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Parker & Stone, Inc., is looking at setting up a new manufacturing plant in South Park to produce garden tools. The company bought some land six years ago for $5.5 million in anticipation of using it as a warehouse and distribution site, but the company has since decided to rent these facilities from a competitor instead. If the land were sold today, the company would net $5.8 million. The company wants to build its new manufacturing plant on this land; the plant will cost $13 million to build, and the site requires $820,000 worth of grading before it is suitable for construction. What is the proper cash flow amount to use as the initial investment in fixed assets when evaluating this project? (Enter your answer in dollars, not millions of dollars, e.g. 1,234,567.) |
| Cash flow amount | $ |
In: Finance
Parker & Stone, Inc., is looking at setting up a new manufacturing plant in South Park to produce garden tools. The company bought some land six years ago for $3.6 million in anticipation of using it as a warehouse and distribution site, but the company has since decided to rent these facilities from a competitor instead. If the land were sold today, the company would net $4.1 million. The company wants to build its new manufacturing plant on this land; the plant will cost $18.1 million to build, and the site requires $950,000 worth of grading before it is suitable for construction. What is the proper cash flow amount to use as the initial investment in fixed assets when evaluating this project?
In: Finance
4. Mrs Garcia, a physics enthusiast, goes to a water park in South Padre Island to test the concepts learned during class. She goes on a water slide that is 265 meters long and is built at an angle with the ground of θ = 30 degrees. – What is her final velocity at the end of the slide?
5. A goalkeeper kicks a soccer ball that is initially resting on the ground. She kicks the ball with an initial velocity of 8 m/s. The initial angle between the ground and the trajectory of the ball is θ=27 degrees. – How long is the ball in the air? – How far does the ball travel? – How high does the ball go? Hint: Use equations of motion and the definition of range and maximum height for projectile motion.
6. Solve the following quadratic equations: 2x 2 + 6x + 1 = 0 (1) 4x 2 + 12x + 2 = 0 (2) 9x 2 − 4x + 12 = 0 (3) (x − 1) x + 3 + 3 (x − 1) = (4 − x) (x − 1)(x − 1) (4) Hint: Factor and simplify using (x − 1).
In: Physics
Elaine was enjoying a pleasant day on the ski slopes at Winter Park. When she got on the lift to the top of Parsenn Bowl (12,000 ft), the weather was fine—windy, but sunny. During the 5- or 10-minute ride, the weather changed suddenly; it became a white-out, with icy surface snow, blowing snow, a very strong wind, and extremely low visibility. Many people fell as they got off the lift, including Elaine. However, she got up and joined her family members as they stood, wondering just how they were going to get down the mountain. Meanwhile, the lift closed due to the terrible conditions (50-mile-an-hour wind and a temperature of −20° F). As she adjusted her stance, Elaine somehow twisted and fell again, which resulted in external rotation of her right knee. There was no pain at the time and she thought she could get up and prepare to get down the mountain, but her knee was too unstable. While she sat on the icy surface, her husband notified the lift operator to call the Ski Patrol. In about 20 minutes they arrived and put her on a sled, which they skied down the slope; when they reached the Ski Patrol headquarters, they transferred the sled to a snowmobile and promptly got her down the mountain and into the emergency room.
What would happen to her body if the homeostatic mechanism failed?
What areas of the body would be the most vulnerable to frostbite?
What are the signs and symptoms of frostbite?
Give an example of a negative feedback mechanism that is describing her condition right now. Label all of the components and put what is occurring in her body at this time.
In: Biology
•South Park Energy is considering replacing the company's Methane Plant with a Nuclear Plant.
•The Methane Plant was built two years ago at a cost of $120M with an expected useful life of 5 years. This plant is being depreciated to zero using 5-year straight-line depreciation. The Methane Plant can be sold today for $70M. If this plant had been kept, it would have had no salvage value at the end of its expected useful life three years from today.
•The Nuclear Plant would cost $500M to build today. Since the Nuclear plant will just be a working prototype, its expected useful life is only 3 years and it falls in the 3-year MACRS depreciation class (yr 1: 33%, yr 2: 45%, yr 3: 15%, yr 4: 7%). The Nuclear Plant is expected to have a salvage value of $40M at the end of the plant's 3-year life. The Nuclear Plant is expected to reduce operating expenses by $150M each year during the plant's 3-year expected life and increase revenues by $40 million each year. The company's marginal tax rate is 40%, and this project has a weighted average cost of capital of 13%.
(Q1) What is the total cash flows during year 3 for this replacement analysis?
(Q2) What is the initial cash flow for this replacement analysis?
In: Finance
You may need to use the appropriate technology to answer this question.
An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more efficiently. Two alternative loading/unloading methods have been proposed. To account for potential differences due to the type of ride and the possible interaction between the method of loading and unloading and the type of ride, a factorial experiment was designed. Use the following data to test for any significant effect due to the loading and unloading method, the type of ride, and interaction. Use α = 0.05.
| Type of Ride | |||
|---|---|---|---|
| Roller Coaster | Screaming Demon | Log Flume | |
| Method 1 | 43 | 52 | 48 |
| 45 | 44 | 44 | |
| Method 2 | 47 | 50 | 50 |
| 49 | 46 | 46 | |
Find the value of the test statistic for method of loading and unloading.
Find the p-value for method of loading and unloading. (Round your answer to three decimal places.)
p-value =
State your conclusion about method of loading and unloading.
Because the p-value > α = 0.05, method of loading and unloading is not significant.Because the p-value ≤ α = 0.05, method of loading and unloading is significant. Because the p-value ≤ α = 0.05, method of loading and unloading is not significant.Because the p-value > α = 0.05, method of loading and unloading is significant.
Find the value of the test statistic for type of ride.
Find the p-value for type of ride. (Round your answer to three decimal places.)
p-value =
State your conclusion about type of ride.
Because the p-value ≤ α = 0.05, type of ride is not significant.Because the p-value ≤ α = 0.05, type of ride is significant. Because the p-value > α = 0.05, type of ride is not significant.Because the p-value > α = 0.05, type of ride is significant.
Find the value of the test statistic for interaction between method of loading and unloading and type of ride.
Find the p-value for interaction between method of loading and unloading and type of ride. (Round your answer to three decimal places.)
p-value =
State your conclusion about interaction between method of loading and unloading and type of ride.
Because the p-value > α = 0.05, interaction between method of loading and unloading and type of ride is significant.Because the p-value > α = 0.05, interaction between method of loading and unloading and type of ride is not significant. Because the p-value ≤ α = 0.05, interaction between method of loading and unloading and type of ride is significant.Because the p-value ≤ α = 0.05, interaction between method of loading and unloading and type of ride is not significant.
2. You may need to use the appropriate technology to answer this question.
The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following data: SST = 282, SSA = 26, SSB = 22, SSAB = 179.Set up the ANOVA table. (Round your values for mean squares and F to two decimal places, and your p-values to three decimal places.)
| Source of Variation |
Sum of Squares |
Degrees of Freedom |
Mean Square |
F | p-value |
|---|---|---|---|---|---|
| Factor A | |||||
| Factor B | |||||
| Interaction | |||||
| Error | |||||
| Total |
Test for any significant main effects and any interaction effect. Use α = 0.05.
Find the value of the test statistic for factor A. (Round your answer to two decimal places.)
Find the p-value for factor A. (Round your answer to three decimal places.)
p-value =
State your conclusion about factor A.
Because the p-value ≤ α = 0.05, factor A is not significant.Because the p-value ≤ α = 0.05, factor A is significant. Because the p-value > α = 0.05, factor A is not significant.Because the p-value > α = 0.05, factor A is significant.
Find the value of the test statistic for factor B. (Round your answer to two decimal places.)
Find the p-value for factor B. (Round your answer to three decimal places.)
p-value =
State your conclusion about factor B.
Because the p-value ≤ α = 0.05, factor B is significant.Because the p-value ≤ α = 0.05, factor B is not significant. Because the p-value > α = 0.05, factor B is not significant.Because the p-value > α = 0.05, factor B is significant.
Find the value of the test statistic for the interaction between factors A and B. (Round your answer to two decimal places.)
Find the p-value for the interaction between factors A and B. (Round your answer to three decimal places.)
p-value =
State your conclusion about the interaction between factors A and B.
Because the p-value > α = 0.05, the interaction between factors A and B is not significant.Because the p-value ≤ α = 0.05, the interaction between factors A and B is not significant. Because the p-value ≤ α = 0.05, the interaction between factors A and B is significant.Because the p-value > α = 0.05, the interaction between factors A and B is significant.
In: Math
Saint Mary’s University jointly runs a dual degree program with the Beijing Normal University at Zhuhai. In order to do so, Saint Mary’s provides faculty to instruct in China. For the spring session scheduled to run from April 22nd to May 31st, 2019 Saint Mary’s had an individual prepared to instruct this course. This person entered into a contract with SMU which stated in part that the individual would instruct in China during the entirety of the spring session, but said nothing about cancellation by either party. At some point on or about late February, this individual advised Saint Mary’s that they would not be able to come to Zhuhai. Assume for the purposes of this assignment that the individual had been diagnosed with cancer, and was unable to travel.
In or about early March Professor Scott had been offered and had accepted a position as the new instructor by Saint Mary’s. A contract was entered into that included, among other things, clear instructions that he would need to secure the appropriate Visa that would allow him to travel to Zhuhai. As time was tight (in legal terms we say that time was of the essence) Scott was encouraged to go ahead and book flights and make the necessary arrangements in order to be in China to start classes on April 22.
In Canada, the Chinese embassy is responsible for issuing appropriate Visas for travel to China. In order to facilitate the processing of applications, the embassy utilizes an independent company known as the Chinese Visa Processing Centre Limited…this company is a separate entity from the government and operates at arm’s length from the embassy. Applications are filled out online, and when complete, the applicant must print the application form and attend in person at the offices of the Chinese Visa Processing Centre where they pay a fee and also provide biometric scans that enable the embassy to conduct their work. The Chinese Visa Processing Centre essentially pre screens visa applications to ensure conformity with the established decision parameters. If there are readily apparent issues, for example an expired passport or things of an administrative nature, then the Chinese Visa Processing Centre will hold an application pending the correction of the issue by the applicant. The Processing Centre also states that applicants who cannot pick up their passport in person must provide a prepaid pre-addressed return envelope so that the passport containing the Visa can be returned to the applicant.
Scott prepared the online application form as advised. Given the type of Visa required, Scott needed a letter, known as the Foreign Expert Invitation Letter issued by the provincial government in Guangdong, China. Although this letter was not mentioned in the contract, Saint Mary’s represented verbally that they would secure the letter for Scott. Saint Mary’s did, in fact secure the letter, which was advanced to Scott via email on March 19. Having completed the application, and with the letter in hand, Scott flew to Ottawa to deliver the visa application.
Before that however, Scott had booked flights from Halifax to Zhuhai that would have him arrive in China on April 19 in time to begin classes on the 22nd. Scott was instructed to secure cancellation insurance on all flights. Scott did, in fact, pay for and receive a policy of insurance that clearly stated that it would cover the cost of flights cancelled due to medical emergencies or death, including medical emergencies or death to immediate family members of the insured party.
While sitting in the departure lounge awaiting his return flight to Halifax, having attended at the Visa Processing Centre as required Scott received a telephone call from the Chinese Visa Processing Centre and was told that the embassy has already had a look at the Foreign Expert Invitation Letter. Scott was advised that the letter would not suffice because it lacked certain information, and also because it needed to be issued by the appropriate government authorities in the Guangdong Province. The letter had actually been issued by the University, in accordance with past practice This issue had not been raised for previous applications.
As a result of this problem, it became impossible to travel as planned and Scott advised his travel agent that the flights would need to be cancelled or changed. Further, Scott and officials at Saint Mary’s decided that he should not rebook any travel until it was absolutely certain that the new letter could be obtained.
On April 19, Scott received a different Foreign Expert Invitation Letter and forwarded it to the Chinese Visa Processing Centre. They acknowledged receipt on April 22 and indicated that he should receive confirmation that the Visa had been processed by April 26.
With this new knowledge, Saint Mary’s and Beijing Normal University at Zhuhai amended the start date of the course to May 6.
On April 26, Scott received word that his Visa had been processed and his passport had been placed in the provided pre-paid, pre-addressed envelope and put in the mail. The expected delivery date was April 29. Unfortunately, on April 29 it was discovered that the passport had been delivered to any entirely different address, not in Halifax Nova Scotia, but in Mississauga Ontario, 2000 kilometres away. The address label on the envelope that had been purchased from Canada Post had been tampered with before it was sold. When it was placed in the postal system by the Chinese Visa Processing Centre, it had two different addresses, and Canada Post picked one but they picked the wrong one. When contacted by Scott, Canada Post officials advised that once the envelope had been placed in the mailbox of the receiver, it became the receiver’s property, and Canada Post could not recover it because this would constitute theft. They took no responsibility for the envelope, saying it was the buyer’s problem.
Fortunately the passport was located. The individual that had the passport said that he would return it if Scott came to get it at his home. When Scott travelled to the home, the gentleman said he would only return it if Scott paid a significant reward. At first Scott declined, but the gentleman indicated that he would call the police and state that Scott was trespassing on his property. Scott felt he had no choice, and so he complied and made the payment.
When Scott returned to his hotel with the passport, the rain started to fall heavily. The stone walkway at the front of the hotel was quite slippery, and unfortunately Scott fell and injured his shoulder. Hotel staff would take no responsibility for the injury, stating Scott should have been more careful as it was raining. A sign on the wall of the hotel indicated that the paving stones could become slippery when wet, and patrons of the hotel were cautioned that the hotel accepted no responsibility for injuries. Unfortunately, the hotel concierge had left a luggage cart in front of the sign such that it was not visible.
In: Operations Management
Network Security: A process can be in one of three states:
running,
ready, and blocked. A job is a kind of process
and can be in one of three states: foreground, background, and
paused.
What’s the similarity between the three process states and the
three job states?
Hint: It’s not a one-to-one mapping.
In: Computer Science
| Business Traveler Rating of United Airlines | |
| 6 | 5 |
| 4 | 5 |
| 6 | 4 |
| 8 | 4 |
| 7 | 4 |
| 7 | 8 |
| 6 | 4 |
| 3 | 5 |
| 3 | 6 |
| 8 | 2 |
| 10 | 5 |
| 4 | 9 |
| 8 | 9 |
| 7 | 8 |
| 8 | 4 |
| 7 | 8 |
| 5 | 9 |
| 9 | 9 |
| 5 | 5 |
| 8 | 9 |
| 4 | 7 |
| 3 | 8 |
| 8 | 3 |
| 10 | |
| 8 | |
| 9 | |
| 6 |
United Airlines has surveyed 50 random business travelers. The business travelers were asked to rate their overall satisfaction with their experience with United Airlines, where 10 was the highest rating. Using the tools in Excel, develop a 95% confidence interval estimate (mean, low, high) of the population mean rating for United Airlines.
In: Statistics and Probability
E13.17 Contributions Received on Behalf of Others
The United Way receives contributions and distributes them to other NFP organizations. Some of its transactions for the current year are as follows:
1. Donors contribute $5 million, designated to specific unaffiliated NFP organizations. $3 million of this money is distributed according to donor wishes during the current year.
2. Donors contribute $2 million, to be distributed to unaffiliated NFP organizations selected by United Way. United Way distributes $1.8 million of these donations in the current year.
3. Donors contribute $1 million, to be distributed to a specific affiliated organization. United Way distributes $900,000 of these donations in the current year.
Required
Prepare journal entries to record the above activities. If the item affects net assets, identify the category affected.
In: Accounting