axis symmetry, graph max or min value, domain, range and all intervals where function increases or decreases. f(x)=5(x-3)^2+6 f(x)=-7(x-8)^2+1 f(x)=-6(x+4)^-8 f(x)=2(x+2)^2+9
In: Math
Topic: Introduction to Convolution
Software used : Matlab
Course : Signal and Systems Lab
1.
a) Make the flowchart or pseudo code for convolution.
b) Implement convolution in MATLAB.
Hint: Make a function using the format: function result = myconv (a,b)
Where a and b are input matrix and result is convolution answer.
c) Compare it with conv command.
2. Let input signal x be [1, 3, –2, 4, -1] and the system h be [-2, 3, 4, –3, 6]. Find the output of the system y using the conv command.
3. Now suppose we add another system j = [3, –1, 2, 4, 1] in series with the above system. Now find the overall response and output y of the above system using the conv command. Hint: The systems h and j should be convolved first and then the resultant should be convolved with x to get the overall response.
4. Again suppose now j is attached in parallel to h. Now find the impulse response y for the system.
5. Now suppose the two systems h and j are again in series and a third system k = [2, 3, 4, 5, 6] has also been attached with them in parallel. Find the impulse response of the overall system and hence the output y. Hint: You will have to make sure that the size of the system k be made equal to the resultant of the size of the system obtained by convolving the systems h and k that are attached in series.
Up until now we have supposed that all signals starting point is same say 0. Now suppose the system h starting point is –2, that of system j is 0 and that of system k is 3. Now handle this situation carefully and get the overall impulse response of the system and hence the output y. Also please draw stem plot of each of system including the input x, systems, h, j, k, the overall response and finally the output y.
6. Write a program without using conv command and for loop to convolve two arbitrary length signals. (Hint: Use toeplitz command)
In: Electrical Engineering
Jeff is a sports fan. He has a wish list to see a 1. baseball, 2. basketball, and 3. football game this year. Two of his friends independently deicde to buy him tickets to one event. John has a probability of selecting tickets to 1,2, and 3 with a probability 1/5, 2/5, and 2/5. Jason has a probability of selecting tickets to 1, 2, and 3, respectively with probability 4/7, 1/7, 2/7, respectively. What is the probability John and Jason give Jeff a ticket to a different type of sporting event? Given the tickets are to different sporting events, what is the probability the event is baseball?
In: Statistics and Probability
Write a C++ program where class 1 and class 2 (which is a base class) should have a derived class (class 4 and class 5). Each of the derived classes should include at least 1 variable, 2 functions (one will be showing the function overriding case, the second one will be showing the function overloading case), 2 constructors (with default values, with parameters).
Then class 3 (composition) (to relate class 1 and class 2) should include 3 variables (first variable is an object belongs to class 1, second variable is an object belongs to class 2,third variable is class 3 own variable), 3 functions.
In: Computer Science
1. A typical α-decay from a parent nucleus AZX may be indicated as :
Group of answer choices
AZX → (A−4)(Z − 2) Y + 42He
AZX → (A+4)(Z+2) Y + 22He
AZX → (A−4)Z Y + 42He
AZX → (A−4)(Z+2) Y + 42He
2. An element of atomic number 83 in a relatively higher energy state decays radioactively to an element of atomic number 84 with lower energy level. This must include
Group of answer choices
an α emission
a β emission
a γ emission
a β & γ emission
3. The half- life of radium-226 is 1.6 × 103 . If a sample initially contains 3.0 × 1016 such nuclei, what is the number of radioactive radium-226 nuclei remaining after 4.8 × 103 years?
Group of answer choices
2.25 × 1012
3.75 × 1016
2.2 × 1016
3.75 × 1015
In: Physics
Hi, I don't think my program is calcualting right at all. When I used a text editor to check the # of batches, for 20, it returned 0, but the program is calculated 543 and 1 batch. On 21, there are 29 batches, but the program calculates 28 batches for Chocolate Type #21. I'd like to make sure it calculates everything correctly before I turn it in on Monday.
Here is my program:
#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;
ifstream infile;
ofstream outfile;
//Maximum number of Chocolate Types
const int ARRAY_SIZE = 25;
int printReport(int ChocTypeArray[], int
ChocPiecesArray[])
{
//Opens output file
outfile.open("ChocolateCo_Production_Results.txt");
//Print Title
outfile <<
"======================================================================================================"
<< endl;
outfile << "================================ O-So-Good
Chocolate Company Report =================================="
<< endl;
outfile <<
"======================================================================================================"
<< endl;
//Print Header
outfile << "Chocolate Type" << setw(42) << "
Pieces" << setw(20) << "Batches" << setw(20)
<< "Average/Batch" << endl;
outfile <<
"======================================================================================================"
<< endl;
for (int count = 0; count < ARRAY_SIZE; count++)
{
float avg = 0;
if (ChocTypeArray[count] > 0)
{
avg = (float)ChocTypeArray[count] /
(float)ChocPiecesArray[count];
}
outfile << count + 1 << "\t\t\t\t" <<
right << setw(24) << ChocTypeArray[count] <<
right << setw(20) << ChocPiecesArray[count] <<
right << setw(20) << avg << endl;
}
// Closes outout file
outfile.close();
return 0;
}
int main()
{
int ChocTypeArray[ARRAY_SIZE];
int ChocPiecesArray[ARRAY_SIZE];
//Initialize arrays
for (int count = 0; count < ARRAY_SIZE; count++)
{
ChocTypeArray[count] = 0;
ChocPiecesArray[count] = 0;
}
//Try to find data file
infile.open("Chocolates.txt");
if (!infile)
{
cout << "Failed to open Chocolates.txt. Make sure
it is in the same directory as the program." << endl;
return -1;
}
//Read data until the end of file
int _chocType, _chocPieces;
while (!infile.eof())
{
infile >> _chocType >> _chocPieces;
// Validates if chocType is between 1 and 25
if (_chocType < 1 || _chocType >
ARRAY_SIZE)
{
continue; //skip
}
else
{
//Adjust for array index
_chocType--;
//Add the pieces to their appropriate type
ChocTypeArray[_chocType] =
ChocTypeArray[_chocType] + _chocPieces;
ChocPiecesArray[_chocType]++;
}
}
//Print the report
printReport(ChocTypeArray, ChocPiecesArray);
return 0;
}
Here is the data from Chocolates.txt:
12
1026
15
248
7 402
10
1076
16
948
14
1174
6
1137
8 719
9 952
14
1516
9 830
14
296
19
596
15
874
23
100
15
1063
16
867
6 87
11
1330
1 217
18
802
15
943
15
165
23
100
2 866
21
656
18
885
7
1221
9
1032
22
490
9
1328
12
584
11
561
14
1355
22
750
12
800
9 686
19
401
11
1121
16
389
3 664
8 676
12
692
1 844
1 994
1 847
24
1173
7 792
8
1076
19
613
14
1085
3
1107
12
891
3
1121
6 870
16
300
16
1092
24
969
12
515
6 403
11
885
7 839
14
328
1
1023
7 653
6 276
11
217
3
1288
6
1109
23
643
23
384
7
1213
6 556
4
1224
9
1271
15
1167
8 595
6 746
1
1284
18
1300
14
747
5 650
4 934
9 952
16
1408
24
1012
12
696
14
333
14
478
5 434
1 548
6 285
9 341
23
925
3 150
11
1166
5 963
8
1010
11
1272
1 587
21
866
12
152
11
1280
2 821
4 778
19
1087
15
690
11
1239
6
1267
4 361
12
704
3 560
16
1231
21
1198
6 697
3 696
6 632
16
1543
10
211
2 285
10
845
24
554
16
1105
6
1048
4
1050
16
552
3
1077
19
1333
19
669
8
1172
21
1217
2 826
18
995
7
1140
5
1084
7
1016
21
624
3 654
5 990
9
1115
23
991
3 324
8 959
16
1483
16
1036
9 694
4 817
24
247
6 477
12
1307
10
596
19
1008
1 843
12
1166
24
693
3 397
16
1000
19
368
9
1101
11
1270
15
172
8 839
12
760
6
1099
16
1119
1 673
10
742
2 858
11
1015
8 771
10
537
11
475
6 857
1 932
14
728
11
914
10
652
19
436
2 415
23
724
10
974
2 874
18
365
14
1158
1 986
7 283
21
870
10
708
2 546
7 919
15
429
9 607
19
591
16
938
2 662
6
1044
3 549
5
1012
19
1003
3 654
18
1436
1 738
14
695
14
655
10
266
11
510
6
1265
7 603
24
687
23
1014
9 557
1 677
16
1177
24
712
9
1275
14
1188
16
311
19
581
23
237
21
1228
23
717
24
729
10
511
7 584
23
1043
21
941
23
100
2 966
23
492
5
1312
1 968
18
699
2 249
24
1062
18
1015
2 924
16
952
14
591
4 899
5 692
11
1435
7 760
2 852
15
964
21
921
7
1131
4 919
6 870
4 778
2
1507
14
213
23
713
23
861
1 595
4 623
7 794
7 880
23
1371
9 455
19
1217
16
187
6
1219
10
1135
24
365
18
906
14
576
23
700
19
444
10 11
3 817
19
1394
10
948
7 666
24
883
6
1447
7 385
1 976
9
1037
14
373
2 526
19
1148
16
1185
24
1338
11
854
5
1004
15
1212
8 281
24
1316
6 15
18
1224
19
654
14
483
4
1428
8 769
19
473
14
1185
12
691
5
1252
1 425
6 459
18
1036
15
713
6 840
9 545
12
515
4 599
1 619
6
1162
9 561
5
1105
24
453
15
456
24
644
15
324
18
808
12
860
23
307
18
552
18
568
8 256
16
1458
23
562
19
660
19
983
9 970
7
1154
21
594
9 590
15
174
3
1048
9
1079
3 536
11
1301
16
508
1 810
21
647
10
802
11 50
24
921
18
195
4 273
5 564
11
314
21
710
7 267
15
224
18
215
9 975
9 328
9 475
23
470
12
649
7 782
16
765
16
1019
9 537
4
1089
21
221
15
372
7 706
19
379
10
1015
8
1244
23
443
1 121
6 732
10
718
23
1084
12
424
23
536
11
308
7 637
18
611
19
870
24
310
15
1145
9
1005
10
672
10 59
16
1235
19
764
18
430
12
1122
8 956
23
704
1 507
8 822
3 761
2
1084
11
1066
19
439
15
859
5 494
15
498
5
1092
15
1457
15
458
18
1133
23 44
10
1215
16
856
8 942
1 321
16
663
1 463
5
1324
6 676
7 858
23
536
2 476
24
358
21
481
5 917
10
1293
4
1176
9 768
10
742
10
1294
6 608
11
237
15
1038
11
330
2
1117
4 82
21
516
16
1222
8
1347
11
922
23
1126
4 868
18
296
24
412
18
407
23
1421
4 930
23
981
2 146
3 348
16
361
18
553
24
1046
2 557
6 396
23
104
3
1197
1 892
6 218
1 865
11
644
6 471
12
938
14
759
2 180
19
739
5
1276
19
1067
7 299
10
715
19
514
7 225
5 574
14
797
18
556
23
531
21
516
15
1463
4
1264
11
1006
12
605
6 592
4 759
6 628
16
1469
8 843
16
638
23
614
24
439
19
775
9 711
8
1304
24
749
16
1143
12
829
16
1063
9 581
8
1113
10
851
14
853
19
781
10 49
16
1035
19
264
18
490
12
922
8 956
23
704
1 507
8 822
3 761
2
1084
14
1221
6 772
7 911
7 545
8 724
10
1005
7
1133
2 189
24
1212
18
1118
21
241
15
1178
3 659
24
867
4 497
8 708
18
1308
11
411
7 500
15
538
8 366
1
1185
19
989
9 759
10
144
8
1210
15
1284
5 361
23
962
5 517
8 637
15
1239
11
992
7 394
2 725
24
114
19
1518
8
1127
12
415
1
1014
15
637
9 860
3 986
21
799
24
211
4
1212
5
1348
8 530
5
1362
9
1114
10
294
8
1414
15
1010
7 987
7 608
10
923
21
837
15
325
16
1127
10
1037
12
980
10
1160
6 331
1 840
18
673
3 561
9 921
24
752
23
1123
21
757
3 722
4 996
19
415
10
650
11
239
5 813
2 349
3 484
16 70
4 596
7 753
9 716
6
1022
4 351
11
185
2 403
12
570
24
905
4 50
9 211
14
737
8 587
5 532
1 544
19 21
5
1096
11
232
1 185
24
507
3 345
16
340
3 755
15
487
7 971
2
1309
11
500
15
968
10
739
8 755
12 60
3 770
18
601
9 284
21 55
15
1144
19
1524
6
1214
7 221
19
391
23
422
9 476
1
1054
1 967
5
1149
1 794
23
1014
4 605
23
860
4 311
14
443
6 659
19 85
1 501
23
346
1 268
8 941
12
918
23
779
18
791
8 561
7
1051
24
554
8 444
14
502
12
1043
9
1080
6 771
1
1274
8 737
19
197
3 703
6 748
10
1029
14
1095
10
1141
9 924
5 962
3 192
10
963
12
521
1
1195
4 529
3
1330
7 900
21
1118
18
1118
5
1060
15
459
18
1107
24
788
16
689
5 392
18
1106
15
848
18
531
12
242
12
669
18
962
14
658
9 799
8 712
21
873
10
1191
11
577
5 499
24
817
23
569
1 529
1
1152
3 813
10
901
21
739
3 641
23
581
10
768
6 810
2
1457
8 698
14
1351
11
1081
21
589
9 848
16
1043
8 710
15
904
11
1171
10 62
16
1097
14
691
3
1183
11
1286
7 606
23 89
7 859
14
481
12
839
2 550
3
1457
3 512
12
465
14
657
21
1149
10
1340
3 765
2 948
9 395
16
662
5 961
23
1389
23
1214
5 890
8 134
22
666
22
777
23
100
22
555
3
1295
11
307
11
605
15
1064
6
1214
1 64
8 907
18
1133
9 636
3
1134
16
1101
6 313
7 791
7
1130
1
1221
21
332
24
697
6 807
2 36
2 747
16
1219
3 859
18
639
18
312
7
1079
10
1074
5 678
18 59
1 325
21 543
In: Computer Science
PA11-3 Comparing, Prioritizing Multiple Projects [LO 11-1, 11-2, 11-3, 11-6]
Hearne Company has a number of potential capital investments.
Because these projects vary in nature, initial investment, and time
horizon, management is finding it difficult to compare them. Assume
straight line depreciation method is used.
Project 1: Retooling Manufacturing Facility
This project would require an initial investment of $5,500,000. It
would generate $982,000 in additional net cash flow each year. The
new machinery has a useful life of eight years and a salvage value
of $1,156,000.
Project 2: Purchase Patent for New Product
The patent would cost $3,855,000, which would be fully amortized
over five years. Production of this product would generate $732,450
additional annual net income for Hearne.
Project 3: Purchase a New Fleet of Delivery
Trucks
Hearne could purchase 25 new delivery trucks at a cost of $180,000
each. The fleet would have a useful life of 10 years, and each
truck would have a salvage value of $6,300. Purchasing the fleet
would allow Hearne to expand its customer territory resulting in
$855,000 of additional net income per year.
Required:
1. Determine each project's accounting rate of return.
(Round your answers to 2 decimal places.)
Accountng Rate of Return:
Project 1 percentage =
Project 2 percentage =
Project 3 percentage =
2. Determine each project's payback period.
(Round your answers to 2 decimal places.)
Payback Period
Project 1 years =
Project 2 years =
Project 3 years =
3. Using a discount rate of 10 percent, calculate the net present value of each project. (Future Value of $1, Present Value of $1, Future Value Annuity of $1, Present Value Annuity of $1.) (Use appropriate factor(s) from the tables provided. Round your intermediate calculations to 4 decimal places and final answers to 2 decimal places.)
Net Present Value
Project 1 =
Project 2 =
Project 3 =
4. Determine the profitability index of each project and prioritize the projects for Hearne. (Round your intermediate calculations to 2 decimal places. Round your final answers to 4 decimal places.)
Profibility Index
Project 1 =
Project 2 =
Project 3 =
In: Accounting
Equilibria with Weak Acids & Weak Bases - Results
|
Exp |
Composition |
Total Vol |
pH |
|
1 |
A few mL of 0.10M NH3 (unchanged) |
n/a |
11.13 |
|
2 |
2.5mL 0.1M NH3 & 7.5mL H2O |
10 ml |
10.82 |
|
3 |
2.5mL 0.1M NH4Cl & 7.5mL H2O |
10 ml |
6.01 |
|
4 |
2.5mL 0.1M NH3 & 2.5mL 0.1M NH4Cl & 5mL H2O |
10 ml |
9.26 |
|
5 |
Take 1mL Solution #4 and add 9mL of water |
10 ml |
9.26 |
Solution 1. Use the concentration of NH3 and the measured pH above to determine the Kb of NH3. (show the ICE table and calculations)
Use the equation (Ka*Kb = 1*10-14) to calculate the Ka for NH4+ ?
Solution 2 Use the equation M1V1 = M2V2 to calculate new conc. of NH3.
Conc. of NH3 ____ pH measured: 10.82
Compare solutions 1 & 2. What effect did diluting the base have on the pH?
Use the new concentration and pH to measure the Kb of NH3 again. Did it change?
Solution 3 Conc. of NH4+ pH of solution 3: 6.01
Use the diluted concentration of NH4+ and measured pH to determine the Ka of NH4+
How does this Ka value compare to the value on pg. 1? (within a power of 10 is good)
Calculate the concentrations for solution 4 and solution 5
|
Sol |
Conc. NH3 (M) |
Conc.NH4+(M) |
pH |
|
2 |
10.82 |
||
|
4 |
9.26 |
||
|
5 |
9.26 |
Compare pH of solutions 2&4. What effect did adding NH4+ have on the equilibrium/pH?
Compare the pH from dilution in solutions 1&2 to the pH change in solutions 4 & 5. Why is the pH change smaller for solutions 4&5 than in solutions 1&2? Think above the ratio of base and conjugate acid. You can also show this mathematically by using the Kb from part 1 with NH3/NH4+ conjugates to determine what the OH- concentration should be.
Note: Solution 4 (page 2) should already be made. (total volume)
|
6 |
2.5mL 0.10M NH3, 2.5mL 0.1M NH4Cl & 1.0mL 0.10M NaOH & 4mL H2O |
10 mL |
|
7 |
2.5mL 0.10M NH3, 2.5mL 0.1M NH4Cl & 1.0mL 0.10M HCl of & 4mL H2O |
10 mL |
|
8 |
2.5mL 0.10M NH3, 2.5mL 0.1M NH4Cl & 5.0mL 0.10M HCl |
10 ml |
|
9 |
2.5mL 0.10M NH3, 2.5mL 0.10M HCl & 5.0mL H2O |
10 ml |
Calculate the dilution concentrations of solution 6.
|
Sol |
Conc. NH3 (M) |
Conc. NH4+ (M) |
Conc. NaOH(M) |
pH |
|
6 |
9.62 |
Compare solutions 4 & 6. What effect did NaOH have on the pH of the solution?
If the NaOH concentration from solution 6 was in water by itself (without the buffer), what would the pH be?
Did NH3 & NH4+ buffer against NaOH? How can you tell?
Calculate the concentrations of solution 7 & 8
|
Sol |
Conc. NH3 (M) |
Conc. NH4+ (M) |
Conc.HCl (M) |
pH |
|
7 |
8.89 |
|||
|
8 |
3.7 |
Compare solutions 4, 7 & 8. The ingredients are essentially the same, but the solutions of 7 & 8 should have a dramatically different pH. Why did 7 work as a buffer, but 8 did not? Compare the concentration of NH3 vs the concentration of HCl.
Calculate the concentrations of solution 9
|
Sol |
Conc. NH3 (M) |
Conc.HCl (M) |
pH |
|
9 |
5.6 |
a) This solution has equal amounts of acid and base. Why is the pH acidic? Explain.
In: Chemistry
Please show work.
1. Find the derivatives dy/dx and d2y/dx and evaluate them at t = 2.
x = t2, y = tln t
2. Find the arc length of the curve on the given interval
x = ln t, y = t + 1, 1 ≤ t ≤ 2
3. Find the area of region bounded by the polar curve on the given interval.
r = tan θ, π/6 ≤ θ ≤ π/3
4. Find the length of the polar curve on the given interval. (12 points)
r = θ, 0 ≤ θ ≤ π/2
In: Math
Problem 9-2A In recent years, Avery Transportation purchased three used buses. Because of frequent turnover in the accounting department, a different accountant selected the depreciation method for each bus, and various methods were selected. Information concerning the buses is summarized as follows.
Bus Acquired Cost Salvage Value Useful Life in Years Depreciation Method
1 1/1/15 $ 98,300 $ 7,000 5 Straight-line
2 1/1/15 118,000 10,000 4 Declining-balance
3 1/1/16 88,640 8,000 4 Units-of-activity
For the declining-balance method, the company uses the double-declining rate. For the units-of-activity method, total miles are expected to be 126,000. Actual miles of use in the first 3 years were 2016, 24,000; 2017, 31,500; and 2018, 30,000.
For Bus #3, calculate depreciation expense per mile under units-of-activity method. (Round answer to 2 decimal places, e.g. 0.50.)
Depreciation expense $________ per mile
Compute the amount of accumulated depreciation on each bus at December 31, 2017. (Round depreciation cost per unit to 2 decimal places, e.g. 0.50 and depreciation rate to 0 decimal places, e.g. 15%. Round final answers to 0 decimal places, e.g. 2,125.)
Accumulated depreciation
BUS 1 $ ________
BUS 2 $ ________
BUS 3 $ ________
If Bus 2 was purchased on April 1 instead of January 1, what is the depreciation expense for this bus in (1) 2015 and (2) 2016? (Round answers to 0 decimal places, e.g. 2,125.)
(1) 2015 (2) 2016
Depreciation expense $_____ $_____
In: Accounting