An experiment was conducted to verify the effect of training at the managerial level in decision making. Two factors were considered in experiment A: training level of the individual (if he has training or does not have training) and B: the type of situation for which the individual had to make the decision (normal or emergency situation).
Sixteen supervisors were selected and 8 were chosen randomly to receive management training. After receiving the training, 4 trained supervisors were selected and 4 of them were not trained to act in a normal situation. In the same way, the other group of 8 supervisors was taken to act in an emergency situation. The decision made by each individual was monitored by the researcher and evaluated on a scale from 0 to 100. The results are presented in the following table:
|
Situation (B) |
Training Level (A) |
Total |
|
|
Training |
No Training |
||
|
Normal |
85 91 80 78 |
53 49 38 45 |
|
|
Sub-Total |
334 |
185 |
519 |
|
Emergency |
76 67 82 71 |
40 52 46 39 |
|
|
Sub-Total |
296 |
177 |
473 |
|
Total |
630 |
362 |
992 |
Will there be significant evidence to conclude that the factors are significant? Test α = 0.05 Perform and present your calculations by hand (not Excel, not Minitab, etc.).
In: Statistics and Probability
|
Temperature |
61 |
70 |
50 |
65 |
48 |
75 |
53 |
|
Attendance |
10 |
16 |
12 |
15 |
8 |
20 |
18 |
__________________________________________________________________________
_________________________________________________________________________
In: Statistics and Probability
An experiment is conducted to determine if classes offered in an online format are as effective as classes offered in a traditional classroom setting. Students were randomly assigned to one of the two teaching methods. Final exam scores reported below. a. Test the claim that the standard deviations for the two groups are equal. What is the p-value of the test? b. Construct a 95% confidence interval on the difference in expected final exam scores between the two groups. Does the data support the claim that there is no difference? Do not use mini tab
| On-line | Classroom |
| 77 | 79 |
| 66 | 64 |
| 70 | 88 |
| 79 | 80 |
| 76 | 66 |
| 58 | 81 |
| 54 | 71 |
| 72 | 84 |
| 56 | 77 |
| 82 | 76 |
| 90 | 89 |
| 68 | 62 |
| 59 | 74 |
| 67 | 68 |
| 71 | 98 |
| 74 | 77 |
| 72 | 65 |
| 62 | 83 |
| 77 | |
| 78 | |
| 76 | |
| 57 | |
| 67 | |
| 69 | |
| 82 | |
| 78 | |
| 80 | |
| 61 | |
| 77 | |
| 65 | |
| 71 | |
| 76 | |
| 58 | |
| 82 | |
| 78 | |
| 74 |
In: Statistics and Probability
This lab experiment is on the preparation of benzoic acid: a Grignard reaction.
In the procedure: following the addition of carbon dioxide; then 6M HCL(aq); diethyl ether was added and the aqueous layer discarded; then 6M NaOH(aq) was added and the ether layer discarded; Finally, concentrated HCL(aq) was added and a precepitate formed, which was filtered and rinsed with cold deionized H2O. The purpose of these steps was to isolate, and thus purify, benzoic acid from both water-soluble and organic-soluble impurities.
a) Provide a balanced equation for each step after the addition of CO2.
b) State the impurities being removed in each step after the addition of CO2.
In questions 1a and 1b; identify the phase (i.e. organic or aqueous) that each compound is in
In: Chemistry
An experiment is conducted to determine if classes offered in an online format are as effective as classes offered in a traditional classroom setting. Students were randomly assigned to one of the two teaching methods. Data below.
a. Test the claim that the standard deviations for the two groups are equal. What is the p-value of the test?
b. Construct a 95% confidence interval on the difference in expected final exam scores between the two groups. Does the data support the claim that there is no difference?
| On-line | Classroom |
| 77 | 79 |
| 66 | 64 |
| 70 | 88 |
| 79 | 80 |
| 76 | 66 |
| 58 | 81 |
| 54 | 71 |
| 72 | 84 |
| 56 | 77 |
| 82 | 76 |
| 90 | 89 |
| 68 | 62 |
| 59 | 74 |
| 67 | 68 |
| 71 | 98 |
| 74 | 77 |
| 72 | 65 |
| 62 | 83 |
| 77 | |
| 78 | |
| 76 | |
| 57 | |
| 67 | |
| 69 | |
| 82 | |
| 78 | |
| 80 | |
| 61 | |
| 77 | |
| 65 | |
| 71 | |
| 76 | |
| 58 | |
| 82 | |
| 78 | |
| 74 |
In: Statistics and Probability
In an experiment to measure the wavelength of light using two slits, it is found that the interference fringes are too close together to easily count them. To spread out the fringe pattern, one could…
A. Increase the slit separation
B. Decrease the slit separation
C. Increase the distance from the slits to the viewing screen
D. Decrease the distance from the slits to the viewing screen
E. Both increasing the distance from the slits to the viewing screen and increasing the slit separation would work
F. Both increasing the distance from the slits to the viewing screen and decreasing the slit separation would work
In: Physics
In an experiment, a group of students will determine the dielectric constant of paper. They have the following materials available, as well as other materials traditionally available in a high school physics lab.
(a) Outline an effective experimental procedure to gather the necessary data that can be used to determine the dielectric constant of paper. Place a check mark next to each item above that the students should use. Draw a labeled diagram to represent the setup used for this procedure.
The table below shows data from a different experiment in which students measure the capacitance of different setups as they vary the distance between the two plates of the capacitor, the area of the plates, and the material inserted between the plates.
| Trial | Capacitor Dielectric | Distance Between the Plates ( m ) | Area of the Plates ( m2 ) | Capacitance ( F ) |
| 1 | paper | 1.00×10−4 | 0.04 | 8.1×10−9 |
| 2 | paper | 1.00×10−4 | 0.09 | 18.3×10−9 |
| 3 | paper | 1.00×10−4 | 0.16 | 32.6×10−9 |
| 4 | paper | 1.00×10−4 | 0.25 | 49.8×10−9 |
| 5 | paper | 2.00×10−4 | 0.25 | 23.1×10−9 |
| 6 | paper | 3.00×10−4 | 0.25 | 18.9×10−9 |
| 7 | paper | 4.00×10−4 | 0.25 | 14.9×10−9 |
| 8 | paper | 5.00×10−4 | 0.25 | 9.2×10−9 |
| 9 | plastic | 1.10×10−4 | 0.04 | 11.3×10−9 |
| 10 | plastic | 1.10×10−4 | 0.09 | 25.3×10−9 |
| 11 | plastic | 1.10×10−4 | 0.16 | 45.1×10−9 |
| 12 | plastic | 1.10×10−4 | 0.25 | 70.4×10−9 |
| 13 | plastic | 2.20×10−4 | 0.25 | 35.2×10−9 |
| 14 | plastic | 3.30×10−4 | 0.25 | 23.5×10−9 |
| 15 | plastic | 4.40×10−4 | 0.25 | 17.6×10−9 |
| 16 | plastic | 5.50×10−4 | 0.25 | 14.1×10−9 |
(b)
i. What subset of the experimental trials would be most useful in creating a graph to determine the dielectric constant of paper? Explain why the selected trials are most useful.
ii. Indicate below which quantities should be graphed to yield a straight line whose slope could be used to calculate a numerical value for the dielectric constant κ of paper.
Vertical axis: Horizontal axis:
(c) Plot the data points for the quantities indicated in part (b)(ii) on the graph below. Clearly scale and label all axes including units, if appropriate. Draw a straight line that best represents the data.
(d) Use the data to determine a value for κ of paper.
(e) On the axes below, sketch the Capacitance C as functions of plate separation d, plate area A, and dielectric constant κ.
In: Physics
In an experiment to determine the effect of nutrition on the attention spans of elementary school students, a group of 45 students is divided into three groups of 15, and randomly assigned to each of three meal plans: no breakfast, light breakfast, and full breakfast. Their attention spans, in minutes, were recorded. Say you want to test the hypothesis that the means of the attention spans are not all the same at a level of significance of 5%.
(a) (3 pts) What are the null and alternative hypotheses?
(b) (4 pts) Suppose that you find MSG=26 and MSE=3.1. Find the F-statistic, and estimate the p-value of your data using the F-table.
(c) (3 pts) Should you accept or reject? Explain.
In: Statistics and Probability
An experiment was conducted to test the effect of a new drug on a viral infection. After the infection was induced in 100 mice, the mice were randomly split into two groups of 50. The control group received no treatment for the infection, while the other group received the drug. After a 30-day period, the proportions of survivors, p̂1 and p̂2, in the two groups were found to be 0.38 and 0.66, respectively. (a) Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use α = 0.05. State the null and alternative hypotheses. H0: (p1 − p2) < 0 versus Ha: (p1 − p2) > 0 H0: (p1 − p2) = 0 versus Ha: (p1 − p2) > 0 H0: (p1 − p2) = 0 versus Ha: (p1 − p2) < 0 H0: (p1 − p2) = 0 versus Ha: (p1 − p2) ≠ 0 H0: (p1 − p2) ≠ 0 versus Ha: (p1 − p2) = 0 Find the test statistic and rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.) test statistic z = rejection region z > z < State your conclusion. H0 is rejected. There is sufficient evidence to indicate that the drug is effective in treating the viral infection. H0 is not rejected. There is insufficient evidence to indicate that the drug is effective in treating the viral infection. H0 is rejected. There is insufficient evidence to indicate that the drug is effective in treating the viral infection. H0 is not rejected. There is sufficient evidence to indicate that the drug is effective in treating the viral infection. (b) Use a 95% confidence interval to estimate the actual difference (p1 − p2) in the survival rates for the treated versus the control groups. (Round your answers to three decimal places.) to
In: Statistics and Probability
The project is to "Design and build an experiment to verify the first law of thermodynamics by stirring air with an electric motor powered paddle, in a well-insulated container." We are planning on finding the work of the motor and seeing if it equal to the change in internal energy of the container. The only problem is that we are confused on how to find the internal energy. What would be the best/easiest way to solve this? Also since the containor is well insulated does that mean that the deltaQ would equal 0?
Thank you very much!
In: Mechanical Engineering