBookData() function should read the books file (CSV format). This function
will call the private parseLine() function. From the returned string array, the following
fields should be placed into the applicable fields of bookInfo[] array.
•
Book title (first title), string
◦ note, of first title is empty, use second title
•
ISBN (10 digit), string
•
ImageURL (first of two), string
•
Publication Year, short
•
Book ID (good reads book ID, which is first), unsigned integer
•
Average Rating, float
Note, since some data field may be invalid, try/catch blocks must be used for the
conversion. The first line is a header line and must be skipped. Blank lines should be
skipped. In order to size the bookInfo[] struct array, you will need to read the file twice;
once to count the data lines and again to read the data. To reset the file to the beginning,
use inFile.clear(); followed by inFile.seekg(0, ios::beg); . To convert
string values into floats or integers, use the stoi() and stof() functions. In order to check
for errors, these should be performed within a try/catch block. Errors should be written
to the exceptions file with a line of 60 ‘-’s, the specific error, the line number (from the
source data file), and on the next line the title “Row Data:”, and on the next line the
complete row followed by a blank line. Refer to the examples for formatting. Duplicate
rows are determined by the same book ID number and the second occurrence written to
the exceptions file. See examples for formatting.
EXTRA CREDIT (up to 25 pts) → The buildWebPage() function should build an HTML
web page of the top topBooksLimit number of highest rated books including a link to the
image and the book information on the GoodReads web site. The Good Reads link is
generated by appending the book ID to the URL" https://www.goodreads.com/book/show/ " within an HREF tag along with the
title. For example, <a
href=https://www.goodreads.com/book/show/24812>The Complete
Calvin and Hobbes</a> for book ID 24812. The passed string is the web page title
(using <title>CS 202 Top Books Page</title> in the header block) and the initial we page
label (using an <h1>title</h1> tag) with a subtitle of “Top Rated Books” (using an
<h2>subtitle</h2> tag). The minimum requirements for the web page include the
title and subtitle headers, followed by the books. The books must be numbered (1, 2, ...),
include the good reads book information link, the book cover image, the ISBN number
(10 digit), and the book average rating. See the provided example for a minimal required
format. The full 25 points will only be awarded if the final web page exceeds the
minimal formatting (see example).
Refer to the example executions for output formatting. Make sure your program includes the
appropriate documentation. See Program Evaluation Criteria for CS 202 for additional
information.
Make File:
You will need to develop a make file. You should be able to type:
make
Which should create the executable. The makefile will be very similar to the previous
assignment makefiles.
Submission:
● Submit a zip file of the program source files, header files, and makefile via the on-line
submission. All necessary files must be included in the ZIP file.
The grader will download, extract, and type make (so you must have a valid, working makefile).
CSV Format
Fields in a CSV file are comma-separated. Typically (but not always), the first line of the file
contains a row showing the field names. This is the case for our data files. A field may contain
a number or may be quoted (that is, enclosed within double-quote characters) indicating string
fields such as book titles. Such strings (names/titles) may have embedded commas and
embedded quote characters (which must be double-quoted). For example,
,"J.K. Rowling, Mary GrandPré, Rufus Beck",
,"A Child Called ""It"": One Child's Courage to Survive",
,"""M"" is for Malice",
,"""Who Could That Be at This Hour?""",
The double-quotes are used to mark a string field and are not actually part of the string. For
example, the first line (above) is actually J.K. Rowling, Mary GrandPré, Rufus Beck .
Where the double-quotes mark only the start and end. Since the double-quote is used to mark the
start and end of a field, a double double-quote is used to signify an actual double-quote. For
example, the second line is A Child Called "It": One Child's Courage to
Survive , the second line is "M" is for Malice , and the third line is "Who Could That
Be at This Hour?" .These requirements can make the reading of CSV files a challenge. In addition, may data
sources in CSV format have imperfect data with various errors include invalid numeric values,
too few fields, or too many fields.
Try/Catch Block Example
Below is an example of how to use the try/catch block for conversion using the C++ stoi()
function.
unsigned int
unsigned long
string
try {
someNumber = 0;
size = 0;
badNum = "12-34";
someNumber = stoi(badNum, &size);
if (size != columns[8].size())
throw
invalid_argument("Conversion Error");
}
catch (exception &err) {
errFile << err.what() << endl;
}

High school graduates: Approximately

74%

of freshmen entering public high schools in the United States in

2005

graduated with their class in

2009

. A random sample of

175

freshmen is chosen. Use Cumulative Normal Distribution Table as needed. Round your answers to at least four decimal places if necessary.

(a)Find the mean

μp

.

Part 2 of 6

(b)Find the standard deviation

σp

.

Part 3 of 6

(c)Find the probability that less than

75%

of freshmen in the sample graduated.

Part 4 of 6

(d)Find the probability that between

64%

and

78%

of freshmen in the sample graduated.

Part 5 of 6

(e)Find the probability that more than

64%

of freshmen in the sample graduated.

Part 6 of 6

(f)Would it be unusual if the sample proportion of freshmen in the sample graduated was more than

83%

?

In a survey of a group of​ men, the heights in the​ 20-29 age group were normally​ distributed, with a mean of 67,4 inches and a standard deviation of 2.0 inches. A study participant is randomly selected. Complete parts​ (a) through​ (d) below.

​(a) Find the probability that a study participant has a height that is less than 68 inches.
The probability that the study participant selected at random is less than 68 inches tall is
nothing. ​(Round to four decimal places as​ needed.)
​(b) Find the probability that a study participant has a height that is between 58 and 71 inches.
The probability that the study participant selected at random is between 68 and 71 inches tall is
nothing. ​(Round to four decimal places as​ needed.)
​(c) Find the probability that a study participant has a height that is more than 71 inches.
The probability that the study participant selected at random is more than 71 inches tall is
nothing. ​(Round to four decimal places as​ needed.)
​(d) Identify any unusual events. Explain your reasoning. Choose the correct answer below.
A. The event in part is unusual because its probability is less than 0.05.
B. than 0.05.
C. than 0.05.